Encountering Infinite loop in case of string handling - c++

#include<iostream>
#include<cstdio>
using namespace std;
class Time
{
int hours=0,scan_hours=0;
int minutes=0,scan_minutes=0;
public:
void input_time_in_format_1(void)
{
cout<<"\n\t Enter the time in the format hh:mm A.M./P.M.: ";
if(scanf("%d",&hours)==1)
{
if(scanf(":%d A.M.",&minutes)==1)
{
hours=(hours+12)%24;
if(hours>13||minutes>60||hours<0||minutes<0)
{
cout<<"\n\t Wrong entry";
hours=minutes=0;
}
else
cout<<"\n\t Your time has been accepted";
}
else if(scanf(":%d P.M.",&minutes)==1)
{
if(hours>13||minutes>60||hours<0||minutes<0)
{
cout<<"\n\t Wrong entry";
hours=minutes=0;
}
else
cout<<"\n\t Your time has been accepted";
}
else
{
cout<<"\n\t Wrong entry";
hours=0;
minutes=0;
}
}
else
{
cout<<"\n\t Wrong entry";
hours=0;
}
}
void input_time_in_format_2(void)
{
cout<<"\n\t Enter the time in the format hh:mm hours: ";
if(scanf("%d",&hours)==1 && hours<24)
{
if(scanf(":%d hours",&minutes)==1 && minutes<60)
cout<<"\n\t Your time has been accepted";
else
{
cout<<"\n\t Wrong entry";
hours=minutes=0;
}
}
else
{
cout<<"\n\t Wrong entry";
hours=0;
}
}
void show_time_in_format_1(void)
{
cout<<"\n\t Showing time in 24 hours format: "<<hours<<":"<<minutes<<" hours";
}
void show_time_in_format_2(void)
{
if(hours>12)
cout<<"\n\t Showing time in 12 hours format: "<<(hours%12)<<":"<<minutes<<" P.M.\n\n";
else
cout<<"\n\t Showing time in 12 hours format: "<<hours<<":"<<minutes<<" A.M.\n\n";
}
void add_time(void)
{
cout<<"\n\t Please enter the hours and minutes respectively";
cin>>scan_hours;
cin>>scan_minutes;
if(minutes+=scan_minutes>=60)
{
hours+=(scan_hours+1);
hours%=24;
}
else
{
hours+=(scan_hours);
hours%=24;
}
}
};
int main()
{
Time t1;
int choice;
do
{
cout<<"\n\t\t\t --Welcome--"<<"\n\n\t Please enter your choice \n\t1.Input time in 12 hours format\n\t2.Input time in 24 hours format\n\t3.Show time in 12 hours format\n\t4.Show time in 24 hours format\n\t5.Add user input time\n\t6.Exit....-->";
cin>>choice;
switch(choice)
{
case 1:cin.ignore();
t1.input_time_in_format_1();
break;
case 2:
t1.input_time_in_format_2();
break;
case 3:
t1.show_time_in_format_2();
break;
case 4:
t1.show_time_in_format_1();
break;
case 5:
t1.add_time();
break;
case 6:
cout<<"\n\t Thank You";
exit(0);
default:
cout<<"\n\n\t Wrong entry";
break;
}
}while(1);
return 0;
}
This is my program to accept a date from the user and to print it in different format. If I choose the case 1 whenever I want to give any input,weather it be correct or wrong, it leads me to an infinite loop. I couldn't find out what's going on. i think I have handled all the exceptions.Feel free to dump it, if you wish.

the most likely cause of the problem is the line:
cin >> choice;
This is failing because the istream contains a newline and this will cause the cin to fail.
Suggest calling:
cin.ignore();
before outputting the prompt/menu then the istream will be empty and the response to the menu, as input by the user, will be placed into the variable `choice;

Related

Program goes into infinite loop, But if removed some functions or lines, it works

