Setting Django admin default action - django

I would like to change the default selected action named "---------" (BLANK_CHOICE_DASH) to another specific action. Is there a better way to implement this than adding some javascript code that would override the action in load time?

1.Override the get_action_choices() method in your ModelAdmin, clear the default blank choice and reorder the list。
class YourModelAdmin(ModelAdmin):
def get_action_choices(self, request):
choices = super(YourModelAdmin, self).get_action_choices(request)
# choices is a list, just change it.
# the first is the BLANK_CHOICE_DASH
choices.pop(0)
# do something to change the list order
# the first one in list will be default option
choices.reverse()
return choices
2.Specific action.Override ModelAdmin.changelist_view, use extra_context to update action_form
ChoiceField.initial used to set the default selected choice.
so if your action name is "print_it", you can do this.
class YourModelAdmin(ModelAdmin):
def changelist_view(self,request, **kwargs):
choices = self.get_action_choices(request)
choices.pop(0) # clear default_choices
action_form = self.action_form(auto_id=None)
action_form.fields['action'].choices = choices
action_form.fields['action'].initial = 'print_it'
extra_context = {'action_form': action_form}
return super(DocumentAdmin, self).changelist_view(request, extra_context)

I think you can override the get_action_choices() method in the ModelAdmin.
class MyModelAdmin(admin.ModelAdmin):
def get_action_choices(self, request, default_choices=BLANK_CHOICE_DASH):
"""
Return a list of choices for use in a form object. Each choice is a
tuple (name, description).
"""
choices = [] + default_choices
for func, name, description in six.itervalues(self.get_actions(request)):
choice = (name, description % model_format_dict(self.opts))
choices.append(choice)
return choices

in your admin.py file
class MyModelAdmin(admin.ModelAdmin):
def get_action_choices(self, request, **kwargs):
choices = super(MyModelAdmin, self).get_action_choices(request)
# choices is a list, just change it.
# the first is the BLANK_CHOICE_DASH
choices.pop(0)
# do something to change the list order
# the first one in list will be default option
choices.reverse()
return choices
and in your class
class TestCaseAdmin(MyModelAdmin):

Related

How to remove "---------" in django admin action

I have no idea how to remove "--------" default action value in django admin.
or replace "------" with any other string ("Select Option").
Thanks..
You could try overriding the ModelAdmin.get_action_choices method. However, this is an undocumented, internal method, so I wouldn't recommend changing it unless it's absolutely essential that you remove/replace the dashes.
remove default action
class YourModelAdmin(ModelAdmin):
def get_action_choices(self, request):
choices = super(DocumentAdmin, self).get_action_choices(request)
# choices is a list, just change it.
# the first is the BLANK_CHOICE_DASH
choices.pop(0)
return choices
replace with other string
class YourModelAdmin(ModelAdmin):
def get_action_choices(self, request):
default_choices = [("", "-----other string----")]
return super(DocumentAdmin, self).get_action_choices(request, default_choices)
set default action for your action, you can see my answer here https://stackoverflow.com/a/41276533/1265727
With the help of #Alasdair my issue is resolved.
I use this code in model.py and its change my default option value to "Select Options"
from django.db.models.fields import BLANK_CHOICE_DASH
BLANK_CHOICE_DASH = [("", "---------")]
def get_action_choices(self, request, default_choices=BLANK_CHOICE_DASH):
"""
Return a list of choices for use in a form object. Each choice is a
tuple (name, description).
"""
choices = [] + default_choices
for func, name, description in six.itervalues(self.get_actions(request)):
choice = (name, description % model_format_dict(self.opts))
choices.append(choice)
return choices
After some time later, i also find a solution of this problem..
You can also override empty_value_display for all admin pages with AdminSite.empty_value_display, or for specific fields like this:
from django.contrib import admin
class AuthorAdmin(admin.ModelAdmin):
fields = ('name', 'title', 'view_birth_date')
def view_birth_date(self, obj):
return obj.birth_date
view_birth_date.short_name = 'birth_date'
view_birth_date.empty_value_display = '???'

