I am writing a function to insert a node in BST,but getting segmentation fault.
/*
Node is defined as
typedef struct node
{
int data;
node * left;
node * right;
}node;
*/
node * findPos(node * tree, int value){
if(tree -> data > value){
return findPos(tree -> left, value);
}
else if (tree -> data < value){
return findPos(tree -> right, value);
}
return tree;
}
node * addNode(int value){
struct node * temp =(struct node *)malloc(sizeof(struct node));
temp->data = value;
temp->left = NULL;
temp -> right = NULL;
return temp;
}
node * insert(node * root, int value)
{
node * ptr = root;
if(ptr == NULL)
return addNode(value);
else if(ptr -> data > value){
ptr->left = findPos(ptr -> left, value);
}
else if(ptr -> data < value){
ptr->right = findPos(ptr -> right, value);
}
return root;
}
i am not able to understand which illegal memory i am trying to access which is giving this error.
Please help me with this.
Thanks in advance :)
Thanks for the help guys!!!
got the program working
/*
Node is defined as
typedef struct node
{
int data;
node * left;
node * right;
}node;
*/
node * addNode(int value){
struct node * temp =(struct node *)malloc(sizeof(struct node));
temp->data = value;
temp->left = NULL;
temp -> right = NULL;
return temp;
}
node * insert(node * root, int value)
{
node * ptr = root;
if(ptr == NULL)
return addNode(value);
else if(ptr -> data > value){
ptr->left = insert(ptr -> left, value);
}
else if(ptr -> data < value){
ptr->right = insert(ptr -> right, value);
}
return root;
}
There are two issues here:
findPos should handle the case in which tree is NULL.
insert should not recursively call findPos. Instead it should recursively call insert. Something like this (haven't tested it):
node * insert(node * root, int value)
{
node * ptr = root;
if(ptr == NULL)
return addNode(value);
else if(ptr -> data > value) {
return insert(ptr -> left, value);
} else if(ptr -> data < value) {
return insert(ptr -> right, value);
} else
return root;
}
Related
My BST code is not showing any output and there is no error?
can someone please explain what I'm doing wrong?
I'm using Visual Code
I ran the code on multiple online compilers as well but just got a segmentation error and on vs code it's not showing anything at all.
#include <iostream>
#include <type_traits>
using namespace std;
class node
{
public:
int data;
node *left, *right;
node(int data){
this->data = data;
this->left = NULL;
this->right = NULL;
}
};
class BST{
public:
node* addNode(int data){
node* newNode = new node(data);
return newNode;
}
void Inorder(node* root){
if(root == NULL)
return;
Inorder(root -> left);
cout << root -> data << "\t";
Inorder(root -> right);
}
node* insert(node* newNode, int data){
if(newNode == NULL)
return addNode(data);
if(data < newNode -> data)
newNode -> left = insert(newNode, data);
else if(data > newNode -> data)
newNode -> right = insert(newNode, data);
return newNode;
}
};
int main(){
node *root = NULL;
BST objbst;
root = objbst.insert(root, 8);
root = objbst.insert(root, 3);
root = objbst.insert(root, 1);
root = objbst.insert(root, 6);
root = objbst.insert(root, 7);
root = objbst.insert(root, 10);
root = objbst.insert(root, 14);
root = objbst.insert(root, 4);
cout << "Inorder traversal: ";
objbst.Inorder(root);
}
if I'm doing something wrong then can someone please tell me what I'm doing wrong?
modify the insert function as given below and then run your code, you need to call left or right instances of node(based on condition) when traversing the tree recursively!
node* insert(node* Node, int data){
if(Node == NULL)
return addNode(data);
if(data < Node -> data)
Node -> left = insert(Node->left, data);
else if(data > Node -> data)
Node -> right = insert(Node->right, data);
return Node;
}
I am writing a code to return data of a node in BST based on id.
