Properly terminating program. Using exceptions - c++

Question:
Is using exceptions the proper way to terminate my program if all I want is to display an error message and close (accounting that I may be deep in the program)? Or can I just explicitly call something like exit(EXIT_FAILURE) instead?
What I'm Currently Doing:
I'm working on a game project and am trying to figure out the best way to terminate the program in the case of an error that calls for such an action. For example, in the case the textures can't be loaded I display an error message and terminate the program.
I'm currently doing this with exceptions like so:
int main()
{
Game game;
try
{
game.run();
}
catch (BadResolutionException & e)
{
Notification::showErrorMessage(e.what(), "ERROR: Resolution");
return 1;
}
catch (BadAssetException & e)
{
Notification::showErrorMessage(e.what(), "ERROR: Assets");
return 1;
}
catch (std::bad_alloc & e)
{
Notification::showErrorMessage(e.what(), "ERROR: Memory");
return 1;
}
return 0;
}
All but bad_alloc are my own defined exceptions derived from runtime_error.
I don't need any manual resource cleanup and I'm using std::unique_ptr for any dynamic allocation. I just need to display the error message and close the program.
Research/Alternatives to Exceptions:
I've looked up a lot of posts on SO and other places and have seen others say anything from don't use exceptions, to use exceptions but your using them wrong. I've also looked up explicitly calling something like exit().
Using exit() sounds nice but I read it won't go back through the call stack up to main cleaning everything up (if I can find this again I'll post the link). Additionally, according to http://www.cplusplus.com/reference/cstdlib/exit/ this should not be used if multiple threads are active. I do expect to be creating a second thread for a short time at least once, and an error could occur in that thread.
Not using exceptions was mentioned in some replies here in relation to games https://gamedev.stackexchange.com/questions/103285/how-industy-games-handle-their-code-errors-and-exceptions
Use exceptions was discussed here: http://www.quora.com/Why-do-some-people-recommend-not-using-exception-handling-in-C++
There are a number of other sources I've read but those were the most recent I looked at.
Personal Conclusion:
Due to my limited experience of working with error handling and using exceptions, I'm not sure if I'm on the right track. I've chosen the route of using exceptions based on the code I posted above. If you agree that I should tackle those cases with exceptions, am I using it correctly?

It's generally considered good practice to let all exceptions propagate through to main. This is primarily because you can be sure the stack is properly unwound and all destructors are called (see this answer). I also think it's more organised to do things this way; you always known where your program will terminate (unless the program crashes). It's also facilitates more consistent error reporting (a point often neglected in exception handling; if you can't handle the exception, you should make sure your user knows exactly why). If you always start with this basic layout
int main(int argc, const char **argv)
{
try {
// do stuff
return EXIT_SUCCESS;
} catch (...) {
std::cerr << "Error: unknown exception" << std::endl;
return EXIT_FAILURE;
}
}
then you won't go far wrong. You can (and should) add specific catch statements for better error reporting.
Exceptions when multithreading
There are two basic ways of executing code asynchronously in C++11 using standard library features: std::async and std::thread.
First the simple one. std::async will return a std::future which will capture and store any uncaught exceptions thrown in the given function. Calling std::future::get on the future will cause any exceptions to propagate into the calling thread.
auto fut = std::async(std::launch::async, [] () { throw std::runtime_error {"oh dear"}; });
fut.get(); // fine, throws exception
On the other hand, if an exception in a std::thread object is uncaught then std::terminate will be called:
try {
std::thread t {[] () { throw std::runtime_error {"oh dear"};}};
t.join();
} catch(...) {
// only get here if std::thread constructor throws
}
One solution to this could be to pass a std::exception_ptr into the std::thread object which it can pass the exception to:
void foo(std::exception_ptr& eptr)
{
try {
throw std::runtime_error {"oh dear"};
} catch (...) {
eptr = std::current_exception();
}
}
void bar()
{
std::exception_ptr eptr {};
std::thread t {foo, std::ref(eptr)};
try {
// do stuff
} catch(...) {
t.join(); // t may also have thrown
throw;
}
t.join();
if (eptr) {
std::rethrow_exception(eptr);
}
}
Although a better way is to use std::package_task:
void foo()
{
throw std::runtime_error {"oh dear"};
}
void bar()
{
std::packaged_task<void()> task {foo};
auto fut = task.get_future();
std::thread t {std::move(task)};
t.join();
auto result = fut.get(); // throws here
}
But unless you have good reason to use std::thread, prefer std::async.

