I have a route with urls that can have an optional extra field. It can be either of the form :
"/my-route/azezaezaeazeaze.123x456.jpg"
"/my-route/azezaezaeazeaze.123x456.6786786786.jpg"
with :
"azezaezaeazeaze" being a mongoId
123x456 two integers separated by "x"
6786786786 a unix timestamp
jpg an image extension (could be jpeg, png, gif...)
all those are separated by a "."
I would like to remove the optional part (the timestamp) from the request with the http rewrite module. So that the second url effectively becomes lie the first.
I made a small test on regex101 to get the groups, but :
- it doesn't seem to be the right syntax for nginx
- I do not see how it will allow me to remove the timestamp
How can I remove the timestamp from that url?
Starting from the right-hand end, you need to match a dot followed by anything
except a dot, so we have (\.[^.]*)$, then moving to the left, we want
to match a dot followed by only digits \.[0-9]*, which we dont want to
capture, and then to the left of that we want everything.
I ended up with something like this:
rewrite ^(.*)\.[0-9]*(\.[^.]*)$ $1$2 ;
Capitalizing on my first attempt and #meuh answer, I ended up with the following :
rewrite ^(/.*\..*)(\..*)(\..*)$ $1$3 last;
Now it works, but I would welcome any comment regarding the style/efficiency of this rewrite.
Related
In my case, i want to validate for url image, some url is valid but result is wrong.
Eg: link image is "https://fuvitech.online/wpcontent/uploads/2021/02/bta16600brg.jpg" or "https://fuvitech.online/wp-content/uploads/2021/02/bta16-600brg.jpg" reponse "The image link is not in the correct format".
My code here:
RuleFor(product => product.Images)
.Length(1, 3000).WithMessage(Labels.importProduct_ExceedDescription, p => ImportHelpers.GetColumnName(typeof(ProductEntity).GetProperty(nameof(p.Images))))
.Matches(#"^(http:\/\/|https:\/\/){1}?[a-z0-9]+([\-\.]{1}[a-z0-9]+)*\.[a-z]{2,5}(:[0-9]{1,5})?(\/.*)?$").WithMessage(Labels.importProduct_UrlNotCorrect, p => ImportHelpers.GetColumnName(typeof(ProductEntity).GetProperty(nameof(p.Images))));
Please help me where the above regex is wrong. Thank you.
Try this:
NOTE the following regex pattern may trigger false positives and also may ignore valid image URLs, because it is very difficult to validate whether a given URL is valid.
^https?:\/\/(?:(?:[A-Za-z0-9]+(?:-[A-Za-z0-9]+)+|[A-Za-z0-9]{2,})\.)+[A-Za-z]{2,}(?::\d+)?\/(?:(?:[A-Za-z0-9]+(?:(?:-[A-Za-z0-9]+)+)?\/)+|)[\w-]+\.(?:jpg|jpeg|png)$
Explanation
^ the start of a line/string.
https?:\/\/ match http with an optional letter s, followed by ://.
(?:(?:[A-Za-z0-9]+(?:-[A-Za-z0-9]+)+|[A-Za-z0-9]{2,})\.)+ This will match things like foo-foo.bar-bar., foo.bar-bar. and foo.
[A-Za-z]{2,} this will match the TLD part, e.g., com, org, this part with the previous part will match things like foo-foo.bar-bar.com, foo.bar-bar.com or foo.com.
(?::\d+)? optional group of (a colon : followed by one or more digits) for port part.
\/(?:(?:[A-Za-z0-9]+(?:(?:-[A-Za-z0-9]+)+)?\/)+|) this check for two things, the first one is /uploads/public-images/, /uploads/images/, the second one is a single /.
[\w-]+ this part for the file name, e.g., bta16-600brg.
\.(?:jpg|jpeg|png) you can add here multiple extensions, you can allow uppercase letters by using for example, [Jj][Pp][Gg] for jpg.
$ the end of the line/string.
See regex demo
Thanks #SaSkY answer my question.
I found my mistake.
This source [.[a-z]{2,5}] only allows domain extensions from 2-5 characters. Example [.com] is valid. But in my case [.online] was not valid.
I changed to [.[a-z]{1,10}].
Im currently trying to redirect from and old website to the new one.
The domain has changed and the subpath has changed, but the end is always the same, so I am trying to create a regex that will ignore the subpath, and only match with the ending, no matter what the combination might be.
Example:
http://shop.kmsport.dk/team-sport/bolde/fodbolde
https://kmsport.dk/collections/fodbolde
http://shop.kmsport.dk/fodbolde/fodbold-udstryr/anforerbind-325
These 3 urls all contain the word "fodbolde" but I only wanna match up the first two, since they both end on "/fodbolde", and ignoring the subpath in the process.
So far I've been able to match up the ends with this:
\/([a-zA-Z]*)*+$
How do I create something to account for the different subpaths?
P.s Its a massive sporting good store, so would be nice not having to creating a unique redirect for every possible combination -.-
If you are only interested in the last part just go with
url.rsplit('/', 1)[-1]
You current regex is not taking /fodbolde into account. If that has to be at the end you could use $ to assert the end of the string like /fodbolde$
One possibility could be to match the start of the string ^https?:// and optionally match shop. (?:shop\.)? followed by kmsport\.sk/
Then use a repeating pattern matching not a forward slash followed by a forward slash zero or more times (?:[^/]+/)* and at the end of the string match fodbolde fodbolde$
^https?://(?:shop\.)?kmsport\.dk/(?:[^/]+/)*fodbolde$
I have two URLs with the patterns:
1.http://localhost:9001/f/
2.http://localhost:9001/flight/
I have a site filter which redirects to the respective sites if the regex matches. I tried the following regex patterns for the 2 URLs above:
http?://localhost[^/]/f[^flight]/.*
http?://localhost[^/]/flight/.*
Both URLS are getting redirected to the first site, as both URLs are matched by the first regex.
