returning the address of a pointer - c++

Question

I'm trying to return the address of a pointer using the code below:
#include <iostream>
using namespace std;
int main(){
int x = 5;
int *p = &x;
//int **pp = &p;
cout << &p << endl;
return 0;
}
However what gets printed is 0x28fea8, which is the same address as x itself. Now if I uncomment the only commented line above and leave everything else as is, then what gets printed is 0x28fea4 which seems to be the correct address of the pointer.
My question is why do I need the uncommented line in order to display the correct address of my pointer?
Why do "cout << p << endl" and "cout << &p << endl" both display 0x28fea8 if that line is left commented?
Shouldn't "cout << &p << endl" display 0x28fea4 regardless of the other line?
I'm using Qt Creator as my compiler/ide if that helps. I downloaded my compiler from the following link: http://web.stanford.edu/~rawatson/qt/windows_install/index.html
EDIT: Ok how silly of me. My issue was that I was comparing addresses by changing values and then re-running the program. Instead I should have compared by printing them all in one program run. When I compare in one program I get different addresses for p and &p, as it should be.

Answer 1

I'm unable to reproduce what you are telling, with this code:
#include <cstdio>
using namespace std;
int main() {
int x = 5;
int* p = &x;
printf("x address: %p\n", &x);
printf("p value: %p\n", p);
printf("p address: %p\n", &p);
return 0;
}
I get the following output:
x address: 0xbfd6bba8
p value: 0xbfd6bba8
p address: 0xbfd6bbac
which is correct and indeed &p is &x+4 which is correct on a 32bit architecture since they are allocated on stack.

Answer 2

int x = 5;
int *p = &x; // b stores addres of variabile a
cout << "Adress of x is : " << p <<endl; // printing the adress of a
cout << "Value of x is : " << *p << endl; // printing the variabile stores in a
int **pp = &p; // pp stores thea adress of p
cout <<"Adress of p is" << pp << endl; //printing the adress of p
cout << "Adress of x is" <<*pp << endl; //printing the adress of x
return 0;
I hope that the comments solve your problem .