There's nothing wrong with catching unrecoverable errors and shutting down your program this way. In fact, it's how exceptions should be used. However, be careful not to cross the line of using exceptions to control the flow of your program in ordinary circumstances. They should always represent an error which cannot be gracefully handled at the level the error occurred.
Calling exit() would not unwind the stack from wherever you called it. If you want to exit cleanly, what you're already doing is ideal.

You have already accepted an answer, but I wanted to add something about this:
Can I just explicitly call something like exit() instead?
You can call exit, but (probably) shouldn't.
std::exit should be reserved for situations where you want to express "exit right now!", not simply "application has nothing left to do".
As an example, if you were to write a controller for a laser used in cancer treatments, your first priority in case something went wrong would be to shut down the laser and call std::exit - or possibly std::terminate (to ensure any side effects of a hanging, slow or crashing application do not kill a patient).
Similar to how exceptions should not be used for controlling application flow, exit should not be used to stop the application in normal conditions.

Is using exceptions the proper way to terminate my program if all I want is to display an error message and close (accounting that I may be deep in the program)?
Yes. This is the reason for using exceptions. An error occurred deep down in the code and something at a higher level will handle it. In your case, at the highest level.
There are arguments for/against exceptions vs. error codes, and this is a good read:
Exceptions or error codes
Can I just explicitly call something like exit() instead?
You can, but you may end up duplicating your logging code. Also, if in the future you decide that you want to handle an exception differently you will have to change all your exit calls. Imagine you wanted a different message, or to fall back on an alternative process.
Another similar question:
Correct usage of exit() in c++?
You also have a flaw in your approach as you don't handle all (C++) exceptions. You want something like this:
int main()
{
Game game;
try
{
game.run();
}
catch (BadResolutionException & e)
{
Notification::showErrorMessage(e.what(), "ERROR: Resolution");
return 1;
}
catch (BadAssetException & e)
{
Notification::showErrorMessage(e.what(), "ERROR: Assets");
return 1;
}
catch (std::bad_alloc & e)
{
Notification::showErrorMessage(e.what(), "ERROR: Memory");
return 1;
}
catch (...)
{
// overload?
Notification::showErrorMessage("ERROR: Unhandled");
return 1;
}
return 0;
}
If you don't handle all* exceptions you could have the game terminate without telling you anything useful.
You can't handle ALL exceptions. See this link:
C++ catching all exceptions

From the documentation:
[[noreturn]] void exit (int status);
Terminate calling process
Terminates the process normally, performing the regular cleanup for terminating programs.
Normal program termination performs the following (in the same order):
Objects associated with the current thread with thread storage duration are destroyed (C++11 only).
Objects with static storage duration are destroyed (C++) and functions registered with atexit are called.
All C streams (open with functions in ) are closed (and flushed, if buffered), and all files created with tmpfile are removed.
Control is returned to the host environment.
Note that objects with automatic storage are not destroyed by calling exit (C++).
If status is zero or EXIT_SUCCESS, a successful termination status is returned to the host environment.
If status is EXIT_FAILURE, an unsuccessful termination status is returned to the host environment.
Otherwise, the status returned depends on the system and library implementation.
For a similar function that does not perform the cleanup described above, see quick_exit.

