Find edge of black and white image - c++

I need to find the edge and generate points of a black and white image like the one below:
I am not sure how to go about doing this. I know OpenCV is an option, but that is way overkill for what is sure to be a simple task. Does anyone know any easy way to do this? Libraries are okay, as long as they aren't too heavyweight (header only preferred)


I would use a Canny Edge Detection, though you can easily experiment with the others that #therainmaker suggests. I would use ImageMagick which is free and installed on most Linux distros and also available for OS X and Windows.
At the command line, you would use this:
convert blob.png -canny 0x1+10%+30% result.png
or this:
convert blob.png -canny 0x1+10%+30% -negate result.png
To use with C++, you would use Magick++, which is described here. There is a reasonable tutorial here.
If you want a description of the theory and examples of usage, including Sobel etc, please look at Anthony Thyssen's excellent pages here.
Depending on what you are actually doing, you may be better served by a Morphological technique (shape detection) rather than an Edge Detection technique. If so, ImageMagick can do that for you also. For example:
convert blob.png -morphology EdgeIn Octagon edgein.png
That technique is described nicely here.
If, you want the outline as a vector path, you can combine ImageMagick and potrace through an intermediate PBM file like this:
convert blob.png -canny 0x1+10%+30% -negate pbm:- | potrace -s -o result.svg
That will give you a nice smooth vector path like this:
<?xml version="1.0" standalone="no"?>
<!DOCTYPE svg PUBLIC "-//W3C//DTD SVG 20010904//EN"
"http://www.w3.org/TR/2001/REC-SVG-20010904/DTD/svg10.dtd">
<svg version="1.0" xmlns="http://www.w3.org/2000/svg"
width="745.000000pt" height="1053.000000pt" viewBox="0 0 745.000000 1053.000000"
preserveAspectRatio="xMidYMid meet">
<metadata>
Created by potrace 1.12, written by Peter Selinger 2001-2015
</metadata>
<g transform="translate(0.000000,1053.000000) scale(0.100000,-0.100000)"
fill="#000000" stroke="none">
<path d="M6145 8276 c-159 -39 -545 -231 -975 -485 -276 -163 -313 -179 -630
-267 -567 -157 -1108 -385 -1550 -652 -182 -111 -178 -107 -359 -289 -173
-174 -351 -387 -483 -579 -42 -61 -84 -116 -92 -123 -8 -7 -18 -25 -21 -41 -3
-16 -13 -34 -21 -41 -8 -7 -27 -33 -41 -58 -14 -25 -41 -68 -58 -96 -18 -27
-48 -81 -66 -120 -18 -38 -44 -83 -57 -100 -38 -46 -183 -353 -246 -516 -142
-373 -156 -550 -76 -979 76 -403 215 -867 299 -999 40 -62 121 -138 167 -157
58 -24 119 -32 179 -22 74 11 276 94 775 316 423 188 561 243 900 362 568 199
1059 434 1478 706 261 170 403 298 552 496 261 346 439 756 494 1138 38 261
72 696 81 1025 8 272 17 342 72 554 85 332 112 563 79 691 -49 188 -210 283
-401 236z m221 -27 c64 -30 115 -84 150 -155 28 -57 29 -64 28 -199 0 -165
-16 -262 -84 -531 -59 -229 -67 -295 -75 -569 -13 -471 -64 -995 -120 -1230
-86 -363 -361 -858 -621 -1119 -229 -229 -721 -529 -1279 -778 -220 -99 -319
-138 -615 -242 -340 -120 -556 -208 -1001 -406 -581 -260 -633 -278 -736 -259
-103 20 -207 116 -273 253 -106 221 -260 821 -301 1176 -35 311 33 578 273
1062 37 75 78 149 91 165 12 15 38 60 56 98 18 39 48 93 66 120 17 28 44 71
58 96 14 25 33 51 41 58 8 7 18 25 21 41 3 16 13 34 21 41 8 7 50 62 92 123
207 300 562 688 732 801 45 30 85 55 88 55 3 0 37 20 76 44 375 232 967 478
1521 631 268 74 353 108 535 216 333 197 793 440 927 491 143 54 243 59 329
17z"/>
</g>
</svg>


