Return unsigned char as a hex value - c++

I'm aiming to be able to return unsigned char as a hex values, this is so I can pass the value from my client to server side.
How my data is generated before trying to be converted into hex:
unsigned char *TestClass::GetKey()
{
// Generate a key of length 32 bytes
memset(this->szKey, 0, 32);
RAND_bytes(this->szKey, 32);
return this->szKey;
}
This what i've currently got so far:
TestClass myTestClass;
void CJSCallDoc::OnDocumentComplete(LPCTSTR strURL,LPDISPATCH pDisp)
{
unsigned char szKey = hex_print(myTestClass.GetKey());
}
unsigned char CJSCallDoc::hex_print(unsigned char* pv)
{
unsigned char *p = pv;
if (NULL == pv)
{
return NULL;
}
else
{
char storedString[256];
size_t len = strlen((const char*)pv);
size_t i = 0;
for (; i < len; ++i)
{
strcpy_s(storedString, 256, "Test");
strcat_s(storedString, reinterpret_cast<char*>(*p++));
}
return *storedString;
}
}
The problem I'm having is with this line:
strcat_s(storedString, reinterpret_cast<char*>(*p++));
This line causes my application to crash and this is the following error I get:
Unhandled exception at 0x01664467 in TestApp.exe: 0xC0000005: Access
violation reading location 0x000000FE.
and the error takes me to tcscat_s.inl:
---> while ((*p++ = *_SRC++) != 0 && --available > 0)
{
}
However when I try and do the following it works fine:
unsigned char CJSCallDoc::hex_print(unsigned char* pv)
{
unsigned char *p = pv;
if (NULL == pv)
{
return NULL;
}
else
{
char storedString[256];
size_t len = strlen((const char*)pv);
size_t i = 0;
for (; i < len; ++i)
{
strcpy_s(storedString, 256, "Test");
strcat_s(storedString, "WORKS");
}
return *storedString;
}
}
Could someone explain to me, what I'm doing wrong and give me some advice in the right direction?

The problem is that you are casting your data to address, in:
strcat_s(storedString, reinterpret_cast<char*>(*p++));
*p++ is equal to whatever your string contains - first element is p from your example, so you are casting this p - decimal value 112, to char*. strcat_s will try to read string from this location which immediately ends with segfault.

Related

any wrong I done for using Openssl for calculating HMAC_SHA1 hash value?

