To implement the logic when contructed object starts background thread for real work, I'm using a pattern like this (simplified):
class A {
std::thread t{&A::run, this};
std::atomic_bool done;
// variables are the question about
std::vector<std::thread> array_for_thread_management;
// ... and other members
protected:
void run() {
...
array_for_thread_management.push_back([](){...});
...
}
public:
A() = default;
// all other constructors deleted because of used
// some members like std::atomic_bool done;
~A() {
done = true;
bi::named_condition cnd{bi::open_only, "cnd"};
cnd.notify_one();
if (t.joinable())
t.join();
for(std::thread& worker : array_for_thread_management) {
if (worker.joinable()) worker.join();
}
}
};
If I'm adding a push of child threads in primary background thread into a vector in run() member, the object hangs on destructor.
even there is no real threads in a vector, just started this without connections from outside and try to stop this by destructor
Of course, once you have this pointer in your run method, you can access class members via this pointer. I guess the problem with your code is that the thread is spawned before any other members are initialized, as it is the first member in your class definition. I suspect with the following definition of class A you'll have no problems with accessing member variables:
class A {
std::atomic_bool done;
// variables are the question about
int i;
std::string s;
std::vector<std::string> v;
// and only after everything above is initialized:
std::thread t{&A::run, this}; // spawn a thread
// ...
}
However, personally I would prefer having a separate method start() which spawns a thread to spawning it inside class constructor implicitly. It may look like this:
class A
{
std::unique_ptr<std::thread> t;
std::atomic<bool> some_flag;
public:
void start()
{
t.reset(new std::thread(&A::run, this));
}
private:
void run()
{
some_flag.store(true);
}
};
Related
I need to work with the same mutex and unique_lock across the main function and class instances. However, I am having trouble assigning the mutex/unique_lock address to a class member variable (that is a mutex&).
This is what I have:
Worker.h
class Worker
{
private:
std::mutex &m_mu;
std::unique_lock<std::mutex> &locker;
public:
void start(std::mutex &mu, std::unique_lock<std::mutex> &locker);
};
Worker.cpp
void Worker::start(std::mutex &mu, std::unique_lock<std::mutex> &locker)
{
this->mu = mu; // error
this->locker = locker; // error
}
I tried doing this->mu(mu); but that doesn't work either. Is there anything I can do to make this work?
Thanks.
You need to pass the mutex reference when you construct your class.
Worker::Worker(std::mutex &mu, std::unique_lock<std::mutex> &locker)
:m_mu(mu), locker(locker)
{}
That's the only place you can initialize a reference. Once it's constructed, you cannot change what it references.
Why do you need the locker? The mutex makes the synchronization, the lock is just a RAII object to ease acquiring the mutex.
You don't need to pass the lock object to the function. As long as the class is referring to the correct mutex you can lock the mutex inside the function like this:
class Worker
{
private:
std::mutex& m_mu;
public:
Worker(std::mutex& mu): m_mu(mu) {} // bind reference during initialization
void start();
};
// Worker.cpp
void Worker::start()
{
std::unique_lock<std::mutex> locker(m_mu); // lock the shared resource
// Do something with it here
}
int main()
{
std::mutex mu;
std::vector<Worker> workers(4, Worker(std::ref(mu)));
// etc...
}
Suppose I have the following code
#include <thread>
#include <iostream>
#include <atomic>
struct FooBase {
void start(){
run_condition_ = true;
t_ = std::thread([this](){
thread_handler();
});
}
virtual ~FooBase(){
run_condition_ = false;
if(t_.joinable())
t_.join();
}
protected:
virtual void thread_handler() = 0;
std::atomic_bool run_condition_{false};
private:
std::thread t_;
};
struct Foo : FooBase {
void thread_handler() override {
while(run_condition_){
std::cout << "Foo derived thread.." << std::endl;
}
}
};
int main(){
Foo f;
f.start();
getchar();
return 0;
}
Here I think because the destructor of the derived class Foo is called before FooBase the thread_handler vtable lookup happens in the base class IF the thread has not yet joined (still running) when the destructor of Foo is done. Since FooBase::thread_handler is pure virtual I am essentially guranteed a sigabort.
