I am using the xslt for transformation but from input 240 characters receiving in one element ,In that element different special characters receiving(eg :---> %,?,/,-,_,#,!,$,^) .
I need to replace the those characters.
It is possible in XSLT 1.0.If it is possible can you please give me the code with examples?.Thanks
Eg:
<remark> whfwlknf234#skl$ck?nvwkld^fnwlfn </remark>
It is possible in XSLT 1.0
Yes, it is possible. Use the translate() function to replace them with ... oh, you didn't say with what.
Related
I'm currently facing an issue with a software i'm working with , this software receives from an external sofware several Xmls that we do need to process , now our issue is that those Xml files contain a lot of nodes which are totally useless and also make the files (xmls) really heavy because of that , in result out program runs very slow to process each one of the xmls , this should be changed in the future and i'd like to prove that by removing those nodes we would improve our processing time a lot , now i'd like as first step to do this manually , using a sample xml and applying a regex syntax to remove all the nodes with value property empty , this is the syntax that i'm using now and through the replace function in notepad i'm able to remove those rows and then remove the empty lines :
<.*(\s\w+?[^=]*?="[^"]*?")*?\s+?value="[""]*?".*?>
Example
<TEST_NODE value="1"/>
<TEST_NODE value=""/>
<TEST_NODE value="0"/>
In my case nodes can be named differently and can have different properties , but the one that i should care for are the ones that contain something in the value property , therefore in this case i should remove the second row
This looks to be working fine , however with very large files (10 mb) the replace notepad++ function seems to have issues and it stop working properly breaking a lot of tags...
I've tried using another software called "Ultraedit" , but there the syntax i guess it's different as i can use regular Expressions but need to select one of those options : Perl , Unix , Ultraedit ; only using "Perl" i'm able to do this replacement but also there , for big files this is not working and i get the following error:
The complexity of matching the expression has exceeded available resources..
Can anyone help me out with this? unfortunately i'm not even that good with Regex and i'm not sure if the above code is good or bad..
Try this:
<(?=[^><]*?value\s*=\s*"")[^><]*>
Replace with nothing.
This might be a case of catastrophic backtracking when the regex runs caused by too many quantifiers applied to too many wide character classes like .
The quantifiers in this answer are only applied to not < or > class which should stop the expression backtracking through XML tags.
You're using the wrong tool for the job. If you're going to be manipulating XML then you need to add XSLT and/or XQuery to your tool kit. Using regular expressions for the job is slow and error-prone.
For example, here are just a few of the bugs in the answer that you accepted:
Elements that use single quotes (value='') won't be matched
Element with whitespace around the equals sign won't be matched
Elements with an attribute whose name ends in value (e.g. xvalue="") will be matched
value="" will be matched inside comment and CDATA nodes
value="" can be matched inside text nodes: <x>value=""</x>
Elements split across multiple lines won't be matched (I suspect)
In XSLT 3.0 this is simply
<xsl:transform version="3.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:mode on-no-match="shallow-copy"/>
<xsl:template match="*[#value='']"/>
</xsl:transform>
Try this regular expression in Notepad++
<[^<]+value=""[^>]*>
I am copying some nodes according to XSLT: Copy child elements of a complex type only once by using a path expression within a copy-of tag:
<xsl:copy-of select="/xs:schema/xs:complexType[#name=current()/xs:element/#type]"/>
In the output all linebreaks are missing at the elements processed by this statement. (Elesewhere they are shown) It looks like this:
...</xs:complexType><xs:complexType....
I can only add linebreaks before and after, but not between them. How can i achive this? Thanx for your help!
You provided too little data to attempt any testing. E.g. it is not clear, what output method uses your script.
Quite often XSLT script contains xsl:strip-space instruction, which causes normalization of text nodes.
This normalization a.o. changes "internal" sequences of "white" chars, including line breaks,
into a single space.
Maybe this is the cause.
Take alse a look at xsl:output instruction in your script.
Does it contain indent="yes" attribute?
If it doesn't, the output contains no line breaks between output elements.
Maybe your script contains in some places output of explicite line breaks
(e.g. <xsl:text>&#aA;</xsl:text>), so these line breaks are rendered.
But if you have no indent="yes" attribute, then no line breaks are inserted
"automatically" between consecutive elements.