Related

Stop program flow in the middle without using an exception

I need to stop the program flow in the middle, and I am currently using an exception for this. This flow is the legal flow and I want to know if I can do it without using an exception.
This is an example of my code, and I cannot change func_2 and func_1:
#include "stdio.h"
void func_3()
{
printf("i am func_3\n");
throw 20;
printf("i am not supposed to be here\n");
}
void func_2()
{
printf("i am func_2\n");
func_3();
printf("i am not supposed to be here\n");
}
void func_1()
{
printf("i am func_1\n");
func_2();
printf("i am not supposed to be here\n");
}
int main()
{
try
{
func_1();
}
catch (int e)
{
printf("i am supposed to be here\n");
}
catch (...)
{
printf("i am not supposed to be here\n");
}
}
I assume that you want to handle an exceptional case and are looking for an alternative to exceptions. I.e. I hope you don't want to continue with the program "normally" after handling your exceptional case, which is possible but not recommended to implement with exceptions.
Possible but not recommended alternatives to exceptions are:
When you want to stop your whole application, then you can use std::exit(0);. You can implement your "catch"-code in a function which you call instead of your "throw"-statement, and call std::exit(0); at the end of that function (or use another exit code to indicate an "unsuccessful" exit). Or you implement an exit handler and register it using std::atexit(&handle_exit);.
Alternative to std::exit(<something>); is abort(); which throws the POSIX signal "SIGABRT" to indicate abnormal termination (which is the default behavior if your program throws and doesn't catch an exception). Your "catch"-code would then go in a signal handler which you register using the POSIX functions. Note that this requires a POSIX system and is thus not as portable as other solutions.
Another (similar) option is to use the "terminate" mechanism: Call std::terminate(); when you would normally throw your exception. Put your "catch"-code in a "terminate handler" function with signature void(*)(), i.e. no parameters and no return value, let's call the function void handle_terminate(). Install a terminate handler using std::set_terminate(&handle_terminate);. I didn't try that one, however, and it sounds damn ugly.
You could implement an exception-like behavior using assembly instructions, but please do not try this at home, as the behavior of such code is highly implementation defined (if not undefined), and way too ugly to implement.
In short, you can't (well ... you could, by using jumps instead, but then you would have two problems to solve).
The exception solution is the one to use, but do not throw a number (a number - especially a magical number in this case doesn't tell you anything).
Instead, define a struct func_3_interrupted {}; minimalistic structure, whose type name tells you it is an "interruption" of func_3, and catch that instead; The structure should be empty (or close to empty) and it should probably not inherit from the std::exception hierarchy.
Return can be used to return to the caller and stop the function being executed
int GLOBAL_FLAG = 1;
function called_function(){
printf("Inside Function")
if(/*some condition*/)
{
GLOBAL_FLAG = 0;
return;
}
/*Normal function code*/
}
int main(){
{
called_function();
if(GLOBAL_FLAG == 1)/*continue program execution*/
printf("Function had been executed.Back to normal flow")
}
So once the return statement is encountered it goes back to the caller that is main here and continues executing rest of the statements in main function.

How do I make a C++ console program exit?

Is there a line of code that will terminate the program?
Something like python's sys.exit()?
While you can call exit() (and may need to do so if your application encounters some fatal error), the cleanest way to exit a program is to return from main():
int main()
{
// do whatever your program does
} // function returns and exits program
When you call exit(), objects with automatic storage duration (local variables) are not destroyed before the program terminates, so you don't get proper cleanup. Those objects might need to clean up any resources they own, persist any pending state changes, terminate any running threads, or perform other actions in order for the program to terminate cleanly.
#include <cstdlib>
...
exit( exit_code );
There are several ways to cause your program to terminate. Which one is appropriate depends on why you want your program to terminate. The vast majority of the time it should be by executing a return statement in your main function. As in the following.
int main()
{
f();
return 0;
}
As others have identified this allows all your stack variables to be properly destructed so as to clean up properly. This is very important.
If you have detected an error somewhere deep in your code and you need to exit out you should throw an exception to return to the main function. As in the following.
struct stop_now_t { };
void f()
{
// ...
if (some_condition())
throw stop_now_t();
// ...
}
int main()
{
try {
f();
} catch (stop_now_t& stop) {
return 1;
}
return 0;
}
This causes the stack to be unwound an all your stack variables to be destructed. Still very important. Note that it is appropriate to indicate failure with a non-zero return value.
If in the unlikely case that your program detects a condition that indicates it is no longer safe to execute any more statements then you should use std::abort(). This will bring your program to a sudden stop with no further processing. std::exit() is similar but may call atexit handlers which could be bad if your program is sufficiently borked.
Yes! exit(). It's in <cstdlib>.
Allowing the execution flow to leave main by returning a value or allowing execution to reach the end of the function is the way a program should terminate except under unrecoverable circumstances. Returning a value is optional in C++, but I typically prefer to return EXIT_SUCCESS found in cstdlib (a platform-specific value that indicates the program executed successfully).
#include <cstdlib>
int main(int argc, char *argv[]) {
...
return EXIT_SUCCESS;
}
If, however, your program reaches an unrecoverable state, it should throw an exception. It's important to realise the implications of doing so, however. There are no widely-accepted best practices for deciding what should or should not be an exception, but there are some general rules you need to be aware of.
For example, throwing an exception from a destructor is nearly always a terrible idea because the object being destroyed might have been destroyed because an exception had already been thrown. If a second exception is thrown, terminate is called and your program will halt without any further clean-up having been performed. You can use uncaught_exception to determine if it's safe, but it's generally better practice to never allow exceptions to leave a destructor.
While it's generally always possible for functions you call but didn't write to throw exceptions (for example, new will throw std::bad_alloc if it can't allocate enough memory), it's often difficult for beginner programmers to keep track of or even know about all of the special rules surrounding exceptions in C++. For this reason, I recommend only using them in situations where there's no sensible way for your program to continue execution.
#include <stdexcept>
#include <cstdlib>
#include <iostream>
int foo(int i) {
if (i != 5) {
throw std::runtime_error("foo: i is not 5!");
}
return i * 2;
}
int main(int argc, char *argv[]) {
try {
foo(3);
}
catch (const std::exception &e) {
std::cout << e.what() << std::endl;
return EXIT_FAILURE;
}
return EXIT_SUCCESS;
}
exit is a hold-over from C and may result in objects with automatic storage to not be cleaned up properly. abort and terminate effectively causes the program to commit suicide and definitely won't clean up resources.
Whatever you do, don't use exceptions, exit, or abort/terminate as a crutch to get around writing a properly structured program. Save them for exceptional situations.
if you are in the main you can do:
return 0;
or
exit(exit_code);
The exit code depends of the semantic of your code. 1 is error 0 e a normal exit.
In some other function of your program:
exit(exit_code)
will exit the program.
This SO post provides an answer as well as explanation why not to use exit(). Worth a read.
In short, you should return 0 in main(), as it will run all of the destructors and do object cleanup. Throwing would also work if you are exiting from an error.
In main(), there is also:
return 0;
#include <cstdlib>
...
/*wherever you want it to end, e.g. in an if-statement:*/
if (T == 0)
{
exit(0);
}
throw back to main which should return EXIT_FAILURE,
or std::terminate() if corrupted.
(from Martin York's comment)
else if(Decision >= 3)
{
exit(0);
}
exit(0); // at the end of main function before closing curly braces
simple enough..
exit ( 0 );
}//end of function
Make sure there is a space on both sides of the 0. Without spaces, the program will not stop.