How do I guard against this? I hack my way through by not having thread_handler as pure virtual
virtual void thread_handler(){}
But I am lost as to how I can guard against this in the baseclass itself, I can implement a join_thread interface in the base class and call this from every derived class, but this seems cumbersome.
There's two issues here, neither of which match precisely what you described.
Your thread only gets stopped in ~FooBase(). This means that if Foo::thread_handler ever reads or writes to any of its members, they will get destroyed out from under it before the thread is stopped.
It you get to the destructor fast enough, it's possible that start() won't have actually invoked thread_handler() on the new thread by the time Foo gets destroyed - which will lead to the pure virtual call.
Either way, you need to ensure that by the time Foo is destroyed, anything related to thread_handler is done. This implies that every derived class from FooBase has to have, in its destructor:
run_condition_ = false;
if (t_.joinable()) {
t_join();
}
Setting aside that this directly doesn't work because t_ is private (you could wrap that into a protected stop()), it's an awkward design if all of your derived classes need to do something special just to work. You could instead put FooBase into its own class that just takes an arbitrary callable as an argument:
class joining_thread {
public:
joining_thread() = default;
~joining_thread() { stop(); }
bool running() const { return run_condition_.load(); }
template <typename... Args>
void start(Args&&... args) {
run_condition_ = true;
t_ = std::thread(std::forward<Args>(args)...);
}
void stop() {
run_condition_ = false;
if (t_.joinable()) t_.join();
}
private:
std::thread t_;
std::atomic_bool run_condition_{false};
};
And then your Foo can just have that as a member:
class Foo {
public:
void start() {
t_.start([this]{
while (t_.running()) { ... }
});
}
private:
// just make me the last member, so it's destroyed first
joining_thread t_;
};
That's still a little awkward with the whole running() thing, but hopefully the idea makes sense.
What you describe is not possible. You call "start" after you have constructed the object. The object is at that stage valid. You have avoided the common problem of calling a virtual function in the constructor, which would have caused issues. There is something called a memory barrier that is implied by any thread calls, so you can count on the fact the new thread will start with a view of memory that existed at the point it was created. Any thing that existed AND was not changed, is fine.
Your problem (as described in another answer) is that you can exit and destroy the object (and it's vtable), before the thread is complete.
The simplest fix for this is use a packaged task. Calling "get" on the future ensures the task is finished before you continue. Consider the code below
#include "stdafx.h"
#include <thread>
#include <iostream>
#include <atomic>
#include <future>
int main()
{
std::atomic<bool> stop{ false };
std::future<void> sync;
std::packaged_task<void()> task([&stop]()
{
while (!stop)
{
std::cout << "Running\n";
}
});
std::thread thread([&task]() {task();});
getchar();
stop = true;
task.get_future().get();
thread.join();
return 0;
}
I'm looking to run a thread in a base class that constantly calls pure virtual method in that class that's overridden by a derived class.
For starting the thread, I've no issue as I can call an HasInitalized() function after it's been constructed. Therefore the thread is started after the class is fully constructed.
However, as the class' lifetime is managed by a shared_ptr, I cannot call a similar method for stopping the thread. If I stop the thread in the destructor, it will cause a seg-fault as the derived class is destroyed before the base and therefore will try to call a function that's not there.
I'm aware I can call a stop function from the derived class but would rather not have to on every instance of the derived class.
Is there a way around this.
Example:
#include "boost/thread.hpp"
class BaseClass
{
public:
BaseClass()
{
}
// Start the thread
void Start()
{
_thread = boost::thread(&BaseClass::ThreadLoop, this);
}
virtual ~BaseClass()
{
_thread.interrupt();
_thread.join();
}
private:
// Will loop until thread is interupted
void ThreadLoop()
{
try
{
while(true)
{
DoSomethingInDerivedClass();
boost::this_thread::interruption_point();
}
}
catch(...)
