I've a function that is currently overloaded for different data types and takes a lambda(function pointer) to initialize those data types. I'm in process of converting them to template instances but haven't been successful yet.
Here's the overloaded version -
#include <iostream>
using namespace std;
void doSome(int (*func)(int &)){
int a;
a = 5;
int res = func(a);
cout << a << "\n";
}
void doSome(int (*func)(double &)){
double a;
a = 5.2;
int res = func(a);
cout << a << "\n";
}
int main() {
doSome([](int &a){
a += 2;
return 1;
});
doSome([](double &a){
a += 2.5;
return 1;
});
return 0;
}
Note that I've taken example of int and double for simplification, they might be some entirely different(and complex) types in actual code.
Here's what I've tried yet -
#include <iostream>
using namespace std;
template <typename F, typename S>
void doSome(F &func){
S a;
auto res = func(a);
cout << res << "\n";
}
template<>
void doSome<typename F, int> (F &func){
int a;
a = 5;
auto res = func(a);
cout << res << "\n";
}
template<>
void dpSome<typename F, double> (F &func){
double a;
a = 5.5
auto res = func(a);
cout << res << "\n";
}
int main() {
doSome([](int &a){
a += 2;
return 1;
});
doSome([](double &a){
a += 2.5;
return 1;
});
return 0;
}
Also while invoking templated functions, if I don't have to pass <any type hints> to the function, that would be much better solution.
There are a few issues with your approach. First, you can't partially specialize function templates, so that's out from the gate. Second, you're taking your function by lvalue reference - which prevents you from passing in a lambda, which is a prvalue.
In this case, it's easy to just add some SFINAE on your function template so that one only participates in overload resolution if it can be called with int& and the other only with double&:
template <class F>
auto doSome(F f)
-> decltype(f(std::declval<int&>()), void())
{
// int& case
}
template <class F>
auto doSome(F f)
-> decltype(f(std::declval<double&>()), void())
{
// double& case
}
If you want to make a generic version of doSome(), which doesn't use SFINAE for overload resolution, it gets a bit more complex.
#include <type_traits> // For std::remove_reference_t.
namespace detail {
// Helper to isolate return and parameter types, for a single-parameter callable.
template<typename T>
struct isolate_types;
// Function.
template<typename R, typename P>
struct isolate_types<R(P)> { using Ret = R; using Param = P; };
// Function pointer.
template<typename R, typename P>
struct isolate_types<R(*)(P)> { using Ret = R; using Param = P; }
// Pointer-to-member-function. Used for lambdas & functors.
// Assumes const this pointer.
template<typename R, typename C, typename P>
struct isolate_types<R (C::*)(P) const> { using Ret = R; using Param = P; };
// Lambda. Uses lambda's operator().
// Credit goes to ecatmur: http://stackoverflow.com/a/13359520/5386374
template<typename T>
struct isolate_types : isolate_types<decltype(&std::remove_reference_t<T>::operator())> {};
// Individual type aliases.
template<typename T>
using IsolateReturn = typename isolate_types<T>::Ret;
template<typename T>
using IsolateParam = typename isolate_types<T>::Param;
// Internal values, used by doSome().
template<typename T> T value;
template<> constexpr int value<int> = 5;
template<> constexpr double value<double> = 5.2;
// Define others as needed...
} // namespace detail
template<typename F>
void doSome(F func) {
// Determine necessary types.
using Ret = detail::IsolateReturn<F>;
using Param = std::remove_reference_t<detail::IsolateParam<F>>;
// And voila.
Param a = detail::value<Param>;
Ret res = func(a); // Can also use auto, if Ret isn't needed elsewhere.
std::cout << a << "\n";
}
Plugging this into your code... and it works.
Note that I'm not sure if this will work with all lambdas as written, and that it currently won't work with references to functions. It's easy enough to extend, however, by adding additional specialisations of isolate_types.
I'm trying to create a generic wrapper function that takes a function as a template argument and takes the same arguments as that function as its arguments. For example:
template <typename F, F func>
/* return type of F */ wrapper(Ts... Args /* not sure how to get Ts*/)
{
// do stuff
auto ret = F(std::forward<Ts>(args)...);
// do some other stuff
return ret;
}
The solution needs to be castable to a function pointer with the same type as func so that I can pass it to a C api. In other words, the solution needs to be a function and not a function object. Most importantly, I need to be able to do work in the wrapper function.
If the inline comments aren't clear, I'd like to be able to do something like the following:
struct c_api_interface {
int (*func_a)(int, int);
int (*func_b)(char, char, char);
};
int foo(int a, int b)
{
return a + b;
}
int bar(char a, char b, char c)
{
return a + b * c;
}
c_api_interface my_interface;
my_interface.func_a = wrapper<foo>;
my_interface.func_b = wrapper<bar>;
I looked for related posts and found these, but none of them are quite what I'm trying to do. Most of these posts concern function objects. Is what I'm trying to do even possible?
Function passed as template argument
Function wrapper via (function object) class (variadic) template
How does wrapping a function pointer and function object work in generic code?
How do I get the argument types of a function pointer in a variadic template class?
