I was trying to use char* pointers to refer to strings and vector<char> & dynamic arrays & I have a doubt with the following results :-
CODE 1:-
#include <iostream>
#include <string>
using namespace std;
int main()
{
cout<<"executing...\n";
string s="abcde";
char *c=&s[0];
cout<<c<<"\n";
s.~string();
cout<<c<<"\n";
cout<<"executed";
return 0;
}
The output of this code is :-
executing...
abcde
abcde
executed
CODE 2:-
#include <iostream>
#include <vector>
using namespace std;
int main()
{
cout<<"executing...\n";
vector<char> v {'a','b','c','d','e'};
char *p=&v[0];
cout<<p<<"\n";
v.~vector();
cout<<p<<"\n";
cout<<"executed";
return 0;
}
The output for this code is :-
executing...
abcde
executed
CODE 3 (with dynamic arrays):-
#include <iostream>
using namespace std;
int main()
{
cout<<"executing...\n";
char* c=new char[20] {'a','b','c','d','e'};
char *p=c;
cout<<p;
delete[] c;
cout<<"\n"<<p<<"\n";
cout<<"executed";
return 0;
}
The output for this code is similar to CODE 2:-
executing...
abcde
executed
I want to know why CODE 1 produces an output different from CODE 2 & CODE 3 ? What problem does string have that it behaves differently from vector<char> & dynamic arrays ?
All the snippets of code access data that has been deleted, which has no defined behavior. Therefore, any further assumption is meaningless and left to the single case. Whether you're accessing a vector, char*, string there's no difference: it's always the same violation.
Well I guess this example is good enough to show that your objects of string & vector are deleted twice hence leading to undefined behaviour :-
#include <iostream>
using namespace std;
class X
{
int x;
public:
X()
{
cout<<"constructing\n";
}
// other member functions...
~X()
{
cout<<"destroying\n";
}
};
int main()
{
X object;
object.~X();
return 0;
}
Output will be :-
constructing
destroying
destroying
When behaviour is undefined there is no use of thinking about "WHY SUCH AN OUTPUT", etc stuffs !! Even I had a doubt regarding the reference counting of C++ strings but as many people are saying strings are no longer reference counted so CODE 1 is also producing undefined behaviour. However I liked you experimenting with codes. It's necessary to learn a language properly. Keep it up !!!
Related
#include <iostream>
#include <cstring>
#include <cstdio>
using namespace std;
int main(){
char a[20];
cout<<strlen(a)<<endl;
return 0;
}
The output of this code is 11.
Why 11? When I have not initialised it.
As stated here: http://en.cppreference.com/w/cpp/string/byte/strlen,
The behavior (of strlen(str)) is undefined if there is no null character in the character array pointed to by str.
The issue you are facing is caused by uninitialized memory. With char a[20]; you are only reserving memory space, but you are not initializing it. Those 20 bytes can have any possible value and you have no guarantees that any of them is set to 0. That causes the unespected return value of the strlen() call, you simply were lucky that the function found a byte set to 0 before it could cause a crash.
To avoid any problem you should initialize your variables before using. For a null terminated sequence of char you can initialize like so:
char a[20] = "";
Or you can use std::string instead:
#include <iostream>
#include <string>
int main() {
std::string a;
std::cout << a.length() << std::endl;
return 0;
}
The output, if you are wondering, is 0.
If you find uninitialized array's length,The behavior is undefined. if you want correct result initialize it. or use this:
int a[20] = {};
or
memset(a,'\0',20) and then after check the length.
#include <iostream>
#include <string>
#include <utility>
using namespace std;
string num1="123456789123456789";
std::pair<int*,int*> cpy(){
int a[(num1.size()%9==0)? num1.size()/9 : num1.size()/9+1];
int b[(num1.size()%9==0)? num1.size()/9 : num1.size()/9+1];
return make_pair(a,b);
}
int main(void){
return 0;
}
-------------------------------------------------------
//if by this style, it can be compiled
std::pair<int*,int*> cpy(){
const int N=5;
int a[5];
int b[5];
return make_pair(a,b);
}
I am writing a program to calculate Big Number such as 19933231289234783278, So I need split the number using 1 000 000 000 system
Why can't return a pair by this way?
You can't return a pair this way, because you are passing wrong types. In this case, array doesn't decay to pointer.
If you change the last line in the function to this :
return make_pair(&a[0],&b[0]);
it will compile, but it will still not work, as you are returning pointers to arrays, which are destroyed, once the function cpy() ends.
By the way, variable lenghts array are not standard c++.
You are trying to return pointer to a temporary value. As result the pointers will be point to a garbage.
Also you trying to cast string with decimal notation to integer.
You should return the pair of integers, which will be obtained by parsing the string at the numbers.
You can see the link below.
http://interactivepython.org/runestone/static/pythonds/BasicDS/ConvertingDecimalNumberstoBinaryNumbers.html
I've been trying to solve an easy problem, but I can't figure why my program doesn't work. I want to concatenate a string.
Can you help me? If so, can you also explain me why it doesn't work?
