add user input to a list in Scala - list

Question

import scala.collection.mutable.MutableList
var x = false
while (!x) {
val list = MutableList[Any]()
val input = scala.io.StdIn.readLine("input pls:\n")
list += input
if (input == "end"){ x = true ; println("Bye!"); sys.exit}
if (input =="show") {println(list)}
}
So whenever I run this program and then enter "show" to print the list it only prints out "show" in the list but why not the other input I have done before? What do I have to change in order to store all the input into my list (append) till i type "show" or "end?

Answer 1

All you need to do is move initialization of list variable up:
val list = MutableList[Any]()
while (!x) {
// ...
}
The way you have it now, a new list is created in every loop iteration and thus previous content is lost.

Answer 2

Scala 2.11.7 on Ubuntu 15.04 / OpenJDK8
I added a line feed "\n" removal function called .stripLineEnd thinking this was needed for the ifs to match, but apparently that is unnecessary and will work fine with or without.
From Documentation:
def stripLineEnd: String
Strip trailing line end character
from this string if it has one.
A line end character is one of
LF - line feed (0x0A hex)
FF - form feed (0x0C hex)
If a line feed
character LF is preceded by a carriage return CR (0x0D hex), the CR
character is also stripped (Windows convention).
And, as #Mifeet said, the code was initializing the list on every loop and need to move the initialization to before the loop.
import scala.collection.mutable.MutableList
var x = false
val list = MutableList[Any]()
while (!x) {
val input = scala.io.StdIn.readLine("input pls:\n").stripLineEnd
list += input
if (input == "end"){ x = true ; println("Bye!"); sys.exit}
if (input =="show") {println(list)}
}