Django: If equals count - django

I have multiple ListViews for a specific model. I have a page that should show the number of results per ListView and link to that ListView.
How do I count the number of items in that View?
dashboard.html
{% if status == 'Open' %}
{{ jobs.count }}
{% endif %}
dashboard view:
Dashboard(ListView):
model = Job
Open View:
class JobOpenList(ListView):
def get_queryset(self):
return Job.objects.filter(status='Open')
Closed View:
class JobClosedList(ListView):
def get_queryset(self):
return Job.objects.filter(status='Closed')

This is not the way to think about things. You can't ask for the number of things in a completely separate view. Instead, you need to calculate them in the view you are currently using.
You can use aggregation to count the number of items in each state:
Job.objects.values('state').annotate(count=Count('state'))

Related

Next and previous buttons for a queryset in a DetailView

I'm new to Django, and I'm working on my first real (i.e., non-tutorial) project. I have class-based ListViews on four models, and the lists can be filtered in various ways. The user can click on anything in a filtered list to get a DetailView of the item. This is all straightforward and works fine.
I would like to have Previous and Next buttons on the detail pages that allow the user to step through the current filtered set in the default order (which is not date or id). I've found various bits and pieces on StackOverflow and elsewhere that look like parts of a solution, but I haven't been able to figure out how to make them all work together in my views.
Here is slightly simplified code for one of my tables. "Works" are various items (plays, operas, ballets, etc.) that were performed in one of two theaters.
models.py
class Work(models.Model):
title = models.CharField(max_length=100)
sort_title = models.CharField(max_length=100)
genre = models.CharField(max_length=50)
class Meta:
ordering = ['sort_title']
The field sort_title strips off articles at the beginnings of titles (which are in German and French) and deals with accented characters and the like, so that the titles will sort correctly alphabetically. This is the order of the filtered sets, and I want to retain that order for the Previous and Next buttons.
views.py
class WorkList(ListView):
context_object_name = 'works'
model = Work
paginate_by = 50
template_name = 'works.html'
def get_queryset(self):
query = self.request.GET.get('q')
if query is not None:
return Work.objects.filter(Q(title__icontains=query))
else:
return Work.objects.all()
class WorkDetail(DetailView):
context_object_name = 'work'
model = Work
template_name = 'work.html'
At the moment, the user can only filter Works by title, but I may add the possibility of filtering by genre (hence the Q, which I'm already using for other views). I'm using Bootstrap 4, and I would use some version of the following for the buttons on the detail pages:
<ul class="pagination pt-3">
<li class="page-link">Previous</li>
<li class="page-link ml-auto">Next</li>
</ul>
But since I don't know how to make this work yet, I don't know what the URLs will be.
I've tried django-next-previous, which works well in the shell, but I can't figure out how to make it work in my views. Since I want to preserve the filtered queryset from the ListView and use it in the DetailView, I've also experimented with this approach to saving the queryset in the session: https://gist.github.com/bsnux/4672788. But I haven't been able to figure out how to use this to pass the queryset between the two views.
Any help would be welcome!
The queries
Previous page:
Work.objects.filter(sort_title__lt=self.object.sort_title).reverse().values('id')[:1]
Next page:
Work.objects.filter(sort_title__gt=self.object.sort_title).values('id')[:1]
Next page if sort_title is not unique - note the gte rather than gt:
Work.objects.filter(sort_title__gte=self.object.sort_title).exclude(id=self.object.id).values('id')[:1]
Explanation
filter(...): The Work object is ordered by the sort_title field by default. So by asking for a sort_title that is greater than the sort_title of the current object, so we will find the next Work object in the set.
self.object is how we access the current object from a DetailView.
values('id'): Only select the values we need to reverse() the URL to a different WorkDetail. I'm making a presumption that this is the id field, but if it's not, it can be substituted with another field.
[:1]: Basically just adds LIMIT 1 to the SQL query. We only need the next in the set.
This all keeps the queries lightweight.
Note that these queries only work (using __lt with reverse() for previous page and __gt for next page) because the default ordering of the Work model is by sort_title ascending.
Putting it together
Given that your ListView and DetailView will be sharing the same queryset logic, it might make sense to use a mixin, for example:
class WorkQueryMixin:
def get_queryset(self):
query = self.request.GET.get('q')
if query is not None:
return Work.objects.filter(Q(title__icontains=query))
else:
return Work.objects.all()
The query parameter could be returned in a different way (e.g. through the session data).
Getting it into context, for example for the next page:
class WorkDetail(WorkQueryMixin, DetailView):
context_object_name = 'work'
model = Work
template_name = 'work.html'
def get_context_data(self, **kwargs):
context = super().get_context_data(**kwargs)
next_id = (
self.get_queryset()
.filter(sort_title__gt=self.object.sort_title)
.values('id')[:1]
)
# There may be no next page
if next_id:
context['next_id'] = next_id[0]['id']
return context
Many thanks to elyas for the great detailed initial answer and for taking the time to coach me through the details of the implementation. I now have functional Previous and Next buttons that retain the current queryset. Here is the code I ended up with, including both Previous and Next buttons, with a genre filter added:
views.py
class WorkQueryMixin:
def get_queryset(self):
query = self.request.GET.get('q')
if query is not None:
return Work.objects.filter(Q(title__icontains=query) |
Q(genre__icontains=query))
else:
return Work.objects.all()
class WorkList(WorkQueryMixin, ListView):
context_object_name = 'works'
model = Work
paginate_by = 50
template_name = 'my_app/works.html'
class WorkDetail(WorkQueryMixin, DetailView):
context_object_name = 'work'
model = Work
template_name = 'my_app/work.html'
def get_context_data(self, **kwargs):
context = super().get_context_data(**kwargs)
prev_pk = (
self.get_queryset()
.filter(sort_title__lt=self.object.sort_title)
.reverse().values('pk')[:1]
)
# There may be no next page
if prev_pk:
context['prev_pk'] = prev_pk[0]['pk']
next_pk = (
self.get_queryset()
.filter(sort_title__gt=self.object.sort_title)
.values('pk').values('pk')[:1]
)
# There may be no next page
if next_pk:
context['next_pk'] = next_pk[0]['pk']
return context
In the template for the Works list view, using classes from Bootstrap 4:
<ul>
{% for work in works %}
<a href="{% url 'my_app:work' work.pk %}?{{
request.GET.urlencode }}" class="list-group-item list-group-
item-action">
{% if work.title == "No title" %}
{{work.title}}
{% else %}
<em>{{work.title}}</em>
{% endif %} ({{work.genre}})
</a>
{% empty %}
<p>No works match this search</p>
{% endfor %}
</ul>
And in the template for the Work detail view:
<ul class="pagination pt-3">
{% if prev_pk %}
<li class="page-link"><a href="{% url 'my_app:work' prev_pk %}?{{
request.GET.urlencode }}">Previous</a></li>
{% endif %}
{% if next_pk %}
<li class="page-link ml-auto"><a href="{% url 'my_app:work' next_pk
%}?{{ request.GET.urlencode }}">Next</a></li>
{% endif %}
</ul>