{
}
}
boost::thread _thread;
protected:
virtual void DoSomethingInDerivedClass() = 0;
};
class DerivedClass : public BaseClass
{
DerivedClass()
{
}
~DerivedClass()
{
// This gets called before base class destructor.
}
protected:
void DoSomethingInDerivedClass();
};
I don't think you will be able to avoid repeating the call to join the thread in the destructor of each derived class. If a thread depends on a non-static object o, then it's a good idea to have a clear ownership relation to guarantee the validity of the object:
The thread should own o and the destruction of o will be handled by the destructor of the thread object, after the joining.
o should own the thread and should join the thread in it's own destructor.
You've chosen the 2nd approach, except the thread depends on the derived object, but the derived object doesn't own the thread directly but through the sub-object (the base-object). Since the thread depends on the derived object, it must be joined in the derived object's destructor.
You should separate the two behaviours: a class to run and join the thread, the base class for the functional hierarchy.
class Runner {
public:
explicit Runner(std::shared_ptr<BaseClass> ptr) : m_ptr(ptr) {
m_thread = boost::thread(&Runner::ThreadLoop, this);
}
~Runner() {
m_thread.interrupt();
m_thread.join();
}
private:
void ThreadLoop() {
try {
while(true) {
m_ptr->DoSomethingInDerivedClass();
boost::this_thread::interruption_point();
}
} catch(...) {
}
}
std::shared_ptr<BaseClass> m_ptr;
std::thread m_thread;
};
My recommendation would be to use a weak_ptr to know when the object's lifetime is over:
The factory instantiates the (derived) object and stores it in a shared_ptr
The factory instantiates the watchdog class and passes it a weak_ptr to the new object
The watchdog thread can now check if the weak pointer is expired each time it needs to access it. When it is expired, the thread will terminate itself.
Here is an example (instead of a factory, I just used main):
#include <thread>
class BaseClass
{
public:
virtual ~BaseClass() = default;
virtual void DoSomethingInDerivedClass() = 0;
};
class DerivedClass : public BaseClass
{
public:
void DoSomethingInDerivedClass() override {}
};
// Will loop until weak_base expires
void ThreadLoop(std::weak_ptr<BaseClass> weak_base)
{
try
{
while (true)
{
std::shared_ptr<BaseClass> base = weak_base.lock();
if (base) {
base->DoSomethingInDerivedClass();
}
else {
break; // Base is gone. Terminate thread.
}
}
}
catch (...)
{
}
}
int main()
{
std::shared_ptr<DerivedClass> obj = std::make_shared<DerivedClass>();
std::thread([&] { ThreadLoop(obj); }).detach();
return 0;
}
Note that there is no need to explicitly stop the thread, since it will stop itself as soon as it detects that the object's lifetime is over. On the other hand, note that the thread may slightly outlive the lifetime of the being-watchted object, which could be considered bad design (it could e.g. defer program termination). I guess one could work around that by joining with the thread in the base class destructor, after signalling that it should terminate (if not already terminated).
I have a class that has a Start method to start a thread that executes the virtual ThreadFunction at a predefined interval. The Stop method sets an event and waits until the the thread terminates (by a WaitForSingleObject on the thread handle).
In the destructor of MyThread, I call the Stop method. So whenever I delete the instance, I'm sure the thread is stopped before the delete returns.
class MyThread
{
void Start();
void Stop();
~MyThread() { Stop(); }
virtual VOID ThreadFunction() { }
};
Next I have a class that derives from MyThread:
class A : MyThread
{
virtual VOID ThreadFunction()
{
for (int i = 0; i < 1000; i++)
TestFunction();
}
void TestFunction() { // Do something }
};
Consider this code:
A a = new A();
a->Start();
delete a;
The problem is that delete a will first call the destructor of A before it will call the destructor of MyThread right? So if the thread was executing the for-loop in the ThreadFunction, the Stop method will be called after a has been destructed. This can lead to an access violation, when ThreadFunction calls TestFunction on a destructed instance.