int computeHMACSHA1Hash(const char * unhashedcstr, char * hashedcstr, const char * key, int returncode)
{
string hashed;
size_t unhashlength = strlen(unhashedcstr);
char * nonconstunhashcstr = new char[unhashlength];
strcpy_s(nonconstunhashcstr, unhashlength + 1, unhashedcstr);
unsigned char* pixels = reinterpret_cast<unsigned char*>(nonconstunhashcstr);
returncode = 0;
HMAC_CTX* context = HMAC_CTX_new();
size_t unhashedstrlength = sizeof(unhashedcstr);
if (context != NULL)
{
if (HMAC_Init_ex(context, key, strlen(key), EVP_sha1(), NULL))
{
if (HMAC_Update(context, pixels, unhashedstrlength))
{
unsigned char hash[EVP_MAX_MD_SIZE];
unsigned int lengthOfHash = 0;
if (HMAC_Final(context, hash, &lengthOfHash))
{
std::stringstream ss;
for (unsigned int i = 0; i < lengthOfHash; ++i)
{
ss << std::hex << std::setw(2) << std::setfill('0') << (int)hash[i];
}
hashed = ss.str();
size_t outputSize = hashed.length() + 1; // +1 for null terminator
strcpy_s(hashedcstr, outputSize, hashed.c_str());
returncode = 0;
}
else
{
returncode = 7;
}
}
else
{
returncode = 6;
}
}
else
{
returncode = 5;
}
HMAC_CTX_free(context);
}
else
{
returncode = 4;
}
return returncode;
}
int main()
{
const char * unhashedcstr = "a=services&l=v1&p=open&k=SD58292829&i=20200918125249803&n=2124&t=1600404769&f={\"invoiceCode\": \"11111\",\"invoiceNo\": \"2222\",\"inTaxAmount\": \"\",\"exTaxAmount\": \"\"}";
char * hashedcstr = new char[100];
int returncode = 0;
const char * key = "SD886A11B0EE428F";
int result = computeHMACSHA1Hash(unhashedcstr, hashedcstr, key, returncode);
return 0;
}
I tried the code above to calculating the HMAC SHA1 hash value for a content, but compared the results on https://www.freeformatter.com/hmac-generator.html#before-output
it looks like I didn't do it right. I'm not sure what I have done wrong though. Any help would be appreciated.
It turned out the result was "d916b4c2d277319bbf18076c158f0cbcf6c3bc57", while on the website https://www.freeformatter.com/hmac-generator.html#before-output, the result was "71482b292f2b2a47b3eca6dad5e7350566d60963". Even when I tried using the string "a=services&l=v1&p=open&k=SD58292829&i=20200918125249803&n=2124&t=1600404769&f={"invoiceCode": "11111","invoiceNo": "2222","inTaxAmount": "","exTaxAmount": ""}" which removed the escape characters, the result was "09be98b6129c149e685ed57a1d19651a602cda0d". It didn't match the correct one.
Is there anything wrong with my code?
Your hash is calculated over the bytes a=se, which are the first four bytes of the whole input string. Thus, you get d916b4c2d277319bbf18076c158f0cbcf6c3bc57 instead of the 09be98b6129c149e685ed57a1d19651a602cda0d that would correspond to the whole string.
The reason is this:
size_t unhashedstrlength = sizeof(unhashedcstr);
Here, sizeof(unhashedcstr) is the size of the unhashedcstr pointer itself (which is of type const char*), not the size of the null-terminated C-style string this unhashedcstr pointer is pointing to. You are compiling a 32-bit program, so the size of a pointer is 4 bytes. Thus, unhashedstrlength is 4.
To get the length of the C-style string, you can do this instead:
size_t unhashedstrlength = strlen(unhashedcstr);
But just as a comment, in modern C++, you should avoid using raw pointers (such as const char*, char*, unsigned char*), C functions (like strlen(), strcpy_s()) and manual memory management (new / delete and new[] / delete[]). You should prefer to use std::string and/or std::vector<unsigned char> instead, wherever possible. When you need to pass a buffer's address to an API function, you can use std::string::data(), std::vector::data(), or more generally, std::data().
By the way, you currently leak memory: you dynamically allocate buffers using new[], but you never deallocate those (using delete[]). So that memory is released by the OS only after the program exits. This is called a memory leak.

longest palindromic substring. Error: AddressSanitizer, heap overflow

#include<string>
#include<cstring>
class Solution {
void shift_left(char* c, const short unsigned int bits) {
const unsigned short int size = sizeof(c);
memmove(c, c+bits, size - bits);
memset(c+size-bits, 0, bits);
}
public:
string longestPalindrome(string s) {
char* output = new char[s.length()];
output[0] = s[0];
string res = "";
char* n = output;
auto e = s.begin() + 1;
while(e != s.end()) {
char letter = *e;
char* c = n;
(*++n) = letter;
if((letter != *c) && (c == &output[0] || letter != (*--c)) ) {
++e;
continue;
}
while((++e) != s.end() && c != &output[0]) {
if((letter = *e) != (*--c)) {
const unsigned short int bits = c - output + 1;
shift_left(output, bits);
n -= bits;
break;
}
(*++n) = letter;
}
string temp(output);
res = temp.length() > res.length()? temp : res;
shift_left(output, 1);
--n;
}
return res;
}
};
input string longestPalindrome("babad");
the program works fine and prints out "bab" as the longest palindrome but there's a heap overflow somewhere. Error like this appears:
Read of size 6 at ...memory address... thread T0
"babad" is size 5 and after going over this for an hour. I don't see the point where the iteration ever exceeds 5
There is 3 pointers here that iterate.
e as the element of string s.
n which is the pointer to the next char of output.
and c which is a copy of n and decrements until it reaches the address of &output[0].
maybe it's something with the memmove or memset since I've never used it before.
I'm completely lost
TL;DR : mixture of char* and std::string are not really good idea if you don't understand how exactly it works.
If you want to length of string you cant do this const unsigned short int size = sizeof(c); (sizeof will return size of pointer (which is commonly 4 on 32-bit machine and 8 on 64-bit machine). You must do this instead: const size_t size = strlen(c);
Address sanitizers is right that you (indirectly) are trying to get an memory which not belongs to you.
How does constructor of string from char* works?
Answer: char* is considered as c-style string, which means that it must be null '\0' terminated.
More details: constructor of string from char* calls strlen-like function which looks like about this:
https://en.cppreference.com/w/cpp/string/byte/strlen
int strlen(char *begin){
int k = 0;
while (*begin != '\0'){
++k;
++begin;
}
return k;
}
If c-style char* string does not contain '\0' it cause accessing memory which doesn't belongs to you.
How to fix?
Answer (two options):
not use mixture of char* and std::string
char* output = new char[s.length()]; replace with char* output = new char[s.length() + 1]; memset(output, 0, s.length() + 1);
Also you must delete all memory which you newed. So add delete[] output; before return res;

