regex: extract text blocks, defined beginning, undefined end - regex

Question

i have text like this:
Date: 01.02.2015 //<-stable format
something
something more
some random more
Date: 02.02.2015
something random
i dont know
so i have many such blocks. Starts with Date... ends with next Date... start.
The text in the lines in the block could be anything, but not Date... format
I need an array at the end, with such blocks:
array[0] = "Date: 01.02.2015
something
something more
some random more"
array[1] = "Date: 02.02.2015
something random
i dont know"
for now i add some unique splitter before Date... than split by the splitter.
Question: is it possible to get such blocks only by regex?
(i use VBA to parse the text, RegExp object)

Answer 1

Instead of split just match using
\bDate:\s\d{1,2}\.\d{1,2}\.\d{4}[\s\S]*?(?=\nDate:|$)
See demo.
https://regex101.com/r/uF4oY4/77
Syntax explanation (from the linked site):
\b assert position at a word boundary: (^\w|\w$|\W\w|\w\W)
Date: matches the characters Date: literally (case sensitive)
\s matches any whitespace character (equal to [\r\n\t\f\v ])
\d{1,2} matches a digit (equal to [0-9]) between 1 and 2 times, as many times as possible, giving back as needed (greedy)
. matches the character . literally (case sensitive)
\d{1,2} matches a digit (equal to [0-9]) between 1 and 2 times, as many times as possible, giving back as needed (greedy)
. matches the character . literally (case sensitive)
\d{4} matches a digit (equal to [0-9]) exactly 4 times
\s matches any whitespace character (equal to [\r\n\t\f\v ])
\S matches any non-whitespace character (equal to [^\r\n\t\f\v ])
*? Quantifier — Matches between zero and unlimited times, as few times as possible, expanding as needed (lazy) , what specified in previous brackets
?= Positive Lookahead - Assert that the following Regex matches
\nDate Option 1
\n matches a line-feed (newline) character (ASCII 10)
Date matches the characters Date: literally (case sensitive)
$: Option 2 - $ asserts position at the end of the string, or before the line terminator right at the end of the string (if any)