I'm new to c++ and have a question with variables
int main() {
int a;
int b;
int c;
int e;
int parafechar;
int loop = 10;
while(loop==10) {
cout<< "Coloque a mensal 1\n";
cin >> a;
cout<< "Coloque a mensal 2\n";
cin >> e;
cout <<"Coloque a nota do cnem\n";
cin >> b;
cout << "Coloque a media dos trabalhos\n";
cin >> c;
if(a>b) {
cout << "A media e : " << a*0.5 + b*0.25 + c*0.25<<endl;
} else {
cout << "A media e : " << e*0.5 + b*0.25 + c*0.25<<endl;
}
cout << "aperte uma tecla para fechar o programa\n";
cin >> parafechar;
}
return 0;
}
after the last line i want the code to run again and all the variables to be set again but the program goes on endless, what should i do ?
( the program is in portuguese but it calculate grades)
thank you for your time and help :)
after the last line i want the code to run again and all the variables to be set again but the program goes on endless, what should i do?
Change the check in while and change the value of loop so that it will eventually meet the condition to stop the loop.
while(loop > 0) {
// Do your stuff...
// Decrement loop. It will eventually become zero
// and the conditional in the while statement will fail.
--loop;
}
The line
while (loop==10)
will give always true because the value of loop is not changing trough out the program.
What i can understand is , You want to iterate your loop 10 Times. So in this case you should write :
while (loop>0){
// your code of calculating grades
loop--;
}
Since you want the loop to be executed 10 times , you can do:
int loop = 10;
while (loop--) {
//do something
}
Related
I have a problem in the following code:
int main()
{
string store;
ofstream ip, ipa;
bool ai = true;
string catch, container, contain;
ifstream datbot("database.txt"), datbrot("datafloor.txt");
string chats, train;
int loop = 0, c = 0;
cout << "->>hi! I AM ALPHA" << endl;
while (datbot.good()) //first loop
{
while (ai) //second loop
{
loop = 0;
c++;
cout << c << ">>";
// USER INPUT
getline(cin, chats);
// DATABASE LOOP CONTROL
unsigned int count = 0;
// DATAFLOOR LOOP CONTROL
unsigned int number = 0;
while (loop == 0) // third loop
{
loop++;
cout << 'i' << endl;
while (getline(datbot, container)) // final loop
{
// cout << "pr" << endl;
count++;
catch = container;
// JUDGMENT TIME
if (catch == chats)
{
//LOOP OF HELL
while (getline(datbrot, contain))
{
num++;
// JUDGMENT TIME
if (number == count)
cout << "->>" << contain << endl;
}
}
}
}
}
}
}
As you can see on my code, there are four main while loops; the final loop is the loop to collect one line at a time, and, at first, it works perfectly. However, it is true and accessible on only the first run. It then is skipped while both the program is still running and other loops continue looping.
So my question is "Is there a way to keep the loop accessible when it is reached by the third loop while the program is still running, or can I keep the loop false after it has returned true?"
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My question is when I run the code,and call for the list,so I press 3,nothing happens and it just skips over the code in for(). Why does this occur and how can I fix it?
Simple code would be welcome.I am now to this.
The first two int before the main checks if the student is qualified for the school,or not.i tested those and they are working great.
The struct describes a student.He/She has a name(nev),marks (bacmagy,bacrom,bacmat,bacvalasz).A boolean value(langexam) is present,to represent is the student has a language exam or not.
bsiker is true,if the formula in calculateBac turns out to be true.
atmente is true,if bsiker and langexam are both true.
The listing would spit out the name,bsiker and atmente.
#include <iostream>
using namespace std;
int atmegye(bool elso, bool masodik){
if (elso && masodik)
return true;
else
return false;
}
int calculateBac(double magy, double mat, double rom, double val){
double osszeg = magy + mat + rom + val;
osszeg = osszeg / 4;
if (magy < 5 || mat < 5 || rom < 5 || val < 5 || osszeg < 6)
return false;
else
return true;
}
int main(){
struct diak{
char nev[32];
bool langexam, atmente, bsiker;
double bacmagy, bacrom, bacmat, bacvalasz, bac;
};
diak v[150];
bool cap = false;
int opcio;
int j, n = 0;
int i = 0;
do{
cout << "\n Welcome. \n 1-new studient \n 2-Change a studient's details \n 3-List \n 4-Exit \n";
cin >> opcio;
switch (opcio){
case 4:{
return 0;
}
case 1:{
cout << "Please give the name of the student: ";
cin >> v[i].nev;
cout << "Hungarian mark: ";
cin >> v[i].bacmagy;
cout << "Romanian mark: ";
cin >> v[i].bacrom;
cout << "Maths mark: ";
cin >> v[i].bacmat;
cout << "Optional mark: ";
cin >> v[i].bacvalasz;
cout << " Do you have a language exam? Please respond with 1 or 0: ";
cin >> v[i].langexam;
v[i].bsiker = calculateBac(v[i].bacmagy, v[i].bacrom, v[i].bacmat, v[i].bacvalasz);
v[i].atmente = atmegye(v[i].bsiker, v[i].langexam);
i = i + 1;
i = n;
cout << n;
break;
}
case 3: {
for(i = 0; i < n; i++)
cout << v[i].nev << " " << v[i].bsiker << " " << endl;
break;
}
}
}while (opcio != 5);
}
This line is wrong:
i = n;
it should be:
n = i;
Your code is just undoing the i = i + 1; line that precedes it.
