RELATED: get user profile in django
The above shows how to get user profile but i read that the accepted answer method is deprecated.
How would I create/get/use user profile in django 1.9?
models.py
from django.contrib.auth.models import User
from django.db.models.signals import post_save
class UserProfile(models.Model):
user = models.OneToOneField(User)
address = models.TextField()
......
def create_user_profile(sender, instance, created, **kwargs):
if created:
UserProfile.objects.create(user=instance)
post_save.connect(create_user_profile, sender=User)
The above code will create a UserProfile record whenever a new user is created on User table. Then you can access the profile details like,
address = request.user.profile.address
get_profile() method returned additional informations about User. Currently, these informations can be stored in Custom User Model or in a seperate model which is related to User Model. You can do that by simply adding one2one relation with User model to your custom User model, or by subclassing the AbstructUserBase model.
Subclassing User Model example:
class MyUser(AbstractBaseUser):
email = models.EmailField(
verbose_name='email address',
max_length=255,
unique=True,
)
date_of_birth = models.DateField()
...
One2One Relation with User model example:
from django.contrib.auth.models import User
class Employee(models.Model):
user = models.OneToOneField(User, on_delete=models.CASCADE)
department = models.CharField(max_length=100)
Related
I've inherited from the AbstractBaseUser as follows:
class User(AbstractBaseUser):
"""
Main User model, inherits from AbstractBaseUser
"""
# Meta
email = models.EmailField(verbose_name='email', max_length=60, unique=True)
username = models.CharField(max_length=40, unique=True) # equals to email
date_joined = models.DateTimeField(verbose_name='date joined', auto_now_add=True)
last_login = models.DateTimeField(verbose_name='last login', auto_now=True)
employee_of = models.OneToOneField(Customer, on_delete=models.SET_NULL, null=True)
So each User is linked to one and only one Customer.
Now within a view I want to access the instance of the current logged in user within the request object and get the employee_of value to get a queryset that contains all users of that customer.
def render_employees(request):
"""
Renders the employees page of the dashboard
:param request:
:return:
"""
# Return the value for the current site for css specific classes
dashboard_site = 'employees'
# Query the employees
qs_employees = User.objects.filter(employee_of=request.user.employee_of) # doesn't find field
...
However the filter doesn't work because request.user.employ_of doesn't seem to return anything. My IDE even suggests e.g. username, date_joined etc. but not employee_of.
Why's that?
class Customer(models.Model):
"""
A table that stores static data about a customer, usually a legal company
"""
legal_name = models.CharField(max_length=50)
street = models.CharField(max_length=30)
street_number = models.CharField(max_length=3)
def __str__(self):
return self.legal_name
Update:
from django.db import models
from django.contrib.auth.models import AbstractBaseUser, BaseUserManager
from applications.customer.models import Customer
from django.conf import settings
BaseUser = settings.AUTH_USER_MODEL
class User(AbstractBaseUser):
"""
Main User model, inherits from AbstractBaseUser
"""
# Relations
user = models.OneToOneField(BaseUser, related_name='user_profile', on_delete=models.CASCADE, null=True) # link to default user model
employee_of = models.OneToOneField(Customer, on_delete=models.SET_NULL, null=True, blank=True)
I linked the user to the default user model via Django admin. However in the view im still not able to access employee_of within request.user
It seems that request.user is a different model. It's User model from django.contrib.auth. https://docs.djangoproject.com/en/4.0/ref/contrib/auth/#django.contrib.auth.models.User.
What you can do about it?
In our app we have UserProfile model that have OnetoOne relation to django User.
You can then store employee_of value there.
class UserProfile(AbstractBaseUser):
user = models.OnetoOneField("auth.User", related_name="user_profile", on_delete=models.CASCADE)
employee_of = models.OneToOneField(Customer, on_delete=models.SET_NULL, null=True)
and then access request.user employees using something like
request.user.user_profile.employee_of
Is possible to give roles/group to admin users to delete only the users they created?
For example:
admin1 created user1, user2
admin2 created user3, user4
admin1 should only have permissions to delete user1 and user2 and not have any access to user3 and user4.
in user model you can add the file creator ForeignKey to admin:
class User(AbstractUser):
creator = models.ForeignKey(User, on_delete=models.CASCADE)
......
when admin delete user check the creator:
def userDelete(request, userId):
user = get_object_or_404(User, id=userId)
if user.creator == request.user: // have access
article.delete()
messages.success(request, 'User Delete')
return redirect('***:***')
Since changing the user model mid-project may result in complications, another approach to extend the existing User model can be:
from django.db import models
from django.contrib.auth.models import User
class CustomUser(models.Model):
user = models.OneToOneField(User, on_delete=models.CASCADE, related_name='custom_user')
created_by = models.ForeignKey(User, on_delete=models.SET_NULL, null=True)
And now you can use the created_by field as mentioned by #ming in their answer.
