I've been trying to solve this problem for a while now. The code below works for 4 digits (it matches with the answer they give) and it even works for 5 consecutive digits (which was what the problem previously asked for), but it doesn't seem to work for 13 consecutive digits.
Can someone tell me what Im doing wrong?
#include <iostream>
#include <cstdlib>
#include <fstream>
using namespace std;
int Char_To_String(char);
int main()
{
/*****************************************************/
/*********** PROJECT EULER: PROBLEM #8 ***************/
/*****************************************************/
fstream file("grid.txt", ios::in); // open file for reading
if(!file)
{
cout << "FILE NOT OPENED!";
return 0;
}
int row = 20;
int column = 50;
int num;
char arr[row][column];
int intarr[row][column];
for(int i = 0; i<row; i++)
{
for(int j = 0; j<column; j++)
{
file >> arr[i][j];
intarr[i][j] = Char_To_String(arr[i][j]);
}
}
long long prod = 1;
long long int maxProd = 1;
for(int i = 0; i<row; i++)
{
for(int j = 0; j<column; j++)
{
if(j<=column-13)
{
int temp = j;
for(int n = 1; n<=13; n++)
{
prod *= intarr[i][temp];
temp++;
}
if(prod > maxProd)
maxProd = prod;
prod = 1;
}
}
}
cout << "maxProd = " << fixed << maxProd << endl;
Related
I am trying to sort a list of indexes based on a list of string, and I receive bellow error - Segmentation fault. I cannot understand why I receive this error and how to solve it?
#include <iostream>
#include <string.h>
using namespace std;
int main() {
int size = 5;
char* mass[size];
int num[size];
for(int i = 0; i < size; i++) {
mass[i] = new char[20];
num[i] = i;
cin >> mass[i];
}
for(int i = 0; i < size; i++){
for(int j = size; j > i; j--)
if(strcmp(mass[num[j-1]], mass[num[j]]) > 0){
int tmp = num[j-1];
num[j-1] = num[j];
num[j] = tmp;
}
}
for(int i = 0; i < size; i++){
cout << mass[num[i]] << ", ";
}
return 0;
}
In the inner loop you start with j = size and then num[j] is an out-of-bounds array access.
In modern C++ you would solve this like this:
#include <iostream>
#include <array>
#include <algorithm>
int main() {
const int size = 5;
std::array<std::string, size> mass;
std::array<int, size> num;
for (int i = 0; i < size; i++) {
std::cin >> mass[i];
num[i] = i;
}
std::ranges::sort(num, [mass](int a, int b) { return mass[a] <= mass[b];});
for(int i = 0; i < size; i++){
std::cout << mass[num[i]] << ", ";
}
std::cout << std::endl;
return 0;
}
1
3 2
6 5 4
10 9 8 7
I want to print the following pattern. I have tried very hard but couldn't make the code for it. I have tried everything which came up to my mind.
#include<iostream>
using namespace std;
int main() {
int i, j, n;
cin >> n;
int k = 0;
for (i = 1;i <= n; i++) {
for (j = 1; j <= i; j++) {
k++;
printf("%d ", k);
}
printf("\n");
}
}
the other code which i tried is this.
#include<iostream>
using namespace std;
int main() {
int i, j, n;
cin >> n;
int k = 0;
for (i = 1; i <= n; i++) {
for (j = i; j >= 1; j--) {
k++;
printf("%d ",j);
}
printf("\n");
}
}
#include <iostream>
#include <stack>
using namespace std;
int main()
{
int previousRow = 0;
for(int row = 1; row <= 4; row++)
{
int rowTracker = row;
for(int col = 0; col < row; col++)
{
cout<<rowTracker - col + previousRow<<" ";
}
previousRow += row;
cout<<endl;
}
return 0;
}
#include<iostream>
void printPattern(unsigned numlevels)
{
unsigned last_num = 1;
for(unsigned i = 0; i < numlevels; ++i)
{
unsigned next_num = i + last_num;
for(unsigned j = next_num; j >= last_num; --j)
{
std::cout << j << ' ';
}
std::cout << '\n';
last_num = next_num + 1;
}
}
int main()
{
unsigned n;
std::cin >> n;
printPattern(n);
return 0;
}
You may also use a stack to implement this. Here is a working answer:
#include <iostream>
#include <stack>
using namespace std;
int main() {
int i, j, n;
stack<int> st;
cin >> n;
int k = 0;
for(i = 1;i <= n; i++) {
for(j = 1; j <= i; j++) {
k++;
st.push(k);
}
while(!st.empty()){
printf("%d ", st.top());
st.pop();
}
printf("\n");
}
}
Hope it helps!
Before reading the code blow, you should really try to do it yourself. This problem is obviously for practice and to develop the programming muscle. Just getting the answer is not going to help.
