I am atempting to post a new url to a service on ESRI (I own it) with a post using Requests. After printing the line post_url the JSON is updated as I want it however when I post it nothing happens despite getting a 200 status. Is the issue with the post or the find / replace?
json_url = "https://www.arcgis.com/sharing/rest/content/items/serviceID?&token=XXX"
update_url = "https://www.arcgis.com/sharing/rest/content/users/USERNAME/folder/items/ServiceNumber/update?"
get_json = requests.get(json_url)
load_json = str(get_json.json())
find = "findme"
replace = "replace"
post_url = load_json.replace(replace, find)
a = requests.post(update_url, data={"url": post_url, "token": "XXXX", "f":"json"})
print a.status_code
The issue is with the post
I changed the post to this:
requests.request("POST", update_url, data={"url": post_url, "token": token, "f":"json"})
update_url needs to be the API update endpoint:
https://www.arcgis.com/sharing/rest/content/users/USERNAME/FOLDER/items/Endpoint /update?"
post_url needs to be: "whatever you want" in my case It was a search and replace variable of the the existing URL in the JSON and update, because of a server migration.
Related
I am trying to get data about a song playing on one of my devices from the spotify API. I have created a view that fetches data from the API and part of it looks like this:
class Song(viewsets.ModelViewSets):
....
room_code = request.data['room_code']
room = Room.objects.filter(code=room_code)[0]
host = room.host
endpoint = 'player/currently-playing'
response = execute_spotify_api_request(host, endpoint)
item = response.get('item')
duration = item.get('duration_ms')
progress = response.get('progress_ms')
album_cover = item.get('album').get('images')[0].get('url')
return Response(response, status=status.HTTP_200_OK)
The execute_spotify_api_request(host, endpoint) is a utility function and it looks like this:
def execute_spotify_api_request(session_id, endpoint, post_=False, put_=False):
tokens = get_user_tokens(session_id)
headers = {'Content-Type': 'application/json',
'Authorization': "Bearer " + tokens.access_token}
if post_:
post(BASE_URL + endpoint, headers=headers)
if put_:
post(BASE_URL + endpoint, headers=headers)
response = get(BASE_URL, {}, headers=headers)
try:
return response.json()
except:
return {'error': 'Could not retrieve a response'}
The full url from which im fetching is ""https://api.spotify.com/v1/me/player/currently-playing"
The problem is with the response that im getting from the API, the response is not an error but data that im not expecting to get. Im getting a response that looks like this:
response = {
"display_name": "Tanatswamanyakara",
"external_urls": {
"spotify": "https://open.spotify.com/user/dlnsysel6bndktbvduz6cl79w"
},
"followers": {
"href": null,
"total": 0
},
"href": "https://api.spotify.com/v1/users/dlnsysel6bndktbvduz6cl79w",
"id": "dlnsysel6bndktbvduz6cl79w",
"images": [],
"type": "user",
"uri": "spotify:user:dlnsysel6bndktbvduz6cl79w"
}
I was hoping to get data (the progress, title, duration, album, artist etc) about the song I am playing on my spotify account but instead I get that response, how do I fix that?
N.B
My access tokens and refresh tokens are working as they should. (so I think)
If the data is not what you are expecting then there's going to be something wrong with your API endpoint. You can use the Spotify developer console to generate the endpoint link, it would be worth debugging your execute_spotify_api_request code and the url it generates against the value in the console.
Having just re-read your code half way through answering, I've noticed that you aren't appending your endpoint variable to your GET url:
response = get(BASE_URL, {}, headers=headers)
This means that the get doesn't have 'player/currently-playing' and just returns the base URL which is probably 'https://api.spotify.com/v1/me/' - hence the response you receive is just your profile data.
I need to bulk load contacts to particular list via Constant Contact API (http://developer.constantcontact.com/docs/contacts-api/contacts-collection.html?method=POST).