A solution would be to add a destructor to class A that calls the Stop method, like this:
class A : MyThread
{
~A()
{
Stop();
}
}
But because I have a more complex class hiërarchy, that involves multiple inherited classes, this would mean I have to call the Stop method in each destructor, which would result in the Stop method being called plenty of times for only one instance that needs to be deleted.
Is there any other way to tackle this problem?
Your destructor in MyThread should be defined as 'virtual'.
class A{
public:
A(){cout<<"A"<<endl;}
virtual ~A(){cout<<"~A"<<endl;}
};
class B : public A{
public:
B(){cout<<"B"<<endl;}
~B(){cout<<"~B"<<endl;}
};
int main(){
A* b = new B();
cout<<"do something"<<endl;
delete b;
b = NULL;
return 0;
}
The result is:
A
B
do something
~B
~A
and when it doesn't use virtual, The result is:
A
B
do something
~A
As Rolle and R. Martinho Fernandes suggested, I needed to separate the two concerns.
class MyThread should not start or stop itself as its responsibility should be limited to the code it executes and not to the lifetime of the thread.
So the solution was to stop the thread from an other class (the same class that started the thread) which is responsible for the lifetime of the thread.
I'm trying to use std::thread from C++11. I couldn't find anywhere if it is possible to have a std::thread inside a class executing one of its function members. Consider the example below...
In my try (below), the function is run().
I compile with gcc-4.4 with -std=c++0x flag.
#ifndef RUNNABLE_H
#define RUNNABLE_H
#include <thread>
class Runnable
{
public:
Runnable() : m_stop(false) {m_thread = std::thread(Runnable::run,this); }
virtual ~Runnable() { stop(); }
void stop() { m_stop = false; m_thread.join(); }
protected:
virtual void run() = 0;
bool m_stop;
private:
std::thread m_thread;
};
class myThread : public Runnable{
protected:
void run() { while(!m_stop){ /* do something... */ }; }
};
#endif // RUNNABLE_H
I'm getting this error and others: (same error with and without the $this)
Runnable.h|9|error: no matching function for call to ‘std::thread::thread(<unresolved overloaded function type>, Runnable* const)’|
When passing a pointer.
Runnable.h|9|error: ISO C++ forbids taking the address of an unqualified or parenthesized non-static member function to form a pointer to member function. Say ‘&Runnable::run’|
Here's some code to mull over:
#ifndef RUNNABLE_H
#define RUNNABLE_H
#include <atomic>
#include <thread>
class Runnable
{
public:
Runnable() : m_stop(), m_thread() { }
virtual ~Runnable() { try { stop(); } catch(...) { /*??*/ } }
Runnable(Runnable const&) = delete;
Runnable& operator =(Runnable const&) = delete;
void stop() { m_stop = true; m_thread.join(); }
void start() { m_thread = std::thread(&Runnable::run, this); }
protected:
virtual void run() = 0;
std::atomic<bool> m_stop;
private:
std::thread m_thread;
};
class myThread : public Runnable
{
protected:
void run() { while (!m_stop) { /* do something... */ }; }
};
#endif // RUNNABLE_H
Some notes:
Declaring m_stop as a simple bool as you were is horribly insufficient; read up on memory barriers
std::thread::join can throw so calling it without a try..catch from a destructor is reckless
std::thread and std::atomic<> are non-copyable, so Runnable should be marked as such, if for no other reason than to avoid C4512 warnings with VC++
That approach is wrong.
The problem is that while the object is still under construction its type is still not the most derived type, but the type of the constructor that is executing. That means that when you start the thread the object is still a Runnable and the call to run() can be dispatched to Runnable::run(), which is pure virtual, and that in turn will cause undefined behavior.
Even worse, you might run into a false sense of security, as it might be the case that under some circumstances the thread that is being started might take long enough for the current thread to complete the Runnable constructor, and enter the myThread object, in which case the new thread will execute the correct method, but change the system where you execute the program (different number of cores, or the load of the system, or any other unrelated circumstance) and the program will crash in production.