What you are looking for is edge detection. If the image is an clean as the one posted above, the results of edge detection will be perfect, and no other processing will be needed to done after it.
So how do we do the edge detection? I'm assuming you know that an image is stored as a 2D matrix with intensity values in the computer. So, if you applied a mask over the image, i.e. take a small matrix, compute its values at different points of the image, and substitute the value at the center of the matrix by the computed result, you can do edge detection.
There are many masks for this purpose. I suggest you look at Sobell, Roberts and Prewit filters. One of the simplest filters you can use is
0 1 0
1 -4 1
0 1 0
You can do this in openCV (but I don't have much experience in it). My preferred tool is by MATLAB. You can use their inbuilt functions such as edge (here's a tutorial), or write a simple code in which you use two for loops to iterate over all pixels in the image and calculate the values applied by these filters.

Related

Clojure: Sets, order and purity

Is (vec #{1 2 3}) guaranteed to always return [1 3 2] or could the order be different?
I am not so much interested in the implementation details behind this but going from unordered to ordered in general in order to keep my functions pure and easily testable.

As mentioned, standard #{} sets (both PersistentArrayMap and PersistentHashMap; depending on the size) are considered unordered.
Regarding purity with respect to calling seq on a set though, the current implementation does seem to return a well-defined, consistent order; just not an easily predictable one:
(let [r (range 1000)
seqs (repeatedly 1000 #(seq (add-randomly #{} r)))]
; See how many different orders were produced
(println (count (set seqs)))
(println (first seqs)))
1
(0 893 920 558 453 584 487 637 972 519 357 716 950 275 530 929 789 389 586 410 433 765 521 451 291 443 798 779 970 249 638 299 121 734 287 65 702 70 949 218 648 812 62 74 774 475 497 580 891 164 282 769 799 273 186 430 641 529 898 370 834 233 298 188 240 110 130 982 620 311 931 882 128 399 989 377 468 259 210 229 153 621 213 670 977 343 958 887 472 7 894 59 934 473 86 756 830 613 491 154 20 224 355 592 610 806 571 466 72 454 888 463 851 770 814 859 58 964 980 205 555 552 60 835 459 175 322 510 662 27 352 493 899 416 777 694 1 631 854 69 101 24 901 547 102 788 713 385 988 135 397 773 490 752 354 884 360 998 961 55 568 797 688 763 269 676 448 527 206 966 165 715 387 652 683 85 721 862 615 681 225 865 297 39 805 274 88 217 46 682 508 149 415 239 478 878 157 345 300 743 921 4 550 204 470 646 77 106 197 405 897 726 776 940 755 902 518 232 260 823 267 119 319 534 222 603 293 95 450 329 144 504 819 818 505 723 992 176 863 471 349 512 710 192 54 92 221 141 502 871 464 801 307 935 758 290 627 517 361 264 137 356 728 976 678 327 234 856 817 104 353 15 48 945 759 242 832 969 50 956 917 557 251 394 116 585 583 75 437 516 994 930 967 687 159 848 995 709 99 540 645 749 479 890 630 916 815 281 402 669 781 740 975 429 309 458 21 388 495 952 626 875 31 113 32 811 827 407 398 136 691 847 825 139 506 396 460 483 589 581 932 174 578 855 331 363 284 208 305 955 796 708 182 256 657 514 731 619 985 485 214 193 685 804 869 836 785 635 442 561 954 656 607 241 314 782 226 235 672 420 418 262 263 304 401 673 40 129 600 729 467 445 317 294 91 810 364 987 880 515 412 553 974 341 117 665 523 172 601 108 156 358 308 908 649 531 923 223 419 365 944 181 417 979 278 56 942 33 13 867 22 618 380 257 338 500 909 993 168 833 496 947 347 501 596 872 792 90 237 826 292 109 216 191 498 829 761 375 525 367 143 742 178 640 247 328 391 990 167 707 36 41 474 187 551 996 528 971 599 376 195 889 316 668 428 303 671 794 905 368 560 565 310 366 118 522 150 886 313 384 