Define error codes while preserving binary compatibility - c++

I have my error codes (about 30 error codes) stored in an enum. A collegue warned me about it because if I change the numerical value of an enum, all code which uses my DLL will have to recompile or else the error codes become inconsistent. I understand the problem: enums become integer constants during the compile process, so the DLL uses the enum values which were valid at compile time, not at runtime as I would prefer.
My question is how I can do better. Please help me. In the following, I explain an idea of mine, but better ideas are welcome if my idea has severe disadvantages.
My first idea is to make a class and store the codes as static constant members
class ErrorCodes
{
public:
static const int ok;
static const int error1;
static const int error2;
};
and define their values in the .cpp
const int ErrorCodes:ok = 0;
const int ErrorCodes:error1 = -1;
const int ErrorCodes:error2 = -2;
Does this fix the above problem? What happens if I add or remove members? What happens if I change the values of the error codes?

Related

How to let the compiler do the offset computations for an odd polymorphism structure, with as little code as possible?

I am not sure if this is possible at all in standard C++, so whether it even is possible to do, could be a secondary way to put my question.
I have this binary data which I want to read and re-create using structs. This data is originally created as a stream with the content appended to a buffer, field by field at a time; nothing special about that. I could simply read it as a stream, the same way it was written. Instead, I merely wanted to see if letting the compiler do the math for me, was possible, and instead implementing the binary data as a data structure instead.
The fields of the binary data have a predictable order which allows it to be represented as a data type, the issue I am having is with the depth and variable length of repeating fields. I am hoping the example code below makes it clearer.
Simple Example
struct Common {
int length;
};
struct Boo {
long member0;
char member1;
};
struct FooSimple : Common {
int count;
Boo boo_list[];
};
char buffer[1024];
int index = 15;
((FooSimple *)buffer)->boo_list[index].member0;
Advanced Example
struct Common {
int length;
};
struct Boo {
long member0;
char member1;
};
struct Goo {
int count;
Boo boo_list[];
};
struct FooAdvanced : Common {
int count;
Goo goo_list[];
};
char buffer[1024];
int index0 = 5, index1 = 15;
((FooAdvanced *)buffer)->goo_list[index0].boo_list[index1].member0;
The examples are not supposed to relate. I re-used some code due to lack of creativity for unique names.
For the simple example, there is nothing unusual about it. The Boo struct is of fixed size, therefore the compiler can do the calculations just fine, to reach the member0 field.
For the advanced example, as far as I can tell at least, it isn't as trivial of a case. The problem that I see, is that if I use the array selector operator to select a Goo object from the inline array of Goo-elements (goo_list), the compiler will not be able to do the offset calculations properly unless it makes some assumptions; possibly assuming that all preceding Goo-elements in the array have zero Boo-elements in the inline array (boo_list), or some other constant value. Naturally, that won't be the case.
Question(s):
What ways are there to achieve the offset computations to be done by the compiler, despite the inline arrays having variable lengths? Unless I am missing something, I believe templates can't help at all, due to their compile-time nature.
Is this even possible to achieve in C++?
How do you handle the case with instantiating a FoodAdvanced object, by feeding a variable number of Goo and Boo element counts to the goo_list and boo_list members, respectively?
If it is impossible, would I have to write some sort of wrapper code to handle the calculations instead?

Conditionally Declaring an Enum at Runtime (C++)

