I've got strings like this in a text file:
10.Divide using the divider at 12C. and pressure at 3.0.
11.Form into cylinders and put on boards, don't handle too much.
This Regex (\d+\.)[A-Z] correctly finds a numeric value, followed by a period, followed by a capital letter.
I want to insert a space between the period and the capital letter. How do I do this?
Actually your regex is wrong:
(\d+.)[A-Z] matches 1-or-more occurennce of digits, follow by ANY CHARACTER. . in regex means any character. The more correct one should be \d+\.[A-Z] (Omitted the group too as it is not required for matching. Note that the . is escaped).
In order to insert space, apart from the solution provided by another answer by using 2 groups: i.e. Find (\d+\.)([A-Z]) (note the dot fixed) and replace with \1 \2, you may also consider using lookaround feature:
Find (?<=\d\.)(?=[A-Z]) and Replace with (a single space). This regex find a spot that is preceded with a digit and then a dot, and is followed by a capital letter. Then we are replacing that spot with a space. (Note that lookahead and lookbehind group is not included in the "matched" result)
You're mostly there. When you wrap a regex subexpression in parentheses, you can refer to it in the "Replace" field of a find and replace operation. So...
Find what: (\d+.)([A-Z])
Replace with: \1 \2
(See similar questions like this one.)
Related
Im using Visual Studio 2017 and in a long long text file Im searching for a particular function but unable to find
here's what the regex Im using
c\.CreateMap\<(\w)+\,\s+Address\>
and I want to in these
c.CreateMap<ClientAddress, Address>()
c.CreateMap<Responses.SiteAddress, Data.Address>()
and so on.
As soon as I add "Address" in the regex it stops matching any.
what am I doing wrong?
You can try this
c\.CreateMap\<\w+\.?\w+?\,\s*\w*?\.?Address\>
Explanation
c\.CreateMap\< - Matches c\.CreateMap\<.
\w+ - Matches any word character one or more time.
\.? - Matches '.' zero or one time.
\, - Matches ','.
\s* - Matches space zero or more time.
\w - Matches word character zero or more time.
\.? - Matches '.' zero or one time.
Address\> - Matches Address\>.
Demo
P.S- In case you also want to match something like this.
c.CreateMap<Responses.SiteAddress.abc, Data.Address.xyz>()
You can use this.
c\.CreateMap\<(\w+\.?\w+?)*\,\s*(?:\w*?\.?)*Address(\.\w*)?\>
Demo
Here is general regex I can suggest:
c\.CreateMap\<[\w.]+,\s+(?:[\w.]+\.)?Address\>\s*\(\s*\)
This will match any term with dots or word characters in the first position in the diamond. In the second, position, it will match Address, or some parent class names, followed by a dot separator, followed by Address.
Demo
Note that I also include the empty function call parentheses in the regex. As well, I allow for flexibility in the whitespace may appear after the diamond, or between the parentheses.
In your second example, you have extra dot which is not handled. Your regex needs little modification. Also, you don't need to escape < or > or , Use this,
c\.CreateMap<([\w.])+,\s+[\w.]*Address>
Demo
To match any of the functions on your question, you can use:
c\.CreateMap[^)]+\)
Regex Demo
Regex Explanation:
I'm trying to find words that are in uppercase in a given piece of text. The words must be one after the other to be considered and they must be at least 4 of them.
I have a "almost" working code but it captures much more: [A-Z]*(?: +[A-Z]*){4,}. The capture group also includes spaces at the start or the end of those words (like a boundary).
I have a playground if you want to test it out: https://regex101.com/r/BmXHFP/2
Is there a way to make the regex in example capture only the words in the first sentence? The language I'm using is Go and it has no look-behind/ahead.
In your regex, you just need to change the second * for a +:
[A-Z]*(?: +[A-Z]+){4,}
Explanation
While using (?: +[A-Z]*), you are matchin "a space followed by 0+ letters". So you are matching spaces. When replacing the * by a +, you matches spaces if there are uppercase after.
Demo on regex101
Replace the *s by +s, and your regex only matches the words in the first sentence.
.* also matches the empty string. Looking at you regex and ignoring both [A-Z]*, all that remains is a sequence of spaces. Using + makes sure that there is at least one uppercase char between every now and then.
You had to mark at least 1 upper case as [A-Z]*(?: +[A-Z]+){4,} see updated regex.
A better Regex will allow non spaces as [A-Z]*(?: *[A-Z]+){4,}.see better regex
* After will indicate to allow at least upper case even without spaces.
I am looking to clean up a regular expression which matches 2 or more characters at a time in a sequence. I have made one which works, but I was looking for something shorter, if possible.
