Here are my codes:
#include <iostream>
#include <string>
using namespace std;
int main()
{
int age1;
int age2;
string name1;
string name2;
cout << "Please enter the name for one people: " << "\n";
getline (cin, name1);
cout << "Please enter the age for this people: " << "\n";
cin >> age1;
cout << "Please enter the name for another people: " << "\n";
getline (cin, name2);
cout << "Please enter the age for this people too: " << "\n";
cin >> age2;
if ( (age1 <= 100 || age2 <= 100) && (age1 < age2) )
{
cout << name1 << " is younger!" << "\n";
}
else if ( (age1 <= 100 || age2 <= 100) && (age1 > age2) )
{
cout << name2 << " is younder!" << "\n";
}
else if ( (age1 <= 100 || age2 <= 100) && (age1 = age2) )
{
cout << name1 << " and " << name2 << " are of the same age!" << "\n";
}
else
{
cout << "You've got some really old people that are well older than 100!";
}
}
The first getline and cin works fine. I am able to be prompted to input.
However, the second getline and cin are prompted at once, thus I can only input for cin. (The second getline is skipped!)
If I use four cins, the program will work properly.
cin >> age1; does not read the newline character following the number. The newline remains in the input buffer, then prematurely stops the second getline.
So, your program already works as long as you enter the first age and the second name on the same line.
One solution would be to skip whitespace after the numbers:
cin >> age1 >> ws;
Live demo.
first: cin>>age; It takes the number and stores into age but at the same
time it leaves the newline character in the buffer itself. so when there is prompt for next name cin finds that left over newline character in the buffer and takes it as the input. that it why it escapes the name2 prompt.
cout << "Please enter the name for one people: " << "\n";
cin>>name1;
cout << "Please enter the age for this people: " << "\n";
cin >> age1;<<--**this left the new line character in input buffer**
cin.get();<<-- **get that newline charachter out of there first**
cout << "Please enter the name for another people: " << "\n";
getline (cin, name2);
cout << "Please enter the age for this people too: " << "\n";
cin >> age2;
now i give name1-> shishir age1->28
name2->ccr age-> 22 it prints ccr is younder!<-- the spelling is wrong too :D
for more info on getline and get() read c++ primer plus listing 4.3, 4.4, 4.5
Happy coding
You need a ; after getline (cin, name);
hope this helps
I would suggest using cin.ignore(100,'\n'). It ignores the amount of characters you specify when you call it(100 in the example above), up to the char you specify as a breakpoint. For example:
cout << "Please enter the name for one people: " << "\n";
getline (cin, name1);
cout << "Please enter the age for this people: " << "\n";
cin >> age1;
cin.ignore(100, '\n');
cout << "Please enter the name for another people: " << "\n";
getline (cin, name2);
cout << "Please enter the age for this people too: " << "\n";
cin >> age2;
cin.ignore(100, '\n');
Related
This question already has answers here:
Using getline(cin, s) after cin [duplicate]
(13 answers)
Closed 5 years ago.
#include<iostream>
#include<string>
#include<cstring>
using namespace std;
void cpp_string();
void cstyle_string();
int main()
{
cpp_string();
cstyle_string();
system("pause");
return 0;
}
void cpp_string()
{
string fName, lName;
char grade;
int age;
cout << "What is your first name?";
getline(cin, fName);
cout << "What is your last name?";
getline(cin, lName);
cout << "What letter grade do you deserve?";
cin >> grade;
cout << "What is your age?";
cin >> age;
cout << "Name: " << fName << ", " << lName << endl;
cout << "Grade: " << grade << endl;
cout << "Age: " << age << endl;
return;
}
void cstyle_string()
{
char fNm[20], lNm[20];
char grade;
int age;
cout << "What is your first name?";
cin.get(fNm, 20).get();
cin.clear();
cout << "What is your last name?";
cin.get(lNm, 20).get();
cout << "What letter grade do you deserve?";
cin >> grade;
cout << "What is your age?";
cin >> age;
cout << "Name: " << fNm << ", " << lNm << endl;
cout << "Grade: " << grade << endl;
cout << "Age: " << age << endl;
return;
}
I'm getting output as
What is your first name?demiurge conon
What is your last name?no
What letter grade do you deserve?a
What is your age?22
Name: demiurge conon, no
Grade: a
Age: 22
What is your first name?What is your last name?What letter grade do you deserve?What is your age?Name: ,
Grade: ╠
Age: -858993460
Press any key to continue . . .
but if I run cstyle_string() in different file then I'm not getting any errors code works perfectly.
I want to know why this is happening?
There are two question.
