now i have the next problem. Suppose i have a list with diferent numbers for example :
let mylist [3 7 12 24 32 54 21 19]
And i want to use this list of numbers like the who of turtles. More accurately , i want that only the turtles that his who is equal to of any of the numbers of the list, do a procedure. I tried to applying directly the "with" command like this: ask turtles with [who = mylist] but is not working and i think that the problem is that i am working with a list not a specific value. Any suggestions?
You can use the foreach statement and then ask every turtle with that number. Example
let mylist [1 2 3]
foreach mylist [ ask turtle ?1 [to do some stuff] ]
Related
I have a list like that:
[[0 1 2] [4 6 9] ... [-1 0 3]]
and I need to get [3 19 ... 2], I mean sum of first element, second and .... n - element.
I´m gonna really appreciate your help.
Update: I tried with that:
to sum-first-item
let out []
ask turtles[
let sum-elem sum map first data-train
set out lput sum-elem out
]
end
Each list's item (in your case: each inner list) can be accessed by using item (see here, but also know about first and last) or as the current element of foreach (see here).
Here a bunch of ways with which you can accomplish your goal. First showing simply how to operate on each inner list, then showing how to directly build a list containing each inner list's sum:
to play-with-lists
print "The original list:"
let list-of-lists [[0 1 2] [4 6 9] [-1 0 3]]
print list-of-lists
print "Manually reporting sums:"
print sum item 0 list-of-lists
print sum item 1 list-of-lists
print sum item 2 list-of-lists
print "Building a list of sums with while loop using 'while':"
let list-of-sums []
let i 0
while [i < length list-of-lists] [
set list-of-sums lput (sum item i list-of-lists) (list-of-sums)
set i i + 1
]
print list-of-sums
print "Building a list of sums with for loop using 'foreach':"
set list-of-sums []
foreach list-of-lists [
inner-list ->
set list-of-sums lput (sum inner-list) (list-of-sums)
]
print list-of-sums
print "Building a list of sums using 'map':"
print map sum list-of-lists
end
Edit: Matteo's version with map sum the-list is the simpler solution so I suggest sticking with that. Still, it is useful to get to know reduce for when you need to do more complex calculations than summing.
Netlogo offers a few very powerful primitives to work with lists. I see you already use map, which runs a reporter for each item of a list and reports the resulting list.
Another one of those is reduce, which combines all items from a list into a single value by applying a reporter to them in turn. I suggest reading up on reduce in the dictionary and playing around with it a bit since it is not immediately obvious how it works (https://ccl.northwestern.edu/netlogo/docs/dictionary.html#reduce).
Combining these two gives you this elegant piece of code:
to try
let the-list[[0 1 2] [4 6 9] [-1 0 3]]
show map [ x -> reduce + x] the-list
;observer: [3 19 2]
end
I want to store values from a variable in a list, adding new variable output for every tick. Lets say the variable outputs a different value every tick. For simplicity this is determined by the formula; 2 * ticks (var = 2 * ticks), thus the list should look something like this after five ticks [0 2 4 6 8]. I cannot get this to work however. Since NetLogo does not allow taking values from the past, how would I go about this?
I now have something like this:
ask turtles[
let var_list [ ]
foreach var_list [
set var_list lput var var_list
]
print var_list
]
This however only gives empty lists or lists only showing the most recent var value (when I change let var_list [] to let var_list [ 0 ]. How can I get it to correctly input the variable value in the table for every tick?
You are using let to create a temporary local variables. There's no problem in retaining values across ticks, but you do need to use global or turtle/patch/link variables.
Here's a complete model to demonstrate
turtles-own [my-list]
to setup
clear-all
create-turtles 1
[ set my-list []
]
reset-ticks
end
to go
ask turtles
[ set my-list fput random 10 my-list
print my-list
]
tick
end
Every time an agent gets a new value for some action they're performing, I want them to add it to the end of a list. If the list has ten or more items on it, I want them to remove the first item on the list, so that the list has the ten most recent values an agent has seen, in order. How might I do that? (Edit: forgot to ask an actual question.)
I want to be able to apply mathematical operations to each item on the list, so I don't want a list of cons cell-like lists, unless there's some easy way to apply mathematical operations to each item in such a list that I don't know about.
Let's build a simple example, where each turtle makes a slight right turn at a random angle at every tick, and stores the history of these angles in a list:
turtles-own [ history ]
to setup
clear-all
create-turtles 3 [
set history [] ; initialize history to an empty list
]
reset-ticks
end
to go
ask turtles [
let angle random 5
right angle
; add the angle of the most recent turn
; at the end of the list
set history lput angle history
if length history > 10 [
; remove the first item from the list
set history but-first history
]
forward 0.1
]
tick
end
I don't want a list of cons cell-like lists, unless there's some easy way to apply mathematical operations to each item in such a list that I don't know about.
I don't know what you mean by "a list of cons cell-like lists", but a simple list like the one we built here is by far the best thing you can use if you want to do math.
To apply an operation to each item, use map. And then you can use functions like sum or mean to operate on the whole list. For example:
to do-math
ask turtles [
let doubled-history map [ a -> a * 2 ] history
show history
show doubled-history
show mean doubled-history
]
end
(Note that this uses NetLogo 6.0.1 syntax.)
Let's see a demonstration:
observer> setup repeat 5 [ go ] do-math
(turtle 2): [4 3 2 1 2]
(turtle 2): [8 6 4 2 4]
(turtle 2): 4.8
(turtle 1): [4 0 1 1 4]
(turtle 1): [8 0 2 2 8]
(turtle 1): 4
(turtle 0): [2 0 4 1 0]
(turtle 0): [4 0 8 2 0]
(turtle 0): 2.8
I have to do some operations in netlogo using Lists. While i can do simple tasks with them i am not yet proficient enough to code my current requirements.
