from googlefinance import getQuotes
import json
import time as t
import re
List = ["A","AA","AAB"]
Time=t.localtime() # Sets variable Time to retrieve date/time info
Date2= ('%d-%d-%d %dh:%dm:%dsec'%(Time[0],Time[1],Time[2],Time[3],Time[4],Time[5])) #formats time stamp
while True:
for i in List:
try: #allows elements to be called and if an error does the next step
Data = json.dumps(getQuotes(i.lower()),indent=1) #retrieves Data from google finance
regex = ('"LastTradePrice": "(.+?)",') #sets parse
pattern = re.compile(regex) #compiles parse
price = re.findall(pattern,Data) #retrieves parse
print(i)
print(price)
except: #sets Error coding
Error = (i + ' Failed to load on: ' + Date2)
print (Error)
It will display the quote as: ['(number)'].
I would like it to only display the number, which means removing the brackets and quotes.
Any help would be great.
Changing:
print(price)
into:
print(price[0])
prints this:
A
42.14
AA
10.13
AAB
0.110
Try to use type() function to know the datatype, in your case type(price)
it the data type is list use print(price[0])
you will get the output (number), for brecess you need to check google data and regex.
Related
Hello everyone I'm making a really simple lookup in a pandas dataframe, what I need to do is to lookup for the input I'm typing as a regex instead of == myvar
So far this is what I got which is very inneficient because there's a lot of Names in my DataFrame that instead of matching a list of them which could be
Name LastName
NAME 1 Some Awesome
Name 2 Last Names
Nam e 3 I can keep going
Bane Writing this is awesome
BANE 114 Lets continue
However this is what I got
import pandas as pd
contacts = pd.read_csv("contacts.csv")
print("regex contacts")
nameLookUp = input("Type the name you are looking for: ")
print(nameLookUp)
desiredRegexVar = contacts.loc[contacts['Name'] == nameLookUp]
print(desiredRegexVar)
I have to type 'NAME 1' or 'Nam e 3' in order results or I wont get any at all, I tried using this but it didnt work
#regexVar = "^" + contacts.filter(regex = nameLookUp)
Thanks for the answer #Code Different
The code looks like this
import pandas as pd
import re
namelookup = input("Type the name you are looking for: ")
pattern = '^' + re.escape(namelookup)
match = contactos['Cliente'].str.contains(pattern, flags=re.IGNORECASE, na=False)
print(contactos[match])
Use Series.str.contains. Tweak the pattern as appropriate:
import re
pattern = '^' + re.escape(namelookup)
match = contacts['Name'].str.contains(pattern, flags=re.IGNORECASE)
contacts[match]
I have n-files in a folder like
source_dir
abc_2017-07-01.tar
abc_2017-07-02.tar
abc_2017-07-03.tar
pqr_2017-07-02.tar
Lets consider for a single pattern now 'abc'
(but I get this pattern randomly from Database, so need double filtering,one for pattern and one for last day)
And I want to extract file of last day ie '2017-07-02'
Here I can get common files but not exact last_day files
Code
pattern = 'abc'
allfiles=os.listdir(source_dir)
m_files=[f for f in allfiles if str(f).startswith(pattern)]
print m_files
output:
[ 'abc_2017-07-01.tar' , 'abc_2017-07-02.tar' , 'abc_2017-07-03.tar' ]
This gives me all files related to abc pattern, but how can filter out only last day file of that pattern
Expected :
[ 'abc_2017-07-02.tar' ]
Thanks
just a minor tweak in your code can get you the desired result.
import os
from datetime import datetime, timedelta
allfiles=os.listdir(source_dir)
file_date = datetime.now() + timedelta(days=-1)
pattern = 'abc_' +str(file_date.date())
m_files=[f for f in allfiles if str(f).startswith(pattern)]
Hope this helps!
latest = max(m_files, key=lambda x: x[-14:-4])
will find the filename with latest date among filenames in m_files.
use python regex package like :
import re
import os
files = os.listdir(source_dir)
for file in files:
match = re.search('abc_2017-07-(\d{2})\.tar', file)
day = match.group(1)
and then you can work with day in the loop to do what ever you want. Like create that list:
import re
import os
def extract_day(name):
match = re.search('abc_2017-07-(\d{2})\.tar', file)
day = match.group(1)
return day
files = os.listdir(source_dir)
days = [extract_day(file) for file in files]
if the month is also variable you can substitute '07' with '\d\d' or also '\d{2}'. Be carefull if you have files that dont match with the pattern at all, then match.group() will cause an error since match is of type none. Then use :
def extract_day(name):
match = re.search('abc_2017-07-(\d{2})\.tar', file)
try:
day = match.group(1)
except :
day = None
return day
As a part of my learning. After i successfully split with help, in my next step, wanted to know if i can split the names of files when the month name is found in the name of the file that matches with the name of the month given in this list below ---
Months=['January','February','March','April','May','June','July','August','September','October','November','December'].