I want to create Profile extending User model.
from django.db import models
from django.contrib.auth.models import User
from rest_framework.authtoken.models import Token
# Create your models here.
class Profile(models.Model):
user = models.OneToOneField(User, on_delete=models.CASCADE)
operatorId = models.CharField(
max_length=50,
default= 'O'+str(user.id), #get user id
blank=False,
unique=True,
)
Want to add operatorId which depends on userId chosen (operator id i O and user.id as a string). How to get current user id? basically, I need to change default every-time I change user. Is it possible?
you should override save method
from django.db import models
from django.contrib.auth.models import User
from rest_framework.authtoken.models import Token
class Profile(models.Model):
user = models.OneToOneField(User, on_delete=models.CASCADE)
operatorId = models.CharField(
max_length=50,
blank=False,
unique=True,
)
def save(self, *args, **kwargs):
self.operatorId = 'O'+str(self.user.id) # set operatorId here
super().save(*args, **kwargs)
note that overriding save has a limitation:
Unfortunately, there isn’t a workaround when creating or updating
objects in bulk, since none of save(), pre_save, and post_save are
called.
check django docs for more info
I am working on an intranet web application which needs two types of users. Normal users that can be setup from django admin and specific type of users -
Employees.
I have the following model for Employee type user.
class Employee(models.Model):
emp_name = models.CharField(max_length=500)
slug = models.SlugField(unique=True, default='')
location = models.CharField(max_length=200)
email = models.EmailField()
experience = models.TextField(blank=True)
primary_skill = models.ManyToManyField(PrimarySkill)
secondary_skill = models.ManyToManyField(SecondarySkill)
I tried having a OneToOneField like this as per the official doc and
this article:
user = models.OneToOneField(User, blank=True, null=True, on_delete=models.CASCADE)
#receiver(post_save, sender=User)
def create_employee(sender, instance, created, **kwargs):
if created:
Employee.objects.create(user=instance)
#receiver(post_save, sender=User)
def save_employee(sender, instance, **kwargs):
instance.employee.save()
I realized that this is the opposite of what I want. Every time a User
is created from the admin, there was an entry created in the
app_employee table.
What I want is this:
Every time an Employee is created, I need a User created.
An Employee can be created using a separate signup form, say emp_signup
How do I approach this scenario?
I have achieved this using a custom user based on AbstractUser inspired by this article.
class CustomUser(AbstractUser):
pass
class Employee(CustomUser):
user = models.OneToOneField(settings.AUTH_USER_MODEL)
# other fields
In settings.py, I then add the following key:
AUTH_USER_MODEL = 'myapp.CustomUser'
And wherever I need to refer the User class, I use get_user_model(), which will substitute our custom user, in views and forms as follows:
views.py
from django.contrib.auth import get_user_model
def user_profile(request):
User = get_user_model()
user = get_object_or_404(User, username=request.user.username)
return render(request, 'user/user_profile.html', {
'site_user': user
})
forms.py
class SignUpForm(UserCreationForm):
class Meta:
model = get_user_model()
fields = ('username', 'email', 'password1', 'password2',)
I have the following models
from django.contrib.auth.models import User
User = settings.AUTH_USER_MODEL
class UserProfile(models.Model):
user = models.OneToOneField(User, on_delete=models.CASCADE, related_name='profile')
class Tutor(UserProfile):
# tutor_fields here
From User object how can I access Tutor? is it with user.profile?
user.profile.select_related('tutor') does not seem to work.
OneToOneField work like ForeignKey except unique=True and you don't need to specify the related_name (you can specify if you want to change it).
For you example:
from django.contrib.auth.models import User
User = settings.AUTH_USER_MODEL
class UserProfile(models.Model):
user = models.OneToOneField(User, on_delete=models.CASCADE, related_name='profile')
class Tutor(UserProfile):
user = models.ForeignKey(UserProfile, on_delete=models.CASCADE, related_name='tutor')
details = models.CharField(max_length=100)
NB: Use a ForeignKey if you want/need one Tutor for many UserProfile, else if you want one (and only one) Tutor for one UserProfile
And you can access to the Tutor bu UserProfile by UserProfile.tutor.details.
As described in the django docs, you should be able to access it with user.user_profile.