Currently, it looks like this for every character that I want to search for:
([A]{2,}|[B]{2,}|[C]{2,}|[D]{2,}|[E]{2,}|...)*
Example input:
AABBBBBBCCCCAAAAAADD
See this question, which I think was asking the same thing you are asking. You want to write a regex that will match 2 or more of the same character. Let's say the characters you are looking for are just capital letters, [A-Z]. You can do this by matching one character in that set and grouping it by putting it in parentheses, then matching that group using the reference \1 and saying you want two or more of that "group" (which is really just the one character that it matched).
([A-Z])\1{1,}
The reason it's {1,} and not {2,} is that the first character was already matched by the set [A-Z].
Not sure I understand your needs but, how about:
[A-E]{2,}
This is the same as yours but shorter.
But if you want multiple occurrences of each letter:
(?:([A-Z])\1+)+
where ([A-Z]) matches one capital letter and store it in group 1
\1 is a backreference that repeats group 1
+ assume that are one or more repetition
Finally it matches strings like the one you've given: AABBBBBBCCCCAAAAAADD
To be sure there're no other characters in the string, you have to anchor the regex:
^(?:([A-Z])\1+)+$
And, if you wnat to match case insensitive:
^(?i)(?:([A-Z])\1+)+$
I use this regex to convert words in TitleCase and confirm each substitution:
:s/\%V\<\([A-Za-z0-9àäâæèéëêìòöôœùüûçÀÄÂÆßÈÉËÊÌÖÔŒÙÜÛ]\)\([A-Za-z0-9àäâæèéëêìòöôœùüûçÀÄÂÆßÈÉËÊÌÖÔŒÙÜÛ]*\)\>/\u\1\L\2/gc
However this matches also the words who are already in Titlecase.
Does anyone know how to change the above regex in order to jump over words who are already in TitleCase?
:s/\%V\<\([a-z0-9àäâæèéëêìòöôœùüûç]\)\([A-Za-z0-9àäâæèéëêìòöôœùüûçÀÄÂÆßÈÉËÊÌÖÔŒÙÜÛ]*\)\>/\u\1\L\2/gc
seems to do the trick, here.
Because you have explicitely included uppercase characters in the range you use in the first letter capture group, your pattern is going to match both foo and Foo. Removing the uppercase characters from that range seems to resolve your immediate problem.
To match only non-titlecase words, you want to match those that start either (a) with a lowercase letter or (b) with two uppercase letters. The following will do it (add accented letters and digits to taste):
\b([A-Z])([A-Z][A-Za-z]*)|\b([a-z])([a-zA-Z]+)
But some words match at groups \1 and \2, others at \3 and \4. I don't use vim so I can't say if it'll let you substitute with this kind of pattern. (E.g., \u\1\3\L\2\4; only two of the four will ever be non-empty)
I have difficulty using Regular Expression (Grep) in TextWrangler to find occurrences of lowercase letter followed by uppercase. For example:
This announcement meansStudents are welcome.
In fact, I want to split the occurrence by adding a colon so that it becomes means: Students
I have tried:
[a-z][A-Z]
But this expression does not work in TextWrangler.
*EDIT: here are the exact contexts in which the occurrences appear (I mean only with these font colors).*
<font color =#48B700> - Stột jlăm wẻ baOne hundred and three<br></font>
<font color =#C0C0C0> »» Qzống pguộc lyời ba yghìm fảy dyổiTo live a life full of vicissitudes, to live a life marked by ups and downs<br></font>
"baOne" and "dyổiTo" must be "ba: One" and "dyổi: To"
Could anyone help? Many thanks.
I do believe (don't have TextWrangler at hand though) that you need to search for ([a-z])([A-Z]) and replace it with: \1: \2
Hope this helps.
Replace ([a-z])([A-Z]) with \1:\2 - I don't have TextWrangler, but it works on Notepad++
The parenthesis are for capturing the data, which is referred to using \1 syntax in the replacement string
This question is ages old, but I stumbled upon it, so someone else might, as well. The OP's comment to Igor's response clarified how the task was meant to be described (& could have be added to the description).
To match only those font-specific lines of the HTML replace
(?<=<font color =#(?:48B700|C0C0C0)>)(.*?[a-z])([A-Z])
with \1: \2
Explanation:
(?<=[fixed-length regex]) is a positive lookbehind and means "if my match has this just before it"
(?:48B700|C0C0C0) is an unnamed group to match only 2 colours. Since they are of the same length, they work in a lookbehind (that needs to be of fixed length)
(.*?[a-z])([A-Z]) will match everything after the > of those begin font tags up to your Capital letters.
The \1: \2 replacement is the same as in Igor's response, only that \1 will match the entire first string that needs separating.
Addition:
Your input strings contain special characters and the part you want to split may very well end in one. In this case they won't be caught by [a-z] alone. You will need to add a character ranger that captures all the letters you care about, something like
(?<=<font color =#(?:48B700|C0C0C0)>)(.*?[a-zḁ-ῼ])([A-Z])
That is the correct pattern for identifying lower case and upper case letters, however, you will need to check matching to be Case Sensitive within the Find/Replace dialogue.