n is initialized as 0 and never set to any other value. Therefore your for loop is not supposed to run any iteration
The problem is in the for loop's conditional. You initialized the value of n to 0, and that value never seems to change. The variable i is also initialized to 0 inside the for loop. When the user chooses option 3, the for loop conditional ( 0 < 0) is evaluated which is false, so the for loop is skipped every time. So, to fix this problem, you need to update the value of n somewhere in your code, or you need to change your conditional statement. Hope this helps!
I know this probably won't help for your assignment, but here's a (one of many) way to handle this is a more c++-like manner, and without using OOP.
The standard library and the c++ type system give us plenty of useful tools to avoid writing bugs in the first place (that's really nice!), and find the one that are left at compile-time (saves a ton of time!). That's what the biggest difference between c and c++ is, and it is a very important one.
#include <iostream>
#include <vector>
#include <string>
#include <string.h>
// fixed-size record to save in data file, for example.
struct diak{
char nev[32];
bool langexam, atmente, bsiker;
double bacmagy, bacrom, bacmat, bacvalasz, bac;
};
void atmegye(diak& student)
{
student.atmente = student.bsiker && student.langexam;
}
void calculateBac(diak& student) // computes grades average, checks if passed.
{
double osszeg = student.bacmagy + student.bacmat + student.bacrom + student.bacvalasz;
student.bac = osszeg / 4.0;
student.bsiker = student.bacmagy >= 5
&& student.bacrom >= 5
&& student.bacmat >= 5
&& student.bacvalasz >= 5
&& student.bac >= 5; // this last test unnecessary, but rules are rules.
}
void AddNewStudent(std::ostream& os, std::istream& is, std::vector<diak>& students)
{
diak new_student;
std::string temp;
while(temp.empty())
{
os << "Student name: ";
is >> temp; // using a temp buffer avoids out of bounds errors
}
if (temp.length() >= sizeof(new_student.nev))
temp.resize(sizeof(new_student.nev) - 1);
strcpy(new_student.nev, temp.c_str());
// input values below SHOULD be validated for range (0-100)
// or whatever makes sense for your school.
os << "Hungarian mark: "; is >> new_student.bacmagy;
os << "Romanian mark: "; is >> new_student.bacrom;
os << "Maths mark: "; is >> new_student.bacmat;
os << "Optional mark: "; is >> new_student.bacvalasz;
// example validation. Validating user input is the worst!
// above ^^^ grades ^^^ can use a common function for validation.
for(;;)
{
os << " Do you have a language exam? Please respond with 1 or 0:";
is >> temp;
if (temp == "0")
{
new_student.langexam = false;
break;
}
if (temp == "1")
{
new_student.langexam = true;
break;
}
// not a valid entry, try again!
}
calculateBac(new_student);
atmegye(new_student);
students.push_back(new_student);
}
void EditSudent(std::ostream& os, std::istream& is, std::vector<diak>& students)
{
// query which student then edit using streams 'os' and 'is' for i/o.
}
// could also be used to write to file...
void PrintStudents(std::ostream& os, const std::vector<diak>& students)
{
// maybe by printing a student number you could reuse this
// function from EditStudent()...
//
// At the same time, it is only 2 lines of code. You decide.
for(size_t i = 0; i < students.size(); i++)
os << students[i].nev << " " << students[i].bsiker << "\n";
os.flush();
}
int main()
{
std::vector<diak> students; // could also be an std::list<>
while(true) // 1 less line of code than do {...} while, and easier to read.
{
int opcio = 0;
std::cout << "\n Welcome."