I have a scenario where turtles have variables called Current-Age and Previous-Age. And turtles can be born and die if they don't meet a certain threshold.
I want to implement the following formula for each patch.
Best-list = (-1/Previous-Age) * (Distance between Patch & Turtle) for all the turtles
Best = Min [ Best-list]
I know the steps involved but have been unsuccessful in coding them. Following are the steps:
Create a list with all the current turtles that are alive
Create a second list which contains the Previous-Age
Create a third list with the distance between an individual patch and each of the live turtles
Then create another list with the output from the the Best-List formula for all the turtles in the list
Finally find the Min value in the list and store the name/who# of turtle with the minimum value in a separate variable called Best-Turtle
This is the code that i tried but didn't work.
set turtle-list (list turtles)
set turtle-age-list n-values length(turtle-list) [0]
set turtle-patch-dist-list n-values length(turtle-list) [0]
set best-list n-values length(turtle-list) [0]
ask patches[
foreach turtle-list(
set turtle-age-list replace-item ?1 turtle-age-list Previous-Age of turtles with [turtle= ?1]
)
]
I couldn't proceed to the next steps since the above code itself was not correct.
Would appreciate help with the code, thanks in advance.
Regards
First, lists are probably not the simplest way to do this. However, if you must use lists for some reason, I think what you're asking for is possible. I'm not exactly sure what you mean with best- are you trying to have each patch assess which turtle is the best turtle for that patch, and store that variable in a global list? I'm going to assume that's what you mean, but if I'm misunderstanding I think you can adapt what I do here to what you need.
First, any list passed to foreach must be the same length. So, since you mean to do this per-patch, make sure that every patch calls the procedure of list creation, not just for checking the lists. Next, review the dictionary for n-values- the syntax for the reporter means you need to use the reporter you're trying to receive- using n-values length(turtle-list) [0] will just give you a list of zeroes that is the same length as the number of turtles.
So each patch needs to create these lists- make sure you either define the patches-own for the list variables, or just use let to define the lists inside the procedure. You would need a list of ordered turtles, their previous ages, and the distance from the patch calling the procedure to each turtle. Next, you can create a list that generates a value according to your formula. Then, you can use the position primitive to find the location of the minimum value in your formula-generated list and use that to index the turtle with that value.
It might look something like
to numerical
set best-turtle []
ask patches [
let turtle-list (sort turtles) ;;; list of sorted turtles
let turtle-prev-age-list n-values length(turtle-list) [ [i] -> [pre_age] of turtle i ] ;;; list of previous ages of turtles, in same order as above
let turtle-patch-dist n-values length(turtle-list) [ [i] -> distance turtle i ] ;;; list of distance from this patch to each turtle, in same order
set best-list n-values length(turtle-list) [ [i] -> ( ( -1 / ( item i turtle-prev-age-list ) ) * ( item i turtle-patch-dist ) ) ] ;;; list of calculated values for each turtle
let best-position position (min best-list) best-list ;;; gets the index of minimum value
set best-turtle lput item best-position turtle-list best-turtle ;;; adds the best turtle for this patch to the global list of best turtles
]
end
The above procedure assumes that your turtles have a pre_age variable, patches have a best-list variable, and the list of each patches 'best turtle' is held in the global variable best-turtle. From there, you can use foreach to ask turtles in the list to do something. Note that if a turtle's previous age is 0, you will get a divide by zero error.
turtles-own [age previous-age]
to-report evalfrom [_patch]
report (- distance _patch) / previous-age
end
to test
ca
crt 25 [
set age (10 + random 75)
set previous-age age - random 10
]
print min-one-of turtles [evalfrom (patch 0 0)]
end
I am looking to add patch variable values to a list of empty lists. The patches are divided into different zones, and I'm trying to see how certain patch variables differ by zone.
I have an empty list of lists (actually contains 12 lists, but for simplicity):
set mylist [[] [] [] []]
And a list corresponding to the different zones:
set zone-list [1 2 3 4]
Here's how I'm trying to build the lists:
(foreach mylist zone-list [set ?1 lput (sum-zone-variable ?2) ?1])
to-report sum-zone-variable [ n ]
report (sum [patch-variable] of patches with [zone = n])
end
When I run this, mylist stays empty (ie unchanged). I think the problem is with the foreach statement, but I can't figure out what it is. Any help?
I can see the thinking behind foreach mylist [ set ?1 ... ], but NetLogo doesn't work that way. set ?1 ... has no effect on the original list. NetLogo lists are immutable, and ?1 is not a reference to an updatable location in a list — it's just a temporary variable into which a value has been copied. So set ?1 ... is something you will basically never write.
If I understand your question correctly, the relevant primitive here is map. This should do the job:
set mylist (map [lput (sum-zone-variable ?2) ?1] mylist zonelist)
Your basic approach is ok except that you must assign to a name. E.g.,
globals [mylist zone-list n-zones]
patches-own [zone zone-variable]
to setup
set n-zones 4
set zone-list n-values n-zones [?]
ask patches [set zone one-of zone-list]
set mylist n-values n-zones [[]]
end
to go
ask patches [set zone-variable random-float 1]
foreach zone-list [
let total sum [zone-variable] of patches with [zone = ?]
let oldvals item ? mylist
set mylist replace-item ? mylist (lput total oldvals)
]
end
However, you might want to use the table extension for this.