I've come across some interesting findings relating to runtime detection that has spurred an interesting question. If I want to declare a global variable based off a condition, I can easily do so during pre-compilation with #ifdefs. However, this produces different binaries, and I am looking for a solution that can be realized during runtime so as to constrain behavior to a single binary.
Example
A classic example that I can perform with arrays or other data types (note, the data types here are all const and must remain so - mirroring the immutable behavior of an enum):
Original (Compile Time):
#ifdef CONDITION
static const int faveNums[] = {......};
#else
static const int faveNums[] = {******};
#endif
Modified (Run Time):
static const int conditonalFaveNums[] = {......};
static const int defaultFaveNums[] = {******};
static const int * const faveNums = IsConditionTrue() ? conditonalFaveNums : defaultFaveNums;
Common Pitfall (Scoping):
This is a common pitfall that will not work, as if/switch conditionals are scoped and therefore unable to be referenced later - thank goodness for the ternary operator!
if(IsConditionTrue())
{
static const int faveNums[] = {......};
}
else
{
static const int faveNums[] = {******};
}
Problem
However, the situation appears to change with enums. Let's try the run time solution, but with an enum this time:
enum conditionalFaveNums = {......};
enum defaultFaveNums = {******};
enum faveNums = IsConditionTrue() ? conditonalFaveNums : defaultFaveNums;
This will not compile.
Compile time defines (as with the first example) can solve this, but is there a way to solve this at run time by conditionally declaring a global enum in C++?
While you can't do exactly what you're asking - the difference between your array and enum examples being that the array is simply data, whereas the enum is a type, and type definitions must be resolvable at compile time - perhaps a more helpful answer is that this is a good thing.
Dynamic data should be represented in a dynamic data structure. std::set is a pretty close conceptual match to an enum, and provides many useful (and efficient) methods that may come in handy later. Even better might be defining an enum listing all possible values at compile time, and then dynamically constructing a set of these values based on runtime information. (The set is thus a proper subset of the enum's range.)
You cannot do this. Key points to remember:
Values of variables can be initialized differently based on run time information.
Types MUST be defined/set at compile time.
You can use
static const int * const faveNums = IsConditionTrue() ? conditonalFaveNums : defaultFaveNums;
since that says what faveNums is to be initialized to at run time, using run time information.
You cannot use
enum faveNums = IsConditionTrue() ? conditonalFaveNums : defaultFaveNums;
since that tries to define the type faveNums using run time information.

Pointers to pointers undefined reference c++ [duplicate]

I am working on a homework assignment, and I have almost everything done except for this obnoxious static value that our professor wishes us to use: value
The header file contains:
private:
static int value;
And we have to have a function calculate the value, like so:
static void calculate()
{
long a = 1L;
int count = 0;
while( a != 0 )
{
a = a << 1;
count++;
}
value = count;
}
This is essentially calculating the number of bits in a long, using bit shifting.
However, I am getting the error " undefined reference to `Class1::value'
I've spent the last hour and a half figuring this out, and it's killing me. Any help would be great, all searches have come up dead.
Thanks!
Update:
I included
int Class1::value = 0;
However, now I am getting an error saying "error: int Class1::value is private
In your *.cpp file add
int ClassName::value = 0;
This will allocate storage for a value.
The piece of code that you actually have in a class declaration just declares this variable (makes the compiler aware that such a variable exists). However, each variable must be declared and defined. A definition will make sure the storage is put aside for this variable and create a symbol your compiler was unable to find before.
You need to define a static data member in (.cpp) source file with following syntax:
datatype Your_ClassName::variable;

Should I use an enum or multiple const for non-sequential constants in c++?