"\n 1-new studient"
"\n 2-Change a studient's details"
"\n 3-List "
"\n 4-Exit \n";
std::cin >> opcio;
switch (opcio)
{
case '1':
AddNewStudent(std::cout, std::cin, students);
break;
case 2:
EditSudent(std::cout, std::cin, students); // << queries student and edit that
break;
case 3:
PrintStudents(std::cout, students);
break;
case 4:
return 0;
}
}
}
Note how the tasks are very well delimited into their own function, this also helps finding bugs faster, as it makes the code easier to read and reason about (the famous divide and conquer strategy).
Having the students array (or list) as a single entity simplifies its management, no extra variable to keep up to date, etc...
In a more serious application, the input validation would be best done using a template, and would give the user an escape character so he could cancel adding the new student at any time.
I want to create a program that when a user inputs something that I didn't define, the program prompts him again.
I did it with if statements but it only loops for 1 time and doesn't do it again. I tried loops but whenever the input is false it just breaks the condition and refuses all inputs alike. In c++.
Any help is much appreciated.
#include <iostream>
#include <string>
using namespace std;
void xD(){string x;
do{cout << "Retry\n";
cin >> x;}while(true);}
//declaring a function to make the shop
void shop(){
string x;
float coins = 500;
float bow_cost = 200;
cout << "welcome to the shop\n";
cout << "Bow(bow)costs 150 coins.\n";
cin >> x;
// if u chose bow you get this and get to choose again
if (x == "bow"){
cout << "you bought the bow.\n you now have " <<coins - bow_cost << " coins." << endl; cin >> x;}
/*now the problem that whenever I excute the code and type something other than bow it gives me the cin only once more and then fails even if I type bow in the 2nd attempt*/
//in my desperate 5k attempt, I tried creating a function for it.. no use.
//i want it o keep prompting me for input till i type "bow" and the other block excutes. but it never happens.
else{xD();}
}
int main(){
string name;
string i;
cout << "if you wish to visit the shop type \"shop\"\n";
cin >> i;
if(i == "shop"){shop();}
else{cin >> i;}
return 0;
}
The problem lies on the condition in this loop block
void xD(){
string x;
do{
cout << "Retry\n";
cin >> x;
}while(true);
}
The while(true) condition makes it loops forever regardless of the input. To fix this, you can change the condition:
void xD(){
string x;
do{
cout << "Retry\n";
cin >> x;
}while(x!="bow");
cout << "you bought the bow. and some other messages"<<endl;
}
That should work. However, it is still too complicated for me. This can be simplified into the snippet below:
void shop(){
string x;
float coins = 500;
float bow_cost = 200;
cout << "welcome to the shop\n";
cout << "Bow(bow)costs 150 coins.\n";
cin >> x;
while (x!="bow"){
cout << "Retry\n";
cin>>x;
}
cout << "you bought the bow.\n you now have " <<coins - bow_cost << " coins." << endl; cin >> x;
}
Instead of doing this approach (which is checking the condition only once):
if (x == "bow"){
cout << "you bought the bow.\n you now have " <<coins - bow_cost << "
coins." << endl; cin >> x;
} else{
xD();
}
which is actually a RECURSIVE invocation to the method xD()
you should do a do-while loop,
example:
while (x.compare("bow") != 0)
{
cout << "sorry, wrong input, try again...";
cin >> x;
}
note the use of the compare method instead of the == operator
here more about it in the documentation
You can use return value of cin >> [your input object] here to check status or istream's method fail(). As soon as input stream fails to parse whole or part of streams it fails and stay in state of failure until you clear it. Unparsed input is preserved (so you can try to parse it differently?)m so if you try to >> again to object of same type, you'll get same failure. To ignore N chars of imput, there is method
istream::ignore(streamsize amount, int delim = EOF)
Example:
int getInt()
{
while (1) // Loop until user enters a valid input
{
std::cout << "Enter an int value: ";
long long x; // if we'll use char, cin would assume it is character
// other integral types are fine
std::cin >> x;
// if (! (std::cin >> x))
if (std::cin.fail()) // has a previous extraction failed?
{
// yep, so let's handle the failure, or next >> will try parse same input
std::cout << "Invalid input from user.\n";
std::cin.clear(); // put us back in 'normal' operation mode
std::cin.ignore(std::numeric_limits<std::streamsize>::max(),'\n'); // and remove the bad input
}
// Thechnically you may do only the above part, but then you can't distingusih invalid format from out of range
else if(( x > std::numeric_limits<int>::max()) ||
( x < std::numeric_limits<int>::min()))
{
std::cout << "Invalid value.\n";
}
else // nope, so return our good x
return x;
}
}
For strings parsing is almost always successful but you'll need some mechanism of comparison of string you have and one that is allowed. Try look for use of std::find() and some container that would contain allowed options, e.g. in form of pair<int,string>, and use int index in switch() statement (or use find_if and switch() within the function you give to it).