Redundant \n
the state of cin
The last cin in cpp_string is cin >> age.
It will leave a \n not extracted.
In first of cstyle_string is cin.get(fNm, 20).get();
The delimiting character is not extracted from the input sequence if found, and remains there as the next character to be extracted from the stream
the cin.get(FNm, 20) will parse empty input before \n, and no characters are available in the stream in actually. In this case, the failbit flag will be set and next all cin >> operator will fail.
You can only call cstyle_string and press enter directly, the same thing will happen.
How do i do that without switching the sequence of asking the questions in my program? I would like to get their age, before asking about the course. However, once the age is keyed in, the program automatically proceeds to print the while/if statement.
#include<iostream>
#include<string>
using namespace std;
int main()
{
int age; //Declares the variable "age"
string name;
string course;
cout << "Hi\n"; //Prints out "Hello World"
cout << "What is your name? ";
getline(cin, name);
cout << "\nHow old are you ? "; //Ask the user their age
cin >> age; //Records the value entered by user
cout << "What course are you picking up in university ? ";
getline(cin, course);
//If number entered is smaller than 0, print the following message
while (age < 0 ) {
cout << "\nYou can't be younger than 0 years old.";
cout << "\nPlease try again";
cout << "\n\nHow old are you ? ";
cin >> age;
}
//If number entered is larger than 100, print the following message
if (age > 100) {
cout << "\nYou are such a blessed person !\n\n";
}
//If number entered is between 1 and 99, print the following message
if (age > 1 && age < 99) {
cout << "Your name is " << name << " ,and you are " << age << " years old.";
cout << "\n You are planning on taking " << course << " in university.";
}
return 0;
}
If getline() is used after cin >>, the getline() sees this newline character as leading whitespace, and it just stops reading any further.
Solution:
Call cin.ignore() before calling getline()
Or
Make a dummy call getline() to consume the trailing newline character from the cin>>
#include<iostream>
#include<string>
using namespace std;
int main()
{
int age; //Declares the variable "age"
string name;
string course;
cout << "Hi\n"; //Prints out "Hello World"
cout << "What is your name? ";
getline(cin, name);
while(true) {
cout << "\nHow old are you ? "; //Ask the user their age
cin >> age; //Records the value entered by user
if(age>=0)
break;
cout << "\nYou can't be younger than 0 years old.\nPlease try again.";
}
cout << "What course are you picking up in university ? ";
getline(cin, course);
//If number entered is larger than 100, print the following message
if (age > 100) {
cout << "\nYou are such a blessed person !\n\n";
}
//If number entered is between 1 and 99, print the following message
if (age > 1 && age < 99) {
cout << "Your name is " << name << " ,and you are " << age << " years old.";
cout << "\n You are planning on taking " << course << " in university.";
}
return 0;
}
I have looked around and can't seem to find an answer to this. I am new to C++ and am attempting to write a program for a class that asks the user for the first and last names of 4 students and their ages. The program will then display the input names and ages and also display the average of the ages.
The issue I am having is that the program allows for input of the first name and age but then skips over the remaining three name input fields and only allows for the remaining three ages to be input.
I apologize if this ends up being a dumb question but I really am at a loss. Any help will be greatly appreciated.
Here is the code I have thus far:
#include <iostream>
#include <string>
using namespace std;
int main()
{
string studentname1;
cout << "Please enter the first student's full name:" << endl;
getline(cin, studentname1);
int age1;
cout << "Please enter the first student's age:" << endl;
cin >> age1;
string studentname2;
cout << "Please enter the second student's full name:" << endl;
getline(cin, studentname2);
int age2;
cout << "Please enter the second student's age:" << endl;
cin >> age2;
string studentname3;
cout << "Please enter the third student's full name:" << endl;
getline(cin, studentname2);
int age3;
cout << "Please enter the third student's age:" << endl;
cin >> age3;
string studentname4;
cout << "Please enter the fourth student's full name:" << endl;
getline(cin, studentname2);
int age4;
cout << "Please enter the fourth student's age:" << endl;
cin >> age4;
cout << "Hello from our group." << endl;
cout << "NAME AGE" << endl;
cout << studentname1 << " " << age1 << endl;
cout << studentname2 << " " << age2 << endl;
cout << studentname3 << " " << age3 << endl;
cout << studentname4 << " " << age4 << endl;
cout << "The average of all our ages is: " << (age1 + age2 + age3 + age4) / 4.00 << endl;
return 0;
}
Since the age variables are int, the cin >> age1; will leave the newline character in the input stream. When next you call getline(), you will get the remainder of that line - which is empty, and so on.
