output overload using template - c++

Question

So I'm trying to overload the output operator using templates, but I keep running into two errors. They are:
Error C2988 unrecognizable template declaration/definition
and
Error C2143 syntax error: missing ',' before '<'
template <typename E> class SLinkedList; //forward declaration
template <typename E>
ostream& operator<< (ostream& out, const SLinkedList<E>& v); //forward declaration
template <typename E>
class SLinkedList {
public:
template <typename E>
friend ostream& operator<< <E>(ostream& out, const SLinkedList<E>& v);
};
template <typename E>
ostream& operator <<(ostream& out, E const SLinkedLst<E>& v) {
while (v->next != NULL) {
out << v->elem;
v->next;
}
return out;
}

Answer 1

<E> is not needed in
friend ostream& operator<< <E>(ostream& out, const SLinkedList<E>& v);
Just get rid of it and it should compile.
You are also missing a ; at the end of you class. In C++ a class and struct declaration must end with a ;
You have an extra E in
ostream& operator <<(ostream& out, E const SLinkedLst<E>& v) {
^ what is this doing here?
You are also missing a ; at then end of
v->next
You are also using the same template name in
template <typename E>
class SLinkedList {
public:
template <typename E>
friend ostream& operator<< <E>(ostream& out, const SLinkedList<E>& v);
};
Which E is the function referring too? You will need to change it to some other name.

Answer 2

Try that instead
template <typename E>
class SLinkedList {
public:
template <typename T>
friend std::ostream& operator << (std::ostream& out, const SLinkedList<T>& v);
};
template <typename E>
std::ostream& operator << (std::ostream& out, const SLinkedList<E>& v) {
while (v->next != NULL) {
out << v->elem;
v->next;
}
return out;
}