567 238 846 962 845 196 162 393 184 219 999 461 89 100 426 604 477 844 541 351 243 131 790 963 629 873 122 933 43 231 61 654 883 598 413 29 784 800 151 369 348 575 693 44 739 258 250 674 539 301 838 424 93 6 684 951 573 408 563 850 616 866 111 997 689 28 456 374 608 737 548 538 895 411 957 134 943 64 623 465 816 334 323 189 280 198 155 295 808 248 587 285 507 227 724 476 941 911 853 494 220 842 103 697 611 170 51 25 261 768 822 201 904 590 489 778 166 447 34 252 978 775 325 594 436 828 535 813 146 741 876 228 907 306 125 276 340 148 482 622 588 17 312 606 3 520 760 720 286 279 879 536 663 12 440 332 330 382 152 544 803 642 435 342 703 783 695 973 2 948 66 484 439 236 556 373 142 359 727 371 772 444 570 757 107 532 984 23 745 719 230 625 47 526 180 786 870 537 659 158 991 350 35 849 644 881 127 927 675 383 533 910 302 564 701 566 821 787 82 76 735 492 718 771 215 97 704 277 926 751 19 335 597 938 57 609 202 68 452 200 868 11 115 946 983 339 431 462 337 698 255 503 546 9 953 857 706 632 457 427 145 5 733 624 831 244 918 824 289 112 925 730 699 712 414 839 802 860 179 344 481 732 661 245 378 913 906 658 266 324 793 680 446 524 254 404 617 283 513 572 705 959 83 634 138 346 14 455 265 449 333 650 639 569 326 746 647 45 53 559 78 924 562 542 912 664 315 914 480 132 753 900 26 766 123 203 667 392 577 807 140 321 795 441 700 268 840 16 320 133 288 381 605 163 81 120 643 79 211 38 173 126 981 421 593 636 98 422 423 614 762 582 666 554 409 574 595 124 747 171 87 169 653 679 843 160 30 400 767 896 928 696 738 809 509 736 207 874 434 690 194 511 73 486 336 96 837 937 10 660 272 499 488 903 386 270 576 717 543 271 18 395 403 469 105 185 52 545 633 114 968 253 612 628 748 209 147 655 750 852 425 864 67 296 602 318 161 651 725 372 406 438 780 711 71 939 579 877 722 42 919 80 885 986 714 677 199 841 754 791 861 591 744 960 37 183 965 892 432 379 63 212 94 362 8 686 692 764 246 190 549 922 177 915 936 820 49 858 390 84)
So yes, it seems that within a single run of a program, the order of (seq #{1 2 3}) can be relied upon, and can be considered pure. The language gives no guarantees though, and this property may not always exist, so really, I wouldn't rely on it. It's an implementation detail.
If you require a consistent ordering, it may be beneficial to have a vector along with the set to define the order. You could do something like:
(def pair [#{} []])
(defn add [p n]
(-> p
(update 0 conj n)
(update 1 conj n)))
(-> pair
(add 1)
(add 2))
=> [#{1 2} [1 2]]
Reference the set when you want to do a membership test, and the vector when you need order. Of course, this requires twice as much memory as it otherwise would though, so this may not always be practical. Additions to both sets and vectors are essentially constant however, so additions will still be quick.

How do you Resample daily with a conditional statement in pandas

I have a pandas data frame below: (it does have other columns but these are the important ones) Date column is the Index
Number_QA_VeryGood Number_Valid_Cells Time
Date
2015-01-01 91 92 18:55
2015-01-02 6 6 18:00
2015-01-02 13 13 19:40
2015-01-03 106 106 18:45
2015-01-05 68 68 18:30
2015-01-06 111 117 19:15
2015-01-07 89 97 18:20
2015-01-08 86 96 19:00
2015-01-10 9 16 18:50
I need to resample daily the first two columns will be resampled with sum.
The last column needs to look at the highest daily value for the Number_Valid_Cells column and use that time for the value.
example output should be: (1/2/02 is line which changed)
Number_QA_VeryGood Number_Valid_Cells Time
Date
2015-01-01 91 92 18:55
2015-01-02 19 19 19:40
2015-01-03 106 106 18:45
2015-01-05 68 68 18:30
2015-01-06 111 117 19:15
2015-01-07 89 97 18:20
2015-01-08 86 96 19:00
2015-01-10 9 16 18:50
What is the best way to get this to work.

