Wrapping an operator[ ] of a private container in derived class - c++

Question

I am trying to implement a wrapping function named: Shape& move_up(int index), that will access and modify1 elements of vector<T*> v, in the derived class, named: class Group.
I am trying to do that by wrapping the T& operator[](int i) { return *v[i]; } of the base class:
Group.h:
// class Group is a container of Shapes
class Group: public Graph_lib::Vector_ref<Shape>{
public:
// constructors
Group::Group()
: upperLeft(0, 0), gridSideX(50), gridSideY(50), gridRowNumber(5), gridColumnNumber(5)
{
// create grid
for (size_t i = 0; i <= gridRowNumber; ++i){
for (size_t j = 0; j <= gridColumnNumber; ++j){
Graph_lib::Rectangle* rec = new Graph_lib::Rectangle(Point(upperLeft.x + gridSideX * j, upperLeft.y + gridSideY * i), gridSideX, gridSideY);
rec->set_fill_color(((i + j) % 2 == 0) ? Color::black : Color::white);
push_back(rec);
}
}
}
Shape& move_up(int i) { return operator[](i).move(0, 70); }
private:
Point upperLeft;
int gridSideX;
int gridSideY;
int gridRowNumber;
int gridColumnNumber;
};
main.cpp
#include <iostream>
#include <vector>
#include "Graph.h"
#include "Simple_window.h"
#include "Group.h"
int main(){
// define a window
Point tl(x_max()/2,0);
int width = 700;
int height = 700;
string label = "class Group";
Simple_window sw(tl, width, height, label);
// instantiate a class Group object
Group gr();
for (size_t i = 0; i < gr.size(); ++i) sw.attach(gr[i]);
sw.wait_for_button();
}
Currently the wrapping function is getting underlined in red, when hover above it displays the following message:
Error: initial value to reference to non-const must be an lvalue
The problem is that I can't find a right way of accessing and modifying the elements in the vector of the base class, thus the following question:
What am I doing wrong? How to correctly implement the Shape& move_up(int index); function?
1. Apply the function move(); that changes the coordinates of a Shape element of the vector.
2. All the additional files for compilation could be found: here and here.

Answer 1

Your function move() returns void:
virtual void move(int dx, int dy);
What do you expect then when you try to have your move_up() return the result of move():
return <something>.move(0, 70);
especially that you previously told the compiler that move_up() shall returns Shape&?

Answer 2

The function move_up() has to:
modify Shape's coordinate
return Shape& such that it could be attache()d to the window object, and its new location displayed on the screen.
To do that it just needs to be separated into two lines, where the first line modifies the Shape object and the second line returns it by reference:
Shape& move_up(int i) {
operator[](i).move(0, 70);
return operator[](i);
}
or as suggested by molbdnilo:
Shape& move_up(int i) {
auto& el = (*this)[i];
el.move(0, 70);
return el;
}