I'm writing porting file-io set of functions from c into a c++ class. "Magic numbers" (unnamed constants) abound.
The functions read a file header which has a number of specific entries whose locations are currently denoted by magic numbers.
I was taught by a veteran programmer a couple years back that using "magic numbers" is inherently evil, and thus, I have since tried to avoid using unnamed constants in my port. So I want to create some sort of list of constants of where the entries are stored.
So far I've come up with two solutions that seem relatively safe -- use a namespace enclosed set of constants or a namespace enclosed enum.
Can I use either solution safely? Would there be any advantages to one over the other?
e.g.
OPTION 1
namespace hdr_pos {
const unsigned int item_1_pos=4;
const unsigned int item_2_pos=8;
const unsigned int item_3_pos=12;
const unsigned int item_4_pos=24;
const unsigned int item_5_pos=32;
};
OPTION 2
namespace hdr_pos {
enum e {
item_1_pos=4,
item_2_pos=8,
item_3_pos=12,
item_4_pos=24,
item_5_pos=32
};
};
Is there anyway to prevent duplicates, to catch if I change the positions due to a future update to the file header, but forget to change one of them?
Please keep this factual and non-subjective. If there is no advantage you know of, feel free to answer that.
Note: I would use more descriptive names, of course, in my actual implementation; I just called things item_<#>_... for examples sake...
I can see two advantages to using an enum. First, some debuggers can translate constants back into enum variable names (which can make debugging easier in some cases). Also, you can declare a variable of an enumerated type which can only hold a value from that enumeration. This can give you an additional form of type checking that you wouldn't have simply by using constants.
Checking to see if a value is duplicated might depend on your particular compiler. The easiest way to do so would probably be to write an external script that will parse your enum definition and report whether or not a value is duplicated (you can run this as part of your build process if you like).
I've dealt with this situation before, for error codes.
I have seen people using enums for error codes, and this pose some issues:
you can assign an int to the enum that doesn't not correspond to any value (too bad)
the value itself is declared in a header, meaning that error code reassignment (this happens...) breaks code compatibility, you also have to take care when adding elements...
you have to define all codes in the same header, even if often times some code are naturally restricted to a small portion of the application, because enums cannot be "extended"
there is no check that a same code is not assigned twice
you cannot iterate over the various fields of an enum
When designing my error codes solution, I thus chose another road: constants in a namespace, defined in source files, which address points 2 and 3. To gain in type safety though, the constants are not int, but a specific Code class:
namespace error { class Code; }
Then I can define several error files:
// error/common.hpp
namespace error
{
extern Code const Unknown;
extern Code const LostDatabaseConnection;
extern Code const LostNASConnection;
}
// error/service1.hpp
// error/service2.hpp
I didn't solved the arbitrary cast issue though (constructor is explicit, but public), because in my case I was required to forward error codes returned by other servers, and I certainly didn't want to have to know them all (that would have been too brittle)
However I did thought about it, by making the required constructor private and enforcing the use of a builder, we're even going to get 4. and 5. in a swoop:
// error/code.hpp
namespace error
{
class Code;
template <size_t constant> Code const& Make(); // not defined here
class Code: boost::totally_ordered<Code>
{
public:
Code(): m(0) {} // Default Construction is useful, 0 is therefore invalid
bool operator<(Code const& rhs) const { return m < rhs.m; }
bool operator==(Code const& rhs) const { return m == rhs.m; }
private:
template <size_t> friend Code const& Make();
explicit Code(size_t c): m(c) { assert(c && "Code - 0 means invalid"); }
size_t m;
};
std::set<Code> const& Codes();
}
// error/privateheader.hpp (inaccessible to clients)
namespace error
{
std::set<Code>& PrivateCodes() { static std::set<Code> Set; return Set; }
std::set<Code> const& Codes() { return PrivateCodes(); }
template <size_t constant>
Code const& Make()
{
static std::pair< std::set<Code>::iterator, bool > r
= PrivateCodes().insert(Code(constant));
assert(r.second && "Make - same code redeclared");
return *(r.first);
}
}
//
// We use a macro trick to create a function whose name depends
// on the code therefore, if the same value is assigned twice, the
// linker should complain about two functions having the same name
// at the condition that both are located into the same namespace
//
#define MAKE_NEW_ERROR_CODE(name, value) \
Make<value>(); void _make_new_code_##value ();
// error/common.cpp
#include "error/common.hpp"
#include "privateheader.hpp"
namespace error
{
Code const Unkown = MAKE_NEW_ERROR_CODE(1)
/// ....
}
A tad more work (for the framework), and only link-time/run-time check of the same assignment check. Though it's easy to diagnose duplicates simply by scanning for the pattern MAKE_NEW_ERROR_CODE
Have fun!
The title of your question suggests that the main reason you have doubts about using a enum is that your constants are non-iterative. But in C++ enum types are non-iterative already. You have to jump through quite a few hoops to make an iterative enum type.
I'd say that if your constants are related by nature, then enum is a pretty good idea, regardless of whether the constants are iterative or not. The main disadvantage of enums though is total lack of type control. In many cases you might prefer to have strict control over the types of your constant values (like have them unsigned) and that's something enum can't help you with (at least yet).
One thing to keep in mind is that you can't take the address of an enum:
const unsigned* my_arbitrary_item = &item_1_pos;
If they're purely constants and require no run-time stuff (like can't init enum with non-enum value) then they should just be const unsigned ints. Of course, the enum is less typing, but that's besides the point.