Generic functor for functions with any argument list
C++ Functors - and their uses
In response to the first 2 responses, I edited the question to make it clear that I need to be able to do work in the wrapper function (i.e. modify some global state before and after the call to the wrapped function)
template<class F, F f> struct wrapper_impl;
template<class R, class... Args, R(*f)(Args...)>
struct wrapper_impl<R(*)(Args...), f> {
static R wrap(Args... args) {
// stuff
return f(args...);
}
};
template<class F, F f>
constexpr auto wrapper = wrapper_impl<F, f>::wrap;
Use as wrapper<decltype(&foo), foo>.
#include <utility>
#include <iostream>
struct c_api_interface { int (*func_a)(int, int); int (*func_b)(char, char, char); };
int foo(int a, int b) { return a + b; }
int bar(char a, char b, char c) { return a + b * c; }
template<typename Fn, Fn fn, typename... Args>
typename std::result_of<Fn(Args...)>::type
wrapper(Args... args) {
std::cout << "and ....it's a wrap ";
return fn(std::forward<Args>(args)...);
}
#define WRAPIT(FUNC) wrapper<decltype(&FUNC), &FUNC>
int main() {
c_api_interface my_interface;
my_interface.func_a = WRAPIT(foo);
my_interface.func_b = WRAPIT(bar);
std:: cout << my_interface.func_a(1,1) << std::endl;
std:: cout << my_interface.func_b('a','b', 1) << std::endl;
return 0;
}
see http://rextester.com/ZZD18334
you may try something like that (Ugly, but works)
#include <iostream>
#include <functional>
struct wrapper_ctx
{
wrapper_ctx ()
{
std::cout << "Before" << std::endl;
}
~wrapper_ctx ()
{
std::cout << "after" << std::endl;
}
};
template <typename F, typename... Args>
auto executor (F&& f, Args&&... args) -> typename std::result_of<F(Args...)>::type
{
wrapper_ctx ctx;
return std::forward<F>(f)( std::forward<Args>(args)...);
}
template <typename F>
class wrapper_helper;
template<typename Ret, typename... Args>
class wrapper_helper <std::function<Ret(Args...)>>
{
std::function<Ret(Args...)> m_f;
public:
wrapper_helper( std::function<Ret(Args...)> f )
: m_f(f) {}
Ret operator()(Args... args) const
{
return executor (m_f, args...);
}
};
template <typename T>
wrapper_helper<T> wrapper (T f)
{
return wrapper_helper <T>(f);
}
int sum(int x, int y)
{
return x + y;
}
int main (int argc, char* argv [])
{
std::function<int(int, int)> f = sum;
auto w = wrapper (f);
std::cout << "Executing the wrapper" << std::endl;
int z = w(3, 4);
std::cout << "z = " << z << std::endl;
}
you probably need something like
template <typename F>
class Wrapper {
public:
Wrapper(F *func) : function(func) {}
operator F* () { return function; }
F *function;
};
Which you can use like void (*funcPtr)(int) = Wrapper<void(int)>(&someFunction);
I think that will be the concise way to do what you want:
template <typename F>
F* wrapper(F* pFunc)
{
return pFunc;
}
and use it like this:
my_interface.func_a = wrapper(foo);
my_interface.func_a(1, 3);
You may try this
template <class R, class... Args>
struct wrap
{
using funct_type = R(*)(Args...);
funct_type func;
wrap(funct_type f): func(f) {};
R operator()(Args&&... args)
{
//before code block
std::cout << "before calling\n";
R ret=func(std::forward<Args>(args)...);
//after code block
std::cout << "After calling\n";
}
};
use like this for example:
int somefunc(double &f, int x);
auto wrapped_somefunc=wrap{somefunc};
double f=1.0;
int x = 2;
auto result=wrapped_somefunc(f,x);
This one is for c++17 and newer uses auto template parameters:
template <auto func, class... Args>
auto wrap_func(Args... args)
{
std::cout << "before calling wrapped func\n";
auto ret = func(args...);
std::cout << "after calling wrapped func\n";
return ret;
}
use for example:
int some_func(int a, int b);
auto ret = wrap_func<some_func>(2, 3);
How can I create a std::function from member function without need for typing std::placeholders::_1, std::placeholders::_2, etc - I would like to "placehold" all arguments, saving only the object itself.
struct Foo{
int bar(int,float,bool) {return 0;}
};
int baz(int,float,bool) {return 0;}
int main() {
Foo object;
std::function<int(int,float,bool)> fun1 = baz; // OK
std::function<int(int,float,bool)> fun2 = std::bind(&Foo::bar, object); // WRONG, needs placeholders
}
I don't want to provide arguments at this stage, I just want to store function + object somewhere. For example I would like to have std::vector with both global functions and member functions. It was easy to do with FastDelegate (fastdelegate::MakeDelegate(object, &Class::function)).
I don't want to use lambda as it would require me to retype arguments as well. I just want old FastDelegate behaviour.
You can use function template which will deduce all member function parameter types, like this:
template<typename Obj, typename Result, typename ...Args>
auto make_delegate(const Obj &x, Result (Obj::*fun)(Args...)) -> // ...