Or you can try
df.groupby(df.index).agg({'Number_QA_VeryGood':'sum','Number_Valid_Cells':'sum','Time':'last'})
Out[276]:
Time Number_QA_VeryGood Number_Valid_Cells
Date
2015-01-01 18:55 91 92
2015-01-02 19:40 19 19
2015-01-03 18:45 106 106
2015-01-05 18:30 68 68
2015-01-06 19:15 111 117
2015-01-07 18:20 89 97
2015-01-08 19:00 86 96
2015-01-10 18:50 9 16
Update: sort_values first
df.sort_values('Number_Valid_Cells').groupby(df.sort_values('Number_Valid_Cells').index)\
.agg({'Number_QA_VeryGood':'sum','Number_Valid_Cells':'sum','Time':'last'})
Out[314]:
Time Number_QA_VeryGood Number_Valid_Cells
Date
1/1/2015 18:55 91 92
1/10/2015 18:50 9 16
1/2/2015 16:40#here.changed 19 19
1/3/2015 18:45 106 106
1/5/2015 18:30 68 68
1/6/2015 19:15 111 117
1/7/2015 18:20 89 97
1/8/2015 19:00 86 96
Data input :
Number_QA_VeryGood Number_Valid_Cells Time
Date
1/1/2015 91 92 18:55
1/2/2015 6 6 18:00
1/2/2015 13 13 16:40#I change here
1/3/2015 106 106 18:45
1/5/2015 68 68 18:30
1/6/2015 111 117 19:15
1/7/2015 89 97 18:20
1/8/2015 86 96 19:00
1/10/2015 9 16 18:50

You can use groupby sum for first two columns, if you have the values of Number_Valid_Cells sorted then
ndf = df.reset_index().groupby('Date').sum()
ndf['Time'] = df.reset_index().drop_duplicates(subset='Date',keep='last').set_index('Date')['Time']
Number_QA_VeryGood Number_Valid_Cells Time
Date
2015-01-01 91 92 18:55
2015-01-02 19 19 19:40
2015-01-03 106 106 18:45
2015-01-05 68 68 18:30
2015-01-06 111 117 19:15
2015-01-07 89 97 18:20
2015-01-08 86 96 19:00
2015-01-10 9 16 18:50

double free or corruption (fasttop): 0x000000000063d070 *** c++ sieve program

I am writing a sieve program in c++. But for every legitimate input, the program always produces output with 4 primes founded and "2 3 5", no matter how the input varies. As I try to run the program via the console, it gives an error message saying that double free or corruption (fasttop): 0x000000000063d070 ***. Btw, I am new to c++.
And also, I am trying to format the output correctly, but the they are just flying around.
This is the desired format.
2 3 5 7 11 13 17 19 23 29 31 37 41 43 47 53 59 61 67 71
73 79 83 89 97 101 103 107 109 113 127 131 137 139 149 151 157 163 167 173
179 181 191 193 197 199 211 223 227 229 233 239 241 251 257 263 269 271 277 281
283 293 307 311 313 317 331 337 347 349 353 359 367 373 379 383 389 397 401 409
419 421 431 433 439 443 449 457 461 463 467 479 487 491 499 503 509 521 523 541
547 557 563 569 571 577 587 593 599 601 607 613 617 619 631 641 643 647 653 659
661 673 677 683 691 701 709 719 727 733 739 743 751 757 761 769 773 787 797 809
811 821 823 827 829 839 853 857 859 863 877 881 883 887 907 911 919 929 937 941
947 953 967 971 977 983 991 997

Aside from your double-free being caused by calling the destructor explicitly as #PaulMcKenzie said in the comments, your problem with only outputting the first few primes is because of this line:
int n = sizeof(is_prime_);
is_prime_ is a pointer and so its size is fixed at compile time (probably 4 or 8 bytes depending on your system).
You already have limit_ as a value, you should use that to work out your n.