Accessing any structs members at run-time

Is it possible to get access to an individual member of a struct or class without knowing the names of its member variables?
I would like to do an "offsetof(struct, tyname)" without having the struct name or member variable name hard coded amoungst other things.
thanks.
Sure. If you have a struct and you know the offset and the type of the member variable, you can access it using pointers.
struct my_struct {
int member1;
char member2;
short member3;
char member4;
}
...
struct my_struct obj;
short member3 = *((short*)((char*)&obj + 5));
That'll get the value of member3, which is 5 bytes on from the start of obj on an x86 computer. However, you want to be careful. First of all, if the struct changes, your data will be garbage. We're casting all over the place, so you get no type safety, and the compiler won't warn you if something's awry. You'll also need to make sure the compiler's not packing the struct to align variables to word boundaries, or the offset will change.
This isn't a pleasant thing to do, and I'd avoid it if I were you, but yes, it can be done.
C and C++ are compiled languages without built-in "reflection" features. This means that regardless of what you do and how you do it, one way or another the path will always start from an explicit hard-coded value, be that a member name or an compile-time offset value. That means that if you want to select a struct member based on some run-time key, you have no other choice but to manually create a mapping of some kind that would map the key value to something that identifies a concrete struct member.
In C++ in order to identify a struct member at run-time you can use such feature as pointers-to-members. In C your only choice is to use an offset value.
Another issue is, of course, specifying the type of the members, if your members can have different types. But you provided no details about that, so I can't say whether you need to deal with it or not.
We had a similar problem some years ago: A huge struct of configuration information that we wanted to reflect on. So we wrote a Perl script to find the struct, parse its members, and output a C++ file that looked like:
struct ConfField
{ const char* name;
int type;
size_t offset;
};
ConfField confFields[] = {
{ "version", eUInt32, 0 },
{ "seqID", eUInt32, 4 },
{ "timestamp", eUInt64, 8 },
// ... lots more ...
{ 0, 0, 0 }
};
And we'd feed the script with the output from gcc -E.
Nowadays, I understand that gccxml can output an XML file representing any C++ source that gcc can compile, since it actually uses the g++ front end to do the parsing. So I'd recommend pairing it with an XML-parsing script (I'd use Python with the lxml library) to find out everything you ever wanted to know about your C++ source.
Somewhere in your code you need to reference the data member in the struct. However you can create a variable that is a pointer to a struct data member and from then on you no longer need to reference it by name.
struct foo
{
int member1;
int member2;
};
typedef int (foo::*intMemberOfFoo);
intMemberOfFoo getMember()
{
if (rand() > RAND_MAX / 2) return &foo::member1;
else return &foo::member2;
}
foo f;
void do_somthing()
{
intMemberOfFoo m = getMember();
f.*m = 0;
}
The technical answer is 'yes' because C++ is Turing-complete and you can do almost anything if you try hard enough. The more practical answer is probably 'no' since there is no safe and easy way of doing exactly what you want.
I agree with GMan. What exactly are you trying to do that makes you think you need this technique?
Well you will have to set up some stuff first, but it can be done. Expanding on Samir's response
struct my_struct {
int member1;
char member2;
short member3;
char member4;
}
you can create a table of offsets:
my_struct tmp;
int my_struct_offsets[4]={
0,
(char*)&(tmp.member2)-(char*)&(tmp.member1),
(char*)&(tmp.member3)-(char*)&(tmp.member1),
(char*)&(tmp.member4)-(char*)&(tmp.member1)
}
this will take into account different alignments on different systems