Refactoring the "view" code - django

Question

My "view" code has an obvious repetition in its code. Is there any way of refactoring the "return" code?
def form_contractor_view(request):
if request.method == 'POST':
form = ContractorForm(request.POST)
if form.is_valid():
form.save()
return redirect('index_view')
else:
return render_to_response(
'form_contractor.html',
{'form': form},
context_instance=RequestContext(request),
)
else:
form = ContractorForm()
return render_to_response(
'form_contractor.html',
{'form': form},
context_instance=RequestContext(request),
)

Answer 1

There is no need for the first else at all. Move the final render back an indent, and that will catch the else case. Note that this is the pattern explicitly described in the documentation.
Also, use render instead of render_to_response.
def form_contractor_view(request):
if request.method == 'POST':
form = ContractorForm(request.POST)
if form.is_valid():
form.save()
return redirect('index_view')
else:
form = ContractorForm()
return render(
request,
'form_contractor.html',
{'form': form},
)

Answer 2

I will give my try:
def form_contractor_view(request):
form = ContractorForm(request.POST or None)
if form.is_valid():
form.save()
return redirect(reverse('index_view')) # <-- you forgot reverse() here
return render(
request,
'form_contractor.html',
{'form': form}
)
I replaced render_to_response with render which does the same thing - you just type less... try to be lazy ;)
I think, this works. not tested though. If request is not done in POST, then is_valid() returns False returning the form as None back again which makes sense. and for the case where the request is done in POST and invalid values in it, then else kicks in and returns the form with error messages... I think, this works.. please test