And will return special delegate object, which will contain your object (or pointer to it) and just forward all passed arguments to member function of underlying object:
template<typename Obj, typename Result, typename ...Args>
struct Delegate
{
Obj x;
Result (Obj::*f)(Args...);
template<typename ...Ts>
Result operator()(Ts&&... args)
{
return (x.*f)(forward<Ts>(args)...);
}
};
You will get following usage syntax:
function<int(int,float,bool)> fun = make_delegate(object, &Foo::bar);
Here is full example:
#include <functional>
#include <iostream>
#include <utility>
using namespace std;
struct Foo
{
int bar(int x, float y, bool z)
{
cout << "bar: " << x << " " << y << " " << z << endl;
return 0;
}
};
int baz(int x, float y, bool z)
{
cout << "baz: " << x << " " << y << " " << z << endl;
return 0;
}
template<typename Obj, typename Result, typename ...Args>
struct Delegate
{
Obj x;
Result (Obj::*f)(Args...);
template<typename ...Ts>
Result operator()(Ts&&... args)
{
return (x.*f)(forward<Ts>(args)...);
}
};
template<typename Obj, typename Result, typename ...Args>
auto make_delegate(const Obj &x, Result (Obj::*fun)(Args...))
-> Delegate<Obj, Result, Args...>
{
Delegate<Obj, Result, Args...> result{x, fun};
return result;
}
int main()
{
Foo object;
function<int(int,float,bool)> fun[] =
{
baz,
make_delegate(object, &Foo::bar) // <---- usage
};
for(auto &x : fun)
x(1, 1.0, 1);
}
Output is:
baz: 1 1 1
bar: 1 1 1
Live Demo on Coliru
If you don't want to use placeholders, then std::bind is not for you:
Use lambda:
Foo object;
std::function<int(int,float,bool)> fun = [&object](int a, float b, bool c) {
return object.bar(a,b,c);
};
You can capture object by value if you wish. Perhaps you realize this is no better than using placeholders, as you're typing parameters anyway — in fact you type more in this case!
You can easily do this with variadic generic lambdas in C++14:
template<typename F, typename C>
auto smart_bind(F f, C* c)
{
return [c, f](auto&&... args) { return (c->*f)(std::forward<decltype(args)>(args)...); };
}
// In your code:
std::function<int(int,float,bool)> fun2 = smart_bind(&Foo::bar, &object);
Live demo: https://ideone.com/deR4fy
I'm trying to create a function which can be called with a lambda that takes either 0, 1 or 2 arguments. Since I need the code to work on both g++ 4.5 and vs2010(which doesn't support variadic templates or lambda conversions to function pointers) the only idea I've come up with is to choose which implementation to call based on arity. The below is my non working guess at how this should look. Is there any way to fix my code or is there a better way to do this in general?
#include <iostream>
#include <functional>
using namespace std;
template <class Func> struct arity;
template <class Func>
struct arity<Func()>{ static const int val = 0; };
template <class Func, class Arg1>
struct arity<Func(Arg1)>{ static const int val = 1; };
template <class Func, class Arg1, class Arg2>
struct arity<Func(Arg1,Arg2)>{ static const int val = 2; };
template<class F>
void bar(F f)
{
cout << arity<F>::val << endl;
}
int main()
{
bar([]{cout << "test" << endl;});
}
A lambda function is a class type with a single function call operator. You can thus detect the arity of that function call operator by taking its address and using overload resolution to select which function to call:
#include <iostream>
template<typename F,typename R>
void do_stuff(F& f,R (F::*mf)() const)
{
(f.*mf)();
}
template<typename F,typename R,typename A1>
void do_stuff(F& f,R (F::*mf)(A1) const)
{
(f.*mf)(99);
}
template<typename F,typename R,typename A1,typename A2>
void do_stuff(F& f,R (F::*mf)(A1,A2) const)
{
(f.*mf)(42,123);
}
template<typename F>
void do_stuff(F f)
{
do_stuff(f,&F::operator());
}
int main()
{
do_stuff([]{std::cout<<"no args"<<std::endl;});
do_stuff([](int a1){std::cout<<"1 args="<<a1<<std::endl;});
do_stuff([](int a1,int a2){std::cout<<"2 args="<<a1<<","<<a2<<std::endl;});
}
Be careful though: this won't work with function types, or class types that have more than one function call operator, or non-const function call operators.
I thought the following would work but it doesn't, I'm posting it for two reasons.