A basic student database using classes, I accept
name,
roll number, and
sgpa(cgpa equivalent but out of 10).
I used while loop, and switch case,but if the code for sgpa validation, and code for displaying all students with same sgpa is removed, the program works neatly, but if not, the program goes into continuous loop, the while loop inside the main, as it accepts the options itself and keeps doing it.
The code fails when i accept the sgpa(while taking the student data) or call the displaySGPA fucntion(option 3)
int totalStudents=0;
class database{
float sgpa;
int roll;
string name;
public:
void getSGPA();
void getData(database []);
friend void displaySGPA(int,database []);
};
//Display Students with same SGPA
void displaySGPA(int temp,database students[]){
int i,sameSGPA=0;
for(i=0;i<totalStudents;i++){
if(students[i].sgpa==temp){
sameSGPA+=1;
}
}
if(sameSGPA>1){
cout<<"\nStudents with SGPA "<<temp<<"."<<endl;
for(i=0;i<totalStudents;i++){
if(students[i].sgpa==temp){
cout<<" "<<students[i].roll<<" "<<students[i].name;
}
}
}
else if(sameSGPA==1){
cout<<"Only one student with the SGPA , "<<temp<<". :"<<endl;
for(i=0;i<totalStudents;i++){
if(students[i].sgpa==temp){
cout<<" "<<students[i].roll<<" "<<students[i].name;
break;
}
}
}
else{
cout<<"No Student with given SGPA."<<endl;
}
}
void database :: getData(database students []){
cout<<"\nEnter Name : ";
cin>>name;
cout<<"Enter Roll. ";
cin>>roll;
getSGPA();
}
//SGPA validation
void database :: getSGPA(){
int x=1,temp;
while(x==1){
cout<<"Enter SGPA : ";
cin>>temp;
if(temp<=10){
sgpa=temp;
break;
}
else{
cout<<"Please enter a valid SGPA.";
}
}
}
//main Loop
int main() {
int x,temp;
database students[50];
while (x!=5){
cout<<"\n1.Enter a New Student.\n3.Display students with same SGPA.\n5.Exit.\n\nYour Choice : ";
cin>>x;
switch(x){
case 1:
students[totalStudents].getData(students);
totalStudents++;
break;
case 3:
cout<<"\nEnter the SGPA.";
cin>>temp;
displaySGPA(temp,students);
break;
case 5:
cout<<"Exiting the program.....";
break;
default:
cout<<"Please select a valid option."<<endl;
}
}
}
I found the bug, it was a type conversion bug, i was accepting a float value but passing it as a int,just worked, don't know why.But thanks for each comment and suggestion.

decision making and recursive functions

i want to make a calculator without the GUI, but i have some problem like this
cout<<"calculator : ";cin>>userAnswer;
if(userAnswer=='yes'){
//procces
} else if(userAnswer=='no'){
//exit
} else{
//here is the problem
}
when the user enters an input that aside from yes or no I want the program to ask the user again whether the user wants to use the calculator again.
but I don't know how. I have used a recursive function, but the number of times a user enters a wrong input, so the program will ask "does the user want to use a calculator?"
You can do it like this -
while (true) {
cout<<"calculator : ";
while(true) {
cin>>userAnswer;
if(userAnswer=='yes'){
//procces
} else if(userAnswer=='no'){
//exit
} else {
break;
}
}
cout<<"Do you want to use a calculator? ";
string feedback;
cin >> feedback;
if ( feedback == "yes") {
continue;
} else {
break;
}
}
You want something like this I guess,
string userAnswer;
cout<<"calculator : ";
cin>>userAnswer;
while(true)
{
while(true)
{
cout<<"\ndoes the user want to use the calculator : ";
cin>>userAnswer;
if(userAnswer=="yes" || userAnswer=="no")
break;
else
cout<<"only yes or no input is valid\n";
}
if(choice=="no")
{
cout<<"\nExiting from the calculator\n";
break;
}
cout<<"Enter your choice: \n";
cout<<"1-Addition\n";
cout<<"2-Subtraction\n";
// your stuff below
}

