My while loops seems to be ignoring my getline - c++

Question

Here's all the code
#include <iostream>
#include <string>
#include <windows.h>
#include <stdlib.h>
using namespace std;
void Pdelay(string str)
{
for (char c : str)
{
std::cout << "" << c << "";
Sleep(100);
}
std::cout << '\n';
}
int main()
{
int exit = 1;
while (exit == 1)
{
cout<< "Type something\n:";
string str;
str.clear();
getline(cin,str);
Pdelay(str);
cout << "\n\n[1]Type something again"<< endl;
cout << "[2]Exit\n:";
cin >> exit;
}
return 0;
}
Whenever I run it, it works properly the first time round, when it loops back it skips the getline and continues with the two cout statements.

Answer 1

Immediately after you use cin, the newline remains in the buffer and is being "eaten" by the subsequent getline. You need to clear the buffer of that additional newline:
// immediately after cin (need to #include <limits>)
std::cin.ignore(std::numeric_limits<std::streamsize>::max(),'\n');
That's why it's not a very good idea to combine std::cin and std::getline. BTW, you can write your code in fully standard compliant C++11, with no additional non-library headers:
#include <chrono>
#include <iostream>
#include <limits>
#include <string>
#include <thread>
void Pdelay(std::string str)
{
for (char c : str)
{
std::cout << "" << c << "" << std::flush;
std::this_thread::sleep_for(std::chrono::milliseconds(100));
}
std::cout << '\n';
}
int main()
{
int ext = 1;
while (ext == 1)
{
std::cout << "Type something\n:";
std::string str;
str.clear();
std::getline(std::cin, str);
Pdelay(str);
std::cout << "\n\n[1]Type something again" << std::endl;
std::cout << "[2]Exit\n:";
std::cin >> ext;
if(!std::cin) // extraction failed
{
std::cin.clear(); // clear the stream
ext = 1;
}
std::cin.ignore(std::numeric_limits<std::streamsize>::max(),'\n');
}
}
I just realized that this question has been asked (in a slightly modified form) before, and the answers are great:
Why does std::getline() skip input after a formatted extraction?