Guessing game where computer generates random number - c++

Question

I am implementing a Guessing game where computer generates random number with the following code:
int main()
{
srand(time(NULL));
while (true){
int num = rand() % 10, guess, tries = 0;
while (true){
cout << "Enter number 1 to 10:";
cin >> guess;
if (tries > 2)
{
break;
}
if (guess > num)
{
cout << "Too High ! Try again"<<endl;
}
if (guess > 10)
{
cout << "Error ReEnter 1 to 10\n";
}
else if (guess < num)
{
cout << "Too Low! Try again"<<endl;
}
else
{
break;
}
tries++;
}
if (tries > 2)
{
cout <<"\nYou ran out of tries!\n";
cout << "\nThe answer is:" << num << endl;
}
else
{
cout << "\nCONGRATZ!! You guess correctly!\n";
}
return 0;
}
}
One of the problems is: yet when user attempt 3 times, the program shows "ran out of tries" even though the user input is correct on 3rd try.
Questions:
1.How do I inform user that their input exceeds 10 and show an error message to user to enter values from 1 to 10 ?
2.How to correct the aforementioned problem?

Answer 1

instead of writing the program for you here is some pseudo code.
get a random number rand()%10+1 1..10 call it R
loop
get user input N
if N == R then show OK and break loop
if N < R show too low
else show too high
increment tries
if tries == 3 then break loop
end loop

Answer 2

You have too many if else conditions that make your code unnecessarily complex, to answer your second question specifically the unwanted behaviour is caused from the:
if (tries > 2)
{
break;
}
which exits the loop regardless of the guess, as it is dependant only on the number of tries. Regarding your first question, I decided to provide you with more simple implementation that includes an answer to it as well.
You could replace your while loop with a do-while loop, terminated when the random number is guessed, i.e.:
int main(){
// initialize random seed
srand (time(NULL));
// generate a random number within [1,10]
int secretRandom = rand() % 10 + 1;
// initialize
int yourGuess = 11;
// input loop
string promptMessage = "Type a a number from 1 to 10."
do{
cout << promptMessage << '\n';
// read input
cin >> yourGuess >> endl;
// guessed number relatively to the randomly generated
if (secretRandom < yourGuess) cout << "The secret number is lower\n";
else if (secretRandom > yourGuess) cout << "The secret number is higher\n";
}while(yourGuess != secretRandom)
// if you guess the random number exit the loop and display success message
cout << "You guessed right!\n";
return 0;
}
To reduce the amount of guesses to specific number you can enclose the do-while loop and the success message in a for loop, for example:
int numberOfGuesses = 3;
for (int i = 0; i <= numberOfGuesses; ++i){
//...
}
If you want to enforce the user to input a number in the range from 1 to 10, you could do it by:
int yourGuess = 11;
int lowerBound = 0;
int upperBound = 10;
do{
cin >> yourGuess;
// not type safe
}while(yourGuess < lowerBound || yourGuess > upperBound);