I have problems with python-openstackclient library.When i run this code to authorize with keystone:
from keystoneclient import session
from keystoneclient.v3 import client
from keystoneclient.auth.identity import v3
password = v3.PasswordMethod(username='idm',password='idm',user_domain_name='idm')
auth = v3.Auth(auth_url='http://127.0.0.1:5000/v3',auth_methods=[password],project_id='idm')
sess = session.Session(auth=auth)
keystone = client.Client(session=sess)
keystone.users.list()
Im getting this error:
keystoneclient.openstack.common.apiclient.exceptions.Unauthorized: The request you have made requires authentication. (HTTP 401)
But when i try openstack client program:
openstack user list
It gives me good output.
I have next global variables in my .bashrc:
export OS_SERVICE_ENDPOINT=http://127.0.0.1:35357/v3
export OS_AUTH_URL=http://127.0.0.1:5000/v3
export OS_TENANT_NAME=idm
export OS_USERNAME=idm
export OS_PASSWORD=idm
export OS_IDENTITY_API_VERSION=3
export OS_URL=http://127.0.0.1:35357/v3
What could be the problem with that python code?
Thanks!
I had the same problem but after applying proposed solution I was getting :
keystoneauth1.exceptions.connection.ConnectFailure: Unable to
establish connection to http://192.0.2.12:35357/v2.0/users:
HTTPConnectionPool(host='192.0.2.12', port=35357): Max retries
exceeded with url: /v2.0/users (Caused by
NewConnectionError(': Failed to establish a new connection:
[Errno 110] Connection timed out',))
Note that my auth_url='https://myopenstack.somewhere.org:13000/v3',
It turns out that the client was discovering and using services on a interface which by default is 'Admin', and is unreachable for me. When forcing the interface to Public it works :
keystone = client.Client(session=sess, interface='Public')
I managed to do it like this:
from keystoneclient import session
from keystoneclient.v3 import client
from keystoneclient.auth.identity import v3
auth = v3.Password(auth_url='http://127.0.0.1:5000/v3',user_id='idm',password='idm',project_id='2545070293684905b9623095768b019d')
sess = session.Session(auth=auth)
keystone = client.Client(session=sess)
keystone.users.list()
Related
I'm having trouble connecting to a RabbitMQ instance (it's my first time doing so). I've spun one up on AWS, and been given access to an admin panel which I'm able to access.
I'm trying to connect to the RabbitMQ server in python/pika with the following code:
import pika
import logging
logging.basicConfig(level=logging.DEBUG)
credentials = pika.PlainCredentials('*******', '**********')
parameters = pika.ConnectionParameters(host='a-25c34e4d-a3eb-32de-abfg-l95d931afc72f.mq.us-west-1.amazonaws.com',
port=5671,
virtual_host='/',
credentials=credentials,
)
connection = pika.BlockingConnection(parameters)
I get pika.exceptions.IncompatibleProtocolError: StreamLostError: ("Stream connection lost: ConnectionResetError(54, 'Connection reset by peer')",) when I run the above.
you're trying to connect through AMQP protocol and AWS is using AMQPS, you should add ssl_options to your connection parameters like this
import ssl
logging.basicConfig(level=logging.DEBUG)
credentials = pika.PlainCredentials('*******', '**********')
context = ssl.SSLContext(ssl.PROTOCOL_TLSv1_2)
parameters = pika.ConnectionParameters(host='a-25c34e4d-a3eb-32de-abfg-l95d931afc72f.mq.us-west-1.amazonaws.com',
port=5671,
virtual_host='/',
credentials=credentials,
ssl_options=pika.SSLOptions(context)
)
connection = pika.BlockingConnection(parameters)
I want to build a python client to talk to my python Google Cloud Endpoints API. My simple HelloWorld example is suffering from an HTTPException in the python client and I can't figure out why.
I've setup simple examples as suggested in this extremely helpful thread. The GAE Endpoints API is running on localhost:8080 with no problems - I can successfully access it in the API Explorer. Before I added the offending service = build() line, my simple client ran fine on localhost:8080.