below is my node class:
struct Node{
int id;
string data;
Node *left;
Node *right;
Node();
};
below is my node constructor: I defined id and data in addNode function
Node :: Node(){
this->left = nullptr;
this->right = nullptr;
}
below is my BST class:
class BST{
private:
Node * root = nullptr;
void setRoot(Node *);
Node* getRoot();
public:
Node *addNode(BST *, int);//helper function
Node *addNode(Node *,int);
string getEntry(BST*,int);//helper function
string getEntry(Node*,int);
}
below is my helper functions:
Node *BST::addNode(BST *bst, int val){
addNode(bst->getRoot(),val);
}
string BST::getEntry(BST* bst,int id){
getEntry(bst->getRoot(),id);
}
below is my addNode class:
Node* BST::addNode(Node* root, int val) {
Node *newNode = new Node();
newNode->id = val;
newNode->data = "Number " + to_string(val);
if (root == nullptr) {
if (getRoot() == nullptr){
setRoot(newNode);
}
setCount(getCount()+1);
return newNode;
}
if (root->id > val) {
root->left = addNode(root->left, val);
} else {
root->right = addNode(root->right, val);
}
return root;
}
below is my getEntry class:
string BST::getEntry(Node *base,int id) {
if (base == nullptr){
return "";
}
if (base->id == id){
cout<<base->data<<endl;
return base->data;
}
getEntry(base->left,id);
getEntry(base->right,id);
}
below are the nodes I passed in from main:
int main(){
BST *newBst = new BST();
newBst->addNode(newBst,1);
newBst->addNode(newBst,2);
newBst->addNode(newBst,3);
newBst->addNode(newBst,2);
newBst->addNode(newBst,3);
newBst->addNode(newBst,5);
newBst->addNode(newBst,7);
newBst->addNode(newBst,10);
cout<<newBst->getEntry(newBst,5)<<endl;
return 0;
}
The code would compile but does not return anything, I tried to debug, at the "return base->data statement", there is an error "can not access memory at address 0xc8". What causes the problem and what can I do about it?
this is the warning I got when I debug the code.
if (base->id != id){
getEntry(base->left,id);
getEntry(base->right,id);
}
As you are using a sorted tree, you know which of the right or left node you need to have a look at. Also, you need to return something:
if (base->id > val){
return getEntry(base->left,id);
}
return getEntry(base->right,id);
But the design with addNode is very bad, you shouldn't have to pass the root twice!
I am trying to understand BSTs and how to insert elements into it iteratively. My node structure implementation looks like so:
struct Node{
Node *left;
Node *right;
T data; //template class
};
And my insertion implementation looks like so:
template<typename T>
bool BST<T>::Insert(const T value)
{
Node *newNode = new Node;
newNode -> data = value;
newNode -> left = NULL;
newNode -> right = NULL;
if(root == NULL) {root = newNode;} //If the BST is empty
else
{//The BST is not empty
Node *ptr = root; //points to the current Node
Node *ptr_parent; //points to the parent Node
while(ptr != NULL)
{
if((ptr -> data) > value)
{
ptr_parent = ptr;
ptr = ptr -> left;
}
if((ptr -> data) < value)
{
ptr_parent = ptr;
ptr = ptr -> right;
}
}
}
ptr = newNode; //insert the newNode at the spot
if((ptr_parent -> data) < value)
ptr_parent -> right = newNode;
else
ptr_parent -> left = newNode;
return true;
}
The insertion works when adding the first Node into an empty tree but I get a segmentation fault whenever i try to add more Nodes. I understand that there are posts that show how to implement insertions into BSTs but most of them show the recursive method, and those with iterative examples are incomplete or too specific. Thank you.
I think I'd do things a little differently. First, I'd simplify the other code a little by adding a ctor to the Node class:
struct Node{
Node *left;
Node *right;
T data;
Node(T const &data) : left(nullptr), right(nullptr), data(data) {}
};
Then you can use a pointer to a pointer to traverse the tree and insert the item:
bool insert(const T value) {
Node **pos;
for (pos = &root; *pos != nullptr;) {
if (value < (*pos)->value)
pos = &(*pos)->left;
else if ((*pos)->value < value )
pos = &(*pos)->right;
else
return false;
}
*pos = new Node(value);
return true;
}
Note that I've delayed creating the new node until after we've dropped out of the loop. This way, if we have a duplicate element, we can just return (without leaking a node, since we haven't allocated a new node yet).
For what it's worth, if you were going to do this recursively, it would probably be easier to use a reference to a pointer instead of a pointer to a pointer.
I was able to make my original code work last night, I'm sharing the answer here:
template<typename T>
bool BST<T>::Insert(const T value)
{
Node *ptr;
Node *ptr_parent;
if(root == NULL)
{//The BST is Empty...
Node *newNode = new Node;
newNode -> data = value;
newNode -> left = NULL;
newNode -> right = NULL;
root = newNode;
ptr = root;
} else { //traversing the tree to find the insertion point
ptr = root;
while(ptr != NULL)
{
if((ptr -> data) == value) {return false;} //to check for duplicates
if(value < (ptr -> data))
{
ptr_parent = ptr;
ptr = ptr -> left;
} else {
ptr_parent = ptr;
ptr = ptr -> right;
}
}
Node *newNode = new Node;
newNode -> data = value;
newNode -> left = NULL;
newNode -> right = NULL;
//checking for parent value to determine if
//the Node is a left or right child
if(value < (ptr_parent -> data))
ptr_parent -> left = newNode;
else
ptr_parent -> right = newNode;
}
++count;//to keep track of the Node count
return true;
}
For my own sake I wanted to solve this without using double pointers.
You didn't handle the case when ptr->data == value so the loop will be infinite whenever a duplicate is found, and ptr = newNode doesn't do anything, it just makes ptr point to newNode. Try this
//ptr holds the address of pointers to nodes.