Verifying output to "Find the numbers between 1 and 1000 whose prime factors' sum is itself a prime" from Allain's Jumping into C++ (ch7 #3)

The question:
Design a program that finds all numbers from 1 to 1000 whose prime factors, when added
together, sum up to a prime number (for example, 12 has prime factors of 2, 2, and 3, which
sum to 7, which is prime). Implement the code for that algorithm.
I modified the problem to only sum unique factors, because I don't see why you'd count a factor twice, as in his example using 12.
My solution. Is there any good (read: automated) way to verify the output of my program?
Sample output for 1 to 1000:
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
17
19
20
22
23
24
25
26
28
29
30
31
34
37
40
41
43
44
46
47
48
49
52
53
58
59
60
61
63
67
68
70
71
73
76
79
80
82
83
88
89
92
94
96
97
99
101
103
107
109
113
116
117
118
120
121
124
127
131
136
137
139
140
142
147
148
149
151
153
157
160
163
164
167
169
171
172
173
176
179
181
184
188
189
191
192
193
197
198
199
202
207
210
211
212
214
223
227
229
232
233
239
240
241
244
251
252
257
261
263
268
269
271
272
273
274
275
277
279
280
281
283
286
289
292
293
294
297
298
306
307
311
313
317
320
325
331
332
333
334
337
347
349
351
352
353
358
359
361
367
368
369
373
376
379
382
383
384
388
389
394
396
397
399
401
404
409
412
414
419
421
423
424
425
428
431
433
439
443
449
454
457
459
461
462
463
464
467
468
472
475
478
479
480
487
491
495
499
503
509
513
521
522
523
524
529
531
538
539
541
544
546
547
548
549
550
557
560
561
562
563
567
569
571
572
575
577
587
588
593
594
599
601
603
604
605
607
612
613
617
619
621
622
628
631
639
640
641
643
646
647
651
652
653
659
661
664
668
673
677
683
684
691
692
694
701
704
709
712
714
718
719
725
726
727
733
736
738
739
741
743
751
752
756
757
759
761
764
765
768
769
772
773
775
777
783
787
792
797
798
801
809
811
821
823
825
827
828
829
833
837
838
839
841
846
847
848
850
853
856
857
859
862
863
873
877
881
883
887
891
892
903
904
907
908
909
911
918
919
922
925
928
929
932
937
941
944
947
953
954
957
960
961
966
967
971
975
977
981
983
991
997
999
Update: I have solved my problem and verified the output of my program using an OEIS given series, as suggested by #MVW (shown in the source given by my new github solution). In the future, I will aim to test my programs by doing zero or more of the following (depending on the scope/importance of the problem):
google keywords for an existing solution to the problem, comparing it against my solution if I find it
unit test components for correctness as they're built and integrated, comparing these tests with known correct outputs