How to Pull info from another model within a DetailsView template (without ForeignKey)?

I am trying to pull data from two models within a DetailsView template (in Django). There is of course a primary model (eg. Articles) associated with the view, which is easy to access. However, I want to access data from a model (eg. Terms). I do not want to use ForeignKey because I will be using many 'Terms' in each 'Article,' and since ForeignKey will allow me to link to only row in the Terms model, I will have to set-up mutiple ForeignKey fields, which can get messy fast.
I was thinking that this could be accomplished using get_context_data or templatetags, but haven't have had any luck yet. Any thoughts?
From Django Documentation you can add any queryset or context value you like to call in your template context like book_list below will list all books and it doesn't has to be linked with any other models..
#views.py
class PublisherDetail(DetailView):
model = Publisher
def get_context_data(self, **kwargs):
# Call the base implementation first to get a context
context = super(PublisherDetail, self).get_context_data(**kwargs)
# Add in a QuerySet of all the books
context['book_list'] = Book.objects.all()
return context
#yourtemplate.html
{% for book in book_list %}
{% if book %}
{{ book.title }}
{% endif %}
{% empty %}
No book_list found.
{% endfor %}

Django: Changing a model after passing it in context

I am changing a list of field's values upon viewing, but I want to pass the unchanged values to the context. The case here is of a primitive notification system where upon viewing the notification, it should change its status to viewed.
views.py
class Notification(TemplateView):
template_name='myapp/notification.html'
def get_context_data(self, **kwargs):
user = self.request.user
user_unread = user.notification_set.filter(viewed=False)
user_read = user.notification_set.filter(viewed=True)
context = super(Notification, self).get_context_data(**kwargs)
context.update({'user_unread': user_unread, 'user_read': user_read})
for msg in user_unread:
msg.viewed = True
msg.save()
return context
The Problem with this code however, is that I am getting duplicated values in the read and unread lists, even though I have saved the new values to the model after updating the context that is passed to the template.
template:
Unread:
<ul>
{% for msg in user_unread %}
<li> {{ msg }} </li>
{% endfor %}
</ul>
Already read:
<ul>
{% for msg in user_read %}
<li> {{ msg }} </li>
{% endfor %}
</ul>
On a sidenote, I am new to CBVs and if there if my view code above could be improved I'd love some pointers.
This is due to the lazy nature of querysets. A queryset does not actually touch the database until you evaluate it, which usually occurs when you iterate. So in your code, you iterate through user_unread in the view, to set the read status: so the contents of the queryset are fixed at that point. But you don't iterate through user_read until you reach the template, so the query is not made until then, after you have updated all the unread notifications.
The way to fix this is to explicitly evaluate the read queryset in the view, before you update the unread ones. You can do this by simply calling list on it:
context.update({'user_unread': user_unread, 'user_read': list(user_read)})
for msg in user_unread:
...
You can try getting another duplicate query set to update the objects. Use non-updated for template context and update only another one.
Like:
def get_context_data(self, **kwargs):
user = self.request.user
user_unread = user.notification_set.filter(viewed=False)
#Do some operation on qs so that it gets evaluated, like
nitems = len(user_unread)
#get another queryset to update
user_unread_toupdate = user.notification_set.filter(viewed=False)
user_read = user.notification_set.filter(viewed=True)
context = super(Notification, self).get_context_data(**kwargs)
context.update({'user_unread': user_unread, 'user_read': user_read})
#Use 2nd queryset
for msg in user_unread_toupdate:
msg.viewed = True
msg.save()
return context
Django would cache for each queryset differently. So once evaluated user_unread will have its own copy of objects.