How use array and add multiple enties in C++

My teacher wanted me to make a program based on An Employee which includes -
His Name
His Id
His Sallary
and we needed to make this using - Structures & Functions & Array as we are not that good in C++ so we just make simple programs . the code of the program i made is below , [ http://pastebin.com/9UFFJseN ]
#include<iostream.h>
#include<conio.h>
#include<dos.h>
#include<process.h>
#include<stdio.h>
struct employee
{
char empname[40];
int empid,empsalary;
}; employee e1;
void add_record(void);
void display_record(void);
void search_record(void);
void welcome();
void exito();
void main()
{
clrscr();
int choice,id;
cout<<"Welcome to Employee Info Menu by Rohit Jalan \n\n\n";
cout<<"1 -> Add Record\n";
cout<<"2 -> Display Record\n";
cout<<"3 -> Search Record\n";
cout<<"4 -> Exit";
cout<<"\n\t\t --> ";
cin>>choice;
switch(choice)
{
case 1: add_record();break;
case 2: display_record();break;
case 3: search_record();break;
case 4: exito();
}
getch();
}
void add_record()
{
clrscr();
cout<<"You have pressed 1\n\n\n";
cout<<"Please enter employee name : ";
gets(e1.empname);
cout<<"Please enter the employee id : ";
cin>>e1.empid;
cout<<"Please enter the employee salary : ";
cin>>e1.empsalary;
cout<<" \n \n \n \n";
main();
}
void display_record()
{clrscr();
cout<<"\nEmployee Name is : ";
puts(e1.empname);
cout<<"\nEmployee ID is : ";
cout<<e1.empid;
cout<<"\nEmployee salary is : ";
cout<<e1.empsalary;
getch();
main();
}
void search_record()
{int id;
clrscr();
cout<<"Please enter the id of the employee\n: ";
cin>>id;
if(id==e1.empid)
{
display_record();
}
else cout<<"\nRecord not found...";
getch();
main();
}
void exito()
{clrscr();
cout<<"\n\n\n\n\t\t\t Thank you. ";
cout<<"\n\n\n\n\n\n\t\t\t Program by \n\n\n";
cout<<"\t\t\t";
delay(500);cout<<"ROHIT";
delay(500);cout<<" JALAN";
cout<<"\n\t\t\t";
delay(500);cout<<"Roll No";
delay(500);cout<<" 11436";
cout<<"\n\t\t\t";
delay(500);cout<<"Class";
delay(500);cout<<" XI-D";
delay(500);cout<<"....";
delay(100);
exit(0);
}
And now my teacher is asking me what if she wishes to enter more then 1 record of data and display more then 1 , or you can say she wants to decide that how much she wants to enter and display , as i am unable to solve her problem i request you all guys to help me in a simple and easy manner as i`m newbie out here . Please don't delay in answer i have a practical examination on 27th Feb 2015 . if you are unable to see my coding -
http://pastebin.com/9UFFJseN#
Thanks In Advance .
In order to perform actions more than once, you need a loop.
unsigned int Display_Menu(void)
{
unsigned int selection = 0;
while (selection != 4)
{
static const char menu_text[] =
"\n"
"Welcome to Employee Info Menu by Rohit Jalan \n\n\n"
"1 -> Add Record\n"
"2 -> Display Record\n"
"3 -> Search Record\n"
"4 -> Exit\n"
"\t\t --> ";
cout.write(menu_text, sizeof(menu_text) - 1);
cin >> selection;
if ((selection >= 1) && (selection <= 4))
{
break;
}
cout << "\nInvalid selection, try again.\n";
}
return selection;
}
The above function displays a menu and if the User enters an invalid choice, it will print the menu again. After a valid choice is received, the function returns to the caller.
This is an example of doing something more than once.
So if your instructor wants to perform more than one action, how would you do it?
Edit 1:
In general a Menu consists of two pieces: 1) Displaying the selections and 2) Processing the choices. The above code handles the displaying of the selections.
// Forward declarations
void Add_Record(void);
void Display_Record(void);
void Search_Record(void);
void Process_Choices(void)
{
unsigned int choice = 0;
do
{
choice = Display_Menu();
switch (choice)
{
case 1: Add_Record(); break;
case 2: Display_Record(); break;
case 3: Search_Record(); break;
}
} while (choice != 4);
}
The above function displays the menu, calls functions according to the User's selection and repeats. It ends when the User enters the number 4.
Again, notice the loop construct that is used for performing actions more than once.