#include <iostream>
#include <cstring>
#include <fstream>
using namespace std;
ifstream in("sirul.in");
ofstream out("sirul.out");
char a[4000]="a",b[4000]="b",aux[4000];
int main()
{ int n,i;
in>>n;
if(n==1)out<<"a";
if(n==2)out<<"b";
for(i=3;i<=n;i++)
{
aux=strcpy(aux,b);
b=strcat(b,a);
a=strcpy(a,aux);
}
return 0;
}
strcpy and strcat work directly on the pointer you pass in as the first argument, then also return is so that you can chain calls. As such, assigning their result back to the destination pointer is redundant. In this case, it's also invalid, as you can't reassign an array.
The fix is to just not assign the return value of those calls:
strcpy(aux,b);
strcat(b,a);
strcpy(a,aux);
However, since you are using C++, you should use std::string instead, which gives you nice value semantics for your string data.
you can not do (see 2)
char b[4000]="b";
char aux[4000];
aux /* 2 */ = strcpy(aux /* 1 */ , b);
because aux is not a pointer, but array. you can pass it as pointer argument (see 1), but you can not "collect" the result "inside" aux (see 2).
As other suggested, just remove "collection" and it will work as you expect.
char b[4000]="b";
char aux[4000];
strcpy(aux /* 1 */ , b);
// or even:
const char *s = strcpy(aux /* 1 */ , b);
Also you are mixing C and C++ in one file.
Also probably there is possibility for buffer overflow.
#include <iostream>
#include <cstring>
#include <fstream>
using namespace std;
ifstream in("sirul.in");
ofstream out("sirul.out");
char a[4000]="a",b[4000]="b",aux[4000];
int main()
{
int n,i;
cin>>n;
if(n==1)cout<<"a";
if(n==2)cout<<"b";
for(i=3;i<=n;i++)
{
strcpy(aux,b);
strcat(b,a);
strcpy(a,aux);
}
return 0;
}
check out definition os strcpy, in should be cin and out should be cout
#include<stdlib.h>
#include<stdio.h>
#include<string.h>
#include<iostream>
using namespace std;
#define attr_size 3
int main(){
const char* attr[attr_size];
int i=0;
for(i=0;i<attr_size;i++){
char* t=(char*)malloc(sizeof(int));
sprintf(t,"%d",i);
string temp="attr";
temp+=t;
attr[i]=temp.c_str();
cout<<attr[i]<<endl;
free(t);
}
for(i=0;i<attr_size;i++){
cout<<attr[i]<<endl;
}
}
And the result is:
attr0
attr1
attr2
attr2
attr
attr2
Actually, I want to get the result that:
attr0
attr1
attr2
attr0
attr1
attr2
Maybe something wrong with loop. Anybody help me?
The problem is that the c_str return a pointer that is temporary. So when the loop continue it's iteration the object you got the pointer from is destructed and the pointer is no longer valid, leading to undefined behavior when you later dereference that pointer.
If you want an array of strings, why not declare it as an array of strings?
There are also other problems with your code, like you only allocating four bytes for a string that can be 12 (with sign and string terminator) characters.
I would suggest you remake your program like this:
#include <iostream>
#include <array>
#include <sstream>
const size_t ATTR_SIZE = 3;
int main()
{
std::array<std::string, ATTR_SIZE> attr;
for (int i = 0; i < ATTR_SIZE; ++i)
{
std::istringstream is;
is << "attr" << i;
attr[i] = is.str();
}
for (const std::string& s : attr)
std::cout << s << '\n';
}
The above uses some C++11 features like std::array (you can use std::vector instead) and range-base for loop (you can use normal iteration instead).
Can anyone explain to me why im getting a ".exe has encountered a problem and needs close"error, it compiles and works sometimes when i fiddle with the char array, but when it does work i sometimes get strange characters at the end of the string.
#include <iostream>
using namespace std;
char* StrReverse3(char*);
char* StrReverse3(char* str)
{
char *p;
int length=0,start=0,end=0;
length=strlen(str);
for(start=0,end=length-1;end>= 0,start<=length-1;end--,start++)
{
p[start]=str[end];
}
return p;
}
int main()
{
char str[100]="Saw my reflection in snow covered hills";
StrReverse3(str);
cin.get();
return 0;
}
You are not initializing p. It's an uninitialized pointer that you are writing to.
Since you are writing this in C++, not C, I'd suggest using std::string and std::reverse:
#include <string>
#include <algorithm>
#include <iostream>
int main()
{
std::string str = "Saw my reflection in snow covered hills";
std::reverse(str.begin(), str.end());
std::cout << str;
return 0;
}
Output:
sllih derevoc wons ni noitcelfer ym waS
See it working online at ideone
char *p; is never initialized, yet p[start] is used as the destination of an assignment. Don't you get compiler warnings from this? I'm amazed it even "works sometimes".
You are accessing memory that wasn't allocated by your program (p can point anywhere!). This is the reason for the problems you have.
I strongly encourage you to
read into the topic of dynamically allocating memory with new and delete to understand a very important topic
read into the standard template library, especially std::string. You should not use raw pointers like char*, always use standard types when possible.
#include <iostream>
#include <cstring>
using namespace std;
char* StrReverse3(char* str){
int length=0,start=0,end=0;
length=strlen(str);
for(start=0,end=length-1;end > start;end--,start++){
char temp;
temp = str[start];
str[start]=str[end];
str[end]=temp;
}
return str;
}
int main(){
char str[100]="Saw my reflection in snow covered hills";
cout << StrReverse3(str);
cin.get();
return 0;
}