Is it possible to enter the terminate_handler twice?

I have some clean up in a terminate_handler and it is possible to throw an exception. Do I need to worry about catching it to prevent recursive calls to the terminate_handler? With gcc, it seems this can't happen and we just go into abort. Is that true of the standard or is the behavior undefined?
A terminate handler is not allowed to return (§18.6.​3.1/2); it must end the program (the default handler calls abort()). If it consisted of:
void my_terminate()
{
throw 5;
}
You'd get undefined behavior, because you would leave the function (because the exception propagates) without having terminated the program. So if you have code that could throw, make sure you catch all exceptions, like this:
void my_terminate()
{
try
{
// stuff
}
catch(...)
{
// too bad
}
abort();
}
However (to answer the title question), I don't see anything that restricts it from being entered again, so this should be technically be fine:
void my_terminate()
{
static int counter = 0;
if (counter++ < 5)
terminate();
abort();
}
No, you cannot resume normal program flow from std::terminate. You can, however, throw a different exception from the unexpected function. Terminate does just that -- program execution terminates after it completes.
EDIT:
That said, you shouldn't be doing anything complicated in std::terminate -- if you're in terminate then things have blown up sufficiently that you should not be trying to continue -- and you shouldn't try to do things like allocate memory in std::terminate for the same reason -- what if the program is in there as a result of a low memory condition? There's nothing you can do about it there.

What happens if I use "throw;" without an exception to throw?

Here's the setup.
I have a C++ program which calls several functions, all of which potentially throw the same exception set, and I want the same behaviour for the exceptions in each function
(e.g. print error message & reset all the data to the default for exceptionA; simply print for exceptionB; shut-down cleanly for all other exceptions).
It seems like I should be able to set the catch behaviour to call a private function which simply rethrows the error, and performs the catches, like so:
void aFunction()
{
try{ /* do some stuff that might throw */ }
catch(...){handle();}
}
void bFunction()
{
try{ /* do some stuff that might throw */ }
catch(...){handle();}
}
void handle()
{
try{throw;}
catch(anException)
{
// common code for both aFunction and bFunction
// involving the exception they threw
}
catch(anotherException)
{
// common code for both aFunction and bFunction
// involving the exception they threw
}
catch(...)
{
// common code for both aFunction and bFunction
// involving the exception they threw
}
}
Now, what happens if "handle" is called outside of the exception class.
I'm aware that this should never happen, but I'm wondering if the behaviour is undefined by the C++ standard.
If handle() is called outside the context of an exception, you will throw without an exception being handled. In this case, the standard (see section 15.5.1) specifies that
If no exception is presently being handled, executing a throw-expression with no operand calls terminate().
so your application will terminate. That's probably not what you want here.
If you use throw inside of a catch block, it will rethrow the exception. If you use throw outside of a catch block, it will terminate the application.
Never, never, never use catch(...) as you might catch application errors that you don't want to catch, e.g. bugs, access violations (depending on how you compiled).
Read the great John Robbins book (Debugging Windows Applications) in which he explains more in detail why you shouldn't do it.