Program on cricket scoreboard

Why is the following code not giving results and how to get results?
Whenever I run the code, it first asks for the names of the players of two teams playing the match, then it shows the menu from which if we select any one of the option it again asks for the batsman name which is not according to the program designed. My research on the code and the problem is that I think buffer memory is full but I don't know how to free it, any help would be beneficial. Thank you
#include<iostream>
#include<string.h>
#include<conio.h>
using namespace std;
class scorecard{
char batname[11][20];
int runscored[11];
char situation[11][10];
char mode[11][15];
char bowlername[11][20];
float oversplayed[11];
int maiden[11];
int runsgiven[11];
int wicketstaken[11];
public:
void updatebatsman(void);
void updatebowler(void);
void displaybat(void);
void displaybowl(void);
void menu(void);
scorecard()
{for(int n=0;n<12;n++)
{
runscored[n]={0};
oversplayed[n]={0};
maiden[n]={0};
runsgiven[n]={0};
wicketstaken[n]={0};
}
}
};
int main()
{
int jb=0;
scorecard s1;
int kb;
s1.menu();
do
{
cout<< "Enter the option"<<endl;
cout<<"(1) Display batting score"<<endl<<"(2) Display Bowling score"<<endl<<"(3) Update batting score"<<endl;
cout<<"(4) Update Bowling score"<<endl;
cin >>kb;
switch(kb)
{
case 1 : s1.displaybat();
break;
case 2 :s1.displaybowl();break;
case 3:s1.updatebatsman();break;
case 4:s1.updatebowler();break;
default:cout<<"Wrong choice";
}
}while (jb<1);
}
void scorecard::updatebowler(void)
{char bowlname[20];
int str,k,option,overnumbers,maidenumb,uprun,upwicket;
cout<<"Enter Bowler name:";
cin.getline(bowlname,20);
for( k=0;k<11;k++)
{str= strcmp(bowlername[k],bowlname);
if (str== 0)
{
cout<<"Menu for Bowler information update "<<endl;
cout<<"(1) Update Number of overs"<<endl<<"(2) Update maiden overs"<<endl<<"(3) Update runs given"<<endl;
cout<<"(4) Update wickets taken"<<endl;
cin >> option;
switch(option)
{
case 1:{cout<<"Enter Numbers of overs to be updated:";
cin >>overnumbers;
cout<<endl;
oversplayed[k]+=overnumbers;
break;
}
case 2:{cout <<"Enter the number of maiden overs to be updated:";
cin>>maidenumb;
cout<<endl;
maiden[k]+=maidenumb;
break;
}
case 3:{cout <<"Enter the number of runs to be added:";
cin>>uprun;
cout<<endl;
runsgiven[k]+=uprun;
break;
}
case 4: {cout<<"Enter number of wickets to be updated:";
cin >>upwicket;
cout<<endl;
wicketstaken[k]+=upwicket;
}
default:cout<<"wroung choice";
}
break;
}
}
if (str!=0)
cout <<"You entered wrong player."<<endl;
}
void scorecard::updatebatsman(void)
{char batsmaname[20];
int str,k;
cout<<"Enter Batsman name:";
cin.getline(batsmaname,20);
for( k=0;k<11;k++)
{str= strcmp(batname[k],batsmaname);
if (str== 0)
{
cout<<"enter runs scored:";
cin>>runscored[k];
cout<<endl<<"enter weather out or not out:";
cin>>situation[k];
cout<<endl<<"enter mode(if batsman out) by which batsman was out:";
cin>>mode[k];
break;
}
}
if (str!=0)
cout <<"You entered wrong player."<<endl;
}
void scorecard::displaybat(void)
{
cout << "Batsman name"<<'t'<<"Runs scored"<<'t'<<"situation"<<'t'<<"mode"<<endl;
for(int j=0;j++;j<12)
{
cout<<batname[j]<<'t'<<runscored[j]<<'t'<<situation[j]<<'t'<<mode[j]<<endl;
}
}
void scorecard::displaybowl(void)
{
cout << "Bowler name"<<'t'<<"overs played"<<'t'<<"maiden overs"<<'t'<<"wicket taken"<<'t'<<"Runs given"<<endl;
cout<<endl;
for(int j=0;j++;j<12)
{
cout<<bowlername[j]<<'t'<<oversplayed[j]<<'t'<<maiden[j]<<'t'<<wicketstaken[j]<<'t'<<runsgiven[j]<<endl;
}
}
void scorecard::menu(void)
{
cout<<"Enter the name of players of batting team"<<endl;
for (int k=0;k<11;k++)
{
cout <<"Enter name of player "<<k+1<<":";
cin>>batname[k];
}
cout <<"Enter the name of players of bowling team"<<endl;
for (int n=0;n<11;n++)
{
cout <<"Enter name of player "<<n+1<<":";
cin>>bowlername[n];
}
}
This is very wrong:
for(int j=0;j++;j<12)
It should be:
for(int j=0; j < 11; j++)
You are also missing a break in your case 4 statement for the options:
case 4: {cout<<"Enter number of wickets to be updated:";
cin >>upwicket;
cout<<endl;
wicketstaken[k]+=upwicket;
break;
}
default:cout<<"wroung choice";
Without the break you will see also the output wrong choice when the user selects option 4.

