OOP: Method for cout output - c++

Question

I have to create a method, which prints all collected data's on screen, here is my try:
bool UnPackedFood::printer() {
cout << " -- Unpacked Products --" << endl;
cout << "barcode: " << getBarcode() << endl;
cout << "product name: " << getBezeichnung() << endl << endl;
cout << "weight: " << getGewicht() << endl;
cout << "price" << getKilopreis() << endl;
return true;
}
In my main:
UnPackedFood upf;
cout << upf.printer();
This shows me the correct output, but it still delivers me a bool value back, which I actually dont need. I tried to declare the method as void, but thats not working.

Answer 1

You should overload << operator for output stream. Then when you type cout << upf it will print your product.
Take a look at this example and try to do something similar to following snippet:
class UnPackedFood {
...
public:
...
friend ostream & operator<< (ostream &out, const UnPackedFood &p);
};
ostream & operator<< (ostream &out, const UnPackedFood &p) {
out << " -- Unpacked Products --" << endl;
out << "barcode: " << p.getBarcode() << endl;
out << "product name: " << p.getBezeichnung() << endl << endl;
out << "weight: " << p.getGewicht() << endl;
out << "price" << p.getKilopreis() << endl;
return out;
}

Answer 2

Three possible solutions:
Don't do cout << upf.printer();, the output is not needed since the function itself does the output.
Instead of writing to the output in the printer function, append to a string and return the string.
Make an overloaded operator<< for UnPackedFood, so you can just do std::cout << upf;