When trying to get the client to talk to the endpoints API, I get the following error:
File "/Applications/GoogleAppEngineLauncher.app/Contents/Resources/GoogleAppEngine-default.bundle/Contents/Resources/google_appengine/google/appengine/dist27/gae_override/httplib.py", line 526, in getresponse
raise HTTPException(str(e))
HTTPException: Deadline exceeded while waiting for HTTP response from URL: http://localhost:8080/_ah/api/discovery/v1/apis/helloworldendpoints/v1/rest?userIp=%3A%3A1
I've tried extending the http deadline. Not only did that not help, but such a simple first call on localhost should not be exceeding a default 5s deadline. I've also tried accessing the discovery URL directly within a browser and that works fine, too.
Here is my simple code. First the client, main.py:
import webapp2
import os
import httplib2
from apiclient.discovery import build
http = httplib2.Http()
# HTTPException happens on the following line:
# Note that I am using http, not https
service = build("helloworldendpoints", "v1", http=http,
discoveryServiceUrl=("http://localhost:8080/_ah/api/discovery/v1/apis/{api}/{apiVersion}/rest"))
# result = service.resource().method([parameters]).execute()
class MainPage(webapp2.RequestHandler):
def get(self):
self.response.headers['Content-type'] = 'text/plain'
self.response.out.write("Hey, this is working!")
app = webapp2.WSGIApplication(
[('/', MainPage)],
debug=True)
Here's the Hello World endpoint, helloworld.py:
"""Hello World API implemented using Google Cloud Endpoints.
Contains declarations of endpoint, endpoint methods,
as well as the ProtoRPC message class and container required
for endpoint method definition.
"""
import endpoints
from protorpc import messages
from protorpc import message_types
from protorpc import remote
# If the request contains path or querystring arguments,
# you cannot use a simple Message class.
# Instead, you must use a ResourceContainer class
REQUEST_CONTAINER = endpoints.ResourceContainer(
message_types.VoidMessage,
name=messages.StringField(1),
)
package = 'Hello'
class Hello(messages.Message):
"""String that stores a message."""
greeting = messages.StringField(1)
#endpoints.api(name='helloworldendpoints', version='v1')
class HelloWorldApi(remote.Service):
"""Helloworld API v1."""
#endpoints.method(message_types.VoidMessage, Hello,
path = "sayHello", http_method='GET', name = "sayHello")
def say_hello(self, request):
return Hello(greeting="Hello World")
#endpoints.method(REQUEST_CONTAINER, Hello,
path = "sayHelloByName", http_method='GET', name = "sayHelloByName")
def say_hello_by_name(self, request):
greet = "Hello {}".format(request.name)
return Hello(greeting=greet)
api = endpoints.api_server([HelloWorldApi])
Finally, here is my app.yaml file:
application: <<my web client id removed for stack overflow>>
version: 1
runtime: python27
api_version: 1
threadsafe: yes
handlers:
- url: /_ah/spi/.*
script: helloworld.api
secure: always
# catchall - must come last!
- url: /.*
script: main.app
secure: always
libraries:
- name: endpoints
version: latest
- name: webapp2
version: latest
Why am I getting an HTTP Deadline Exceeded and how to I fix it?
On your main.py you forgot to add some variables to your discovery service url string, or you just copied the code here without it. By the looks of it you were probably suppose to use the format string method.
"http://localhost:8080/_ah/api/discovery/v1/apis/{api}/{apiVersion}/rest".format(api='helloworldendpoints', apiVersion="v1")
By looking at the logs you'll probably see something like this:
INFO 2015-11-19 18:44:51,562 module.py:794] default: "GET /HTTP/1.1" 500 -
INFO 2015-11-19 18:44:51,595 module.py:794] default: "POST /_ah/spi/BackendService.getApiConfigs HTTP/1.1" 200 3109
INFO 2015-11-19 18:44:52,110 module.py:794] default: "GET /_ah/api/discovery/v1/apis/helloworldendpoints/v1/rest?userIp=127.0.0.1 HTTP/1.1" 200 3719
It's timing out first and then "working".