How to Return a structure

How Can I return all the structures when i choose 7.Logout after i insert a record from the Admin menu, and if i return to the admin menu, i'll see the record again.
For Example
User:Admin
Pass:Admin
then i choose 2.Insert Product after that Ill go choose 1.display , after that i 7.log out. now i want to login again as Admin but i want to see all the data again.please help this is our thesis project.
#include <iostream>
#include <string>
#include <iomanip>
#include <conio.h>
using namespace std;
struct product{
string pname,pid;
int qnty;
double price;
product *ptr;
};
//Function Declaration
void Menu(string username);
void InsertProduct();
void DeleteProduct();
void DisplayProduct();
void SearchProduct();
void PurchaseProduct();
//
product *head;
int main() //Account Login
{
int pw=0,n;
char pwc=' ';
string username,password;
cout<<"\n ==============================================================================="<<endl<<endl;
cout<<"\t\t\t LICA'S GROCERY STORE"<<endl<<endl;
cout<<" ==============================================================================="<<endl<<endl;
cout<<"\t\t\t Username: ";
getline(cin, username);
cout<<"\n\t\t\t Password: ";
do
{
pwc=getch();
if(pwc==13||pwc==' ')
{
break;
}
cout<<"*";
password+=pwc;
pw++;
}
while(pwc!=13||pwc!=' ');
n=username.length();
for(int a=0; a!=n; a++)
{
if(isupper(username.at(a)))
{
username.at(a) = tolower(username.at(a));
}
}
if(username=="admin" && password=="Admin")
{
system("CLS");
cout<<"\n ==============================================================================="<<endl<<endl;
cout<<"\t\t\t\t WELCOME ADMIN!"<<endl<<endl;
cout<<" ==============================================================================="<<endl<<endl;
Menu(username);
return main();
}
else if(username=="cashier" && password=="Cashier")
{
system("CLS");
cout<<"\n ==============================================================================="<<endl<<endl;
cout<<"\t\t\t\t WELCOME CASHIER!"<<endl<<endl;
cout<<" ==============================================================================="<<endl<<endl;
Menu(username);
}
else
{
system("CLS");
cout
<<"\n\t\t Invalid Username or Password. Please Try Again"<<endl;
return main();
}
system("pause");
return 0;
}
//
//
//
//
//
void Menu(string username)
{
head=NULL;
int menu;
if(username=="admin")
{
do
{
cout
<<"\t MENU: "
<<"\n\n\t\t\t A. FILE MAINTENANCE" <<endl
<<"\n\t\t\t\t 1. Display All Products"<<endl
<<"\t\t\t\t 2. Insert New Product"<<endl
<<"\t\t\t\t 3. Delete A Product" <<endl
<<"\t\t\t\t 4. Search A Product"<<endl
<<"\n\t\t\t B. SALES MODULE"<<endl
<<"\n\t\t\t\t 5. Cashier"<<endl
<<"\t\t\t\t 6. Print Receipt."<<endl
<<"\n\t\t\t C. EXIT"<<endl
<<"\n\t\t\t\t 7. Log Out"<<endl;
cout<<"\n\t Choose an option (1 to 7 only): ";
cin>>menu;
cin.ignore();
switch(menu)
{
case 1:
cout<<"\n ============================================================================="<<endl<<endl;
cout<<"\t\t\t DISPLAY ALL PRODUCTS"<<endl<<endl;
cout<<" ============================================================================="<<endl<<endl;
DisplayProduct();
system("pause");
system("CLS");
break;
case 2:
cout<<"\n ============================================================================="<<endl<<endl;
cout<<"\t\t\t INSERT NEW PRODUCT"<<endl;
cout<<" ============================================================================="<<endl<<endl;
InsertProduct();
break;
case 3:
cout<<"\n ============================================================================="<<endl<<endl;
cout<<"\t\t\t DELETE A PRODUCT"<<endl;
cout<<" ============================================================================="<<endl<<endl;