ModelChoiceField in forms.Form won't validate if queryset is overridden

I have a django ModelChoiceField that won't validate if I override the queryset.
class PersonalNote(forms.Form):
tile = ModelChoiceField(queryset=Tile.objects.none())
note = forms.CharField()
form = PersonalNote()
form.fields['tile'].queryset = Tile.objects.filter(section__xxx=yyy)
The form.is_valid() error is: "Select a valid choice. That choice is not one of the available choices".
If Tile.objects.none() is replaced with Tile.objects.all() it validates, but loads far too much data from the database. I've also tried:
class PersonalNote(forms.Form):
tile = ModelChoiceField(queryset=Tile.objects.none())
note = forms.CharField()
def __init__(self, *args, **kwargs):
yyy = kwargs.pop('yyy', None)
super(PersonalNote, self).__init__(*args, **kwargs)
if yyy:
self.fields['tile'].queryset = Tile.objects.filter(section__xxx=yyy)
What might be wrong here? Note the real application also overrides the label, but that does not seem to be a factor here:
class ModelChoiceField2(forms.ModelChoiceField):
def label_from_instance(self, obj):
assert isinstance(obj,Tile)
return obj.child_title()
After 2 hours I found the solution. Because you specified a queryset of none in the class definition, when you instantiate that PersonalNote(request.POST) to be validated it is referenceing a null query set
class PersonalNote(forms.Form):
tile = ModelChoiceField(queryset=Tile.objects.none())
note = forms.CharField()
To fix this, when you create your form based on a POST request be sure to overwrite your queryset AGAIN before you check is_valid()
def some_view_def(request):
form = PersonalNote(request.POST)
**form.fields['tile'].queryset = Tile.objects.filter(section__xxx=yyy)**
if form.is_valid():
#Do whatever it is
When you pass an empty queryset to ModelChoiceField you're saying that nothing will be valid for that field. Perhaps you could filter the queryset so there aren't too many options.
I also had this problem. The idea is to dynamically change the queryset of a ModelChoiceField based on a condition (in my case it was a filter made by another ModelChoiceField).
So, having the next model as example:
class FilterModel(models.Model):
name = models.CharField()
class FooModel(models.Model):
filter_field = models.ForeignKey(FilterModel)
name = models.CharField()
class MyModel(models.Model):
foo_field = models.ForeignKey(FooModel)
As you can see, MyModel has a foreign key with FooModel, but not with FilterModel. So, in order to filter the FooModel options, I added a new ModelChoiceField on my form:
class MyForm(forms.ModelForm):
class Meta:
model = MyModel
def __init__(self, *args, **kwargs):
# your code here
self.fields['my_filter_field'] = forms.ModelChoiceField(FilterModel, initial=my_filter_field_selected)
self.fields['my_filter_field'].queryset = FilterModel.objects.all()
Then, on your Front-End you can use Ajax to load the options of foo_field, based on the selected value of my_filter_field. At this point everyting should be working. But, when the form is loaded, it will bring all the posible options from FooModel. To avoid this, you need to dynamically change the queryset of foo_field.
On my form view, I passed a new argument to MyForm:
id_filter_field = request.POST.get('my_filter_field', None)
form = MyForm(data=request.POST, id_filter_field=id_filter_field)
Now, you can use that argument on MyForm to change the queryset:
class MyForm(forms.ModelForm):
# your code here
def __init__(self, *args, **kwargs):
self.id_filter_field = kwargs.pop('id_filter_field', None)
# your code here
if self.id_filter_field:
self.fields['foo_field'].queryset = FooModel.objects.filter(filter_field_id=self.id_filter_field)
else:
self.fields['foo_field'].queryset = FooModel.objects.none()

How to override the queryset giving the filters in list_filter?