I can successfully add contacts using the same JSON string as below into the following API GUI website(https://constantcontact.mashery.com/io-docs (find Tab POST 'add contact' to collection):
update_contact = {"lists": [{"id": "1"}],"email_addresses": [{"email_address": "yasmin1.abob19955#gmail.com"}],"first_name": "Ronald","last_name": "Martone"}
However when I run the same JSON string in my python code I get error 400 with the error message from my response object as the following:
[{"error_key":"query.param.invalid","error_message":"The query parameter first_name is not supported."},
{"error_key":"query.param.invalid","error_message":"The query parameter last_name is not supported."},{"error_key":"query.param.invalid","error_message":"The query parameter lists is not supported."},{"error_key":"query.param.invalid","error_message":"The query parameter email_addresses is not supported."}]
How can two of the same API calls produce different results?and how do I get my python code to work?
code:
import requests
headers = {
'Authorization': 'Bearer X',
'X-Originating-Ip': '1',
'Content-Type': 'application/json'
}
update_contact = {"lists": [{"id": "1"}],"email_addresses": [{"email_address": "yasmin1.abob19955#gmail.com"}],"first_name": "Ronald","last_name": "Martone"}
r_2 = requests.post('https://api.constantcontact.com/v2/contacts?action_by=ACTION_BY_OWNER&api_key=x', headers=headers ,params = update_contact)
print(r_2.text)
You will need to change params to data
r_2 = requests.post('https://api.constantcontact.com/v2/contacts?action_by=ACTION_BY_OWNER&api_key=x', headers=headers ,data = update_contact)
Additionally, you can use a multipart endpoint to upload contacts as well. I have found this to be very easy especially if your contacts are in a csv file.
A sample code would look like this:
import requests as r
import csv
from datetime import datetime
url = 'https://api.constantcontact.com/v2/activities/addcontacts?api_key=<your_api_key>'
headers = {'Authorization': 'Bearer <access_token>',
'X-Originating-Ip': '<ip>',
'content-type': 'multipart/form-data'}
files = {'file_name': 'Book1.csv',
'data': ('Book1.csv', open('Book1.csv', 'rb'),
'application/vnd.ms-excel', {'Expires': '0'}),
'lists':('<insert_listIds_seperated_by_commas>')}
response = r.post(url, headers=headers, files=files)
with open('CC_Upload_Response_Data.csv', 'a', newline='') as f:
writer = csv.writer(f)
time_stamp = datetime.now().strftime('%m-%d-%Y %H:%M')
row = [response, response.text, time_stamp]
writer.writerow(row)
The headers of your csv file need to be like so: "First Name" "Last Name" "Email Address" "Custom Field 1" "Custom Field 2" and so on. You can find a complete list of column names here: http://developer.constantcontact.com/docs/bulk_activities_api/bulk-activities-import-contacts.html
The csv file that this code appends acts like a log if you are going to schedule you .py file to run nightly. The log records the response code, response text and adds a timestamp.
Mess around with it a little and get it the way you like.
I am trying to short an URL using Google API but using only the requests module.
The code looks like this:
import requests
Key = "" # found in https://developers.google.com/url-shortener/v1/getting_started#APIKey
api = "https://www.googleapis.com/urlshortener/v1/url"
target = "http://www.google.com/"
def goo_shorten_url(url=target):
payload = {'longUrl': url, "key":Key}
r = requests.post(api, params=payload)
print(r.text)
When I run goo_shorten_url it returns:
"error": {
"errors": [
{
"domain": "global",
"reason": "required",
"message": "Required",
"locationType": "parameter",
"location": "resource.longUrl"
}
],
"code": 400,
"message": "Required"
}
But the longUrl parameter is there!
What am I doing wrong?
At first, please confirm that "urlshortener api v1" is enabled at Google API Console.
Content-Type is required as a header. And please use data as a request parameter. The modified sample is as follows.
Modified sample :
import json
import requests
Key = "" # found in https://developers.google.com/url-shortener/v1/getting_started#APIKey
api = "https://www.googleapis.com/urlshortener/v1/url"
target = "http://www.google.com/"
def goo_shorten_url(url=target):
headers = {"Content-Type": "application/json"}
payload = {'longUrl': url, "key":Key}
r = requests.post(api, headers=headers, data=json.dumps(payload))
print(r.text)
If above script doesn't work, please use an access token. The scope is https://www.googleapis.com/auth/urlshortener. In the case of use of access token, the sample script is as follows.
Sample script :
import json
import requests
headers = {
"Authorization": "Bearer " + "access token",
"Content-Type": "application/json"
}
payload = {"longUrl": "http://www.google.com/"}
r = requests.post(
"https://www.googleapis.com/urlshortener/v1/url",
headers=headers,
data=json.dumps(payload)
)
print(r.text)
Result :
{
"kind": "urlshortener#url",
"id": "https://goo.gl/#####",
"longUrl": "http://www.google.com/"
}
Added 1 :
In the case of use tinyurl.com
import requests
URL = "http://www.google.com/"
r = requests.get("http://tinyurl.com/" + "api-create.php?url=" + URL)
print(r.text)
Added 2 :
How to use Python Quickstart
You can use Python Quickstart. If you don't have "google-api-python-client", please install it. After installed it, please copy paste a sample script from "Step 3: Set up the sample", and create it as a python script. Modification points are following 2 parts.