Although, its not very elegant/efficient as multiple copies of similar queryset are loaded, so if number of records high, it will be slower.

Django ListView: taking a time difference in all items

I'm rather new to Class Based Views, so this is probably obvious, but any tips are appreciated. I want to display "time left" for each item on a list. That is if I have 10 objects, each should display in the template the number of days, hours, mn left until a deadline arrives. Here's my attempt:
model.py
class Law(models.Model):
deadline = models.DateTimeField(_(u'The Deadline'),)
name = ..
more_stuff = ..
views.py
class LawList(ListView):
model = Law
context_object_name = 'law'
template_name = 'template.html'
template.html
{% for l in law %}
<h3>{{ l.deadline }} - {{l.name }} </h3>
{{l.more_stuff}}
{% endfor %}
all good up to here. However I would like to have {{l.time-left}} instead of {{l.deadline}}. Is there a way for the view to calculate this and pass it to the template?
I thought of adding a get_context_data to the 'LawList' view, but I don't know how to do so for every item in my list. Below is what works for a single item.
# views.py, below the section above
def get_context_data(self, **kwargs):
context = super(LawList, self).get_context_data(**kwargs)
context['time_left'] = Law.objects.all()[0].deadline - timezone.now()
but I'm a little stuck. Thanks!
have a look at the timeuntil template tag

loop in Django template: how to control the loop iterator?

I'm using Django to show a list of posts. Each post has a 'is_public' field, so if one post's 'is_public' equals to False, it should not be shown to the user. Also, I want to show a fixed number of posts in one page, but this number can be changing depending on views.
I decided to crop the queryset in template as a few views are using the same template, generating it in the view means a lot of repeated codes.
If written in python, it should look like this:
i=number_of_posts_to_show_in_one_page
while i:
if qs[i].is_public == True:
#show qs[i] to the page
i--
As the django template does not support while loop and for loop seems hard to control, is there a way of achieving this? Or should I do it in another way?(One idea is to crop the qs before looping)Thanks!
Update:
I've written this template tag to pre-process the queryset:
#register.simple_tag(takes_context=True)
def pre_process_list(context,list,numbers):
#if not user.has_perm('admin'):
context['result_list']=list.filter(is_public=True, is_removed=False)[0:numbers]
#else:
#context['result_list']=list[0:numbers]
return ''
Before using for loop in the template, I'll pass the queryset to this templage tag, and use a simple for loop to show its result.
If in the future I want to show non-public posts to admins(which is not decided yet), I can write in some logic like the commented ones, and have them styled differently in the template.
{% for post in posts %}
{% if post.is_public %}
{{ post }}
{% endif %}
{% endfor %}
Though this would be a perfect use case for a manager.
You could write a simple manager that filters public posts.
class PublicPostManager(models.Manager):
def get_query_set(self):
return super(PublicPostManager, self).get_query_set().filter(is_public=True)
Then you would add it to your Post Class:
class Post(models.Model):
...
public = PublicPostManager()
Then you could pass post.public.all() as public_posts to your template and simplify your loop:
{% for post in public_posts %}
{{ post }}
{% endfor %}
#arie has a good approach with the manager, but you can easily do the same without writing a manager:
# View
posts = Post.objects.filter(is_public=True) # or use the manager
# Now, you can either limit the number of posts you send
# posts = posts[:5] (only show five in the view)
return render_to_response('foo.html',{'posts':posts})
# Template
# Or you can do the limits in your template itself:
{% for post in posts|slice:":5" %}
{{ post }}
{% endfor %}
See the slice filter on more information.
However, since this is a common operation, with django 1.3 you can use class based views to automate most of this.