To save people the time if they had the same idea
If someone knows why this doesn't work, I'm not 100% sure I understand (although I have my suspicions)
Code follows:
#include <iostream>
#include <functional>
template <typename Ret>
unsigned arity(std::function<Ret()>) { return 0; }
template <typename Ret, typename A1>
unsigned arity(std::function<Ret(A1)>) { return 1; }
template <typename Ret, typename A1, typename A2>
unsigned arity(std::function<Ret(A1, A2)>) { return 2; }
// rinse and repeat
int main()
{
std::function<void(int)> f = [](int i) { }; // this binds fine
// Error: no matching function for call to 'arity(main()::<lambda(int)>)'
std::cout << arity([](int i) { });
}
Compile time means of obtaining the arity of a function or a function object, including that of a lambda:
int main (int argc, char ** argv) {
auto f0 = []() {};
auto f1 = [](int) {};
auto f2 = [](int, void *) {};
std::cout << Arity<decltype(f0)>::value << std::endl; // 0
std::cout << Arity<decltype(f1)>::value << std::endl; // 1
std::cout << Arity<decltype(f2)>::value << std::endl; // 2
std::cout << Arity<decltype(main)>::value << std::endl; // 2
}
template <typename Func>
class Arity {
private:
struct Any {
template <typename T>
operator T ();
};
template <typename T>
struct Id {
typedef T type;
};
template <size_t N>
struct Size {
enum { value = N };
};
template <typename F>
static Size<0> match (
F f,
decltype(f()) * = nullptr);
template <typename F>
static Size<1> match (
F f,
decltype(f(Any())) * = nullptr,
decltype(f(Any())) * = nullptr);
template <typename F>
static Size<2> match (
F f,
decltype(f(Any(), Any())) * = nullptr,
decltype(f(Any(), Any())) * = nullptr,
decltype(f(Any(), Any())) * = nullptr);
public:
enum { value = Id<decltype(match(static_cast<Func>(Any())))>::type::value };
};
This way works:
template<typename F>
auto call(F f) -> decltype(f(1))
{
return f(1);
}
template<typename F>
auto call(F f, void * fake = 0) -> decltype(f(2,3))
{
return f(2,3);
}
template<typename F>
auto call(F f, void * fake = 0, void * fake2 = 0) -> decltype(f(4,5,6))
{
return f(4,5,6);
}
int main()
{
auto x1 = call([](int a){ return a*10; });
auto x2 = call([](int a, int b){ return a*b; });
auto x3 = call([](int a, int b, int c){ return a*b*c; });
// x1 == 1*10
// x2 == 2*3
// x3 == 4*5*6
}
It works for all callable types (lambdas, functors, etc)
What is currying?
How can currying be done in C++?
Please Explain binders in STL container?
1. What is currying?
Currying simply means a transformation of a function of several arguments to a function of a single argument. This is most easily illustrated using an example:
Take a function f that accepts three arguments:
int
f(int a,std::string b,float c)
{
// do something with a, b, and c
return 0;
}
If we want to call f, we have to provide all of its arguments f(1,"some string",19.7f).
Then a curried version of f, let's call it curried_f=curry(f) only expects a single argument, that corresponds to the first argument of f, namely the argument a. Additionally, f(1,"some string",19.7f) can also be written using the curried version as curried_f(1)("some string")(19.7f). The return value of curried_f(1) on the other hand is just another function, that handles the next argument of f. In the end, we end up with a function or callable curried_f that fulfills the following equality:
curried_f(first_arg)(second_arg)...(last_arg) == f(first_arg,second_arg,...,last_arg).
2. How can currying be achieved in C++?
The following is a little bit more complicated, but works very well for me (using c++11)... It also allows currying of arbitrary degree like so: auto curried=curry(f)(arg1)(arg2)(arg3) and later auto result=curried(arg4)(arg5). Here it goes:
#include <functional>
namespace _dtl {
template <typename FUNCTION> struct
_curry;
// specialization for functions with a single argument
template <typename R,typename T> struct
_curry<std::function<R(T)>> {
using
type = std::function<R(T)>;
const type
result;
_curry(type fun) : result(fun) {}
};
// recursive specialization for functions with more arguments
template <typename R,typename T,typename...Ts> struct
_curry<std::function<R(T,Ts...)>> {
using
remaining_type = typename _curry<std::function<R(Ts...)> >::type;
using
type = std::function<remaining_type(T)>;
const type
result;
_curry(std::function<R(T,Ts...)> fun)
: result (
[=](const T& t) {
return _curry<std::function<R(Ts...)>>(
[=](const Ts&...ts){
return fun(t, ts...);
}
).result;
}
) {}
};
}
template <typename R,typename...Ts> auto
curry(const std::function<R(Ts...)> fun)
-> typename _dtl::_curry<std::function<R(Ts...)>>::type
{
return _dtl::_curry<std::function<R(Ts...)>>(fun).result;
}
template <typename R,typename...Ts> auto
curry(R(* const fun)(Ts...))
-> typename _dtl::_curry<std::function<R(Ts...)>>::type
{
return _dtl::_curry<std::function<R(Ts...)>>(fun).result;
}
#include <iostream>
void
f(std::string a,std::string b,std::string c)
{
std::cout << a << b << c;
}
int
main() {
curry(f)("Hello ")("functional ")("world!");
return 0;
}
View output
OK, as Samer commented, I should add some explanations as to how this works. The actual implementation is done in the _dtl::_curry, while the template functions curry are only convenience wrappers. The implementation is recursive over the arguments of the std::function template argument FUNCTION.
For a function with only a single argument, the result is identical to the original function.