Move the service discovery request inside the request handler:
class MainPage(webapp2.RequestHandler):
def get(self):
service = build("helloworldendpoints", "v1",
http=http,
discoveryServiceUrl=("http://localhost:8080/_ah/api/discovery/v1/apis/{api}/{apiVersion}/rest")
.format(api='helloworldendpoints', apiVersion='v1'))
I'm trying to access a web service that uses a self-generated certificate using pysimplesoap and python 2.7.9
from pysimplesoap.client import SoapClient
import base64
username = 'webuser'
password = 'webpassword'
base64string = base64.encodestring('%s:%s' % (username, password)).replace('\n', '')
# real address / login removed
client = SoapClient(wsdl='https://url:port/webservice.asmx?WSDL',
http_headers={'Authorization': 'Basic %s'%base64string}, sessions=True,
cacert=None)
response = client.StatusInfo(... removed ...)
print(response)
Trying this throws the error message
urllib2.URLError: <urlopen error [SSL: CERTIFICATE_VERIFY_FAILED] certificate verify failed (_ssl.c:581)>
There are tips on how to bypass the problem by fixing urllib2, but is there a simpler way that allows me to tell pysimplesoap to ignore all SSL certificate client side errors. I'm using Windows7 and plan to port the code to a Raspian/Debian Linux, so a solution should not depend on the operating system.
Answering my own question here,
adding the 1st & 3rd line will ignore certification verification
import ssl
from pysimplesoap.client import SoapClient
ssl._create_default_https_context = ssl._create_unverified_context
There's a longer discussion about this here where you can learn why this is not a good idea...
Hi i need help to get info from web service on secure site with pfx certificate with password.
i tried more then one example..
code example:
import requests
wsdl_url = 'blabla'
requests.get(wsdl_url, cert='cert.pfx', verify=True)
other example:
import urllib3
import certifi
wsdl_url = 'blabla'
http = urllib3.PoolManager(
cert_reqs='CERT_REQUIRED', # Force certificate check.
ca_certs=certifi.where() # Path to the Certifi bundle.
)
certifi.where()
# You're ready to make verified HTTPS requests.
try:
r = http.request('GET', wsdl_url)
print r
except urllib3.exceptions.SSLError as e:
print "wrong"
# Handle incorrect certificate error.
Error type:
connection aborted
an existing connection was forcibly closed by the remote host
help please
I am facing a bit of a situation,
Scenario: I got a django rest api running on my localhost:8000 and I want to access the api using my command line. I have tried urllib2 and python requests libs to talk to the api but failed(i'm getting a 503 error). But when I pass google.com as the url, I am getting the expected response. So I believe my approach is correct but I'm doing something wrong. please see the code below :
import urllib, urllib2, httplib
url = 'http://localhost:8000'
httplib.HTTPConnection.debuglevel = 1
print "urllib"
data = urllib.urlopen(url);
print "urllib2"
request = urllib2.Request(url)
opener = urllib2.build_opener()
feeddata = opener.open(request).read()
print "End\n"
Envioroments:
OS Win7
python v2.7.5
Django==1.6
Markdown==2.3.1
colorconsole==0.6
django-filter==0.7
django-ping==0.2.0
djangorestframework==2.3.10
httplib2==0.8
ipython==1.0.0
jenkinsapi==0.2.14
names==0.3.0
phonenumbers==5.8b1
requests==2.1.0
simplejson==3.3.1
termcolor==1.1.0
virtualenv==1.10.1
Thanks
I had a similar problem, but found that it was the company's proxy that was preventing from pinging myself.
503 Reponse when trying to use python request on local website
Try:
>>> import requests
>>> session = requests.Session()
>>> session.trust_env = False
>>> r = session.get("http://localhost:5000/")
>>> r
<Response [200]>
>>> r.content
'Hello World!'
If you are registering your serializers with DefaultRouter then your api will appear at
http://localhost:8000/api/ for an html view of the index
http://localhost:8000/api/.json for a JSON view of the index
http://localhost:8000/api/appname for an html view of the individual resource
http://localhost:8000/api/appname/.json for a JSON view of the individual resource
you can check the response in your browser to make sure your URL is working as you expect.