Wrong answer in UVa online judge [closed] - c++

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I was trying to solve a really simple problem on UVa online judge. The problem code is: 10071. You can find the problem here: https://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=94
My code looks like this:
#include<iostream>
using namespace std;
int main(){
int v,t,a,d;
cin >> v >> t;
t = t*2;
d = (v)*t;
cout << d << endl;
}
But it says wrong answer. What went wrong and how to solve it?

You have not read the complete question.
Correct solution is as follows:
#include <stdio.h>
int main()
{
int a,b,c;
while(scanf("%d%d",&a,&b)==2)
{
printf("%d\n",(a*b)*2);
}
return 0;
}
As you may notice above, there can be multiple test cases. You have to account for it. So I have a while loop for it.

Related

program get compile successfully but during run time it takes infinite no of values during first while loop [closed]

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The programe takes n number of test cases and each test case takes takes 4 values a,b,c,d from user and these values are used to calculate the value of max.
#include<bits/stdc++.h>
using namespace std;
void numofjok(int ar[3], int arr[4]);
int main(){
cout << "Enter the no of test cases:";
int n=0,max=0,al=0,bo=0;
int a,b,c,d;\\user input
int arr[4] ={a,b,c,d}, ar[3]= {al,bo,max};
cin>>n;\\test_cases
while(n--){
cin>>a>>b>>c>>d;\\during runtime it takes infinte no of values.
numofjok(ar,arr);
}
return 0;
}
}
I have tried the taking input using for loop but the problem presist.

how do I print a vector of vector of bools [closed]

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Here's what I tried
#include <iostream>
#include <vector>
using std::vector;
using std::cin;
using std::cout;
using std::endl;
const int n{5},s{9},arr[]{2,3,7,8,11};
vector<vector<bool>>dp;
void print(){
for(auto &x :dp){
for(bool y:x){
cout<<y<<' ';
}
cout<<endl;
}
}
int main(){
print();
}
The program crashes with nothing being printed.
What is the correct way to do it. Also what does auto stand for in this case.
What is the correct way to do it.
Your example program is a correct way.
The program crashes
It shouldn't. Either you are mistaken, or there is something wrong with your system.
... with nothing being printed.
This makes sense. You are printing a vector of vector of bool that is empty. There is nothing to print.

Need help whit c++ pointers [closed]

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I'm studing about c++ semantics and syntax, I really don't know what is the problem with this code, it compile but stop working. I will apreciate your help, thanks.
#include <iostream>
#include <string.h>
using namespace std;
char* func(char* M)
{
int initval = 2;
char *x= new char[10];
x="idea";
strcpy(x, M+initval);
return x;
}
int main()
{
char* x;
char s[10]= "alguna";
x= func(s);
cout << *x << endl;
return 0;
}
Before this is closed, the x="idea"; is where your problem lies. You throw away your buffer and point it to a constant value, then try to assign to it, which almost always is illegal (should always be illegal, but apparently it is compiling for you...).

Char pointer in c++ [closed]

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I am running the below code. I am getting run time error.
#include <iostream>
using namespace std;
int main() {
char *p="hello";
//p="Hi";
*p='G';
cout<<*p;
return 0;
}
if this is giving error then what is use of const char *p="hello";In this case my string should be constant not in char *p="hello"
char *p="hello";
*p='G';
You make p point to a constant, "hello". But then you try to modify what p points to. By definition, constants cannot be modified.

Tic-Tac-Toe Game c++ [closed]

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XO Game C++
This code returns only "It’s a Tie !!" .. What's the error in my code?
#include <stdio.h>
int main()
{
char a1,b1,c1,a2,b2,c2,a3,b3,c3;
scanf("%c%c%c\n%c%c%c\n%c%c%c",&a1,&b1,&c1,&a2,&b2,&c2,&a3,&b3,&c3);
if(a1==b1==c1=='X'||a2==b2==c2=='X'||a3==b3==c3=='X'||a1==a2==a3=='X'
||b1==b2==b3=='X'||c1==c2==c3=='X'||a1==b2==c3=='X'||c1==b2==a3=='X'){
printf("X wins\n");
}
if(a1==b1==c1=='O'||a2==b2==c2=='O'||a3==b3==c3=='O'||a1==a2==a3=='O'
||b1==b2==b3=='O'||c1==c2==c3=='O'||a1==b2==c3=='O'||c1==b2==a3=='O'){
printf("O wins\n");
}
if(a1!=b1!=c1||a2!=b2!=c2||a3!=b3!=c3||a1!=a2!=a3
||b1!=b2!=b3||c1!=c2!=c3||a1!=b2!=c3||c1!=b2!=a3){
printf("It’s a Tie !!\n");
}
}
a1==b1==c1=='X'
This doesn't do what you think it does. It compares a1 to the boolean result of b1==c1=='X', probably giving false.
To check whether they are all equal, you need
a1=='X' && b1=='X' && c1=='X'