Node **ptr = &root;
while(*ptr != NULL){
if((*ptr)->data > T)
ptr = &(*ptr)->right;
else
ptr = &(*ptr)->left;
//Not handling duplicates
}
//Change the value of the pointer to newNode
*ptr = newNode;
Use hard pointers
Node **ptr = &root; //points to the current Node
Node **ptr_parent; //points to the parent Node
When you are trying to do this
ptr = newNode; //insert the newNode at the spot
it doesn't do anyithing because you need to modify the pointer which points to the left or the right subnode
something like this:
template<typename T>
bool BST<T>::Insert(const T value)
{
Node *newNode = new Node;
newNode -> data = value;
newNode -> left = NULL;
newNode -> right = NULL;
if(root == NULL) {root = newNode;} //If the BST is empty
else
{//The BST is not empty
Node **ptr = &root; //points to the current Node
Node **ptr_parent; //points to the parent Node
while((*ptr) != NULL)
{
if(((*ptr) -> data) > value)
{
ptr_parent = ptr;
ptr = &ptr -> left;
}
if(((*ptr) -> data) < value)
{
ptr_parent = ptr;
ptr = &ptr -> right;
}
}
}
(*ptr) = newNode; //insert the newNode at the spot
if(((*ptr_parent) -> data) < value)
(*ptr_parent) -> right = newNode;
else
(*ptr_parent) -> left = newNode;
return true;
}
As I understand, it is failing because of following line:
ptr = newNode; //insert the newNode at the spot
after the while loop your ptr is NULL otherwise you can not exit from the while loop. You are assigning a struct to NULL, which is not right.
Hopefully this helps. Everything else looks normal.
void insert(node* root, int value)
{
if (root == NULL)
{
root = new node;
root->data = value;
return;
}
while(!((root->data < value && root->right == NULL) || (root->data >= value && root->left == NULL)))
{
if (root->data < value)
root = root->right;
else
root = root->left;
}
if (root->data < value)
{
root->right = new node;
root->right->data = value;
} else
{
root->left = new node;
root->left->data = value;
}
}
template <class T>
class TreeNode{
private:
T data;
TreeNode<T>* right,*left;
public:
void setData(T d){
this->data =d;
}
T getData(){
return this->data;
}
void setRight(TreeNode<T>* r){
this->right =r;
}
TreeNode<T>* getRight(){
return this->right;
}
void setLeft(TreeNode<T>* r){
this->left =r;
}
TreeNode<T>* getLeft(){
return this->left;
}
static TreeNode<T>* newNode(T data){
TreeNode<T>* n = new TreeNode<T>();
n->setData(data);
n->setRight(NULL);
n->setLeft(NULL);
return n;
}
};
template <class T>
class BinaryTree{
private:
TreeNode<T>* root;
public:
void insert(T data){
TreeNode<T>* n = TreeNode<T>::newNode(data);
if(root==NULL)
root = n;
else{
TreeNode<T>* t = root;
while(t!=NULL){
if(n->getData() >= t->getData()){
if(t->getRight()==NULL){
t->setRight(n); //newnode attached as right child in tree
t = NULL;
}
else
t = t->getRight();
}
else{
if(t->getLeft()==NULL){
t->setLeft(n); //newnode attached as left child in tree
t=NULL;
}
else
t = t->getLeft();
}
}
}
}
void preorder(){
TreeNode<T>* t = root;
preorderUtil(t);
}
void preorderUtil(TreeNode<T>* node){
if(node==NULL)
return;
preorderUtil(node->getLeft());
cout<<node->getData()<<" ";
preorderUtil(node->getRight());
}
};
I answered a case here Binary Search Tree insertion doesn't work see if it helps
void insert(int val)
{
Node *newNode;
newNode=new Node;
newNode->data=val;
Node *currentNode=root;
Node *parentNode;
if(root==NULL)
{
newNode->left=NULL;
newNode->right=NULL;
}
else
{
while(currentNode!=NULL)
{
if((currentNode->data)>val)
{
parentNode=currentNode;
currentNode=currentNode->left;
}
if((currentNode->data)<val)
{
parentNode=currentNode;
currentNode=currentNode->right;
}
}
}
currentNode=newNode;
if((parentNode->data)<val)
{
parentNode->right=newNode;
}
else
{
parentNode->right=newNode;
}
}
I am trying to just write a basic function that reverses a singly-linked list which is recursive. I was wondering if i tackled this in the right approach? Maybe someone can give me some pointers.