How can I propagate exceptions between threads?

We have a function which a single thread calls into (we name this the main thread). Within the body of the function we spawn multiple worker threads to do CPU intensive work, wait for all threads to finish, then return the result on the main thread.
The result is that the caller can use the function naively, and internally it'll make use of multiple cores.
All good so far..
The problem we have is dealing with exceptions. We don't want exceptions on the worker threads to crash the application. We want the caller to the function to be able to catch them on the main thread. We must catch exceptions on the worker threads and propagate them across to the main thread to have them continue unwinding from there.
How can we do this?
The best I can think of is:
Catch a whole variety of exceptions on our worker threads (std::exception and a few of our own ones).
Record the type and message of the exception.
Have a corresponding switch statement on the main thread which rethrows exceptions of whatever type was recorded on the worker thread.
This has the obvious disadvantage of only supporting a limited set of exception types, and would need modification whenever new exception types were added.
C++11 introduced the exception_ptr type that allows to transport exceptions between threads:
#include<iostream>
#include<thread>
#include<exception>
#include<stdexcept>
static std::exception_ptr teptr = nullptr;
void f()
{
try
{
std::this_thread::sleep_for(std::chrono::seconds(1));
throw std::runtime_error("To be passed between threads");
}
catch(...)
{
teptr = std::current_exception();
}
}
int main(int argc, char **argv)
{
std::thread mythread(f);
mythread.join();
if (teptr) {
try{
std::rethrow_exception(teptr);
}
catch(const std::exception &ex)
{
std::cerr << "Thread exited with exception: " << ex.what() << "\n";
}
}
return 0;
}
Because in your case you have multiple worker threads, you will need to keep one exception_ptr for each of them.
Note that exception_ptr is a shared ptr-like pointer, so you will need to keep at least one exception_ptr pointing to each exception or they will be released.
Microsoft specific: if you use SEH Exceptions (/EHa), the example code will also transport SEH exceptions like access violations, which may not be what you want.
Currently, the only portable way is to write catch clauses for all the types of exceptions that you might like to transfer between threads, store the information somewhere from that catch clause and then use it later to rethrow an exception. This is the approach taken by Boost.Exception.
In C++0x, you will be able to catch an exception with catch(...) and then store it in an instance of std::exception_ptr using std::current_exception(). You can then rethrow it later from the same or a different thread with std::rethrow_exception().
If you are using Microsoft Visual Studio 2005 or later, then the just::thread C++0x thread library supports std::exception_ptr. (Disclaimer: this is my product).
If you're using C++11, then std::future might do exactly what you're looking for: it can automagically trap exceptions that make it to the top of the worker thread, and pass them through to the parent thread at the point that std::future::get is called. (Behind the scenes, this happens exactly as in #AnthonyWilliams' answer; it's just been implemented for you already.)
The down side is that there's no standard way to "stop caring about" a std::future; even its destructor will simply block until the task is done. [EDIT, 2017: The blocking-destructor behavior is a misfeature only of the pseudo-futures returned from std::async, which you should never use anyway. Normal futures don't block in their destructor. But you still can't "cancel" tasks if you're using std::future: the promise-fulfilling task(s) will continue running behind the scenes even if nobody is listening for the answer anymore.] Here's a toy example that might clarify what I mean:
#include <atomic>
#include <chrono>
#include <exception>
#include <future>
#include <thread>
#include <vector>
#include <stdio.h>
bool is_prime(int n)
{
if (n == 1010) {
puts("is_prime(1010) throws an exception");
throw std::logic_error("1010");
}
/* We actually want this loop to run slowly, for demonstration purposes. */
std::this_thread::sleep_for(std::chrono::milliseconds(100));
for (int i=2; i < n; ++i) { if (n % i == 0) return false; }
return (n >= 2);
}
int worker()
{
static std::atomic<int> hundreds(0);
const int start = 100 * hundreds++;
const int end = start + 100;
int sum = 0;
for (int i=start; i < end; ++i) {
if (is_prime(i)) { printf("%d is prime\n", i); sum += i; }
}
return sum;
}
int spawn_workers(int N)
{
std::vector<std::future<int>> waitables;
for (int i=0; i < N; ++i) {
std::future<int> f = std::async(std::launch::async, worker);
waitables.emplace_back(std::move(f));
}
int sum = 0;
