It's possible to use variable inside forms.py? I'm using field with choices based on queryset from Platform model. My url and view contain this id but I don't know how to give this to forms.py to my queryset.
forms.py:
class OrderCreateForm(forms.ModelForm):
platform = forms.CharField(choices=Platform.objects.filter(client_id=variable_from_view_or_url).values_list('id', 'name').order_by('id'))
class Meta:
model = Order
fields = ('price', 'deadline', 'finished', 'client', 'platform')
view.py:
#user_passes_test(lambda u: u.is_staff, login_url='/account/login/')
def order_create(request, request_client_id):
dict = {}
dict['form_order'] = OrderCreateForm()
return render(request, 'panel/order/form.html', dict)
Yes and no.
The way you are doing it you can't but you can define the choices in the init method of the form
def __init__(self, client_id, *args, **kwargs):
super(OrderCreateForm, self).__init__(*args, **kwargs)
self.fields['platform'].choices = Platform.objects.filter(client_id=client_id).values_list('id', 'name').order_by('id')
then call it with an id
OrderCreateForm(request_client_id)
Related
I have one model name is cityform
i want to get url parmeter in this CityFrom hwo can i do this?
here is my url
path('state/city/<int:id>/', City.as_view(), name="city")
http://localhost:8000/country/state/city/3/
here is my form
class
CityFrom(forms.ModelForm):
def __init__(self, *args, **kwargs):
super(CityFrom,self).__init__(*args, **kwargs)
print(args)
print(kwargs)
self.fields['state'] = forms.ModelChoiceField(
empty_label = 'Select',
queryset = State.objects.all()
)
class Meta:
model = City
fields = ('state', 'name')
in this form i want to access id = 3
here is my view
from django.views import View
class City(View):
def get(self, request, *args, **kwargs):
Forms = CityFrom()
return render(request, 'albums/add.html', {'Forms': Forms})
Pass url parameter as keyword argument from views.py as following.
form = CityFrom(id=kwargs.get("id"))
To get the id in your forms.py, use following code in your form's __init__ method.
self.id = kwargs.get('id')
Your form should look like this.
CityFrom(forms.ModelForm):
def __init__(self, *args, **kwargs):
self.id = kwargs.get('id')
super(CityFrom,self).__init__(*args, **kwargs)
self.fields['state'] = forms.ModelChoiceField(
empty_label = 'Select',
queryset = State.objects.all()
)
class Meta:
model = City
fields = ('state', 'name')
* Call super after getting the id in your form as above. Here order of calling super is important.
Try
CityFrom(forms.ModelForm):
def __init__(self, *args, **kwargs):
self.id = kwargs.pop('id')
super(CityFrom,self).__init__(*args, **kwargs)
I want to set a dynamic variable into queryset of forms.py , I used __init__ to pass the dynamic variable , I think the code in forms.py is correct, the problem is how to pass the variable in views?
forms.py :
class ContainerForm(forms.ModelForm):
vehicle=forms.ModelChoiceField(required=False,queryset=Vehicle.objects.all(),widget=forms.Select(attrs={'class':'form-control'}))
def __init__(self, *args, **kwargs):
vehicle_id = kwargs.pop('vehicle_id',None)
super(ContainerForm, self).__init__(*args, **kwargs)
if vehicle_id:
self.fields['vehicle'].queryset = Vehicle.objects.filter(id=vehicle_id)
views.py
class ContainerCreate(CreateView):
form_class = ContainerForm(id= vehicle_id)
template_name = 'vehicule_app/container_form.html'
the error said :
Exception Value:'ContainerForm' object is not callable
If you want to use the vehicle_id from the URL, then you can exclude the field from the model form:
class ContainerForm(forms.ModelForm):
class Meta:
model = Container
exclude = ['vehicle']
You can then fetch the parameter from self.kwargs, and set the value on the form's instance in get_form_kwargs:
class ContainerCreate(CreateView):
form_class = ContainerForm
template_name = 'vehicule_app/container_form.html'
def get_form_kwargs(self):
kwargs = super(ContainerCreate, self).get_form_kwargs()
if kwargs['instance'] is None:
kwargs['instance'] = Container()
kwargs['instance'].vehicle_id = self.kwargs['pk'] # Fetch the vehicle_id from the URL
return kwargs
Note that the above code will not validate the id from the URL. The user could change it to any value they like.
If you want to keep the vehicle field in the form but with a single choice, then override the __init__ method and set the queryset.
class ContainerForm(forms.ModelForm):
class Meta:
model = Container
def __init__(self, *args, **kwargs):
vehicle_id = kwargs.pop('vehicle_id')
self.fields['vehicle'].queryset = Vehicle.objects.filter(id=vehicle_id)
Then in the get_form_kwargs method, add vehicle_id to kwargs instead:
class ContainerCreate(CreateView):
form_class = ContainerForm
template_name = 'vehicule_app/container_form.html'
def get_form_kwargs(self):
kwargs = super(ContainerCreate, self).get_form_kwargs()
kwargs['vehicle_id'] = self.kwargs['pk']
return kwargs
I want for filter a ModelChoiceField with the current user. I found a solution very close that I want to do, but I dont understand
Django: How to get current user in admin forms
The answer accepted says
"I can now access the current user in my forms.ModelForm by accessing self.current_user"
--admin.py
class Customer(BaseAdmin):
form = CustomerForm
def get_form(self, request,obj=None,**kwargs):
form = super(Customer, self).get_form(request, **kwargs)
form.current_user = request.user
return form
--forms.py
class CustomerForm(forms.ModelForm):
default_tax = forms.ModelChoiceField(queryset=fa_tax_rates.objects.filter(tenant=????))
class Meta:
model = fa_customers
How do I get the current user on modelchoice queryset(tenant=????)