_curry(std::function<R(T,Ts...)> fun)
: result (
[=](const T& t) {
return _curry<std::function<R(Ts...)>>(
[=](const Ts&...ts){
return fun(t, ts...);
}
).result;
}
) {}
Here the tricky thing: For a function with more arguments, we return a lambda whose argument is bound to the first argument to the call to fun. Finally, the remaining currying for the remaining N-1 arguments is delegated to the implementation of _curry<Ts...> with one less template argument.
Update for c++14 / 17:
A new idea to approach the problem of currying just came to me... With the introduction of if constexpr into c++17 (and with the help of void_t to determine if a function is fully curried), things seem to get a lot easier:
template< class, class = std::void_t<> > struct
needs_unapply : std::true_type { };
template< class T > struct
needs_unapply<T, std::void_t<decltype(std::declval<T>()())>> : std::false_type { };
template <typename F> auto
curry(F&& f) {
/// Check if f() is a valid function call. If not we need
/// to curry at least one argument:
if constexpr (needs_unapply<decltype(f)>::value) {
return [=](auto&& x) {
return curry(
[=](auto&&...xs) -> decltype(f(x,xs...)) {
return f(x,xs...);
}
);
};
}
else {
/// If 'f()' is a valid call, just call it, we are done.
return f();
}
}
int
main()
{
auto f = [](auto a, auto b, auto c, auto d) {
return a * b * c * d;
};
return curry(f)(1)(2)(3)(4);
}
See code in action on here. With a similar approach, here is how to curry functions with arbitrary number of arguments.
The same idea seems to work out also in C++14, if we exchange the constexpr if with a template selection depending on the test needs_unapply<decltype(f)>::value:
template <typename F> auto
curry(F&& f);
template <bool> struct
curry_on;
template <> struct
curry_on<false> {
template <typename F> static auto
apply(F&& f) {
return f();
}
};
template <> struct
curry_on<true> {
template <typename F> static auto
apply(F&& f) {
return [=](auto&& x) {
return curry(
[=](auto&&...xs) -> decltype(f(x,xs...)) {
return f(x,xs...);
}
);
};
}
};
template <typename F> auto
curry(F&& f) {
return curry_on<needs_unapply<decltype(f)>::value>::template apply(f);
}
In short, currying takes a function f(x, y) and given a fixed Y, gives a new function g(x) where
g(x) == f(x, Y)
This new function may be called in situations where only one argument is supplied, and passes the call on to the original f function with the fixed Y argument.
The binders in the STL allow you to do this for C++ functions. For example:
#include <functional>
#include <iostream>
#include <vector>
using namespace std;
// declare a binary function object
class adder: public binary_function<int, int, int> {
public:
int operator()(int x, int y) const
{
return x + y;
}
};
int main()
{
// initialise some sample data
vector<int> a, b;
a.push_back(1);
a.push_back(2);
a.push_back(3);
// here we declare a function object f and try it out
adder f;
cout << "f(2, 3) = " << f(2, 3) << endl;
// transform() expects a function with one argument, so we use
// bind2nd to make a new function based on f, that takes one
// argument and adds 5 to it
transform(a.begin(), a.end(), back_inserter(b), bind2nd(f, 5));
// output b to see what we got
cout << "b = [" << endl;
for (vector<int>::iterator i = b.begin(); i != b.end(); ++i) {
cout << " " << *i << endl;
}
cout << "]" << endl;
return 0;
}
Simplifying Gregg's example, using tr1:
#include <functional>
using namespace std;
using namespace std::tr1;
using namespace std::tr1::placeholders;
int f(int, int);
..
int main(){
function<int(int)> g = bind(f, _1, 5); // g(x) == f(x, 5)
function<int(int)> h = bind(f, 2, _1); // h(x) == f(2, x)
function<int(int,int)> j = bind(g, _2); // j(x,y) == g(y)
}
Tr1 functional components allow you to write rich functional-style code in C++. As well, C++0x will allow for in-line lambda functions to do this as well:
int f(int, int);
..
int main(){
auto g = [](int x){ return f(x,5); }; // g(x) == f(x, 5)
auto h = [](int x){ return f(2,x); }; // h(x) == f(2, x)
auto j = [](int x, int y){ return g(y); }; // j(x,y) == g(y)
}
And while C++ doesn't provide the rich side-effect analysis that some functional-oriented programming languages perform, const analysis and C++0x lambda syntax can help:
struct foo{
int x;
int operator()(int y) const {
x = 42; // error! const function can't modify members
}
};
..
int main(){
int x;
auto f = [](int y){ x = 42; }; // error! lambdas don't capture by default.
}
Hope that helps.
Have a look at Boost.Bind which makes the process shown by Greg more versatile:
transform(a.begin(), a.end(), back_inserter(b), bind(f, _1, 5));
This binds 5 to f's second argument.
It’s worth noting that this is not currying (instead, it’s partial application). However, using currying in a general way is hard in C++ (in fact, it only recently became possible at all) and partial application is often used instead.
Other answers nicely explain binders, so I won't repeat that part here. I will only demonstrate how currying and partial application can be done with lambdas in C++0x.