Some suggestions:
You need to check the properties of your calculated numbers.
Here that means
calculating the prime factors and
calculating their sum and
testing if that sum is a prime number.
Which is what your program should do in the first place, by the way.
So one nice option for checking is comparing your output with a known solution or the output of a another program which is known to work. The tricky bit is to have such a solution or program available. And I neglect that your comparison could be plagued by errors as well :-)
If you just compare it with other implementations, e.g. programs from other folks here, it would turn out more of a voting, it would not be a proof. It would just give increased probability that your program is correct, if several independent implementations come up with the same result. Of course all implementations could err :-)
The more agree the better.
And the more diverse the implementations are, the better.
E.g. you could use different programming languages, algebraic systems or a friend with time and paper and pencil and Wikipedia. :-)
Another means is to add checks to your intermediate steps, to get more confidence in your result. Kind of building a chain of trust.
You could output the prime factors you determined and compare it with the output
of a prime factorization program which is known to work.
Then you check if your summing works.
Finally you could check if the primality test you apply to the candidate sums is working correctly by feeding it with known prime numbers and non prime numbers and so on.
That is kind of what folks do with unit testing for example. Trying to cover most parts of the code as working, hoping if the parts work, that the whole will work.
Or you could formally prove your program step by step, using Hoare Calculus for example or another formal method.
But that is tricky, and you might end up shifting program errors to errors in the proof.
And today, in the era of internet, of course, you could internet search for the solution:
Try searching for sum of prime factors is prime in the online encyclopedia of integer sequences, which should give you series A100118. :-)
It is the problem with multiplicity, but shows you what the number theory pros do, with Mathematica and program fragments to calculate the series, the argument for the case of 1 and literature. Quite impressive.

Here's the answer I get. I exclude 1 as it has no prime divisors so their sum is 0, not a prime.
Haskell> filter (isPrime . sum . map fst . primePowers) [2..1000]
[2,3,4,5,6,7,8,9,10,11,12,13,16,17,18,19,20,22,23,24,25,27,29,31,32,34,36,37,40,
41,43,44,47,48,49,50,53,54,58,59,61,64,67,68,71,72,73,79,80,81,82,83,88,89,96,97
,100,101,103,107,108,109,113,116,118,121,125,127,128,131,136,137,139,142,144,149
,151,157,160,162,163,164,165,167,169,173,176,179,181,191,192,193,197,199,200,202
,210,211,214,216,223,227,229,232,233,236,239,241,242,243,250,251,256,257,263,269
,271,272,273,274,277,281,283,284,288,289,293,298,307,311,313,317,320,324,328,331
,337,343,345,347,349,352,353,358,359,361,367,373,379,382,383,384,385,389,390,394
,397,399,400,401,404,409,419,420,421,428,431,432,433,435,439,443,449,454,457,461
,462,463,464,467,472,478,479,484,486,487,491,495,499,500,503,509,512,521,523,529
,538,541,544,547,548,557,561,562,563,568,569,570,571,576,577,578,587,593,595,596
,599,601,607,613,617,619,622,625,630,631,640,641,643,647,648,651,653,656,659,661
,665,673,677,683,691,694,701,704,709,714,715,716,719,727,729,733,739,743,751,757
,759,761,764,768,769,773,777,780,787,788,795,797,798,800,808,809,811,819,821,823
,825,827,829,838,839,840,841,853,856,857,858,859,862,863,864,877,881,883,885,887
,903,907,908,911,919,922,924,928,929,930,937,941,944,947,953,956,957,961,967,968
,971,972,977,983,991,997,1000]
Haskell> primePowers 12
[(2,2),(3,1)]
Haskell> primePowers 14
[(2,1),(7,1)]
You could hard-code this list in and test against it. I'm pretty confident these results are without error.
(read . is "of").

Qt application killed because Out Of Memory (OOM)