How do I call the self.current_user in the modelform(forms.py)
Override __init__ constructor of the CustomerForm:
class CustomerForm(forms.ModelForm):
...
def __init__(self, *args, **kwargs):
super(CustomerForm, self).__init__(*args, **kwargs)
self.fields['default_tax'].queryset =
fa_tax_rates.objects.filter(tenant=self.current_user))
Queryset in the form field definition can be safely set to all() or none():
class CustomerForm(forms.ModelForm):
default_tax = forms.ModelChoiceField(queryset=fa_tax_rates.objects.none())
Just to sum up the solution because it was very hard for me to make this work and understand the accepted answer
In admin.py
class MyModelForm (forms.ModelForm):
def __init__(self, *args,**kwargs):
super (MyModelForm ,self).__init__(*args,**kwargs)
#retrieve current_user from MyModelAdmin
self.fields['my_model_field'].queryset = Staff.objects.all().filter(person_name = self.current_user)
#The person name in the database must be the same as in Django User, otherwise use something like person_name__contains
class MyModelAdmin(admin.ModelAdmin):
form = MyModelForm
def get_form(self, request, *args, **kwargs):
form = super(MyModelAdmin, self).get_form(request, *args, **kwargs)
form.current_user = request.user #get current user only accessible in MyModelAdminand pass it to MyModelForm
return form
I have a model like so:
class GiveAbsolute(serializers.Field):
def to_native(self,value):
# this where it give an error (self doesn't have request)
# what i want it to give full url
# like: http://www.blabla.com/othermodel/1
return reverse('link_to_othermodel',
args=[value],
request=self.request)
class SomethingSerializer(serializers.ModelSerializer):
# field with foreign key
othermodel = GiveAbsolute(source="othermodel.id")
class Meta:
model=Something
fields("fields1","othermodel")
is there a way to achieve this ?
thanks
From the source
The request object is an entry of the context dictionary. ie.
request = self.context.get('request')
In your case, just do:
self.request = self.context.get('request')
then build the url
self.request.build_absolute_uri(reverse('some_url_name'))
Based on the answer of mariodev, here is a reusable solution for Models ; I use it to provide URLs to service (see them as metheds) on django models.
Reusable components
serializers.py
class RequestAwareSerializer(serializers.ModelSerializer):
"""
A serializer which fields can access the request object.
"""
def __init__(self, *args, **kwargs):
self.request = kwargs.pop('request', None)
super(RequestAwareSerializer, self).__init__(*args, **kwargs)
class APIMethodField(serializers.Field):
""" To get the absolute URL of a method accessible via the API
"""
def __init__(self, url_action_name, *args, **kwargs):
self._url_name = url_action_name
super(APIMethodField, self).__init__(source='*', *args, **kwargs)
def to_native(self, obj):
"""
#param objid the ID of the object
#param method_url_name, the name of the url, as in urls.py
"""
return reverse_lazy(self._url_name, args=[obj.id],
request=self.parent.request)
views.py
class ChattyModelViewSet(ModelViewSet):
""" ModelViewSet which informs the serializer about the request
(abstract)
"""
def get_serializer(self, instance=None, data=None,
files=None, many=False, partial=False):
serializer_class = self.get_serializer_class()
context = self.get_serializer_context()
return serializer_class(instance, data=data, files=files, many=many,
partial=partial, context=context,
request=self.request)
Example use
urls.py
url(r'^v1/maildomain/(?P<maildomain_id>\d+)/check/$',
views.MailDomainDetail.as_view(), name='maildomain_dns_check')
serializers.py
class MailDomainSerializer(RequestAwareSerializer):
checkdns_url = APIMethodField(url_action_name='maildomain_dns_check')
class Meta:
model = MailDomain()
fields = ('name', 'checkdns_url')
views.py
class MailDomainView(ChattyModelViewSet):
model = MailDomain
serializer_class = MailDomainSerializer
The only thing in DRF, that has an access to request object is the view, so you need to figure out how to pass your request from view to serializer, for example in generic ListView you can use get_serializer.
Then, when you already have it in your serializer, you can use self.parent (which is a parent serializer) to capture it from the field itself:
class GiveAbsolute(serializers.Field):
def to_native(self,value):
return reverse('link_to_othermodel',
args=[value],
request=self.parent.request)
class SomethingSerializer(serializers.ModelSerializer):
# field with foreign key
othermodel = GiveAbsolute(source="othermodel.id")
class Meta:
model=Something
fields=("fields1","othermodel")
def __init__(self, *args, **kwargs):
self.request = kwargs.pop('request', None)
super(SomethingSerializer, self).__init__(*args, **kwargs)
class SomethingView(generics.ListAPIView):
model = Something
serializer_class = SomethingSerializer
def get_serializer(self, instance=None, data=None,
files=None, many=False, partial=False):
serializer_class = self.get_serializer_class()
context = self.get_serializer_context()
return serializer_class(instance, data=data, files=files, many=many,
partial=partial, context=context, request=self.request)
I want to use forms.ModelMultipleChoiceField in a form. I know it takes a queryset, however the query set I will be using take the param user which I normally pass in a view using request.user. However this is in a form, how do I pass request.user? do I need to?
Entry.objects.filter(request.user)
You should override your form's init method:
class MyForm(forms.ModelForm):
class Meta:
model = Entry
def __init__(self, user=None, *args, **kwargs):
super(MyForm, self).__init__(*args,**kwargs)
if user is not None:
form_choices = Entry.objects.filter(user)
else:
form_choices = Entry.objects.all()
self.fields['my_mfield'] = forms.ModelMultipleChoiceField(
queryset=form_choices
)
and in your views, when it's time to instantiate the form:
form = MyForm(request.user)
or
form = MyForm()