When my file name is like this
1.Non IVR Entries Transactions December_16_2016_07_49_22 PM.txt
2.Denied_Calls_SMS_Sent_December_14_2016_05_33_41 PM.txt
Please note that the names of files is not same..i.e why i need to split it like
Non IVR Entries Transactions as one part and December_16_2016_07_49_22 PM as another.
import os
import os.path
import csv
path = 'C:\\Users\\akhilpriyatam.k\\Desktop\\tes'
text_files = [os.path.splitext(f)[0] for f in os.listdir(path)]
for v in text_files:
print (v[0:9])
print (v[10:])
os.chdir('C:\\Users\\akhilpriyatam.k\\Desktop\\tes')
with open('file.csv', 'wb') as csvfile:
thedatawriter = csv.writer(csvfile,delimiter=',')
for v in text_files:
s = (v[0:9])
t = (v[10:])
thedatawriter.writerow([s,t])
import re
import calendar
fullname = 'Non IVR Entries Transactions December_16_2016_07_49_22 PM.txt'
months = list(calendar.month_name[1:])
regex = re.compile('|'.join(months))
iter = re.finditer(regex, fullname)
if iter:
idx = [it for it in iter][0].start()
filename, timestamp = fullname[:idx],fullname[idx:-4]
print filename, timestamp
else:
print "Month not found"
Assuming that you want the filename and timestamp as splits and the month occurs only once in the string, I hope the following code solves your problem.
I'm trying to get the temperature from a json source. It's nested and I can't figure out how to get a nested value from a json file or url
So here comes my code so far:
#! /usr/bin/python
import urllib2
import json
f = urllib2.urlopen('http://api.openweathermap.org/data/2.5/find?q=London&units=metric')
json_string = f.read()
parsed_json = json.loads(json_string)
temp = parsed_json['list']
print "Current temperature is: %s" % (temp)
f.close()
Right now I can get all values at once but not just a particular value (temp in my case)
I prefer to get the value clean without u'temp': if possible.
u'temp' is how Python represents unicode objects which is what JSON strings get parsed into in Python. Is this what you're looking for?
print temp[0]['main']['temp']
I don't know the structure of the API you're calling, so this may be making quite a few assumptions, but it will get you the raw temperature.
You are getting several values back. To list them all do:
import urllib2
import json
f = urllib2.urlopen('http://api.openweathermap.org/data/2.5/find?q=London&units=metric')
json_string = f.read()
parsed_json = json.loads(json_string)
for each in parsed_json['list']:
country = each['sys']['country']
temperature = each['main']['temp']
print "Current Temperature in {} is {}".format(country, temperature)
Output
Current Temperature in CA is 11.73
Current Temperature in GB is 11.8
I'm trying to create a data-scraping file for a class, and the data I have to scrape requires that I use while loops to get the right data into separate arrays-- i.e. for states, and SAT averages, etc.
However, once I set up the while loops, my regex that cleared the majority of the html tags from the data broke, and I am getting an error that reads:
Attribute Error: 'NoneType' object has no attribute 'groups'
My Code is:
import re, util
from BeautifulSoup import BeautifulStoneSoup
# create a comma-delineated file
delim = ", "
#base url for sat data
base = "http://www.usatoday.com/news/education/2007-08-28-sat-table_N.htm"
#get webpage object for site
soup = util.mysoupopen(base)
#get column headings
colCols = soup.findAll("td", {"class":"vaTextBold"})
#get data
dataCols = soup.findAll("td", {"class":"vaText"})
#append data to cols
for i in range(len(dataCols)):
colCols.append(dataCols[i])
#open a csv file to write the data to
fob=open("sat.csv", 'a')
#initiate the 5 arrays
states = []
participate = []
math = []
read = []
write = []
#split into 5 lists for each row
for i in range(len(colCols)):
if i%5 == 0:
states.append(colCols[i])
i=1
while i<=250:
participate.append(colCols[i])
i = i+5
i=2
while i<=250:
math.append(colCols[i])
i = i+5
i=3
while i<=250:
read.append(colCols[i])
i = i+5
i=4
while i<=250:
write.append(colCols[i])
i = i+5
#write data to the file
for i in range(len(states)):
states = str(states[i])
participate = str(participate[i])
math = str(math[i])
read = str(read[i])
write = str(write[i])
#regex to remove html from data scraped
#remove <td> tags
line = re.search(">(.*)<", states).groups()[0] + delim + re.search(">(.*)<", participate).groups()[0]+ delim + re.search(">(.*)<", math).groups()[0] + delim + re.search(">(.*)<", read).groups()[0] + delim + re.search(">(.*)<", write).groups()[0]
#append data point to the file
fob.write(line)
Any ideas regarding why this error suddenly appeared? The regex was working fine until I tried to split the data into different lists. I have already tried printing the various strings inside the final "for" loop to see if any of them were "None" for the first i value (0), but they were all the string that they were supposed to be.
Any help would be greatly appreciated!
It looks like the regex search is failing on (one of) the strings, so it returns None instead of a MatchObject.
Try the following instead of the very long #remove <td> tags line:
out_list = []
for item in (states, participate, math, read, write):
try:
out_list.append(re.search(">(.*)<", item).groups()[0])
except AttributeError:
print "Regex match failed on", item
sys.exit()
line = delim.join(out_list)
That way, you can find out where your regex is failing.
Also, I suggest you use .group(1) instead of .groups()[0]. The former is more explicit.