Code example: (Explanation in comments)
#include <iostream>
#include <functional>
using namespace std;
const function<int(int, int)> & simple_add =
[](int a, int b) -> int {
return a + b;
};
const function<function<int(int)>(int)> & curried_add =
[](int a) -> function<int(int)> {
return [a](int b) -> int {
return a + b;
};
};
int main() {
// Demonstrating simple_add
cout << simple_add(4, 5) << endl; // prints 9
// Demonstrating curried_add
cout << curried_add(4)(5) << endl; // prints 9
// Create a partially applied function from curried_add
const auto & add_4 = curried_add(4);
cout << add_4(5) << endl; // prints 9
}
If you're using C++14 it's very easy:
template<typename Function, typename... Arguments>
auto curry(Function function, Arguments... args) {
return [=](auto... rest) {
return function(args..., rest...);
}; // don't forget semicolumn
}
You can then use it like this:
auto add = [](auto x, auto y) { return x + y; }
// curry 4 into add
auto add4 = curry(add, 4);
add4(6); // 10
Some great answers here. I thought I would add my own because it was fun to play around with the concept.
Partial function application: The process of "binding" a function with only some of its parameters, deferring the rest to be filled in later. The result is another function with fewer parameters.
Currying: Is a special form of partial function application where you can only "bind" a single argument at a time. The result is another function with exactly 1 fewer parameter.
The code I'm about to present is partial function application from which currying is possible, but not the only possibility. It offers a few benefits over the above currying implementations (mainly because it's partial function application and not currying, heh).
Applying over an empty function:
auto sum0 = [](){return 0;};
std::cout << partial_apply(sum0)() << std::endl;
Applying multiple arguments at a time:
auto sum10 = [](int a, int b, int c, int d, int e, int f, int g, int h, int i, int j){return a+b+c+d+e+f+g+h+i+j;};
std::cout << partial_apply(sum10)(1)(1,1)(1,1,1)(1,1,1,1) << std::endl; // 10
constexpr support that allows for compile-time static_assert:
static_assert(partial_apply(sum0)() == 0);
A useful error message if you accidentally go too far in providing arguments:
auto sum1 = [](int x){ return x;};
partial_apply(sum1)(1)(1);
error: static_assert failed "Attempting to apply too many arguments!"
Other answers above return lambdas that bind an argument and then return further lambdas. This approach wraps that essential functionality into a callable object. Definitions for operator() allow the internal lambda to be called. Variadic templates allow us to check for someone going too far, and an implicit conversion function to the result type of the function call allows us to print the result or compare the object to a primitive.
Code:
namespace detail{
template<class F>
using is_zero_callable = decltype(std::declval<F>()());
template<class F>
constexpr bool is_zero_callable_v = std::experimental::is_detected_v<is_zero_callable, F>;
}
template<class F>
struct partial_apply_t
{
template<class... Args>
constexpr auto operator()(Args... args)
{
static_assert(sizeof...(args) == 0 || !is_zero_callable, "Attempting to apply too many arguments!");
auto bind_some = [=](auto... rest) -> decltype(myFun(args..., rest...))
{
return myFun(args..., rest...);
};
using bind_t = decltype(bind_some);
return partial_apply_t<bind_t>{bind_some};
}
explicit constexpr partial_apply_t(F fun) : myFun(fun){}
constexpr operator auto()
{
if constexpr (is_zero_callable)
return myFun();
else
return *this; // a callable
}
static constexpr bool is_zero_callable = detail::is_zero_callable_v<F>;
F myFun;
};
Live Demo
A few more notes:
I chose to use is_detected mainly for enjoyment and practice; it serves the same as a normal type trait would here.
There could definitely be more work done to support perfect forwarding for performance reasons
The code is C++17 because it requires for constexpr lambda support in C++17
And it seems that GCC 7.0.1 is not quite there yet, either, so I used Clang 5.0.0
Some tests:
auto sum0 = [](){return 0;};
auto sum1 = [](int x){ return x;};
auto sum2 = [](int x, int y){ return x + y;};
auto sum3 = [](int x, int y, int z){ return x + y + z; };
auto sum10 = [](int a, int b, int c, int d, int e, int f, int g, int h, int i, int j){return a+b+c+d+e+f+g+h+i+j;};
std::cout << partial_apply(sum0)() << std::endl; //0
static_assert(partial_apply(sum0)() == 0, "sum0 should return 0");
std::cout << partial_apply(sum1)(1) << std::endl; // 1
std::cout << partial_apply(sum2)(1)(1) << std::endl; // 2
std::cout << partial_apply(sum3)(1)(1)(1) << std::endl; // 3
static_assert(partial_apply(sum3)(1)(1)(1) == 3, "sum3 should return 3");
std::cout << partial_apply(sum10)(1)(1,1)(1,1,1)(1,1,1,1) << std::endl; // 10
//partial_apply(sum1)(1)(1); // fails static assert
auto partiallyApplied = partial_apply(sum3)(1)(1);
std::function<int(int)> finish_applying = partiallyApplied;
std::cout << std::boolalpha << (finish_applying(1) == 3) << std::endl; // true
auto plus2 = partial_apply(sum3)(1)(1);
std::cout << std::boolalpha << (plus2(1) == 3) << std::endl; // true
std::cout << std::boolalpha << (plus2(3) == 5) << std::endl; // true
Currying is a way of reducing a function that takes multiple arguments into a sequence of nested functions with one argument each:
full = (lambda a, b, c: (a + b + c))
print full (1, 2, 3) # print 6
# Curried style
curried = (lambda a: (lambda b: (lambda c: (a + b + c))))
print curried (1)(2)(3) # print 6
Currying is nice because you can define functions that are simply wrappers around other functions with pre-defined values, and then pass around the simplified functions. C++ STL binders provide an implementation of this in C++.
