How to rename root and children element XSLT - xslt

Question

How do I rename root 'channel' and children 'item' to 'Records' and 'Record' respectively?
Input
<?xml version="1.0" encoding="utf-8"?>
<rss version="2.0" xmlns:atom="http://www.w3.org/2005/Atom">
<channel>
<item>
<title>A</title>
<link>/news/view/25857/A.html</link>
<guid isPermaLink="true">/news/view/25857/A.html</guid>
<comments>/news/25857/A.html</comments>
<pubDate>Sat, 03 Oct 2015 00:42:42 GMT</pubDate>
<description><![CDATA[]]></description>
<category>headline,hacker,bank,cybercrime,data loss,fraud</category>
</item>
</channel>
</rss>
XSLT
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes"/>
<xsl:template match="#* | node()">
<xsl:copy>
<xsl:apply-templates select="#* | node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="item/comments">
<taglink>
<xsl:text></xsl:text>
<xsl:value-of select="text()" />
</taglink>
</xsl:template>
<!--delimits values if separated by comma-->
<xsl:template match="item/category[contains(.,',')]">
<category>
<xsl:variable name="elementName" select="name(..)"/>
<xsl:call-template name="splitIntoElements">
<xsl:with-param name="baseName" select="name(..)" />
<xsl:with-param name="txt" select="." />
</xsl:call-template>
</category>
</xsl:template>
<xsl:template name="splitIntoElements">
<xsl:param name="baseName" />
<xsl:param name="txt" />
<xsl:param name="delimiter" select="','" />
<xsl:param name="index" select="1" />
<xsl:variable name="first" select="substring-before($txt, $delimiter)" />
<xsl:variable name="remaining" select="substring-after($txt, $delimiter)" />
<xsl:element name="value">
<xsl:choose>
<xsl:when test="$first">
<xsl:value-of select="$first" />
</xsl:when>
<xsl:otherwise>
<xsl:value-of select="$txt" />
</xsl:otherwise>
</xsl:choose>
</xsl:element>
<xsl:if test="$remaining">
<xsl:call-template name="splitIntoElements">
<xsl:with-param name="baseName" select="$baseName" />
<xsl:with-param name="txt" select="$remaining" />
<xsl:with-param name="index" select="$index" />
<xsl:with-param name="delimiter" select="$delimiter" />
</xsl:call-template>
</xsl:if>
</xsl:template>
</xsl:stylesheet>
Output
<?xml version="1.0" encoding="utf-8"?>
<rss xmlns:atom="http://www.w3.org/2005/Atom" version="2.0">
<channel>
<item>
<title>A</title>
<link>/news/view/25857/A.html</link>
<guid isPermaLink="true">/news/view/25857/A.html</guid>
<taglink>/news/25857/A.html</taglink>
<pubDate>Sat, 03 Oct 2015 00:42:42 GMT</pubDate>
<description/>
<category>
<value>headline</value>
<value>hacker</value>
<value>bank</value>
<value>cybercrime</value>
<value>data loss</value>
<value>fraud</value>
</category>
</item>
</channel>
</rss>
Expected Output - There are many 'item' within 'channel' so there is expected be have many 'records' within 'record'
<?xml version="1.0" encoding="utf-8"?>
<rss xmlns:atom="http://www.w3.org/2005/Atom" version="2.0">
<Records>
<Record>
<title>A</title>
<link>/news/view/25857/A.html</link>
<guid isPermaLink="true">/news/view/25857/A.html</guid>
<taglink>/news/25857/A.html</taglink>
<pubDate>Sat, 03 Oct 2015 00:42:42 GMT</pubDate>
<description/>
<category>
<value>headline</value>
<value>hacker</value>
<value>bank</value>
<value>cybercrime</value>
<value>data loss</value>
<value>fraud</value>
</category>
</Record>
</Records>
</rss>

Answer 1

You can simply add a couple of templates that match element to be renamed, and spit out the new element name, for example :
<xsl:template match="channel">
<Records>
<xsl:apply-templates/>
</Records>
</xsl:template>
<xsl:template match="item">
<Record>
<xsl:apply-templates/>
</Record>
</xsl:template>