My program doesn't quite work right - c++

Question

#include <iostream>
using namespace std;
/* run this program using the console pauser or add your own getch, system("pause") or input loop */
string numString(int k)
{
string str;
switch (k) {
case 0 : str ="ZERO"; break;
case 1 : str ="ONE"; break;
case 2 : str ="TWO"; break;
case 3 : str ="THREE"; break;
case 4 : str ="FOUR"; break;
case 5 : str ="FIVE"; break;
case 6 : str ="SIX"; break;
case 7 : str ="SEVEN"; break;
case 8 : str ="EIGHT"; break;
case 9 : str ="NINE"; break;
}
return str;
}
int main(int argc, char** argv) {
int value;
int digit;
cout << "Enter a number: ";
cin >> value;
while (value > 0 )
{
digit = value % 10;
value = value / 10;
cout << numString(value) << endl;
}
return 0;
}
My program is supposed to prompt the user for an integer value read that value, and output the word equivalent of each digit
For example if "9502" was entered it would output "NINE FIVE ZERO TWO"
Yet mine only outputs "NINE ZERO" and then stops. I can't figure out what I'm doing wrong, any help at all is greatly appreciated.

Answer 1

Yet mine only outputs "NINE ZERO" and then stops.
That's literally what you told it to do!
while (value > 0 )
You'll have to find some other way to signal a "termination" condition if zero is supposed to be valid.
Traditionally we let the system's own end-of-file signalling take care of that for us, so that we don't have to "reserve" some otherwise-valid input and use it as a signal flag.
while (cin >> value) {
digit = value % 10;
value = value / 10;
cout << numString(value) << endl;
}
That fixes your loop, although unfortunately your maths are still wrong and your output is not what you intend. In fact, your digit variable is not used at all. I am not going to spoonfeed an algorithm here: you'll have to work out on paper how to achieve the business logic. :)

Answer 2

This is an analysis of your program using the input 9502.
Iteration 1, in main:
(new) value = 9502 / 10;
(new) digit = 9502 % 10;
value == 950;
digit == 2;
call numString(950);
// Note: there is no case for 950 in numString so an empty string is returned.
Iteration 2, in main:
(new) value = 950 / 10;
(new) digit = 950 % 2;
value == 95;
digit == 0;
call numString(95);
// Note: there is no case for 95 in numString so an empty string is returned.
The above iterations and variable values can be obtained with pen & paper (or a note pad). You can also do the same with something called a debugger.
I hope this helps.