I implemented currying with variadic templates as well (see Julian's answer). However, I did not make use of recursion or std::function. Note: It uses a number of C++14 features.
The provided example (main function) actually runs at compile time, proving that the currying method does not trump essential optimizations by the compiler.
The code can be found here: https://gist.github.com/Garciat/c7e4bef299ee5c607948
with this helper file: https://gist.github.com/Garciat/cafe27d04cfdff0e891e
The code still needs (a lot of) work, which I may or may not complete soon. Either way, I'm posting this here for future reference.
Posting code in case links die (though they shouldn't):
#include <type_traits>
#include <tuple>
#include <functional>
#include <iostream>
// ---
template <typename FType>
struct function_traits;
template <typename RType, typename... ArgTypes>
struct function_traits<RType(ArgTypes...)> {
using arity = std::integral_constant<size_t, sizeof...(ArgTypes)>;
using result_type = RType;
template <size_t Index>
using arg_type = typename std::tuple_element<Index, std::tuple<ArgTypes...>>::type;
};
// ---
namespace details {
template <typename T>
struct function_type_impl
: function_type_impl<decltype(&T::operator())>
{ };
template <typename RType, typename... ArgTypes>
struct function_type_impl<RType(ArgTypes...)> {
using type = RType(ArgTypes...);
};
template <typename RType, typename... ArgTypes>
struct function_type_impl<RType(*)(ArgTypes...)> {
using type = RType(ArgTypes...);
};
template <typename RType, typename... ArgTypes>
struct function_type_impl<std::function<RType(ArgTypes...)>> {
using type = RType(ArgTypes...);
};
template <typename T, typename RType, typename... ArgTypes>
struct function_type_impl<RType(T::*)(ArgTypes...)> {
using type = RType(ArgTypes...);
};
template <typename T, typename RType, typename... ArgTypes>
struct function_type_impl<RType(T::*)(ArgTypes...) const> {
using type = RType(ArgTypes...);
};
}
template <typename T>
struct function_type
: details::function_type_impl<typename std::remove_cv<typename std::remove_reference<T>::type>::type>
{ };
// ---
template <typename Args, typename Params>
struct apply_args;
template <typename HeadArgs, typename... Args, typename HeadParams, typename... Params>
struct apply_args<std::tuple<HeadArgs, Args...>, std::tuple<HeadParams, Params...>>
: std::enable_if<
std::is_constructible<HeadParams, HeadArgs>::value,
apply_args<std::tuple<Args...>, std::tuple<Params...>>
>::type
{ };
template <typename... Params>
struct apply_args<std::tuple<>, std::tuple<Params...>> {
using type = std::tuple<Params...>;
};
// ---
template <typename TupleType>
struct is_empty_tuple : std::false_type { };
template <>
struct is_empty_tuple<std::tuple<>> : std::true_type { };
// ----
template <typename FType, typename GivenArgs, typename RestArgs>
struct currying;
template <typename FType, typename... GivenArgs, typename... RestArgs>
struct currying<FType, std::tuple<GivenArgs...>, std::tuple<RestArgs...>> {
std::tuple<GivenArgs...> given_args;
FType func;
template <typename Func, typename... GivenArgsReal>
constexpr
currying(Func&& func, GivenArgsReal&&... args) :
given_args(std::forward<GivenArgsReal>(args)...),
func(std::move(func))
{ }
template <typename... Args>
constexpr
auto operator() (Args&&... args) const& {
using ParamsTuple = std::tuple<RestArgs...>;
using ArgsTuple = std::tuple<Args...>;
using RestArgsPrime = typename apply_args<ArgsTuple, ParamsTuple>::type;
using CanExecute = is_empty_tuple<RestArgsPrime>;
return apply(CanExecute{}, std::make_index_sequence<sizeof...(GivenArgs)>{}, std::forward<Args>(args)...);
}
template <typename... Args>
constexpr
auto operator() (Args&&... args) && {
using ParamsTuple = std::tuple<RestArgs...>;
using ArgsTuple = std::tuple<Args...>;
using RestArgsPrime = typename apply_args<ArgsTuple, ParamsTuple>::type;
using CanExecute = is_empty_tuple<RestArgsPrime>;
return std::move(*this).apply(CanExecute{}, std::make_index_sequence<sizeof...(GivenArgs)>{}, std::forward<Args>(args)...);
}
private:
template <typename... Args, size_t... Indices>
constexpr
auto apply(std::false_type, std::index_sequence<Indices...>, Args&&... args) const& {
using ParamsTuple = std::tuple<RestArgs...>;
