I'm looking to pull data from some code, to do that I thought I could use regex.
An example of the code I have is:
If IsNumeric(varCS) And IsNumeric(varGTV) And IsNumeric(varTV) Then
logInfo("GO")
shtDst.Range("D6").Value = shtSrc.Cells(varCS, varGTV).Value
shtDst.Range("G104").Value = shtSrc.Cells(varCS, varTV).Value
I would like the result to be:
"D6"
"G104"
The regex I've tried is:
.*(?:Range\((.*)\))?.*
and replacing with:
\1
However this results in just blank lines.
I've looked at lookahead and lookbehind but those seem to require a fixed length string.
I've been using Notepad++ plus various online regex test sites to verify my results.
Have a try with (don't make Range... optional):
Ctrl+H
Find what: ^(?:.*?Range\((.+?)\).*?|.+)$
Replace with: $1
This is working with the given example.
Try replacing [\S\s]*?("[^"]*?").* with $1\r\n (Example)
Related
I would like to append _OLD to the end of each strings that starts with SR_ but before the symbol ' or without it
For example my text is the following:
SR_Apple
When the 'SR_APPLE' rotten, we must discard it.
I would like the find and replace to do:
SR_Apple_OLD
When the 'SR_APPLE_OLD' rotten, we must discard it.
I have tried (SR_*)+$.*(?='\s) based on what i Learned but no luck so far. Please help. Thx in Adv
For simple cases you should be able to use
Find: (\bSR_[\w]+)
Replace: $1_OLD
(\bSR_.+?)('|$) and $1_OLD$2 could also work if the text after SR_ is more complex
The lookbehind you're using is only matching the string if it ends with a ' so it won't find the text not in quotes.
regex101 is a useful tool for debugging expressions
Given this example text:
<abr:rules>
<abr:ruleTypeDefinition>
<abr:code>ABB</abr:code>
<abr:ownership>
<abr:owner organization="NT" application="DCS" subapplication="FM"/>
...lines...
...........
</abr:rules>
<abr:rules>
<abr:ruleTypeDefinition>
<abr:code>ADE</abr:code>
<abr:ownership>
<abr:owner organization="NT" application="DCS" subapplication="CM"/>
...lines...
...........
</abr:rules> (end of group)
I would like to find and remove all that goes from <abr:rules> to </abr:rules> with the condition that subapplication IS NOT "CM". Organization and application are the same, <abr:code> it's any string.
What I tried so far is
<abr:rules>\n<abr:ruleTypeDefinition>\n<abr:code>[a-zA-Z0-9]{3,}<\/abr:code>\n<abr:ownership>\n<.*"(FM|PSD|SSC)"\/>\n(?s).*?\n<\/abr:rules>\n
which works but only because I know the other subapplication names.
Is there any way to do it with Regex only ?
Try the following find and replace:
Find:
<abr:rules>((?!subapplication=).)*subapplication="(?!CM")[^"]+"((?!</abr:rules>).)*</abr:rules>
Replace:
(empty string)
Demo
Note: The above pattern will only work if you enable dot in Notepad++ to match newlines. If you don't want to do that, then you may use [\S\s] instead of dot.
You should not use regex for xml, you can read why here:
https://stackoverflow.com/a/1732454/3763374
Instead you can use some parser like Xpath
I'm trying to select text between ></ . Example below I want "text"
>text</
but I'm unable to do so.
tried the following but it doesn't like the slash at the end of the regex
\>(.*?)\<\
I'm trying to do this in TextPad. How is this supposed to be done?
I'm ultimately wanting to delete all text between these two characters so all I'm left with is something like: <element></element>
RegEx wise, you can use 3 groupings and for the replace only use the first and 3rd group: \1\3.
Find: (>)(.*)(</)
Replace: \1\3
Try doing:
\>(.*?)\<\/
The regex that you were trying would actually have given error because you had a \ and nothing after that.
You are close.. use the following:
(>).*?(<\/)
And replace with \1\2
See DEMO
OR
You can use lookbehind and lookaheads:
(?<=>)(.*?)(?=<\/)
And replace with '' (empty string)
See DEMO
Within Notepad++, I want to replace many instances of the type ``string'' by \command{string} where string can be any string of characters. I am fairly close to what I want to achieve with:
Find: (?<=``)(.*?)(?='')
Replace: \\command{\1}
There is still a problem. With the regex code above, instead of \command{string} I get ``\command{string}'' and I am not sure why the `` and '' are not removed?
It is because you are using lookaround assertions. Lookaround (zero-width) assertions only assert that a position can be matched and do not "consume" any characters on the string. You can use the below regular expression.
Find: ``([^']+)''
Replace: \\command{\1}
You need to wrap everything into a capture group and use that. NP++ seems to not support lookahead/behind, but you dont need that for this specific case anyway:
``([^']+)'' -> \\command{\1}
This will make sure it does not match two commands (longest match) in something like:
run ``ls -l'' or ``ls -a''
Im trying to use the following regex to search and replace in multiple files in notepad++
([^\n]*)(state="1")([^\n]*)*.
This searches and finds state="1" in the first line of each file and works fine.
However, when I try to replace state="1" using:
Replace with: $1 state="5"
it cuts off the rest of the line.
I thought that it might be possible to get the rest of the line using:
Replace with: $1 state="5" $2
However, $2 doesnt seem to exist as a variable.
Is there some way to attach the rest of the line into variable $2?
Cheers
Heres an image to show how
(?=\A[^\n]*)state="1"
is not working
Ive updated my version of notepad++ and everything
Each capture group, (…), is assigned a number, so $2 represents the second capture group, (state="1"). The remainder of the line is captured in $3.
Either remove the capture group around state="1":
([^\n]*)state="1"([^\n]*)*.
Or use $3:
Replace with: $1 state="5" $3
Also, given the simplicity of the task, I don't see why you couldn't just search for state="1" and replace with state="5". There doesn't seem to be any need for regular expressions here.
Update There's nothing in the pattern listed so far which limits the result to only matching strings on the first line. If you need that I'd recommend using a pattern like this:
(?=\A[^\n]*)state="1"
With these settings:
Update There seems to be some strange behavior with the \A (beginning of text) anchor inside the lookbehind. Removing from the lookbehind seems to work. Try this pattern:
\A([^\n]*)state="1"
And replace with:
$1state="5"
All the other settings should be fine.