Given the following models
class AnotherModel(models.Model):
n = models.IntegerField()
class MyModel(models.Model):
somefield = models.ForeignKey(AnotherModel)
and admin
class MyModelAdmin(admin.ModelAdmin):
list_filter = ('somefield',)
how can I filter the instances of AnotherModel to show only those with a given n value in my admin filter?
I need something like:
Filter
By somefield
all
[list of AnotherModel instances with given n]
See ModelAdmin.queryset and ModelAdmin.formfield_for_foreignkey. From the docs:
The queryset method on a ModelAdmin returns a QuerySet of all model instances that can be edited by the admin site. One use case for overriding this method is to show objects owned by the logged-in user:
class MyModelAdmin(admin.ModelAdmin):
def queryset(self, request):
qs = super(MyModelAdmin, self).queryset(request)
if request.user.is_superuser:
return qs
return qs.filter(author=request.user)
The formfield_for_foreignkey method on a ModelAdmin allows you to override the default formfield for a foreign keys field. For example, to return a subset of objects for this foreign key field based on the user:
class MyModelAdmin(admin.ModelAdmin):
def formfield_for_foreignkey(self, db_field, request, **kwargs):
if db_field.name == "car":
kwargs["queryset"] = Car.objects.filter(owner=request.user)
return super(MyModelAdmin, self).formfield_for_foreignkey(db_field, request, **kwargs)
This uses the HttpRequest instance to filter the Car foreign key field to only display the cars owned by the User instance.
[update]
Sorry, I failed to read the "filter" part. In Django >= 1.4 you can pass a subclass of django.contrib.admin.SimpleListFilter in the list_filter argument list, which you can use in order to override the lookups and queryset methods.
from datetime import date
from django.contrib import admin
from django.utils.translation import ugettext_lazy as _
class DecadeBornListFilter(admin.SimpleListFilter):
# Human-readable title which will be displayed in the
# right admin sidebar just above the filter options.
title = _('decade born')
# Parameter for the filter that will be used in the URL query.
parameter_name = 'decade'
def lookups(self, request, model_admin):
"""
Returns a list of tuples. The first element in each
tuple is the coded value for the option that will
appear in the URL query. The second element is the
human-readable name for the option that will appear
in the right sidebar.
"""
return (
('80s', _('in the eighties')),
('90s', _('in the nineties')),
)
def queryset(self, request, queryset):
"""
Returns the filtered queryset based on the value
provided in the query string and retrievable via
`self.value()`.
"""
# Compare the requested value (either '80s' or '90s')
# to decide how to filter the queryset.
if self.value() == '80s':
return queryset.filter(birthday__gte=date(1980, 1, 1),
birthday__lte=date(1989, 12, 31))
if self.value() == '90s':
return queryset.filter(birthday__gte=date(1990, 1, 1),
birthday__lte=date(1999, 12, 31))
class PersonAdmin(admin.ModelAdmin):
list_filter = (DecadeBornListFilter,)
Edit - this method has been pointed out to have issues, see below
You can do it like this:
Let's say you have a model called Animal, which has a ForeignKey field to a model called Species. In a particular admin list, you want to allow only certain species to be shown in the animals filter choices.
First, specify a custom ListFilter called SpeciesFilter in the Animal's ModelAdmin:
class AnimalAdmin(ModelAdmin):
list_filter = (('species', SpeciesFilter),)
Then define the SpeciesFilter:
from django.contrib.admin.filters import RelatedFieldListFilter
class SpeciesFilter(RelatedFieldListFilter):
def __init__(self, field, request, *args, **kwargs):
"""Get the species you want to limit it to.
This could be determined by the request,
But in this example we'll just specify an
arbitrary species"""
species = Species.objects.get(name='Tarantula')
#Limit the choices on the field
field.rel.limit_choices_to = {'species': species}
#Let the RelatedFieldListFilter do its magic
super(SpeciesFilter, self).__init__(field, request, *args, **kwargs)
That should do it.
I found another method similar to #seddonym, but doesn't mess with the caching. It is based on this Django code, but uses undocumented method field_choices, which can be subject to change in the future Django releases. The code for #seddonym's case would be:
from django.contrib.admin.filters import RelatedFieldListFilter
class SpeciesFilter(RelatedFieldListFilter):
def field_choices(self, field, request, model_admin):
return field.get_choices(include_blank=False, limit_choices_to={'name': 'Tarantula'})
Or in my case the working code is:
from django.contrib.admin.filters import RelatedFieldListFilter
class UnitFilter(RelatedFieldListFilter):
def field_choices(self, field, request, model_admin):
return field.get_choices(include_blank=False, limit_choices_to={'pk__in': request.user.administrated_units.all()})
I had to create my lookup fields from db table. I created custom filter class as below and displaying only related values to logged in user and filter accordingly:
class ShiftFilter_Org(admin.SimpleListFilter):
title = 'Organisation'
parameter_name = 'org'
def lookups(self, request, model_admin):
"""Get the organisations you want to limit"""
qs_org = Organisation.objects.filter(users=request.user)
list_org = []
for og in qs_org:
list_org.append(
(og.id, og.name)
)
return (
sorted(list_org, key=lambda tp:tp[1])
)
def queryset(self, request, queryset):
if self.value():
return queryset.filter(org=self.value())
For more visit Getting the most out of Django Admin filters
To use RelatedFieldListFilter like suggested in some answers, you need to pass a tuple to list_filter. Following the classes definition used in the original question, you would have:
class MyModelAdmin(admin.ModelAdmin):
class AnotherModelListFilter(admin.RelatedFieldListFilter):
def field_choices(self, field, request, model_admin):
ordering = self.field_admin_ordering(field, request, model_admin)
return field.get_choices(
include_blank=False,
ordering=ordering,
limit_choices_to=dict(n=<THE_VALUE_YOU_WANT>),
)
list_filter = (('somefield', AnotherModelListFilter),)

Django: make ModelChoiceField evaluate queryset at run-time

I've overridden the default manager of my models in order to show only allowed items, according to the logged user (a sort of object-specific permission):
class User_manager(models.Manager):
def get_query_set(self):
""" Filter results according to logged user """
#Compose a filter dictionary with current user (stored in a middleware method)
user_filter = middleware.get_user_filter()
return super(User_manager, self).get_query_set().filter(**user_filter)
class Foo(models.Model):
objects = User_manager()
...
In this way, whenever I use Foo.objects, the current user is retrieved and a filter is applied to default queryset in order to show allowed records only.
Then, I have a model with a ForeignKey to Foo:
class Bar(models.Model):
foo = models.ForeignKey(Foo)
class BarForm(form.ModelForm):
class Meta:
model = Bar
When I compose BarForm I'm expecting to see only the filteres Foo instances but the filter is not applied. I think it is because the queryset is evaluated and cached on Django start-up, when no user is logged and no filter is applied.
Is there a method to make Django evalutate the ModelChoice queryset at run-time, without having to make it explicit in the form definition? (despite of all performance issues...)
EDIT
I've found where the queryset is evaluated (django\db\models\fields\related.py: 887):
def formfield(self, **kwargs):
db = kwargs.pop('using', None)
defaults = {
'form_class': forms.ModelChoiceField,
'queryset': self.rel.to._default_manager.using(db).complex_filter(self.rel.limit_choices_to),
'to_field_name': self.rel.field_name,
}
defaults.update(kwargs)
return super(ForeignKey, self).formfield(**defaults)
Any hint?
Had exactly this problem -- needed to populate select form with user objects from a group, but fun_vit's answer is incorrect (at least for django 1.5)
Firstly, you don't want to overwrite the field['somefield'].choices object -- it is a ModelChoiceIterator object, not a queryset. Secondly, a comment in django.forms.BaseForm warns you against overriding base_fields:
# The base_fields class attribute is the *class-wide* definition of
# fields. Because a particular *instance* of the class might want to
# alter self.fields, we create self.fields here by copying base_fields.
# Instances should always modify self.fields; they should not modify
# self.base_fields.
This worked for me (django 1.5):
class MyForm(ModelForm):
users = ModelMultipleChoiceField(queryset=User.objects.none())
def __init__(self, *args, **kwargs):
super(MyForm, self).__init__(*args,**kwargs)
site = Site.objects.get_current()
self.fields['users'].queryset = site.user_group.user_set.all()
class Meta:
model = MyModel
i use init of custom form:
class BT_Form(forms.ModelForm):
def __init__(self, *args, **kwargs):
super(BT_Form, self).__init__(*args, **kwargs)
#prepare new values
cities = [(u'',u'------')] #default value
cities.extend([
(
c.pk,
c.__unicode__()
) for c in City.objects.filter(enabled=True).all()
])
self.fields['fly_from_city'].choices = cities #renew values
No way: I had to rewrite queryset definition (which is evaluated at startup)