void reverse(Node*& p) {
if (!p) return;
Node* rest = p->next;
if (!rest) return;
reverse(rest);
p->next->next = p;
p->next = NULL;
p = rest;
}
That's not the most efficient way, but to do it, you can call the reverse method with the "next" pointer until there is no next. Once there, set next to previous. After returning from the recursion, set next to previous. See the recursive version here for an example. From the link:
Node * reverse( Node * ptr , Node * previous)
{
Node * temp;
if(ptr->next == NULL) {
ptr->next = previous;
previous->next = NULL;
return ptr;
} else {
temp = reverse(ptr->next, ptr);
ptr->next = previous;
return temp;
}
}
reversedHead = reverse(head, NULL);
This might be helpful
List
{
public:
.....
void plzReverse()
{
Node* node = myReverse(head);
node->next = NULL;
}
private:
Node * myReverse(Node * node)
{
if(node->next == NULL)
{
head = node;
return node;
}
else
{
Node * temp = myReverse(node->next);
temp ->next = node;
return node;
}
}
}
Another solution might be:
List
{
public:
.....
void plzReverse()
{
Node* node = myReverse(head, head);
node->next = NULL;
}
private:
Node * myReverse(Node * node, Node*& rhead)
{
if(node->next == NULL)
{
rhead = node;
return node;
}
else
{
Node * temp = myReverse(node->next,rhead);
temp ->next = node;
return node;
}
}
}
This is what you need:
Node* reverse(Node* p) {
if (p->next == NULL) {
return p;
} else {
Node* t = reverse(p->next); // Now p->next is reversed, t is the new head.
p->next->next = p; // p->next is the current tail, so p becomes the new tail.
p->next = NULL;
return t;
}
}
The recursive solution can look quite pretty, even in C++:
Node* reverse(Node* pivot, Node* backward = 0) {
if (pivot == 0) // We're done
return backward;
// flip the head of pivot from forward to backward
Node* rest = pivot->next;
pivot->next = backward;
// and continue
return reverse(rest, pivot);
}
Most C++ compilers do tail call optimization so there's no reason to believe this to be less efficient than an iterative solution.
Here is the solution that preserves return value as void.
void reverse(Node*& p) {
if (!p) return;
Node* rest = p->next;
if (!rest) {
rest = p;
return;
}
reverse(rest);
p->next->next = p;
p->next = NULL;
p = rest;
}
linkedList *reverseMyNextPointer(linkedList *prevNode, linkedList *currNode)
{
linkedList *tempPtr;
if(!currNode)
return prevNode;
else
{
tempPtr = currNode->next;
currNode->next = prevNode;
return reverseMyNext(currNode,tempPtr);
}
}
head = reverseMyNextPointer(nullptr,head);
I'm trying to make a BST and need to print it inorder, postorder, and preorder.
The thing am not sure about is how to create this tree in my main() function.
struct Tree_Node
{
Tree_Node *right;
Tree_Node *left;
int info;
};
class bTree
{
private:
Tree_Node *root;
public:
bTree();
void bTree::Insert(Tree_Node*& tree, int item);
void bTree::preorderPrint(Tree_Node *root);
};
bTree::bTree()
{
root = NULL;
}
void bTree::Insert(Tree_Node*& tree, int item)
{
if (tree == NULL)
{
tree = new Tree_Node;
tree->right = NULL;
tree->left = NULL;
tree->info = item;
}
else if (item < tree->info)
Insert(tree->left, item);
else
Insert(tree->right, item);
}
void bTree::preorderPrint(Tree_Node *root)
{
if ( root != NULL )
{
cout << root->info << " ";
preorderPrint( root->left );
preorderPrint( root->right );
}
}
void main()
{
// This is where I need help at
// I'm not sure how to insert a new node
bTree Test;
Test.Insert(
}
By the looks of things, you can just write
Test.Insert(Test.root, 3); // Insert 3
Test.Insert(Test.root, 4); // Insert 4
and that should work. Of course, you'll have to make root public.
However, this is a bit awkward, since the first parameter will always be bTree.root - and you don't need to make that public. Remember that the user of your data type (you or anyone else) shouldn't have to care about internals such as nodes - they only care about their data. Instead, I'd recommend making a convenience Insert method which only needs to take an integer (not a tree node) - this is called Overloading.
void bTree::Insert(int item)
{
Insert(root, item);
}
// Keep the other insert method, but make it private.
Then you can just write:
Test.Insert(3);
Test.Insert(4);
void bTree::Insert(int item)
{
Tree_Node * node = new Tree_Node;
node->left = NULL;
node->right = NULL;
node->info = item;
if (root == NULL)
{
root = node;
return;
}
Tree_Node * t = root;
Tree_Node * p = root;
while(1)
{
if (item < t->info)
{
t = t->left;
if(t == NULL)
{
p->left = node;
return;
}
}
else if(item > t->info)
{
t = t->right;
if(t == NULL)
{
p->right = node;
return;
}
}
else //item already exists in the tree
return;
p = t;
}
}
//now you can insert nodes like
Test.Insert(5);
Test.Insert(6);