1. Scope
Before :
SCOPES = 'https://www.googleapis.com/auth/drive.metadata.readonly'
After :
SCOPES = 'https://www.googleapis.com/auth/urlshortener'
2. Script
Before :
def main():
"""Shows basic usage of the Google Drive API.
Creates a Google Drive API service object and outputs the names and IDs
for up to 10 files.
"""
credentials = get_credentials()
http = credentials.authorize(httplib2.Http())
service = discovery.build('drive', 'v3', http=http)
results = service.files().list(
pageSize=10,fields="nextPageToken, files(id, name)").execute()
items = results.get('files', [])
if not items:
print('No files found.')
else:
print('Files:')
for item in items:
print('{0} ({1})'.format(item['name'], item['id']))
After :
def main():
credentials = get_credentials()
http = credentials.authorize(httplib2.Http())
service = discovery.build('urlshortener', 'v1', http=http)
resp = service.url().insert(body={'longUrl': 'http://www.google.com/'}).execute()
print(resp)
After done the above modifications, please execute the sample script. You can get the short URL.
I am convinced that one CANNOT use ONLY requests to use google api for shorten an url.
Below I wrote the solution I ended up with,
It works, but it uses google api, which is ok, but I cannot find much documentation or examples about it (Not as much as I wanted).
To run the code remember to install google api for python first with
pip install google-api-python-client, then:
import json
from oauth2client.service_account import ServiceAccountCredentials
from apiclient.discovery import build
scopes = ['https://www.googleapis.com/auth/urlshortener']
path_to_json = "PATH_TO_JSON"
#Get the JSON file from Google Api [Website]
(https://console.developers.google.com/apis/credentials), then:
# 1. Click on Create Credentials.
# 2. Select "SERVICE ACCOUNT KEY".
# 3. Create or select a Service Account and
# 4. save the JSON file.
credentials = ServiceAccountCredentials.from_json_keyfile_name(path_to_json, scopes)
short = build("urlshortener", "v1",credentials=credentials)
request = short.url().insert(body={"longUrl":"www.google.com"})
print(request.execute())
I adapted this from Google's Manual Page.
The reason it has to be so complicated (more than I expected at first at least) is to avoid the OAuth2 authentication that requires the user (Me in this case) to press a button (to confirm that I can use my information).
As the question is not very clear this answer is divided in 4 parts.
Shortening URL Using:
1. API Key.
2. Access Token
3. Service Account
4. Simpler solution with TinyUrl.
API Key
At first, please confirm that "urlshortener api v1" is enabled at Google API Console.
Content-Type is required as a header. And please use data as a request parameter. The modified sample is as follows.
(Seems not to be working despite what the API manual says).
Modified sample :
import json
import requests
Key = "" # found in https://developers.google.com/url-shortener/v1/getting_started#APIKey
api = "https://www.googleapis.com/urlshortener/v1/url"
target = "http://www.google.com/"
def goo_shorten_url(url=target):
headers = {"Content-Type": "application/json"}
payload = {'longUrl': url, "key":Key}
r = requests.post(api, headers=headers, data=json.dumps(payload))
print(r.text)
Access Token:
If above script doesn't work, please use an access token. The scope is https://www.googleapis.com/auth/urlshortener. In the case of use of access token, the sample script is as follows.
This answer in Stackoverflow shows how to get an Access Token: Link.
Sample script :
import json
import requests
headers = {
"Authorization": "Bearer " + "access token",
"Content-Type": "application/json"
}
payload = {"longUrl": "http://www.google.com/"}
r = requests.post(
"https://www.googleapis.com/urlshortener/v1/url",
headers=headers,
data=json.dumps(payload)
)
print(r.text)
Result :
{
"kind": "urlshortener#url",
"id": "https://goo.gl/#####",
"longUrl": "http://www.google.com/"
}
Using Service Account
To avoid the user need to accept the OAuth authentication (with a pop up screen and all that) there is a solution that uses authentication from machine to machine using a Service Account (As mentioned in another proposed answer).