Your XPath expression only selects the xs:complexType elements, not the whitespace that separates them.
When you're working with a vocabulary such as XSD that doesn't use mixed content (except perhaps in annotations) it's probably best to remove all whitespace text nodes from the input using xsl:strip-space and then to generate new whitespace in the output using xsl:output indent='yes'.
I have the following string,
';#6;#'
The above string could be anything, E.g.:
';#1;#' or ';#2;#' , or ';#3;#' ...
I need to be able to replace the contents between the ' and '
Is this possible using something like translate in XSLT 1.0?
This kind of thing is quite difficult in XSLT 1.0. Take a look at the library of string-handling functions available at www.exslt.org - some of them come with XSLT implementations that you can copy into your stylesheet and call (typically as xsl:call-template).
Use substring and concat functions.
Hi all
I am using xslt 1.0. I have the char code as FOA7 which has to displayed as a corresponding character. My input is
<w:sym w:font="Wingdings" w:char="F0A7"/>
my xslt template is
<xsl:template match="w:sym">
<xsl:variable name="char" select="#w:char"/>
<span font-family="{#w:fonts}">
<xsl:value-of select="concat('&#x',$char,';')"/>
</span>
</xsl:template>
It showing the error as ERROR: 'A decimal representation must immediately follow the "&#" in a character reference.'
Please help me in fixing this..Thanks in advance...
This isn't possible in (reasonable) XSLT. You can work around it.
Your solution with concat is invalid: XSLT is not just a fancy string-concatenator, it really transforms the conceptual tree. An encoded character such as is a single character - if you were to somehow include the letters & # x f 0 a 7 ; then the XSLT processor would be required to include these letters in the XML data - not the string! So that means it will escape them.
There's no feature in XSLT 1.0 that permits converting from a number to a character with that codepoint.
In XSLT 2.0, as Michael Kay points out, you can use codepoints-to-string() to achieve this.
There are two solutions. Firstly, you could use disable-output-escaping. This is rather nasty and not portable. Avoid this at all costs if you can - but it will probably work in your transformer, and it's probably the only general, simple solution, so you may not be able to avoid this.
The second solution would be to hardcode matches for each individual character. That's a mess generally, but quite possible if you're dealing with a limited set of possibilities - that depends on your specific problem.
Finally, I'd recommend not solving this problem in XSLT - this is typically something you can do in pre/post processing in another programming environment more appropriately. Most likely, you've an in-memory representation of the XML document to be able to use XSLT in the first place, in which case this won't even take much CPU time.
<span font-family="{#w:font}">
<xsl:value-of select="concat('&#x', #w:char, ';')"
disable-output-escaping="yes"/>
</span>
Though check #Eamon Nerbonne's answer, why you shouldn't do it at all.
If you were using XSLT 2.0 (which you aren't), you could write a function to convert hex to decimal, and then use codepoints-to-string() on the result.
use '&' for '&' in output:
<xsl:value-of select="concat('&#x',$char,';')"/>
I need a test for a variable which would evaluate to true in two cases:
There is a string inside which contains any non white space characters
There is any node (which can be possibly empty)
and the variable is filled with apply-template call result.
I tried
test="normalize-space($var)"
but this doesn't cover the empty tag possibility. I also tried simply this:
test="$var"
but this evaluate to true even for white space only strings.
By the way "$var/*" produces an error "Expression ...something I don't remember... node-set" which is I think because of apply-template variable instantiation.
Is there any (which means even multi level decision) solution for this?
EDIT: I forgot to say that it's for XSLT 1.0 and preferably without any exslt extensions or similar.
If you want to check whether a result tree fragment contains any child nodes then you need exsl:node-set e.g.
<xsl:if test="exsl:node-set($variable)/node()"
xmlns:exsl="http://exslt.org/common">
Without that extension function (or a similar one your particular XSLT 1.0 processor offers) you can't perform that check.
Hope this helps:
"string($variable)" will test true if the string has any characters in it, false if it equals ''.
http://www.dpawson.co.uk/xsl/sect2/N3328.html#d4474e64
Contains no child nodes: not(node())
Contains no text content: not(string(.))
Contains no text other than whitespace: not(normalize-space(.))
Contains nothing except comments: not(node()[not(self::comment())])