In a Django form, how do I make a field readonly (or disabled) so that it cannot be edited?

In a Django form, how do I make a field read-only (or disabled)?
When the form is being used to create a new entry, all fields should be enabled - but when the record is in update mode some fields need to be read-only.
For example, when creating a new Item model, all fields must be editable, but while updating the record, is there a way to disable the sku field so that it is visible, but cannot be edited?
class Item(models.Model):
sku = models.CharField(max_length=50)
description = models.CharField(max_length=200)
added_by = models.ForeignKey(User)
class ItemForm(ModelForm):
class Meta:
model = Item
exclude = ('added_by')
def new_item_view(request):
if request.method == 'POST':
form = ItemForm(request.POST)
# Validate and save
else:
form = ItemForm()
# Render the view
Can class ItemForm be reused? What changes would be required in the ItemForm or Item model class? Would I need to write another class, "ItemUpdateForm", for updating the item?
def update_item_view(request):
if request.method == 'POST':
form = ItemUpdateForm(request.POST)
# Validate and save
else:
form = ItemUpdateForm()
As pointed out in this answer, Django 1.9 added the Field.disabled attribute:
The disabled boolean argument, when set to True, disables a form field using the disabled HTML attribute so that it won’t be editable by users. Even if a user tampers with the field’s value submitted to the server, it will be ignored in favor of the value from the form’s initial data.
With Django 1.8 and earlier, to disable entry on the widget and prevent malicious POST hacks you must scrub the input in addition to setting the readonly attribute on the form field:
class ItemForm(ModelForm):
def __init__(self, *args, **kwargs):
super(ItemForm, self).__init__(*args, **kwargs)
instance = getattr(self, 'instance', None)
if instance and instance.pk:
self.fields['sku'].widget.attrs['readonly'] = True
def clean_sku(self):
instance = getattr(self, 'instance', None)
  if instance and instance.pk:
    return instance.sku
  else:
    return self.cleaned_data['sku']
Or, replace if instance and instance.pk with another condition indicating you're editing. You could also set the attribute disabled on the input field, instead of readonly.
The clean_sku function will ensure that the readonly value won't be overridden by a POST.
Otherwise, there is no built-in Django form field which will render a value while rejecting bound input data. If this is what you desire, you should instead create a separate ModelForm that excludes the uneditable field(s), and just print them inside your template.
Django 1.9 added the Field.disabled attribute: https://docs.djangoproject.com/en/stable/ref/forms/fields/#disabled
The disabled boolean argument, when set to True, disables a form field using the disabled HTML attribute so that it won’t be editable by users. Even if a user tampers with the field’s value submitted to the server, it will be ignored in favor of the value from the form’s initial data.
Setting readonly on a widget only makes the input in the browser read-only. Adding a clean_sku which returns instance.sku ensures the field value will not change on form level.
def clean_sku(self):
if self.instance:
return self.instance.sku
else:
return self.fields['sku']
This way you can use model's (unmodified save) and avoid getting the field required error.
awalker's answer helped me a lot!
I've changed his example to work with Django 1.3, using get_readonly_fields.
Usually you should declare something like this in app/admin.py:
class ItemAdmin(admin.ModelAdmin):
...
readonly_fields = ('url',)
I've adapted in this way:
# In the admin.py file
class ItemAdmin(admin.ModelAdmin):
...
def get_readonly_fields(self, request, obj=None):
if obj:
return ['url']
else:
return []
And it works fine. Now if you add an Item, the url field is read-write, but on change it becomes read-only.
To make this work for a ForeignKey field, a few changes need to be made. Firstly, the SELECT HTML tag does not have the readonly attribute. We need to use disabled="disabled" instead. However, then the browser doesn't send any form data back for that field. So we need to set that field to not be required so that the field validates correctly. We then need to reset the value back to what it used to be so it's not set to blank.
So for foreign keys you will need to do something like:
class ItemForm(ModelForm):
def __init__(self, *args, **kwargs):
super(ItemForm, self).__init__(*args, **kwargs)
instance = getattr(self, 'instance', None)
if instance and instance.id:
self.fields['sku'].required = False
self.fields['sku'].widget.attrs['disabled'] = 'disabled'
def clean_sku(self):
# As shown in the above answer.
instance = getattr(self, 'instance', None)
if instance:
return instance.sku
else:
return self.cleaned_data.get('sku', None)
This way the browser won't let the user change the field, and will always POST as it it was left blank. We then override the clean method to set the field's value to be what was originally in the instance.
For Django 1.2+, you can override the field like so:
sku = forms.CharField(widget = forms.TextInput(attrs={'readonly':'readonly'}))
I made a MixIn class which you may inherit to be able to add a read_only iterable field which will disable and secure fields on the non-first edit:
(Based on Daniel's and Muhuk's answers)
from django import forms
from django.db.models.manager import Manager
# I used this instead of lambda expression after scope problems
def _get_cleaner(form, field):
def clean_field():
value = getattr(form.instance, field, None)
if issubclass(type(value), Manager):
value = value.all()
return value
return clean_field
class ROFormMixin(forms.BaseForm):
def __init__(self, *args, **kwargs):
super(ROFormMixin, self).__init__(*args, **kwargs)
if hasattr(self, "read_only"):
if self.instance and self.instance.pk:
for field in self.read_only:
self.fields[field].widget.attrs['readonly'] = "readonly"
setattr(self, "clean_" + field, _get_cleaner(self, field))
# Basic usage
class TestForm(AModelForm, ROFormMixin):
read_only = ('sku', 'an_other_field')
I ran across a similar problem.
It looks like I was able to solve it by defining a get_readonly_fields method in my ModelAdmin class.
Something like this:
# In the admin.py file
class ItemAdmin(admin.ModelAdmin):
def get_readonly_display(self, request, obj=None):
if obj:
return ['sku']
else:
return []
The nice thing is that obj will be None when you are adding a new Item, or it will be the object being edited when you are changing an existing Item.
get_readonly_display is documented here.
I've just created the simplest possible widget for a readonly field - I don't really see why forms don't have this already:
class ReadOnlyWidget(widgets.Widget):
"""Some of these values are read only - just a bit of text..."""
def render(self, _, value, attrs=None):
return value
In the form:
my_read_only = CharField(widget=ReadOnlyWidget())
Very simple - and gets me just output. Handy in a formset with a bunch of read only values.
Of course - you could also be a bit more clever and give it a div with the attrs so you can append classes to it.
For django 1.9+
You can use Fields disabled argument to make field disable.
e.g. In following code snippet from forms.py file , I have made employee_code field disabled
class EmployeeForm(forms.ModelForm):
employee_code = forms.CharField(disabled=True)
class Meta:
model = Employee
fields = ('employee_code', 'designation', 'salary')
Reference
https://docs.djangoproject.com/en/dev/ref/forms/fields/#disabled
How I do it with Django 1.11 :
class ItemForm(ModelForm):
disabled_fields = ('added_by',)
class Meta:
model = Item
fields = '__all__'
def __init__(self, *args, **kwargs):
super(ItemForm, self).__init__(*args, **kwargs)
for field in self.disabled_fields:
self.fields[field].disabled = True
One simple option is to just type form.instance.fieldName in the template instead of form.fieldName.
You can elegantly add readonly in the widget:
class SurveyModaForm(forms.ModelForm):
class Meta:
model = Survey
fields = ['question_no']
widgets = {
'question_no':forms.NumberInput(attrs={'class':'form-control','readonly':True}),
}
Yet again, I am going to offer one more solution :) I was using Humphrey's code, so this is based off of that.
However, I ran into issues with the field being a ModelChoiceField. Everything would work on the first request. However, if the formset tried to add a new item and failed validation, something was going wrong with the "existing" forms where the SELECTED option was being reset to the default ---------.
Anyway, I couldn't figure out how to fix that. So instead, (and I think this is actually cleaner in the form), I made the fields HiddenInputField(). This just means you have to do a little more work in the template.
So the fix for me was to simplify the Form:
class ItemForm(ModelForm):
def __init__(self, *args, **kwargs):
super(ItemForm, self).__init__(*args, **kwargs)
instance = getattr(self, 'instance', None)
if instance and instance.id:
self.fields['sku'].widget=HiddenInput()
And then in the template, you'll need to do some manual looping of the formset.
So, in this case you would do something like this in the template:
<div>
{{ form.instance.sku }} <!-- This prints the value -->
{{ form }} <!-- Prints form normally, and makes the hidden input -->
</div>
This worked a little better for me and with less form manipulation.
I was going into the same problem so I created a Mixin that seems to work for my use cases.
class ReadOnlyFieldsMixin(object):
readonly_fields =()
def __init__(self, *args, **kwargs):
super(ReadOnlyFieldsMixin, self).__init__(*args, **kwargs)
for field in (field for name, field in self.fields.iteritems() if name in self.readonly_fields):
field.widget.attrs['disabled'] = 'true'
field.required = False
def clean(self):
cleaned_data = super(ReadOnlyFieldsMixin,self).clean()
for field in self.readonly_fields:
cleaned_data[field] = getattr(self.instance, field)
return cleaned_data
Usage, just define which ones must be read only:
class MyFormWithReadOnlyFields(ReadOnlyFieldsMixin, MyForm):
readonly_fields = ('field1', 'field2', 'fieldx')
As a useful addition to Humphrey's post, I had some issues with django-reversion, because it still registered disabled fields as 'changed'. The following code fixes the problem.
class ItemForm(ModelForm):
def __init__(self, *args, **kwargs):
super(ItemForm, self).__init__(*args, **kwargs)
instance = getattr(self, 'instance', None)
if instance and instance.id:
self.fields['sku'].required = False
