Treat escaped newline as line continuation - c++

Question

Here is an example of the syntax -- two groups of items:
I_name m_name parameter1=value parameter2=value
I_name m_name parameter1=value \
parameter2=value
My question is how to define the skip-type.
It is not just space_type but space_type minus newline.
But newline followed by backslash is a skip-type.
E.g.
I define name like that:
qi::rule<Iterator, std::string(), ascii::space_type> m_sName;
m_sName %= qi::lexeme[ascii::alpha >> *ascii::alnum];
This is obviously not correct, as the space_type must include newline-backslash.

Answer 1

The following grammar works for me.
*("\\\n" | ~qi::char_('\n')) % '\n'
It will ignore any newline after the backslash. And the following is a simple test.
#include <vector>
#include <string>
#include <boost/config/warning_disable.hpp>
#include <boost/spirit/include/qi.hpp>
#define BOOST_TEST_MODULE example
#include <boost/test/unit_test.hpp>
typedef std::vector<std::string> Lines;
inline auto ParseLines(std::string const& str) {
Lines lines;
namespace qi = boost::spirit::qi;
if (qi::parse(
str.begin(), str.end(),
*("\\\n" | ~qi::char_('\n')) % '\n',
lines)) {
return lines;
}
else {
throw std::invalid_argument("Parse error at ParseLines");
}
}
BOOST_AUTO_TEST_CASE(TestParseLines) {
std::string const str =
"I_name m_name parameter1=value parameter2=value\n"
"I_name m_name parameter1 = value \\\n"
"parameter2 = value";
Lines const expected{
"I_name m_name parameter1=value parameter2=value",
"I_name m_name parameter1 = value parameter2 = value"
};
BOOST_TEST(ParseLines(str) == expected);
}
You should use "-std=c++14 -lboost_unit_test_framework" for compilation. Anyway, it is easy to convert the code for c++03.

Answer 2

qi::blank is exactly that. It's qi::space without newlines.
You can do this too: ("\\\n" | qi::blank)
To be able to declare a rule with such a skipper, define a skipper grammar:
template <typename It>
struct my_skipper : qi::grammar<It> {
my_skipper() : my_skipper::base_type(start) {}
qi::rule<It> start = ("\\\n" | qi::blank);
};
Full Demo
Live On Coliru
#include <boost/spirit/include/qi.hpp>
#include <boost/fusion/include/adapted.hpp>
#include <map>
namespace qi = boost::spirit::qi;
namespace ast {
struct record {
std::string iname, mname;
std::map<std::string, std::string> params;
};
using records = std::vector<record>;
}
BOOST_FUSION_ADAPT_STRUCT(ast::record, iname, mname, params)
template <typename It>
struct my_parser : qi::grammar<It, ast::records()> {
using Skipper = qi::rule<It>;
my_parser() : my_parser::base_type(start) {
skipper = ("\\\n" | qi::blank);
name = +qi::graph;
key = +(qi::graph - '=');
param = key >> '=' >> name;
record = name >> name >> *param;
records = *(record >> +qi::eol);
start = qi::skip(qi::copy(skipper)) [ records ];
}
private:
Skipper skipper;
qi::rule<It, ast::records(), Skipper> records;
qi::rule<It, ast::record(), Skipper> record;
qi::rule<It, ast::records()> start;
qi::rule<It, std::pair<std::string, std::string>()> param;
qi::rule<It, std::string()> name, key;
};
int main() {
#if 1
using It = boost::spirit::istream_iterator;
It f(std::cin >> std::noskipws), l;
#else
using It = std::string::const_iterator;
std::string const input = "something here a=1\n";
It f = input.begin(), l = input.end();
#endif
ast::records data;
bool ok = qi::parse(f, l, my_parser<It>(), data);
if (ok) {
std::cout << "Parsed:\n";
for (auto& r : data) {
std::cout << "\t" << r.iname << " " << r.mname;
for (auto& p : r.params)
std::cout << " [" << p.first << ": " << p.second << "]";
std::cout << "\n";
}
} else {
std::cout << "Parse failed\n";
}
if (f!=l)
std::cout << "Remaining input: '" << std::string(f,l) << "'\n";
}
Prints (for the input in your question):
Parsed:
I_name m_name [parameter1: value] [parameter2: value]
I_name m_name [parameter1: value] [parameter2: value]