Consider that if() statement is a one_direction road, it checks the condition and if the condition was satisfied it goes to its bracket and do blah blah blah , if there is any problem with condition compiler passes ifand jump to compile other codes.
Every time that you begin to compile the codes it begins from int main() function. You did the wrong thing in the if and else statements again
Here is the correct code .I did the necessary changes.
#include "stdafx.h"
#include <iostream>
#include <string>
using std::string;
using std::cin;
using std::cout;
#define coins 500 ;
#define bow_cost 200 ;
int shop(string x)
{
//There is no need to allocate extra memory for 500 and 200 while they are constant.``
cout << "welcome to the shop\n";
cout << "Bow(bow)costs 150 coins.\n";
do
{
cout << "Input another :\n";
cin >> x;
if (x == "bow")
{
return (coins - bow_cost); //return to function as integer
}
} while (true);
}
int main()
{
string name, i;
cout << "if you wish to visit the shop type \"shop\"\n";
cin >> i;
if (i == "shop")
{
cout << "Input :\n";
cin >> name;
cout << shop(name) << "you bought the bow.\n you now have " << " coins." << "\n";
}
//argument passed to shop funnction parameters.
system("pause");
return 0;
}
I'm new to programming and to c++ so I know this is probably a silly question but I would really appreciate the help. just as the tittle says, I'm trying to make a subtraction while type loop that reaches a desired value, in this case: 0
The code uses two random numbers from the user input. The first number is the minuend, the second is the subtrahend
However, the problem that I'm having is that if subtraction surpasses desired value, the loop will not display it and the user will see displayed a number higher value than 0. I want to fix so it displays the negative number closest to 0 and then stop. Here's the code:
#include <iostream>
using namespace std;
int main()
{
int a;
int b;
cout <<" enter a: ";
cin >> a;
cout << "enter b: ";
cin >> b;
while ( a > 0 )
{
cout << a << '\n';
a= a-b;
}
return 0;
}
What am I doing wrong, how can I fix it? Thanks
You're printing a before decreasing it. Try switching the statements inside your loop like so:
while ( a > 0 )
{
a = a - b;
cout << a << '\n';
}
You could just add
cout << a << '\n';
again after your loop - you know you have the right value then. Or you could possibly avoid duplicating that line by switching to using a do ... while loop.
Hi i just switched this code:
while ( a > 0 )
{
cout << a << '\n';
a= a-b;
}
to this and it worked as you explained:
while ( a > 0 )
{
a= a-b;
cout << a << '\n';
}
I'm just following a simple c++ tutorial on do/while loops and i seem to have copied exactly what was written in the tutorial but i'm not yielding the same results. This is my code:
int main()
{
int c=0;
int i=0;
int str;
do
{
cout << "Enter a num: \n";
cin >> i;
c = c + i;
cout << "Do you wan't to enter another num? y/n: \n";
cin >> str;
} while (c < 15);
cout << "The sum of the numbers are: " << c << endl;
system("pause");
return (0);
}
Right now, after 1 iteration, the loop just runs without asking for my inputs again and only calculating the sum with my first initial input for i.
However if i remove the second pair of cout/cin statements, the program works fine..
can someone spot my error please? thank you!
After you read the string with your cin >> str;, there's still a new-line sitting in the input buffer. When you execute cin >> i; in the next iteration, it reads the newline as if you just pressed enter without entering a number, so it doesn't wait for you to enter anything.
The usual cure is to put something like cin.ignore(100, '\n'); after you read the string. The 100 is more or less arbitrary -- it just limits the number of characters it'll skip.
If you change
int str;
to
char str;
Your loop works as you seem to intend (tested in Visual Studio 2010).
Although, you should also probably check for str == 'n', since they told you that they were done.
...and only calculating the sum with my first initial input for i...
This is an expected behavior, because you are just reading the str and not using it. If you enter i >= 15 then loop must break, otherwise continues.
I think you wanted this thing
In this case total sum c will be less than 15 and continue to sum if user inputs y.
#include<iostream>
using namespace std;
int main()
{
int c=0;
int i=0;
char str;
do
{
cout << "Enter a num: \n";
cin >> i;
c = c + i;
cout << "Do you wan't to enter another num? y/n: \n";
cin >> str;
} while (c < 15 && str=='y');
cout << "The sum of the numbers are: " << c << endl;
return 0;
}