self.fields['sku'].widget.attrs['disabled'] = 'disabled'
def clean_sku(self):
# As shown in the above answer.
instance = getattr(self, 'instance', None)
if instance:
try:
self.changed_data.remove('sku')
except ValueError, e:
pass
return instance.sku
else:
return self.cleaned_data.get('sku', None)
As I can't yet comment (muhuk's solution), I'll response as a separate answer. This is a complete code example, that worked for me:
def clean_sku(self):
if self.instance and self.instance.pk:
return self.instance.sku
else:
return self.cleaned_data['sku']
Based on Yamikep's answer, I found a better and very simple solution which also handles ModelMultipleChoiceField fields.
Removing field from form.cleaned_data prevents fields from being saved:
class ReadOnlyFieldsMixin(object):
readonly_fields = ()
def __init__(self, *args, **kwargs):
super(ReadOnlyFieldsMixin, self).__init__(*args, **kwargs)
for field in (field for name, field in self.fields.iteritems() if
name in self.readonly_fields):
field.widget.attrs['disabled'] = 'true'
field.required = False
def clean(self):
for f in self.readonly_fields:
self.cleaned_data.pop(f, None)
return super(ReadOnlyFieldsMixin, self).clean()
Usage:
class MyFormWithReadOnlyFields(ReadOnlyFieldsMixin, MyForm):
readonly_fields = ('field1', 'field2', 'fieldx')
if your need multiple read-only fields.you can use any of methods given below
method 1
class ItemForm(ModelForm):
readonly = ('sku',)
def __init__(self, *arg, **kwrg):
super(ItemForm, self).__init__(*arg, **kwrg)
for x in self.readonly:
self.fields[x].widget.attrs['disabled'] = 'disabled'
def clean(self):
data = super(ItemForm, self).clean()
for x in self.readonly:
data[x] = getattr(self.instance, x)
return data
method 2
inheritance method
class AdvancedModelForm(ModelForm):
def __init__(self, *arg, **kwrg):
super(AdvancedModelForm, self).__init__(*arg, **kwrg)
if hasattr(self, 'readonly'):
for x in self.readonly:
self.fields[x].widget.attrs['disabled'] = 'disabled'
def clean(self):
data = super(AdvancedModelForm, self).clean()
if hasattr(self, 'readonly'):
for x in self.readonly:
data[x] = getattr(self.instance, x)
return data
class ItemForm(AdvancedModelForm):
readonly = ('sku',)
Two more (similar) approaches with one generalized example:
1) first approach - removing field in save() method, e.g. (not tested ;) ):
def save(self, *args, **kwargs):
for fname in self.readonly_fields:
if fname in self.cleaned_data:
del self.cleaned_data[fname]
return super(<form-name>, self).save(*args,**kwargs)
2) second approach - reset field to initial value in clean method:
def clean_<fieldname>(self):
return self.initial[<fieldname>] # or getattr(self.instance, fieldname)
Based on second approach I generalized it like this:
from functools import partial
class <Form-name>(...):
def __init__(self, ...):
...
super(<Form-name>, self).__init__(*args, **kwargs)
...
for i, (fname, field) in enumerate(self.fields.iteritems()):
if fname in self.readonly_fields:
field.widget.attrs['readonly'] = "readonly"
field.required = False
# set clean method to reset value back
clean_method_name = "clean_%s" % fname
assert clean_method_name not in dir(self)
setattr(self, clean_method_name, partial(self._clean_for_readonly_field, fname=fname))
def _clean_for_readonly_field(self, fname):
""" will reset value to initial - nothing will be changed
needs to be added dynamically - partial, see init_fields
"""
return self.initial[fname] # or getattr(self.instance, fieldname)
For the Admin version, I think this is a more compact way if you have more than one field:
def get_readonly_fields(self, request, obj=None):
skips = ('sku', 'other_field')
fields = super(ItemAdmin, self).get_readonly_fields(request, obj)
if not obj:
return [field for field in fields if not field in skips]
return fields
Here is a slightly more involved version, based on christophe31's answer. It does not rely on the "readonly" attribute. This makes its problems, like select boxes still being changeable and datapickers still popping up, go away.
Instead, it wraps the form fields widget in a readonly widget, thus making the form still validate. The content of the original widget is displayed inside <span class="hidden"></span> tags. If the widget has a render_readonly() method it uses that as the visible text, otherwise it parses the HTML of the original widget and tries to guess the best representation.
import django.forms.widgets as f
import xml.etree.ElementTree as etree
from django.utils.safestring import mark_safe
def make_readonly(form):
"""
Makes all fields on the form readonly and prevents it from POST hacks.
"""
def _get_cleaner(_form, field):
def clean_field():
return getattr(_form.instance, field, None)
return clean_field
for field_name in form.fields.keys():
form.fields[field_name].widget = ReadOnlyWidget(
initial_widget=form.fields[field_name].widget)
setattr(form, "clean_" + field_name,
_get_cleaner(form, field_name))
form.is_readonly = True
class ReadOnlyWidget(f.Select):
"""
Renders the content of the initial widget in a hidden <span>. If the
initial widget has a ``render_readonly()`` method it uses that as display
text, otherwise it tries to guess by parsing the html of the initial widget.
"""
def __init__(self, initial_widget, *args, **kwargs):
self.initial_widget = initial_widget
super(ReadOnlyWidget, self).__init__(*args, **kwargs)
