How to do you call a function inside separated class? - c++

Question

So, I tried to make this code :
#include <iostream>
using namespace std;
class BuckysClass{
public:
void setName(string x){
name = x;
}
string getName(){
return name;
}
private:
string name;
};
int main()
{
BuckysClass bo;
bo.setName("Buckingham Palace");
cout << bo.getName();
return 0;
}
BECOMING TO A SEPARATED CLASS like this :
#include "BuckysClass.h"
#include <iostream>
#include <string>
using namespace std;
int main (){
BuckysClass bo;
bo.setName("Buckingham Palace");
cout << bo.getName();
return 0;
}
==============
#ifndef BUCKYSCLASS_H
#define BUCKYSCLASS_H
class BuckysClass
{
public:
void setName(string x);
string getName();
private:
string name;
};
#endif // BUCKYSCLASS_H
=============
#include "BuckysClass.h"
#include <iostream>
#include <string>
using namespace std;
BuckysClass::BuckysClass()
{
}
void setName(string x){
name = x;
}
string getName(){
return name;
}
When I run the first code, I succeed,
but I got error when running the separated class code,
help me find out what's wrong ???
I tried to use different code,
but it seems I can't find the reason,
the closest reason I believe, is the main doesnt call the function on the separated class properly.

Answer 1

If you write this code:
void setName(string x){
name = x;
}
string getName(){
return name;
}
The compiler interprete it as two functions called setName and getName, it has no idea they are member functions of your BuckysClass class.
You have to precise it with the following syntax:
void BuckysClass::setName(string x){
name = x;
}
string BuckysClass::getName(){
return name;
}
Additionally, here you are defining a default constructor:
BuckysClass::BuckysClass()
{
}
But you didn't put it in the class prototype. You have to add it somewhere in the class prototype definition in your .h file, or your compiler won't recognize it:
class BuckysClass
{
public:
BuckysClass(); // Default constructor.
void setName(string x);
string getName();
private:
string name;
};