Paramiko SSH - Multiple Authentication Credentials with Python - python-2.7

Question

I have the following code:
import paramiko
import time
import re
import sys
import random
import fileinput
ip_address = raw_input("Enter a valid WAP IP: ")
#Open SSHv2 connection to devices
def open_ssh_conn(ip):
try:
#Logging into device
session = paramiko.SSHClient()
#AutoAddPolicy
session.set_missing_host_key_policy(paramiko.AutoAddPolicy())
#Passing the necessary
session.connect(ip, username = 'myUsername', password = 'myPassword')
#Start an interactive shell session on the switch
connection = session.invoke_shell()
#Commands
connection.send("enable\n")
time.sleep(1)
connection.send("show version\n")
time.sleep(1)
#Checking command output for IOS syntax errors
output = connection.recv(65535)
#Checking command output for IOS Syntax errors
if re.search(r"% Invalid input detected at", output):
print "* There was at least one IOS syntax error on device %s" % ip
else:
print "\nDONE for device %s" % ip
#Test for reading command output
print output + "\n"
#Closing the connection
session.close()
except paramiko.AuthenticationException:
print "* Invalid username or password. \n* Please check
the username/password file or the device configuration!"
print "* Closing program...\n"
#Calling the SSH function
open_ssh_conn(ip_address)
How can I test multiple credential without getting kick out of the program when an exception is caught?
for example, try this new credentials:
session.connect(ip, username = 'myNewUsername', password = 'myNewPassword')

Answer 1

I figured it out! I created a nested list with the credentials:
list = [['username1', 'password1'], ['username2', 'password2'], \
['username3', 'password3']]
Then, created a for loop and put my code inside:
for elem in list:
my code...
# this is the connect line:
session.connect(ip, username = elem[0], password = elem[1])
That did it!!!!