def render(self, *args, **kwargs):
def guess_readonly_text(original_content):
root = etree.fromstring("<span>%s</span>" % original_content)
for element in root:
if element.tag == 'input':
return element.get('value')
if element.tag == 'select':
for option in element:
if option.get('selected'):
return option.text
if element.tag == 'textarea':
return element.text
return "N/A"
original_content = self.initial_widget.render(*args, **kwargs)
try:
readonly_text = self.initial_widget.render_readonly(*args, **kwargs)
except AttributeError:
readonly_text = guess_readonly_text(original_content)
return mark_safe("""<span class="hidden">%s</span>%s""" % (
original_content, readonly_text))
# Usage example 1.
self.fields['my_field'].widget = ReadOnlyWidget(self.fields['my_field'].widget)
# Usage example 2.
form = MyForm()
make_readonly(form)
Today I encountered the exact same problem for a similar use case. However, I had to deal with a class-based views. Class-based views allow inheriting attributes and methods thus making it easier to reuse code in a neat manner.
I will answer your question by discussing the code needed for creating a profile page for users. On this page, they can update their personal information. However, I wanted to show an email field without allowing the user to change the information.
Yes, I could have just left out the email field but my OCD would not allow it.
In the example below I used a form class in combination with the disabled = True method. This code is tested on Django==2.2.7.
# form class in forms.py
# Alter import User if you have created your own User class with Django default as abstract class.
from .models import User
# from django.contrib.auth.models import User
# Same goes for these forms.
from django.contrib.auth.forms import UserCreationForm, UserChangeForm
class ProfileChangeForm(UserChangeForm):
class Meta(UserCreationForm)
model = User
fields = ['first_name', 'last_name', 'email',]
def __init__(self, *args, **kwargs):
super().__init__(*args, **kwargs)
self.fields['email'].disabled = True
As one can see, the needed user fields are specified. These are the fields that must be shown on the profile page. If other fields need to be added one has to specify them in the User class and add the attribute name to the fields list of the Meta class of this form.
After getting the required metadata the __init__ method is called initializing the form. However, within this method, the email field parameter 'disabled' is set to True. By doing so the behavior of the field in the front-end is altered resulting in a read-only field that one cannot edit even if one changes the HTML code. Reference Field.disabled
For completion, in the example below one can see the class-based views needed to use the form.
# view class in views.py
from django.contrib import messages
from django.contrib.messages.views import SuccessMessageMixin
from django.contrib.auth.mixins import LoginRequiredMixin
from django.views.generic import TemplateView, UpdateView
from django.utils.translation import gettext_lazy as _
class ProfileView(LoginRequiredMixin, TemplateView):
template_name = 'app_name/profile.html'
model = User
def get_context_data(self, **kwargs):
context = super().get_context_data(**kwargs)
context.update({'user': self.request.user, })
return context
class UserUpdateView(LoginRequiredMixin, SuccesMessageMixin, UpdateView):
template_name = 'app_name/update_profile.html'
model = User
form_class = ProfileChangeForm
success_message = _("Successfully updated your personal information")
def get_success_url(self):
# Please note, one has to specify a get_absolute_url() in the User class
# In my case I return: reverse("app_name:profile")
return self.request.user.get_absolute_url()
def get_object(self, **kwargs):
return self.request.user
def form_valid(self, form):
messages.add_message(self.request, messages.INFO, _("Successfully updated your profile"))
return super().form_valid(form)
The ProfileView class only shows an HTML page with some information about the user. Furthermore, it holds a button that if pressed leads to an HTML page configured by the UserUpdateView, namely 'app_name/update_profile.html'. As one can see, the UserUpdateView holds two extra attributes, namely 'form_class' and 'success_message'.
The view knows that every field on the page must be filled with data from the User model. However, by introducing the 'form_class' attribute the view does not get the default layout of the User fields. Instead, it is redirected to retrieve the fields through the form class. This has a huge advantage in the sense of flexibility.
By using form classes it is possible to show different fields with different restrictions for different users. If one sets the restrictions within the model itself every user would get the same treatment.
The template itself is not that spectacular but can be seen below.
# HTML template in 'templates/app_name/update_profile.html'
{% extends "base.html" %}
{% load static %}
{% load crispy_form_tags %}
{% block content %}
<h1>
Update your personal information
<h1/>
<div>
<form class="form-horizontal" method="post" action="{% url 'app_name:update' %}">
{% csrf_token %}
{{ form|crispy }}
<div class="btn-group">
<button type="submit" class="btn btn-primary">
Update
</button>
</div>
</div>