DeleteProduct();
break;
case 4:
cout<<"\n ============================================================================="<<endl<<endl;
cout<<"\t\t\t SEARCH A PRODUCT" <<endl;
cout<<" ============================================================================="<<endl<<endl;
SearchProduct();
break;
case 5:
cout<<"\n ============================================================================="<<endl<<endl;
cout<<"\t\t\t PURCHASE PRODUCTS"<<endl;
cout<<" ============================================================================="<<endl<<endl;
PurchaseProduct();
case 7:
cout<<"\n\n THANK YOU ADMIN!"<<endl<<endl;
break;
default:
cout<<"\n\n INVALID INPUT!"<<endl<<endl;
}
}while(menu!=7);
}
else
{
cout
<<"Choose an Option"
<<"\n1.Sales Module"
<<"\n2.Exit"<<endl;
cin>>menu;
switch(menu)
{
case 1:
cout<<"Sales Module";
break;
case 2:
cout<<"Exit!";
break;
default:
cout<<"Invalid Input!";
}
}
}
void InsertProduct()
{
product *newproduct;
newproduct=new product;
cout<<"\n\n\tEnter Product Name:";getline(cin,newproduct->pname);
cout<<"\n\tEnter Product Quantity:";cin>>newproduct->qnty;
cout<<"\n\tEnter Product ID:";cin>>newproduct->pid;
cout<<"\n\tEnter Product Price:";cin>>newproduct->price;
cin.ignore();
newproduct->ptr=NULL;
if(head==NULL)
head=newproduct;
else
{
product *lastproduct;
lastproduct=head;
while(lastproduct->ptr!=NULL)
lastproduct=lastproduct->ptr;
lastproduct->ptr=newproduct;
}
cout<<"\n\tProduct is inserted"<<endl;
system("pause");
system("CLS");
}
void DeleteProduct()
{
DisplayProduct();
product *current,*previous;
current=head;
int x;
if (current==NULL)
{
cout<<"\n\t\tNo Products Found.";
}
else
{
cout<<"\n\t\tEnter Product No. to delete:";
cin>>x;
int i=1;
if(x==1)
{
head=current->ptr;
delete current;
cout<<"\n\t\tProduct is deleted";
DisplayProduct();
}
else
{
while(i<x&&current!=NULL)
{
previous=current;
current=current->ptr;
i=i++;
}
if(current==NULL)
{
cout<<"\n\t\tProduct does not Exist";
}
else
{
previous->ptr=current->ptr;
delete current;
cout<<"\n\t\tProduct is deleted";
DisplayProduct();
}
}
}
system("pause");
system("CLS");
}
void DisplayProduct()
{
product *current;
current=head;
int i=1;
cout<<setiosflags(ios::left);
while(current!=NULL)
{
cout<<"\n\t\t"<<setw(4)<<i;
cout<<setw(25)<<current->pname<<setw(3)<<current->qnty <<setw(3)<<current->pid <<setw(3)<<current->price;
current=current->ptr;
i++;
}
}
void SearchProduct()
{
string sid;//Name to search
product *current;
current=head;
if (current==NULL)
cout<<"\n\t\tNo Products Found";
else
{
cout<<"\n\t\tEnter product to search: ";
cin>>sid;
int i=1;
while(sid.compare(current->pid))
{
current=current->ptr;
if (current==NULL)
break;
i++;
}
if(current!=NULL)
cout<<"\n\t\t"<<current->pid<<" is Product No."<<i;
else
cout<<"\n\t\t"<<sid<<" is not in the list.";
DisplayProduct();
cout<<endl;
}
system("pause");
system ("CLS");
}
void PurchaseProduct()
{
}
Your data is in memory until you save it to hardk disk, so you need to implement some mechanism for doing that.
You can choose among several options such as using data bases, plain files(XML, YAML, JSON, etc ...) and object searialization wich I think it's your best option right now. There are several libraries out there for doing that, but for start I recommend you use this tutorial. Then move to A practical guide to C++ serialization.
I recommend serialization because I realized you are just starting with C++. And others options like data bases and formated files(xml, Yaml, etc...) require more complex code.
Have fun!!! After you read all this stuff and (try to put it in practice), if you still can't solve your problem, come back here, and we will happy to help you.