The issue with your code is that for each row, the range you want to print is not being determined correctly. You should first find the range and then print the numbers. Ther can be multiple approaches to it. Below is one of them.
for(i=1;i<=n;i++){
int max = i*(i+1)/2;
int min = i*(i-1)/2 + 1;
for(j=max;j>=min;j--){
printf("%d ",j);
}
printf("\n");
}
Here is a simple method
int main(int argc, char* argv[])
{
int n = 4; // suppose print 4 lines
for (int i = 1; i <= n; ++i)
{
int i0 = (i + 1) * i / 2; // first number of line i
for (int j = 0; j < i; j++)
cout << i0 - j << " ";
cout << endl;
}
return 0;
}
thanx everyone for your responses. I was able to do it on my own. Below is what I did. if there is any correction let me know
#include<iostream>
using namespace std;
int main(){
int i,j,n,temp;
cin>>n;
int k=0;
for(i=1;i<=n;i++){
k=k+i,temp=k;
for(j=1;j<=i;j++){
cout<<temp<<+" ";
temp--;
}
cout<<("\n");
}
}
My code works fine when the file Im reading from only contains ints, but when I have floats in the file it doesnt seem to work, for example if I have 1.5 in the file it will only read it as 1 and it wont read any of the numbers after it.
Anyone knows whats causing this? The dynamic array where everything is saved in is a float so Im not sure what to do at this point
#include <iostream>
#include <fstream>
#include <string>
float *allocateArray(std::string fileName, int &arraySize, int &counter)
{
int a = 0;
std::ifstream myReadFile;
myReadFile.open(fileName);
float *arr = new float[arraySize]{0.0};
while (myReadFile >> a)
{
counter++;
if(counter == arraySize)
{
arr[arraySize -1] = a;
}
else
{
float *tempArray = new float[arraySize +1]{0.0};
for(int i = 0; i < arraySize; i++)
{
tempArray[i] = arr[i];
}
delete[] arr;
arraySize++;
arr = new float[arraySize];
for(int x = 0; x < arraySize; x++)
{
arr[x] = tempArray[x];
}
arr[arraySize-1] = a;
}
}
myReadFile.close();
return arr;
}
void output(float *arr, int arraySize,int counter)
{
float sum = 0.0;
for(int x = 0; x < arraySize; x++)
{
sum += arr[x];
}
float average = sum/counter;
std::cout << "Output: ";
for(int i = 0; i < arraySize; i++)
{
if(arr[i] > average)
{
std::cout << arr[i] << " ";
}
}
}
int main()
{
int arraySize = 1;
int counter = 0;
float *arr = allocateArray("input.in", arraySize, counter);
std::cout << "Input: ";
for(int x = 0; x < arraySize; x++)
{
std::cout << arr[x] << " ";
}
output(arr, arraySize, counter);
getchar();
return 0;
}
I would like to point out some random integers using the regular print function, then print again the same integers using pointer notation. When I use pointer notation I run into some trouble. If anyone could send some tips it'd be much appreciated. If i comment out a specific line of code, the program will compile completely, but not with the outputs I'd like.
#include <iostream>
#include <ctime>
#include <stdlib.h> //srand(), rand()
using namespace std;
void printArray(int[], int);
//void printToday(int , );
int main()
{
int i = 0;
const int SZ = 100;
int myArray[SZ] ={0};
srand(time(0));
int myArrayTotal = 0;
int *thelight;
thelight = myArray;
for (int i = 0; i <=100; i++)
{
myArray[i]= i+rand()%1000 ;
}
cout << "Array Notation:\n\n";
printArray(myArray, SZ);
system("pause");
system("cls");
cout << "Pointer Notation: \n\n";
int k = 0;
for (int i = 0; i < 10; ++i)
{
for (int j = 0; j < 10; ++j)
{
cout<< *(thelight + k)<< "\t";
++k; //if I comment out this line the second part of the program will run, but it isn' the values I want.
} cout<< endl;
}
}
void printArray(int ArrayName[], int ArraySize)
{
int k = 0;
for (int i = 0; i < 10; ++i)
{
for(int j = 0; j < 10 ; ++j)
{
cout << ArrayName[k] << "\t";
++k;
}cout << endl;
}
}
Thank you
I'm trying to make a C++ program start creating an array and takes the values from the user , then print every value + star as much the value is .. Example : the user had entered 5 then the output must be like this
5*****
Input
1
2
3
4
5
6
output
1*
2**
3***
4****
and so on
.. help :(
#include <iostream>
using namespace std;
void main()
{
int arr[10];
for (int i = 0; i < 10; i++)
{
cin >> arr[i];
int x = arr[i];
for (int j = 0; x <= arr[i]; j++)
{
cout<< "*";
}
}
}
And another help please can you give me some useful link to practice on programming to be professional
Your code is wrong. Use the following code:
#include <iostream>
using namespace std;
int main() {
int arr[10];
for (int i = 0; i < 10; i++)
{
cin >> arr[i];
int x = arr[i];
for (int j = 0; j < x; j++){ // your condition was wrong
cout<< "*";
}
cout<<endl; // for better formatting
}
return 0;
}
For edited question
int main() {
int arr[10];
for (int i = 0; i < 10; i++)
{
cin >> arr[i];
}
for (int i = 0; i < 10; i++)
{
int x = arr[i];
cout << x;
for (int j = 0; j < x; j++){ // your condition was wrong
cout << "*";
}
cout << endl;
}
return 0;
}
#include <iostream>
using namespace std;
void main()
{
int nbValues = 10;
int arr[nbValues];
// First recover the values
for (int i = 0; i < nbValues; i++)
{
cin >> arr[i];
}
// Then print the output
for (int i = 0; i < nbValues; i++)
{
int x = arr[i];
cout << x;// Print the number
for (int j = 0; j < x; j++)
{
cout<< "*";// Then print the stars
}
cout << endl;// Then new line
}
}