Also, you have a copy-paste bug in your code. getline(cint, studentname2); is run for students 2, 3 and 4.
You can either solve the problem by using getline() for all input:
string agestring;
getline(cin, agestring)
stringstream(agestring) >> age1;
or clear cin when you're done reading the age:
cin >> age1;
cin.ignore();
I am having some issues with my simple code of creating a dvd & software list to import into a csv file.
I have the output working fine but for some reason my program is skipping my first part of the code. If I take out the IF statement, that bit of code works so I am not understanding why.
my output looks like this:
Would you like to add new media? Enter M for Movie or S for software: m
Enter the name of the Movie (20 Chararters or less)Name: Enter a rating for
your movie 1-5:
I am not getting any errors in my compiler (Visual Studio 2013) and it does not allow me to input a name and skips right to rating.
Any explanations or suggestions would be appreciated as I want to fix this before I move on to adding more.
here is my code:
#include <iostream>
#include <fstream>
#include <string>
using namespace std;
int main(){
string typeM = "movie";
string typeS = "software";
char answer, mediainput;
int rating = 0;
string dir, type;
string moviename,softname;
do
{
cout << "Would you like to add new media? Enter M for Movie or S for software: ";
cin >> mediainput;
cout << endl;
if (mediainput == 'm' || mediainput == 'M')
{
cout << "Enter the name of the Movie (20 Chararters or less) \n Name: ";
getline(cin, moviename);
cout << endl;
cout << "Enter a rating for your movie " << moviename << " 1-5 ";
cin >> rating;
if (rating < 1 || rating > 5)
{
cout << "You must enter a number from 1 to 5. Enter a number rating: ";
cin >> rating;
cout << endl;
}
ofstream outdata("DVD_Software_inventory.csv", ios_base::app);
outdata << moviename << "," << typeM << "," << rating << "," << endl;
outdata.close();
}
if (mediainput == 's' || mediainput == 'S')
{
cout << "Enter the name of the software (20 Chararters or less) \n Software name: " << endl;
getline(cin, softname);
cout << "Enter the directory it is in \n Directory: ";
cin >> dir;
ofstream outdata("DVD_Software_inventory.csv", ios_base::app);
outdata << softname << "," << typeS << ",," << dir << "," << endl;
outdata.close();
}
cout << "\n\nWould you like to add more? Y/N ";
cin >> answer;
cout << endl;
if (answer == 'N' || answer == 'n')
{
cout << "** End of Program **" << endl;
break;
}
} while (answer == 'Y' || answer == 'y');
system("pause");
return(0);
}
The problem is that while your cin >> statement ignores "\n" (the newline character), the character is still in cin's buffer. getline(), however,
does not ignore the "\n" character.
The solution, therefore, is to explicitly tell cin to ignore the "\n" character:
cin.ignore(std::numeric_limits<std::streamsize>::max(), '\n');
getline(cin, moviename);
(credit to http://www.cplusplus.com/forum/beginner/24470/)
I am trying to learn C++, anyway I am on if statements.
I coded a program that ask a two user their full name and ages (fictional users), it ask user1 its name and age and user2 the same, but somehow asking the user2's name gets skipped and end up asking the user2's age
why ?
here is my code :
#include <iostream>
#include <string>
using namespace std;
int main()
{
string usernameone;
string usernametwo;
int age1;
int age2;
//ask the users their name and age
cout << "Hi may I know your full name ? : ";
getline ( cin, usernameone, '\n');
cout << "\nHello " << usernameone << " May I know now whats your age ? : ";
cin >> age1;
cout << "Ok thanks for the information, now may I talk to the other user ? thanks.\n\n";
cout << "Hello may I know your full name ? : ";
getline ( cin, usernametwo, '\n');
cout << "\nHello " << usernametwo << " May I know now whats your age ? : ";
cin >> age1;
if(age1 < age2)
{
cout << "looks like " << usernameone << " is older than " << usernametwo;
}
else
{
cout << "ok " << usernametwo << " is older than " << usernameone;
}
if(age2 && age1 >= 100)
{
cout << "your both lying your age can't be 100 and above";
}
cin.ignore();
cin.get();
return 0;
}
cin >> age1;
cout << "Ok thanks for the information, now may
I talk to the other user ? thanks.\n\n";
cout << "Hello may I know your full name ? : ";
leaves '\n' in input stream and you are reading it in the next read
getline ( cin, usernametwo, '\n');
You can ignore this character with:
cin >> age1;
cout << "Ok thanks for the information, now may
I talk to the other user ? thanks.\n\n";
cout << "Hello may I know your full name ? : ";
cin.ignore();
getline ( cin, usernametwo, '\n');