To run this part of the code remember to install google api for python first with pip install google-api-python-client, then:
import json
from oauth2client.service_account import ServiceAccountCredentials
from apiclient.discovery import build
scopes = ['https://www.googleapis.com/auth/urlshortener']
path_to_json = "PATH_TO_JSON"
#Get the JSON file from Google Api [Website]
(https://console.developers.google.com/apis/credentials), then:
# 1. Click on Create Credentials.
# 2. Select "SERVICE ACCOUNT KEY".
# 3. Create or select a Service Account and
# 4. save the JSON file.
credentials = ServiceAccountCredentials.from_json_keyfile_name(path_to_json, scopes)
short = build("urlshortener", "v1",credentials=credentials)
request = short.url().insert(body={"longUrl":"www.google.com"})
print(request.execute())
Adapted from Google's Manual Page.
Even simpler:
In the case of use tinyurl.com
import requests
URL = "http://www.google.com/"
r = requests.get("http://tinyurl.com/" + "api-create.php?url=" + URL)
print(r.text)
def sendEmail(to,apNumber,paperType,zipedFile):
sg = sendgrid.SendGridAPIClient(apikey=os.environ.get("API-KEY"))
to_email = mail.Email( "to#email.com")
from_email = mail.Email( "from#email.com" )
subject = 'This is a test email'
content = mail.Content('text/plain', 'Example message.')
message = mail.Mail(from_email, subject, to_email, content)
response = sg.client.mail.send.post(request_body = message.get())
return response
Setup Environment Variables.
To Set up environment Variable follow the below 3 steps
echo "export SENDGRID_API_KEY='YOUR_API_KEY'" > sendgrid.env
echo "sendgrid.env" >> .gitignore
source ./sendgrid.env
import os
from sendgrid import SendGridAPIClient
from sendgrid.helpers.mail import Mail
message = Mail(
from_email='...#gmail.com',
to_emails='....#gmail.com',
subject='Sending with Twilio SendGrid is Fun',
html_content='<strong>and easy to do anywhere, even with Python</strong>')
try:
**sg = sendgrid.SendGridAPIClient(api_key=os.environ.get('SENDGRID_API_KEY'))**
response = sg.send(message)
print(response.status_code)
print(response.body)
print(response.headers)
except Exception as e:
print(e)
I got the same error "UnauthorizedError: HTTP Error 401: Unauthorized"
I refactored the code from
sg = sendgrid.SendGridAPIClient(api_key=os.environ.get('SENDGRID_API_KEY'))
to
sg=SendGridAPIClient('......IeltIytmFYeQ0aSOt2UBYvv2E6Xh...')
Then it started working.
I change my API key settings to Full access in SendGrid portal.
I was getting "HTTP/1.1 401 Unauthorized" error in PHP. See the screenshot.
I solved it by removing getenv() from the API key.
Replace:
$apiKey = getenv("SendGrid_API_Key");
$sendgrid = new \SendGrid($apiKey);
with:
$apiKey = ("SendGrid_API_Key");
$sendgrid = new \SendGrid($apiKey);
I created a new key and that solved my issue. Exact issue for this is still unknown.
As it was functional before.
The error for me was because I used the wrong key , actually, one needs to use the key that is created the first time when one create the Api key , which one cannot edit again. So one have to click "Create Api key" button and use this key
When trying to pull data from the youtube gdata api using urllib2.urlopen, I receive a HTTP 403 error. I've turned off the CSRF middleware for debugging purposes, and the view I'm using looks like this:
def videos (request):
params = {}
youtube_search_url = 'http://gdata.youtube.com/feeds/api/videos'
params['order_by'] = 'relevance'
params['max_results'] = 10
params['safeSearch'] = 'strict'
params['v'] = 2
params['key'] = '<developer key>'
f = urllib2.urlopen(youtube_search_url, encoded_params)
...
Any ideas?
When you make an API request, use the X-GData-Key request header to specify your developer key as shown in the following example:
X-GData-Key: key=<developer_key>
Include the key query parameter in the request URL.
http://gdata.youtube.com/feeds/api/videos?q=SEARCH_TERM&key=DEVELOPER_KEY
^^ Straight from the horse's mouth. You are missing the X-GData-Key request header.
The key seems to be required in both url and the header, so given your previous code try this:
req = urllib2.Request(youtube_search_url, encoded_params, { "X-GData-Key": '<developer key>' })
f = urllib2.urlopen(req)