ASCII Dec to Char in C++ - c++

Question

I want to get every characters of ASCII in normal char. If I only put char key only, it would return dec.
My request:
char alph = //ascii dec to normal char
For example: A in dec is 65
Note: I don't have the characters, but I do have the ASCII codes in dec like 65.

Answer 1

because I need user input like 65
In this case you can do this:
#include <iostream>
using namespace std;
int main() {
int code;
cout << "Enter a char code:" << endl;
cin >> code;
char char_from_code = code;
cout << char_from_code << endl;
return 0;
}
This will ouput:
Enter a char code:
65
A

Answer 2

It seems you have misunderstood the concept.
The numerical value is always there. Whether you print it as the letter or the numerical value depends on how you print.
std::cout will print chars as letters (aka chars) so you'll need to cast it to another integer type to print the value.
char c = 'a';
cout << c << endl; // Prints a
cout << (uint32_t)c << endl; // Prints 97
cout << endl;
uint32_t i=98;
cout << i << endl;
cout << (char)i << endl;
Output:
a
97
98
b

Answer 3

This is the method, very simple and then just need to make your own user interface to get input dec
#include <iostream>
using namespace std;
int main() {
int dec = 65;
cout << char(dec);
cin.get();
return 0;
}

Answer 4

Looks like you need hex/unhex converter. See at boost, or use this bicycle:
vector<unsigned char> dec2bin( const string& _hex )
{
vector<unsigned char> ret;
if( _hex.size() < 2 )
{
return ret;
}
for( size_t i = 0; i <= _hex.size() - 2; i += 2 )
{
string two = string( _hex.data() + i, 2 );
stringstream ss( two );
string ttt = ss.str();
int tmp;
ss >> /*hex >>*/ tmp;
unsigned char c = (unsigned char)tmp;
ret.insert( ret.end(), c );
}
return ret;
}
int main()
{
string a = "65";
unsigned char c = dec2bin( a )[0];
cout << (char)c << endl;
return 0;
}