I am running a Qt application on embedded Linux platform. The system has 128 MB RAM, 512MB NAND, no swap. The application uses a custom library for the peripherals, the rest are all Qt and c/c++ libs. The application uses SQLITE3 as well.
After 2-3 hours, the machine starts running very slow, shell commands take 10 or so seconds to respond. Eventually the machine hangs, and finally OOM killer kills the application, and the system starts behaving at normal speed.
After some system memory observations using top command reveals that while application is running, the system free memory is decreasing, while slab keeps on increasing. These are the snaps of top given below. The application is named xyz.
At Application start :
Mem total:126164 anon:3308 map:8436 free:32456
slab:60936 buf:0 cache:27528 dirty:0 write:0
Swap total:0 free:0
PID VSZ VSZRW^ RSS (SHR) DIRTY (SHR) STACK COMMAND
776 29080 9228 8036 528 968 0 84 ./xyz -qws
781 3960 736 1976 1456 520 0 84 sshd: root#notty
786 3676 680 1208 764 416 0 88 /usr/libexec/sftp-server
770 3792 568 1948 1472 464 0 84 {sshd} sshd: root#pts/0
766 3792 568 956 688 252 0 84 /usr/sbin/sshd
388 1864 284 552 332 188 0 84 udevd --daemon
789 2832 272 688 584 84 0 84 top
774 2828 268 668 560 84 0 84 -sh
709 2896 268 556 464 80 0 84 /usr/sbin/inetd
747 2828 268 596 516 68 0 84 /sbin/getty -L ttymxc0 115200 vt100
777 2824 264 444 368 68 0 84 tee out.log
785 2824 264 484 416 68 0 84 sh -c /usr/libexec/sftp-server
1 2824 264 556 488 64 0 84 init
After some time :
Mem total:126164 anon:3312 map:8440 free:9244
slab:83976 buf:0 cache:27584 dirty:0 write:0
Swap total:0 free:0
PID VSZ VSZRW^ RSS (SHR) DIRTY (SHR) STACK COMMAND
776 29080 9228 8044 528 972 0 84 ./xyz -qws
781 3960 736 1976 1456 520 0 84 sshd: root#notty
786 3676 680 1208 764 416 0 88 /usr/libexec/sftp-server
770 3792 568 1948 1472 464 0 84 {sshd} sshd: root#pts/0
766 3792 568 956 688 252 0 84 /usr/sbin/sshd
388 1864 284 552 332 188 0 84 udevd --daemon
789 2832 272 688 584 84 0 84 top
774 2828 268 668 560 84 0 84 -sh
709 2896 268 556 464 80 0 84 /usr/sbin/inetd
747 2828 268 596 516 68 0 84 /sbin/getty -L ttymxc0 115200 vt100
777 2824 264 444 368 68 0 84 tee out.log
785 2824 264 484 416 68 0 84 sh -c /usr/libexec/sftp-server
1 2824 264 556 488 64 0 84 init
Funnily though, I can not see any major changes in the output of top involving the application itself. Eventually the application is killed, top output after that :
Mem total:126164 anon:2356 map:916 free:2368
slab:117944 buf:0 cache:1580 dirty:0 write:0
Swap total:0 free:0
PID VSZ VSZRW^ RSS (SHR) DIRTY (SHR) STACK COMMAND
781 3960 736 708 184 520 0 84 sshd: root#notty
786 3724 728 736 172 484 0 88 /usr/libexec/sftp-server
770 3792 568 648 188 460 0 84 {sshd} sshd: root#pts/0
766 3792 568 252 0 252 0 84 /usr/sbin/sshd
388 1864 284 188 0 188 0 84 udevd --daemon
819 2832 272 676 348 84 0 84 top
774 2828 268 512 324 96 0 84 -sh
709 2896 268 80 0 80 0 84 /usr/sbin/inetd
747 2828 268 68 0 68 0 84 /sbin/getty -L ttymxc0 115200 vt100
785 2824 264 68 0 68 0 84 sh -c /usr/libexec/sftp-server
1 2824 264 64 0 64 0 84 init
The dmesg shows :
sh invoked oom-killer: gfp_mask=0xd0, order=2, oomkilladj=0
[<c002d4c4>] (unwind_backtrace+0x0/0xd4) from [<c0073ac0>] (oom_kill_process+0x54/0x1b8)
[<c0073ac0>] (oom_kill_process+0x54/0x1b8) from [<c0073f14>] (__out_of_memory+0x154/0x178)
[<c0073f14>] (__out_of_memory+0x154/0x178) from [<c0073fa0>] (out_of_memory+0x68/0x9c)
[<c0073fa0>] (out_of_memory+0x68/0x9c) from [<c007649c>] (__alloc_pages_nodemask+0x3e0/0x4c8)