I have tried http?://localhost[^/]/[f]/.* also for the 1st url. I am Unable to get what am i missing . I feel that this regex should not accept any thing other than "f", but it is allowing "flight" as well.
Please help me by pointing the mistake i have done.
Keep things simple:
.*/f(/[^/]*)?$
vs
.*/flight(/[^/]*)?$
Adding ? before $ makes the trailing slash with optional path term optional.
The first one will be caught with following regex;
/^http:[\/]{2}localhost:9001\/f[^light]$/
The other one will be disallowed and can be found with following regex
/^http:[\/]{2}localhost:9001\/flight\/$/
You regex has several issues: 1) p? means optional p (htt:// will match), 2) [^/] will only match : in your URLs since it will only capture 1 character (and you have a port number), 3) [^light] is a negated character class that means any character that is not l, i, g, h, or t.
So, if you want to only capture localhost URLs, you'd better use this regex for the 1st site:
http://localhost[^/]*/f/.*
And this one for the second
http://localhost[^/]*/flight/.*
Please also bear in mind that depending on where you use the regexps, your actual input may or may not include either the protocol.
These should work for you:
http[s]{0,1}:\/\/localhost:[0-9]{4}\/f\/
http[s]{0,1}:\/\/localhost:[0-9]{4}\/flight\/
You can see it working here
I've got a large database of projects and issue trackers, some of which have urls.
I'd like to query it to figure out a list of urls for each project, but many have extra data I'd like to avoid.
I'd like to do something like this:
substring(tracker_extra_field_data.field_data FROM 'http://([^/]*).*')
Except some urls are https, and I'd like to capture that as well as the first sub directory.
For example, given the url:
https://dev.foo.com/bar/action/?param=val
I'd like the select to return:
https://dev.foo.com/bar/
Is there a semi-simple way to do this with substring/regex in pgsql?
try this:
select substring('https://dev.foo.com/bar/action/?param=val' from '(https?://([^/]*/){1,2})');
template1=# select substring('https://dev.foo.com/bar/action/?param=val' from '(https?://([^/]*/){1,2})');
substring
-------------------------
https://dev.foo.com/bar/
(1 row)
template1=# select substring('http://dev.foo.com/bar/action/?param=val' from '(https?://([^/]*/){1,2})');
substring
------------------------
http://dev.foo.com/bar/
Updated after I didn't read the Q properly at first.
Use the pattern
^https?://[^/]+(?:/[^/]+)?/?
^ .. start of string
? .. zero or one atoms
(?:) .. non-capturing parens
[^/]+ .. any character except /, 1 or more of them
This only accepts URLs starting with http:// or https:// (protocol header required).
->SQLfiddle with a bigger test case.
I'm basically not in the clue about regex but I need a regex statement that will recognise anything after the / in a URL.
Basically, i'm developing a site for someone and a page's URL (Local URL of Course) is say (http://)localhost/sweettemptations/available-sweets. This page is filled with custom post types (It's a WordPress site) which have the URL of (http://)localhost/sweettemptations/sweets/sweet-name.
What I want to do is redirect the URL (http://)localhost/sweettemptations/sweets back to (http://)localhost/sweettemptations/available-sweets which is easy to do, but I also need to redirect any type of sweet back to (http://)localhost/sweettemptations/available-sweets. So say I need to redirect (http://)localhost/sweettemptations/sweets/* back to (http://)localhost/sweettemptations/available-sweets.
If anyone could help by telling me how to write a proper regex statement to match everything after sweets/ in the URL, it would be hugely appreciated.
To do what you ask you need to use groups. In regular expression groups allow you to isolate parts of the whole match.
for example:
input string of: aaaaaaaabbbbcccc
regex: a*(b*)
The parenthesis mark a group in this case it will be group 1 since it is the first in the pattern.
Note: group 0 is implicit and is the complete match.
So the matches in my above case will be:
group 0: aaaaaaaabbbb
group 1: bbbb
In order to achieve what you want with the sweets pattern above, you just need to put a group around the end.
possible solution: /sweets/(.*)
the more precise you are with the pattern before the group the less likely you will have a possible false positive.
If what you really want is to match anything after the last / you can take another approach:
possible other solution: /([^/]*)
The pattern above will find a / with a string of characters that are NOT another / and keep it in group 1. Issue here is that you could match things that do not have sweets in the URL.
Note if you do not mind the / at the beginning then just remove the ( and ) and you do not have to worry about groups.
I like to use http://regexpal.com/ to test my regex.. It will mark in different colors the different matches.
Hope this helps.
I may have misunderstood you requirement in my original post.
if you just want to change any string that matches
(http://)localhost/sweettemptations/sweets/*
into the other one you provided (without adding the part match by your * at the end) I would use a regular expression to match the pattern in the URL but them just blind replace the whole string with the desired one:
(http://)localhost/sweettemptations/available-sweets
So if you want the URL:
http://localhost/sweettemptations/sweets/somethingmore.html
to turn into:
http://localhost/sweettemptations/available-sweets
and not into:
localhost/sweettemptations/available-sweets/somethingmore.html
Then the solution is simpler, no groups required :).
when doing this I would make sure you do not match the "localhost" part. Also I am assuming the (http://) really means an optional http:// in front as (http://) is not a valid protocol prefix.
so if that is what you want then this should match the pattern:
(http://)?[^/]+/sweettemptations/sweets/.*
This regular expression will match the http:// part optionally with a host (be it localhost, an IP or the host name). You could omit the .* at the end if you want.
If that pattern matches just replace the whole URL with the one you want to redirect to.
use this regular expression (?<=://).+