Unable to allocate memory via pointer

I wrote this function, in which the intention is to combine the character equivalent of
argument 3, with argument 2. Then allocate memory for argument 1 and return it. Based on debug statements inserted into the function everything seems to be correct, but it appears to be freeing the memory on return. Why is this? or am I missing something else?
I'm not accustomed to programming on a mac and I can't get gdb to work, so I'm kinda flying blind.
Function
bool BraviaIpCtrl::setVolume(char *output, const char *input, unsigned short value)
{
bool success = false;
output = nullptr;
if(value <= 100)
{
int msgLen = 24;
output = new char[msgLen];
memset(output, 0, sizeof(*output));
std::string numbers = std::to_string(value).c_str();
size_t len = numbers.length();
memcpy(output, input, msgLen);
memcpy(output + (msgLen - 1) - len, numbers.c_str(), len);
success = true;
}
return success;
}
Test Function call
char* test = nullptr;
if(bc.setVolume(test, bc.bctl_volume_set, 43) && test != nullptr)
{
std::cout << *test << std::endl;
}
else
{
std::cout << "NOPE!!" << std::endl;
}
As #mailtreyak pointed out, you are passing a pointer to char:
a copy of pointer output (let's say output_copy) is used within the function,
if you make output_copy point to some different data/memory, your output pointer is still pointing to its previous data/memory,
as soon as you exit the function the modification you expect has not happened (but this is correct, because the data/memory output is pointing to have not been modified at all).
Here below you can find another way using PointerToPointer (**):
bool BraviaIpCtrl::setVolume(char** output, const char* input, unsigned short value)
{
bool success = false;
*output = nullptr;
if (value <= 100)
{
int msgLen = 24;
*output = new char[msgLen];
memset(*output, 0, msgLen);
std::string numbers(*output);
size_t len = numbers.length();
memcpy(*output, input, msgLen);
memcpy(*output + (msgLen - 1) - len, numbers.c_str(), len);
success = true;
}
return success;
}
and calling code:
char* test = nullptr;
if (bc.setVolume(&test, bc.bctl_volume_set, 43) && test != nullptr)
{
std::cout << *test << std::endl;
}
else
{
std::cout << "NOPE!!" << std::endl;
}
Please pay much attention to this error in your previous code:
int msgLen = 24;
output = new char[msgLen];
memset(output, 0, sizeof(*output));
should be instead:
int msgLen = 24;
output = new char[msgLen];
memset(output, 0, msgLen);
this because you want to set 24 bytes, not just only 1 byte (1 = sizeof(*output), the size of a pointer to char)
The problem is that you are passing the pointer variable to the function and like any other variable it is passed by value, so the method "setVolume" is making a local copy of pointer test and assigning memory. The calling test method has no way of seeing this change.
Why not change the method implementation to return the address of the array instead.
char * BraviaIpCtrl::setVolume(const char *input, unsigned short value)
{
char* output = NULL;
if(value <= 100)
{
int msgLen = 24;
output = new char[msgLen];
memset(output, 0, sizeof(*output));
std::string numbers = std::to_string(value).c_str();
size_t len = numbers.length();
memcpy(output, input, msgLen);
memcpy(output + (msgLen - 1) - len, numbers.c_str(), len);
}
return output;
}