[<c007649c>] (__alloc_pages_nodemask+0x3e0/0x4c8) from [<c0076598>] (__get_free_pages+0x14/0x4c)
[<c0076598>] (__get_free_pages+0x14/0x4c) from [<c002f528>] (get_pgd_slow+0x14/0xdc)
[<c002f528>] (get_pgd_slow+0x14/0xdc) from [<c0043890>] (mm_init+0x84/0xc4)
[<c0043890>] (mm_init+0x84/0xc4) from [<c0097b94>] (bprm_mm_init+0x10/0x138)
[<c0097b94>] (bprm_mm_init+0x10/0x138) from [<c00980a8>] (do_execve+0xf4/0x2a8)
[<c00980a8>] (do_execve+0xf4/0x2a8) from [<c002afc4>] (sys_execve+0x38/0x5c)
[<c002afc4>] (sys_execve+0x38/0x5c) from [<c0027d20>] (ret_fast_syscall+0x0/0x2c)
Mem-info:
DMA per-cpu:
CPU 0: hi: 0, btch: 1 usd: 0
Normal per-cpu:
CPU 0: hi: 42, btch: 7 usd: 0
Active_anon:424 active_file:11 inactive_anon:428
inactive_file:3 unevictable:0 dirty:0 writeback:0 unstable:0
free:608 slab:29498 mapped:14 pagetables:59 bounce:0
DMA free:692kB min:268kB low:332kB high:400kB active_anon:0kB inactive_anon:0kB active_file:4kB inactive_file:0kB unevictable:0kB present:24384kB pages_scanned:0 all_unreclaimable? no
lowmem_reserve[]: 0 103 103
Normal free:1740kB min:1168kB low:1460kB high:1752kB active_anon:1696kB inactive_anon:1712kB active_file:40kB inactive_file:12kB unevictable:0kB present:105664kB pages_scanned:0 all_unreclaimable? no
lowmem_reserve[]: 0 0 0
DMA: 3*4kB 3*8kB 5*16kB 2*32kB 4*64kB 2*128kB 0*256kB 0*512kB 0*1024kB 0*2048kB 0*4096kB = 692kB
Normal: 377*4kB 1*8kB 4*16kB 1*32kB 2*64kB 0*128kB 0*256kB 0*512kB 0*1024kB 0*2048kB 0*4096kB = 1740kB
30 total pagecache pages
0 pages in swap cache
Swap cache stats: add 0, delete 0, find 0/0
Free swap = 0kB
Total swap = 0kB
32768 pages of RAM
687 free pages
1306 reserved pages
29498 slab pages
59 pages shared
0 pages swap cached
Out of memory: kill process 774 (sh) score 339 or a child
Killed process 776 (xyz)
So it's obvious that there is a memory leak, it must be my app since my app is killed. But I am not doing any malloc s from the program. I have taken care as to limit the scope of variables so that they are deallocated after they are used. So I am at a complete loss as to why is slab increasing in the top output. I have tried http://valgrind.org/docs/manual/faq.html#faq.reports but didn't work.
Currently trying to use Valgrind on desktop (since I have read it only works for arm-cortex) to check my business logic.
Addittional info :
root#freescale ~/Application/app$ uname -a
Linux freescale 2.6.31-207-g7286c01 #2053 Fri Jun 22 10:29:11 IST 2012 armv5tejl GNU/Linux
Compiler : arm-none-linux-gnueabi-4.1.2 glibc2.5
cpp libs : libstdc++.so.6.0.8
Qt : 4.7.3 libs
Any pointers would be greatly appreciated...

I don't think the problem is directly in your code.
The reason is obvious: your application space does not increase (both RSS and VSW do not increase).
However, you do see the number of slabs increasing. You cannot use or increase the number of slabs from your application - it's a kernel-only thingie.
Some obvious causes of slab size increase from the top of my head:
you never really close network sockets
you read many files, but never close them
you use many ioctls
I would run strace and look at its output for a while. strace intercepts interactions with the kernel. If you have memory issues, I'd expect repeated calls to brk(). If you have other issues, you'll see repeated calls to open without close.

If you have some data structure allocation, check for the correctness of adding children and etc.. I had similar bug in my code. Also if you make big and large queries to the database it may use more ram memory. Try to find some memory leak detector to find if there is any leak.