Get the max element in an array that ends with a 0 - c++

Question

So, I am writing a code which creates an array with an elements and amount of elements written by user and then a code generates a biggest value which last digit is zero. So, I have accomplished a step of writing an array which is elements entered by user. The hardest part( for me) is to complete a code which generates biggest value which last digit is zero. So yeah, I need an advice in completing this code. Thank you.
for example :
An array - 2 20 25 300 55555
The biggest number which last digit is zero is 300
So yeah, I need an advice in completing this code. Here is a code what I have done so far :
#include "stdafx.h"
#include <stdlib.h>
#include <windows.h>
#include <time.h>
int GetAmount() {
int howmany;
printf("Enter amount of elements - ");
scanf_s("%i", &howmany);
return howmany;
}
void GetArray(int a[], int n) {
printf("Enter elements - \n");
for (int i = 0; i < n; i++)
{ printf("%i ->", i);
scanf_s("%i", &a[i]);
}
}
int LastDigitZero(int n[], int a) {
for (int i = 0; i < a; i++)
{
if (n[i] % 10 == 0) {
return 0;
}
}
}
int maxvalue(int a[], int n) {
int temp = 0;
for (int i = 0; i < n; i++)
{
if (a[i] > temp) {
temp = a[i];
}
}
return temp;
}
void main() {
int amount = GetAmount();
int array[100];
GetArray(array, amount);
int max = maxvalue(array, amount);
printf("Max Value is %i\n", max);
}
Thank you for your attention, have a nice day! :)

Answer 1

It works! That's how it looks!
#include "stdafx.h"
#include <stdlib.h>
#include <windows.h>
#include <time.h>
int GetAmount() {
int howmany;
printf("Enter amount of elements - ");
scanf_s("%i", &howmany);
return howmany;
}
void GetArray(int a[], int n) {
printf("Enter elements - \n");
for (int i = 0; i < n; i++)
{ printf("%i ->", i);
scanf_s("%i", &a[i]);
}
}
int maxvalue(int a[], int n) {
int temp = 0;
for (int i = 0; i < n; i++)
{
if (a[i] % 10 == 0 && a[i] > temp) {
temp = a[i];
}
}
return temp;
}
void main() {
int amount = GetAmount();
int array[100];
GetArray(array, amount);
int max = maxvalue(array, amount);
printf("The biggest number which last digit is zero is %i\n ", max);
system("pause");
}
Thank you guys for the answers! That was fast!!! :)

Answer 2

You almost have it. First any number that ends in 0 mod 10 is 0 so that is how you can check if the last digit is 0. With that you would change maxvalue() to
int maxvalue(int a[], int n) {
int temp = a[0];
for (int i = 1; i < n; i++)
{
if (a[i] % 10 == 0 && a[i] > temp) {
temp = a[i];
}
}
return temp;
}
I also made a change to set temp to the value of a[0] as if your array is all negative numbers then 0 would be the largest number. Since temp is already a[0] we can then start the for loop at 1.

Answer 3

You should check if there is a solution, in this example you could check that the value returned by maxValue finishes by 0 (if none of the values finishes by 0 then it would return a[0]):
int maxValue(int a[], int n) {
int temp= a[0]
for (int i(1); i<n;i++) {
if (a[i] % 10 == 0 && (temp % 10 != 0 || a[i] > temp )) temp = a[i];
}
return temp;
}