using ArgsTuple = std::tuple<Args...>;
using RestArgsPrime = typename apply_args<ArgsTuple, ParamsTuple>::type;
using CurryType = currying<FType, std::tuple<GivenArgs..., Args...>, RestArgsPrime>;
return CurryType{ func, std::get<Indices>(given_args)..., std::forward<Args>(args)... };
}
template <typename... Args, size_t... Indices>
constexpr
auto apply(std::false_type, std::index_sequence<Indices...>, Args&&... args) && {
using ParamsTuple = std::tuple<RestArgs...>;
using ArgsTuple = std::tuple<Args...>;
using RestArgsPrime = typename apply_args<ArgsTuple, ParamsTuple>::type;
using CurryType = currying<FType, std::tuple<GivenArgs..., Args...>, RestArgsPrime>;
return CurryType{ std::move(func), std::get<Indices>(std::move(given_args))..., std::forward<Args>(args)... };
}
template <typename... Args, size_t... Indices>
constexpr
auto apply(std::true_type, std::index_sequence<Indices...>, Args&&... args) const& {
return func(std::get<Indices>(given_args)..., std::forward<Args>(args)...);
}
template <typename... Args, size_t... Indices>
constexpr
auto apply(std::true_type, std::index_sequence<Indices...>, Args&&... args) && {
return func(std::get<Indices>(std::move(given_args))..., std::forward<Args>(args)...);
}
};
// ---
template <typename FType, size_t... Indices>
constexpr
auto curry(FType&& func, std::index_sequence<Indices...>) {
using RealFType = typename function_type<FType>::type;
using FTypeTraits = function_traits<RealFType>;
using CurryType = currying<FType, std::tuple<>, std::tuple<typename FTypeTraits::template arg_type<Indices>...>>;
return CurryType{ std::move(func) };
}
template <typename FType>
constexpr
auto curry(FType&& func) {
using RealFType = typename function_type<FType>::type;
using FTypeArity = typename function_traits<RealFType>::arity;
return curry(std::move(func), std::make_index_sequence<FTypeArity::value>{});
}
// ---
int main() {
auto add = curry([](int a, int b) { return a + b; });
std::cout << add(5)(10) << std::endl;
}
These Links are relevant:
The Lambda Calculus page on Wikipedia has a clear example of currying
http://en.wikipedia.org/wiki/Lambda_calculus#Motivation
This paper treats currying in C/C++
http://asg.unige.ch/site/papers/Dami91a.pdf
C++20 provides bind_front for doing currying.
For older C++ version it can be implemented (for single argument) as follows:
template <typename TFunc, typename TArg>
class CurryT
{
private:
TFunc func;
TArg arg ;
public:
template <typename TFunc_, typename TArg_>
CurryT(TFunc_ &&func, TArg_ &&arg)
: func(std::forward<TFunc_>(func))
, arg (std::forward<TArg_ >(arg ))
{}
template <typename... TArgs>
auto operator()(TArgs &&...args) const
-> decltype( func(arg, std::forward<TArgs>(args)...) )
{ return func(arg, std::forward<TArgs>(args)...); }
};
template <typename TFunc, typename TArg>
CurryT<std::decay_t<TFunc>, std::remove_cv_t<TArg>> Curry(TFunc &&func, TArg &&arg)
{ return {std::forward<TFunc>(func), std::forward<TArg>(arg)}; }
https://coliru.stacked-crooked.com/a/82856e39da5fa50d
void Abc(std::string a, int b, int c)
{
std::cerr << a << b << c << std::endl;
}
int main()
{
std::string str = "Hey";
auto c1 = Curry(Abc, str);
std::cerr << "str: " << str << std::endl;
c1(1, 2);
auto c2 = Curry(std::move(c1), 3);
c2(4);
auto c3 = Curry(c2, 5);
c3();
}
Output:
str:
Hey12
Hey34
Hey35
If you use long chains of currying then std::shared_ptr optimization can be used to avoid copying all previous curried parameters to each new carried function.
template <typename TFunc>
class SharedFunc
{
public:
struct Tag{}; // For avoiding shadowing copy/move constructors with the
// templated constructor below which accepts any parameters.
template <typename... TArgs>
SharedFunc(Tag, TArgs &&...args)
: p_func( std::make_shared<TFunc>(std::forward<TArgs>(args)...) )
{}
template <typename... TArgs>
auto operator()(TArgs &&...args) const
-> decltype( (*p_func)(std::forward<TArgs>(args)...) )
{ return (*p_func)(std::forward<TArgs>(args)...); }
private:
std::shared_ptr<TFunc> p_func;
};
template <typename TFunc, typename TArg>
SharedFunc<
CurryT<std::decay_t<TFunc>, std::remove_cv_t<TArg>>
>
CurryShared(TFunc &&func, TArg &&arg)
{
return { {}, std::forward<TFunc>(func), std::forward<TArg>(arg) };
}
https://coliru.stacked-crooked.com/a/6e71f41e1cc5fd5c