Split string of digits into individual cells, including digits within parentheses/brackets - regex

Question

I have a column where each cell has a string of digits, ?, -, and digits in parentheses/brackets/curly brackets. A good example would be something like the following:
3????0{1012}?121-2[101]--01221111(01)1
How do I separate the string into different cells by characters, where a 'character' in this case refers to any number, ?, -, and value within the parentheses/brackets/curly brackets (including said parentheses/brackets/curly brackets)?
In essence, the string above would turn into the following (spaced apart to denote a separate cell):
3 ? ? ? ? 0 {1012} ? 1 2 1 - 2 [101] - - 0 1 2 2 1 1 1 1 (01) 1
The amount of numbers within the parentheses/brackets/curly brackets vary. There are no letters in any of the strings.

Answer 1

Here you are!
RegEx method:
Sub Test_RegEx()
Dim s, col, m
s = "3????0{1012}?121-2[101]--01221111(01)1"
Set col = CreateObject("Scripting.Dictionary")
With CreateObject("VBScript.RegExp")
.Global = True
.Pattern = "(?:\d|-|\?|\(\d+\)|\[\d+\]|\{\d+\})"
For Each m In .Execute(s)
col(col.Count) = m
Next
End With
MsgBox Join(col.items) ' 3 ? ? ? ? 0 {1012} ? 1 2 1 - 2 [101] - - 0 1 2 2 1 1 1 1 (01) 1
End Sub
Loop method:
Sub Test_Loop()
Dim s, col, q, t, k, i
s = "3????0{1012}?121-2[101]--01221111(01)1"
Set col = CreateObject("Scripting.Dictionary")
q = "_"
t = True
k = 0
For i = 1 To Len(s)
t = (t Or InStr(1, ")]}", q) > 0) And InStr(1, "([{", q) = 0
q = Mid(s, i, 1)
If t Then k = k + 1
col(k) = col(k) & q
Next
MsgBox Join(col.items) ' 3 ? ? ? ? 0 {1012} ? 1 2 1 - 2 [101] - - 0 1 2 2 1 1 1 1 (01) 1
End Sub

Answer 2

Something else to look at :)
Sub test()
'String to parse through
Dim aStr As String
'final string to print
Dim finalString As String
aStr = "3????0{1012}?121-2[101]--01221111(01)1"
'Loop through string
For i = 1 To Len(aStr)
'The character to look at
char = Mid(aStr, i, 1)
'Check if the character is an opening brace, curly brace, or parenthesis
Dim result As String
Select Case char
Case "["
result = loop_until_end(Mid(aStr, i + 1), "]")
i = i + Len(result)
result = char & result
Case "("
result = loop_until_end(Mid(aStr, i + 1), ")")
i = i + Len(result)
result = char & result
Case "{"
result = loop_until_end(Mid(aStr, i + 1), "}")
i = i + Len(result)
result = char & result
Case Else
result = Mid(aStr, i, 1)
End Select
finalString = finalString & result & " "
Next
Debug.Print (finalString)
End Sub
'Loops through and concatenate to a final string until the end_char is found
'Returns a substring starting from the character after
Function loop_until_end(aStr, end_char)
idx = 1
If (Len(aStr) <= 1) Then
loop_until_end = aStr
Else
char = Mid(aStr, idx, 1)
Do Until (char = end_char)
idx = idx + 1
char = Mid(aStr, idx, 1)
Loop
End If
loop_until_end = Mid(aStr, 1, idx)
End Function

Answer 3

Assuming the data is in column A starting in row 1 and that you want the results start in column B and going right for each row of data in column A, here is alternate method using only worksheet formulas.
In cell B1 use this formula:
=IF(OR(LEFT(A1,1)={"(","[","{"}),LEFT(A1,MIN(FIND({")","]","}"},A1&")]}"))),IFERROR(--LEFT(A1,1),LEFT(A1,1)))
In cell C1 use this formula:
=IF(OR(MID($A1,SUMPRODUCT(LEN($B1:B1))+1,1)={"(","[","{"}),MID($A1,SUMPRODUCT(LEN($B1:B1))+1,MIN(FIND({")","]","}"},$A1&")]}",SUMPRODUCT(LEN($B1:B1))+1))-SUMPRODUCT(LEN($B1:B1))),IFERROR(--MID($A1,SUMPRODUCT(LEN($B1:B1))+1,1),MID($A1,SUMPRODUCT(LEN($B1:B1))+1,1)))
Copy the C1 formula right until it starts giving you blanks (there are no more items left to split out from the string in the A cell). In your example, need to copy it right to column AA. Then you can copy the formulas down for the rest of your Column A data.