{% endblock %}
As can be seen, the form tag holds an action tag that holds the view URL routing.
After pressing the Update button the UserUpdateView gets activated and it validates if all conditions are met. If so, the form_valid method is triggered and adds a success message. After successfully updating the data the user is returned to the specified URL in the get_success_url method.
Below one can find the code allowing the URL routing for the views.
# URL routing for views in urls.py
from django.urls import path
from . import views
app_name = 'app_name'
urlpatterns = [
path('profile/', view=views.ProfileView.as_view(), name='profile'),
path('update/', view=views.UserUpdateView.as_view(), name='update'),
]
There you have it. A fully worked out implementation of class-based views using form so one can alter an email field to be read-only and disabled.
My apologies for the extremely detailed example. There might be more efficient ways to design the class-based views, but this should work. Of course, I might have been wrong about some things said. I'm still learning as well. If anyone has any comments or improvements let me know!
You can do it just like this:
Check if the request is update or save a new object.
If request is update then disable field sku.
If request is to add a new object then you must render the form with out disabling the field sku.
Here is an example of how to do like this.
class Item(models.Model):
sku = models.CharField(max_length=50)
description = models.CharField(max_length=200)
added_by = models.ForeignKey(User)
class ItemForm(ModelForm):
def disable_sku_field(self):
elf.fields['sku'].widget.attrs['readonly'] = True
class Meta:
model = Item
exclude = ('added_by')
def new_item_view(request):
if request.method == 'POST':
form = ItemForm(request.POST)
# Just create an object or instance of the form.
# Validate and save
else:
form = ItemForm()
# Render the view
def update_item_view(request):
if request.method == 'POST':
form = ItemForm(request.POST)
# Just create an object or instance of the form.
# Validate and save
else:
form = ItemForm()
form.disable_sku_field() # call the method that will disable field.
# Render the view with the form that will have the `sku` field disabled on it.
Is this the simplest way?
Right in a view code something like this:
def resume_edit(request, r_id):
.....
r = Resume.get.object(pk=r_id)
resume = ResumeModelForm(instance=r)
.....
resume.fields['email'].widget.attrs['readonly'] = True
.....
return render(request, 'resumes/resume.html', context)
It works fine!
If you are working with Django ver < 1.9 (the 1.9 has added Field.disabled attribute) you could try to add following decorator to your form __init__ method:
def bound_data_readonly(_, initial):
return initial
def to_python_readonly(field):
native_to_python = field.to_python
def to_python_filed(_):
return native_to_python(field.initial)
return to_python_filed
def disable_read_only_fields(init_method):
def init_wrapper(*args, **kwargs):
self = args[0]
init_method(*args, **kwargs)
for field in self.fields.values():
if field.widget.attrs.get('readonly', None):
field.widget.attrs['disabled'] = True
setattr(field, 'bound_data', bound_data_readonly)
setattr(field, 'to_python', to_python_readonly(field))
return init_wrapper
class YourForm(forms.ModelForm):
#disable_read_only_fields
def __init__(self, *args, **kwargs):
...
The main idea is that if field is readonly you don't need any other value except initial.
P.S: Don't forget to set yuor_form_field.widget.attrs['readonly'] = True
Start from disable fields mixin:
class ModelAllDisabledFormMixin(forms.ModelForm):
def __init__(self, *args, **kwargs):
'''
This mixin to ModelForm disables all fields. Useful to have detail view based on model
'''
super().__init__(*args, **kwargs)
form_fields = self.fields
for key in form_fields.keys():
form_fields[key].disabled = True
then:
class MyModelAllDisabledForm(ModelAllDisabledFormMixin, forms.ModelForm):
class Meta:
model = MyModel
fields = '__all__'
prepare view:
class MyModelDetailView(LoginRequiredMixin, UpdateView):
model = MyModel
template_name = 'my_model_detail.html'
form_class = MyModelAllDisabledForm
place this in my_model_detail.html template:
<div class="form">
<form method="POST" enctype="multipart/form-data">
{% csrf_token %}
{{ form | crispy }}
</form>
</div>
You will obtain same form as in update view but with all fields disabled.
Based on the answer from #paeduardo (which is overkill), you can disable a field in the form class initializer:
class RecordForm(ModelForm):
def __init__(self, *args, **kwargs):
super().__init__(*args, **kwargs)
var = self.fields['the_field']
var.disabled = True
If you are using Django admin, here is the simplest solution.
class ReadonlyFieldsMixin(object):
def get_readonly_fields(self, request, obj=None):
if obj:
return super(ReadonlyFieldsMixin, self).get_readonly_fields(request, obj)
else:
return tuple()
class MyAdmin(ReadonlyFieldsMixin, ModelAdmin):
readonly_fields = ('sku',)
I think your best option would just be to include the readonly attribute in your template rendered in a <span> or <p> rather than include it in the form if it's readonly.
Forms are for collecting data, not displaying it. That being said, the options to display in a readonly widget and scrub POST data are fine solutions.