Sorting through array of pointers - c++

Question

When I try to display the test scores in the function sortArray, I can only access the memory address. How to I access the values of the scores?? Also is the sortArray function correct overall?
#include <iostream>
using namespace std;
void sortArray(int *[], int);
int main()
{
int *testScores = nullptr;
//dynamically allocate an array
int scoreNUMS;
int score;
cout << "Please enter the total number of test scores" << endl;
cin >> scoreNUMS;
testScores = new int[scoreNUMS];
//dynamically allocates an array large enough to hold scoreNUMS
for(int i = 1; i <= scoreNUMS; i++)
{
cout << "Enter student " << i << "'s test score" << endl;
cin >> score;
if (score <= -1)
{
cout << "Please enter positive numbers only!" << endl;
}
*(testScores + i) = score;
//puts the input score in the array
}
sortArray(&testScores, scoreNUMS);
return 0;
}
Im not sure if the function below is correct because I was unaware where to place the * and the &
void sortArray(int *array[], int size)
{
bool swap;
int temp;
do
{
swap = false;
for(int count = 0;count < (size - 1); count++)
{
if(array[count] > array[count + 1])
{
temp = *array[count];
array[count] = array[count + 1];
array[count + 1] = &temp;
swap = true;
}
}
}while(swap);
for(int i = 0; i < size; i++)
cout << *(array + 1) << endl;
}

Answer 1

Error: Array consist scoreNUMS elements, the first one is testScores[0] - first index is zero. And last index is scoreNUMS-1
You must write
for(int i = 0; i < scoreNUMS; i++)
PS: You can use next prototype:
void sortArray(int [], int);
UPD: passing an array to a function is performed by passing a pointer to the first element of the array. (Your array does not copied when you pass it to function)
And run function by this way: sortArray(testScores, scoreNUMS);