Signature Scanner Value not correct

I'm learning about signature scanning and having some problems. My code is sort of ugly but it should work,,, can't understand how to fix my problem. My main function memory.findSignature() in my main returns a garbage value and therefor my when i read and give RemoteHealth a value it is also garbage.
Main:
LPCSTR signature = "\x48\x4A\x85\x2A\x44\x49";
LPCSTR mask = "xxxxxx";
uintptr_t healthAddr = memory.findSignature(CS.client.dwBase, CS.client.dwSize, signature, mask);
int RemoteHealth = memory.readAddress<int>(healthAddr);
std::cout << "value:" << std::hex << RemoteHealth << " address:" << healthAddr <<std::endl;
memory.h:
bool memoryCompare(const byte* data, const byte* mask, const char* szMask) {
for (; *szMask; ++szMask, ++data, ++mask) {
if (*szMask == 'x' && *data != *mask) {
return false;
}
}
return true;
}
uintptr_t findSignature(uintptr_t sigStart, uintptr_t sigSize, const char* signature, const char* mask) {
byte* data = new byte[sigSize];
SIZE_T bytesRead;
ReadProcessMemory(procHandle, (LPVOID)sigStart, data, sigSize, &bytesRead);
for (uintptr_t i = 0; i < sigSize; i++) {
if (this->memoryCompare((const byte*)(data + i), (const byte*)signature, mask)) {
delete[] data;
return sigStart + i;
}
}
delete[] data;
return NULL;
}
I don't know what would explain this but i know the issue is in one of my two memory functions...
http://prntscr.com/mqpx9h
http://prntscr.com/mqpz85
http://prntscr.com/mqpzqm
the return in memoryCompare are flipped, but the values still are garbage in read.... the address just reads as first in module :/

Own strncpy() C++

I am trying to implement my own version of strncpy(), i found a source code from this link.
But I encountered a Unhandled exception at 0x00411ad5 in exercise 2.exe: 0xC0000005: Access violation writing location 0x00417800. everytime the code reaches this code while((x++ < n) && (*dest++ = *source++));
Here is the complete code:
char *strncpy(char * destination, const char * source, size_t n){
char *dest;
dest = destination;
size_t x=0;
while((x++ < n) && (*dest++ = *source++)); //this is where unhandled exception occurs
while(x++ < n){
*dest++ = 0;
}
return dest;
}
int main(){
char *sample = "blue";
char * sample2 = "red";
cout << strncpy(sample, sample2, 5);
getch();
return 0;
}
Please tell me why this occurs and how should I fix it? Thanks!
Your destination is "blue" which is a string literal, that is a constant. As such it is located in a read-only part of memory (and pointed at by local sample variable), thus error when writing.
Try this:
int main(){
char sample[] = "blue";
char * sample2 = "red";
cout << strncpy(sample, sample2, 5);
getch();
return 0;
}
which makes sample an array in local, writeable memory.
You cannot write to a string constant (sample); write to a char array instead:
int main(){
char *sample = "blue";
char buffer[5];
cout << strncpy(buffer, sample, sizeof(buffer));
getch();
return 0;
}
First, it was already explained to you that you can't overwrite a string that is defined like that.
Second, you cant use cout << strncpy if that function returns pointer to the end of the copied string.
There are two main problems with your program
The first one is that function strncpy has to return destination instead of dest
char *strncpy(char * destination, const char * source, size_t n){
char *dest;
dest = destination;
size_t x=0;
while((x++ < n) && (*dest++ = *source++)); //this is where unhandled exception occurs
while(x++ < n){
*dest++ = 0;
}
// return dest;
return destination;
}
The second one is that string literals are immutable. Any attempt to modify a string literal results in undefined behaviour.
Thus main function should be rewritten the following way
int main(){
char sample[] = "blue";
char * sample2 = "red";
cout << strncpy(sample, sample2, sizeof( sample ) );
getch();
return 0;
}
Also it is a bad style of programming to use variable with name x as a count. It is better to use for example i.
I would write the function simpler
char * strncpy( char *destination, const char *source, size_t n )
{
char *dest = destination;
while ( n-- && ( *dest++ = *source++ ) );
while ( n-- ) *dest++ = '\0';
return destination;
}