I defined a user-command in gdb, but I can't find it the next time.
How to make it still? I did't find the answer in here.
for example:
(gdb)define mycommand
>printf "--------backtrace----"
>where
>end
You should define the command in your ~/.gdbinit file, details of which can be found here. This configuration file is processed each time gdb is started, recreating your custom command.
Related
I am running a cpp code in xcode along with opencv. Inside the cpp code, there is a command line:
system("svm-scale -r allrange test_ind>> test_ind_scaled")
When i run the code, it's give a error like svm-scale: command not found
But when i run this command line (svm-scale -r allrange test_ind>> test_ind_scaled) from terminal, it's giving no error.
Any suggestion how to run this command line from inside the cpp code ?
Any suggestions would be greatly appreciated.
Try running svm-scale with its full path. Reading other xcode-related questions hinted that xcode might not use your PATH variable, so system doesn't know where to look for the specific command.
I have more than 10 symbol files to add at runtime in gdb
add-symbol-file build/i386//fat 0x80a211dc
add-symbol-file build/i386/fs/cd9660/cd9660 0x00000ac0
add-symbol-file build/i386/fs/ntfs/ntfs 0x00001518
Adding all files one by one in gdb is very time consuming job & takes more time. Does gdb have only one command to add all files at proper place?
I used gdb command
set debug-file-directory
but it does not work, so plz help
There's no built-in command to do what you want.
However, you can automate gdb using either the built-in command language (the "CLI") or using Python. I don't know how you find those addresses, but the idea would be to automate that with a script.
For the CLI this automation could perhaps be done via the shell command, writing a sequence of add-symbol-file commands to a file, which you'd then source.
For Python you can simply write a program that eventually uses gdb.execute to evaluate the add-symbol-file commands you need.
I have built a bash script to start up some processes in my system. It simply calls the process and associated config file. Same as I would call from the command line.
#!/bin/bash
# Start specified process in a new session
setsid $1 &>/dev/null &
So to start up someprocess, I would call from the command line:
root#supercomputer:~# start someprocess
This works like a charm. Every process, every time. But when I make a system call from a different running C++ process, someprocess never starts up.
system( "start someprocess" )
This approach for 90% of my processes, except for one. The only difference in the working and not working processes is that the non-working one uses proprietary libraries underneath. I recently added the setsid option to the bash script in hopes that starting a new session would help, but it made no difference. I've also tried popen, and execv. No change.
So my question is what is the difference between calling something with system() and just making that same call from the command line?
All processes are written in C++ on Linux.
.bashrc is only invoked if bash is run as interactive, non-login shell. If it's invoked as non-interactive shell, as when using system() on a script with a bash shebang, it only reads the configuration file pointed to by $BASH_ENV.
That means you have the following options:
add -l to the shebang - causes the shell to read ~/.profile at startup
set $BASH_ENV to the script you want sourced before calling system()
add -i to the shebang - invokes bash as interactive shell and causes it to read ~/.bashrc, but will also effect how bash handles input/output.
I'd recommend the first option.
You can find a detailed explanation of how bash reads it's startup files here. I'm not sure this will solve your problem completely, but it may at leas shed some light on that part of the issue.
Check the environment variables that are used in the system() call. For example, call system to print out some of the variables, and see if they match what you see from the command line.
Likely they are not being sourced correctly.
I'm trying to debug a CUDA program, but when I'm launching gdb like so:
$ gdb -i=mi <program name>
$ r <program arguments>
I'm getting:
/home/wvxvw/Projects/cuda/exercise-1-udacity/cs344/HW2/hw:
error while loading shared libraries: libcudart.so.5.0:
cannot open shared object file: No such file or directory
Process gdb-inferior killed
(formatted for readability)
(I'm running gdb using M-xgdb) If that matters, then CUDA libraries are in the .bashrc
export PATH="/usr/local/cuda/bin:$PATH"
export LD_LIBRARY_PATH="$LD_LIBRARY_PATH:/usr/local/cuda/lib64"
error while loading shared libraries: libcudart.so.5.0
This error has nothing to do with GDB: your executable, when run from inside GDB, can't find the library it needs.
export LD_LIBRARY_PATH="$LD_LIBRARY_PATH:/usr/local/cuda/lib64"
GDB runs your program in a new $SHELL, so that should have worked. I wonder if there is some interaction with emacs.
In any case, this:
(gdb) set env LD_LIBRARY_PATH /usr/local/cuda/lib64
(gdb) run
should fix this problem.
Update:
as I've mentioned it before, ld path is set properly
No, it isn't. If it was, you wouldn't have the problem.
Now, I don't know why it isn't set properly. If you really want to find out, start by running GDB outside emacs (to exclude possible emacs interactions).
If the problem is still present, gdb show env, shell env, adding echo "Here" to your ~/.basrc, etc. should help you find where things are not working as you expect them.
I've had this problem as well. One way to look at it is that even if the LD_LIBRARY_PATH variable is correct when you enter show env into gdb, it may not be correct when you actually execute the program because gdb executes $SHELL -c <program> to run the program. Try this as a test, run $SHELL from the command line and then echo $LD_LIBRARY_PATH. Is it correct? If not, then you probably need to add it to your rc (.tcshrc in my case).
I had a similar problem when trying to run gdb on windows 7. I use MobaXterm to access a Linux toolbox. I installed gdb separately from http://www.gnu.org/software/gdb/ . I got it to work by making sure gdb could find the correct .dll files as mentioned by Employed Russian. If you have MobaXterm installed the .dll files should appear in your home directory in MobaXterm/slash/bin.
gdb however did not recognize the LD_LIBRARY_PATH variable. For me, it worked when I used the PATH variable instead:
(gdb) set env PATH C:\Users\Joshua\Documents\MobaXterm\slash\bin
(gdb) run
I would think using PATH instead of LD_LIBRARY_PATH might work for you provided you put the correct path to your library.
gdb is looking for a library, so why are you concerned with the include path? You may want to try to set the gdb option "solib-search-path" to point to the location of the libcudart.so.5.0 library.
I am a beginner and got some trouble in RE.
I have an ELF 'bomb' and an unknown file 'model.abc'.
The correct way to run bomb is:
bomb model.abc
Now I want to use gdb to see the value of some addresses when running it. Can any one help me?
First start gdb from a shell prompt:
$ gdb bomb
Then run your program from the (gdb) prompt with the command line you want:
(gdb) run model.abc
You need to launch your program this way because gdb doesn't allow you to specify command line arguments for your program on the gdb command line.
Another, more convenient way of debugging a program with arguments:
gdb --args program <arguments>
If you don't have symbols, you'll have to start from the entry point. To figure our where it is, use:
(gdb) info file
Symbols from "/.../tesprog".
Local exec file:
`/.../tesprog', file type elf32-i386.
Entry point: 0x804abc0
Then you can set breakpoint on it before running:
break *0x804abc0
Note that the entry will be most often the library startup code (ctr0.s), it might take a while to get to the actual code written by the programmer.