for (std::future<int> &f : waitables) {
sum += f.get(); /* may throw an exception */
}
return sum;
/* But watch out! When f.get() throws an exception, we still need
* to unwind the stack, which means destructing "waitables" and each
* of its elements. The destructor of each std::future will block
* as if calling this->wait(). So in fact this may not do what you
* really want. */
}
int main()
{
try {
int sum = spawn_workers(100);
printf("sum is %d\n", sum);
} catch (std::exception &e) {
/* This line will be printed after all the prime-number output. */
printf("Caught %s\n", e.what());
}
}
I just tried to write a work-alike example using std::thread and std::exception_ptr, but something's going wrong with std::exception_ptr (using libc++) so I haven't gotten it to actually work yet. :(
[EDIT, 2017:
int main() {
std::exception_ptr e;
std::thread t1([&e](){
try {
::operator new(-1);
} catch (...) {
e = std::current_exception();
}
});
t1.join();
try {
std::rethrow_exception(e);
} catch (const std::bad_alloc&) {
puts("Success!");
}
}
I have no idea what I was doing wrong in 2013, but I'm sure it was my fault.]
You problem is that you could receive multiple exceptions, from multiple threads, as each could fail, perhaps from different reasons.
I am assuming the main thread is somehow waiting for the threads to end to retrieve the results, or checking regularly the other threads' progress, and that access to shared data is synchronized.
Simple solution
The simple solution would be to catch all exceptions in each thread, record them in a shared variable (in the main thread).
Once all threads finished, decide what to do with the exceptions. This means that all other threads continued their processing, which perhaps, is not what you want.
Complex solution
The more complex solution is have each of your threads check at strategic points of their execution, if an exception was thrown from another thread.
If a thread throws an exception, it is caught before exiting the thread, the exception object is copied into some container in the main thread (as in the simple solution), and some shared boolean variable is set to true.
And when another thread tests this boolean, it sees the execution is to be aborted, and aborts in a graceful way.
When all thread did abort, the main thread can handle the exception as needed.
An exception thrown from a thread will not be catchable in the parent thread. Threads have different contexts and stacks, and generally the parent thread is not required to stay there and wait for the children to finish, so that it could catch their exceptions. There is simply no place in code for that catch:
try
{
start thread();
wait_finish( thread );
}
catch(...)
{
// will catch exceptions generated within start and wait,
// but not from the thread itself
}
You will need to catch exceptions inside each thread and interpret exit status from threads in the main thread to re-throw any exceptions you might need.
BTW, in the absents of a catch in a thread it is implementation specific if stack unwinding will be done at all, i.e. your automatic variables' destructors may not even be called before terminate is called. Some compilers do that, but it's not required.
Could you serialize the exception in the worker thread, transmit that back to the main thread, deserialize, and throw it again? I expect that for this to work the exceptions would all have to derive from the same class (or at least a small set of classes with the switch statement thing again). Also, I'm not sure that they would be serializable, I'm just thinking out loud.
There is, indeed, no good and generic way to transmit exceptions from one thread to the next.
If, as it should, all your exceptions derive from std::exception, then you can have a top-level general exception catch that will somehow send the exception to the main thread where it will be thrown again. The problem being you loose the throwing point of the exception. You can probably write compiler-dependent code to get this information and transmit it though.
If not all your exception inherit std::exception, then you are in trouble and have to write a lot of top-level catch in your thread ... but the solution still hold.
You will need to do a generic catch for all exceptions in the worker (including non-std exceptions, like access violations), and send a message from the worker thread (i suppose you have some kind of messaging in place?) to the controlling thread, containing a live pointer to the exception, and rethrow there by creating a copy of the exception.
Then the worker can free the original object and exit.
See http://www.boost.org/doc/libs/release/libs/exception/doc/tutorial_exception_ptr.html. It is also possible to write a wrapper function of whatever function you call to join a child thread, which automatically re-throws (using boost::rethrow_exception) any exception emitted by a child thread.