Here is my scenario. I am getting this date from a database:
11-AUG-15 10.38.00.000000000 AM
Is there any way to format this string to look something similar to mm/dd/yy?
So far I have tried the following with no luck:
DateFormat()
CreateODBCDate()
LSParseDateTime()
Every time I use one of the above, I get the following error:
11-AUG-15 10.38.00.000000000 AM is an invalid date or time string.
Any advise will be greatly appreciated.
Thanks!
parseDateTime("11-AUG-15 10.38.00.000000000 AM", "dd-MMM-yy hh.mm.ss.S aa");
Run me: http://trycf.com/gist/aac6d63777ae1b0e9aa3/acf?theme=monokai
Then you are free to use DateFormat() or DateTimeFormat()to format the date object.
Related
I'm writing an application with Flutter. I read the times and dates from a source. The date and time format string sent by the resource is:
(Day, Month, Year, Hour, Minute, Second)
07.04.2021 13:30:00
03.04.2021 11:30:00
04.04.2021 17:30:00
03.04.2021 17:30:00
I want to convert this date and time format to DateTime data type with DateTime.parse() function. Here are some examples of what this function accepts as strings and what I need:
"2012-02-27 13:27:00"
"20120227 13:27:00"
"20120227T132700"
I have to convert the string type data coming to me from the source into one of these formats. But in Dart language I couldn't create the Regular Expression needed to do this and couldn't find it anywhere.
I would be very grateful if anyeone could help me understand what I should do.
If you have to play a lot with the dates, you could use the Jiffy package to ease your development.
DateTime yourDatetime = Jiffy("07.04.2021 13:30:00", "dd.MM.yyyy hh:mm:ss").dateTime;
This is a piece a cake by using regular expressions:
var regExp = RegExp(r'(\d{4}-?\d\d-?\d\d(\s|T)\d\d:?\d\d:?\d\d)');
use DateFormat.parse and DateFormat.format from intl package:
https://api.flutter.dev/flutter/intl/DateFormat/parse.html
https://api.flutter.dev/flutter/intl/DateFormat/format.html
final date = DateFormat("yyyy.MM.dd HH:mm:ss").parse("07.04.2021 13:30:00");
DateFormat("yyyy-MM-dd HH:mm:ss").format(date);
DateTime.parse accepts only a subset of ISO 8601 formats: https://api.flutter.dev/flutter/dart-core/DateTime/parse.html
So I've looked through documentation and previous answers on here, but can't seem to figure this out.
I have a STRING that represents a date. A normal output looks as such:
2018-09-19 17:47:12
If I do this, I get it to return in this format 2018-09-19 17:47:12.000:
SELECT
date_parse(click_time,'%Y-%m-%d %H:%i:%s') click_time
FROM
table.abc
But that's not the output I need. I was just trying to show that I'm close, but clearly missing something. When I change click_time to date_parse(click_time,'%Y-%m-%d'), it sends back INVALID_FUNCTION_ARGUMENT: Invalid format: "2018-09-19 17:47:12" is malformed at " 17:47:12"
So there's clearly something I'm not doing correctly to get it to simply return 2018-09-19.
date_parse converts a string to a timestamp. As per the documentation, date_parse does this:
date_parse(string, format) → timestamp
It parses a string to a timestamp using the supplied format.
So for your use case, you need to do the following:
cast(date_parse(click_time,'%Y-%m-%d %H:%i:%s')) as date )
For your further reference, you can go to the below link for prestodb online documentation https://prestodb.github.io/docs/current/functions/datetime.html
I have a column that I've converted to datetime using pandas so it's now in the format datetime64.
LOCAL_TIME_ON
2014-06-21 15:32:09
2014-06-07 20:17:13
I want to extract the hour to a new column. The only thing I've found that works is below, however, I get a SettingWithCopyWarning. Does anyone have a cleaner way I can do this?
TRIP_INFO_TIME['TIME_HOUR'] = pd.DatetimeIndex(TRIP_INFO_TIME['LOCAL_TIME_ON']).hour.astype(int)
C:\Program Files (x86)\JetBrains\PyCharm Community Edition 2016.1.4\helpers\pydev\pydevconsole.py:1: SettingWithCopyWarning:
A value is trying to be set on a copy of a slice from a DataFrame.
Try using .loc[row_indexer,col_indexer] = value instead
See the caveats in the documentation: http://pandas.pydata.org/pandas-docs/stable/indexing.html#indexing-view-versus-copy
'''
try this:
TRIP_INFO_TIME['TIME_HOUR'] = TRIP_INFO_TIME['LOCAL_TIME_ON'].dt.hour
The following program in SAS EG 9.3 is giving me results as below:
DATA work.header;
calculation='"A00",'
||'"399",'
|| '"NOM",'
|| PUT(DATE(), yymmddn8.)
||","
||put(time(),hhmm8.2);
Run;
Results I'm getting as below:
"A00","399","NOM",20141028,10:03.76
However I would like the time to be "100345" like hhmmss?
Any help would be appreciated.
The format to use is TIME8., which will give you a time of the format HH:MM:SS
e.g.
put(time(),time8.);
Gives:
10:46:40
To remove the colons from this, you'll have to use string functions, I would go for:
compress(put(time(),time8.),'','dk');
Which only keeps the numeric characters, giving:
104640
I have some code that reads a datetime from a sqlite database, the datetime is returned as a string. when I try to convert it to a date using QDateTime::FromString it returns an invalid date. Below is the time as returned from the database and conversion.
Why is this failing to parse?
// -this is the value returned from the DB currentServerTime=2012-01-17 19:20:27.0
QString format("yyyy/MM/dd hh:mm:ss");
QString qCurrentServerTime(currentServerTime);
now = QDateTime::fromString(qCurrentServerTime, format);
No expert in QT, but if QDateTime::fromString() works as one would (reasonably) expect and according to this, you're not using the correct pattern.
You indicate the string read from the sqllite database is like "2012-01-17 19:20:27.0", then your format should be like yyyy-MM-dd HH:mm:ss.z.
In detail:
Your separator should by '-' not '/' (as you show in the example)
The time seems to be in 24 hours format (19 -> 7 p.m.) (so use HH instead of hh)
You have one digit for milliseconds, so add .z.