How to use EVAL command to replace some text in string and return it back to different variable?
I want ti replace $ character in extracted text and any other string like ABSD or #EANF#.
I have this.
SET !VAR1 EVAL("var s=\"{{!EXTRACT}}\"; s.replace(/\$/g, "");")
SET !VAR1 EVAL("'{{!EXTRACT}}'.replace(/[\\$|ABSD|#EANF#]/g, '');")
Related
I have a sql procedure code. We are migrating the code on different schema. I need to replace all the dimension tables schema.
Example:
Old schemas: DBO.ABC_DIM, DBO.XYZ_DIM
After replace: MART.ABC_DIM, MART.XYZ_DIM
Could any one let me know how we can do this using regex replace.
Thanks
Sky
You must use:
in the "Find what" field:
(DBO)\.
and in the "Replace with" field:
MART\.
Don't forget to place the cursor at beginning of the file. Otherwise the replacements begin after actually cursor position
EDITED:
So in this case if you have others, you can use that:
Find field:
\b(DBO\.)(.+?)_DIM\b
Replace field:
MART\.$2_DIM
Some like:
DBO.ABC_DIM, DBO.XYZ_DIM,
DBO.ABC_DTL, DBO.ABC_2_BCD
become:
MART.ABC_DIM, MART.XYZ_DIM,
DBO.ABC_DTL, DBO.ABC_2_BCD
LAST EDIT:
The above fail with:
DBO.ABC_DIM, DBO.XYZ_DIM,
DBO.ABC_DTL, DBO.ABC_2_BCD, DBO.ABC_DIM, DBO.XYZ_DIM,
DBO.ABC_DTL, DBO.ABC_2_BCD,
DBO.ABC_DIM, DBO.XYZ_DIM,
Because in the second row match DBO.ABC_DTL, DBO.ABC_2_BCD, DBO.ABC_DIM
And DBO.ABC_DTL become MART.ABC_DTL
So the right solution is:
Find field:
(DBO\.)(.[^\.]+?)_DIM
Replace field:
MART\.$2_DIM
see matching results here: http://refiddle.com/refiddles/596b348175622d74ff020000
if you open that schema in VIM, do press esc and then
:s%/DBO/MART
and press enter
:s (colon and s) for substitute
/DBO find DBO
/MART replace it with MART
once you verify that all the DBOs are replace with MART, you need to save the changes by esc and :wq
1 File:
<DisplayName>**just_an_example**</DisplayName>
<DisplayName>**just_an_example**</DisplayName>
<DisplayName>**just_an_example**</DisplayName>
<DisplayName>**just_an_example**</DisplayName>
2 File
**example1**
**example2**
**example3**
**example4**
What do I need:
In notepad++ native search/replace dialog, search for "just_an_example" and replace it with the values from 2nd file, in sequence.
Output:
<DisplayName>**example1**</DisplayName>
<DisplayName>**example2**</DisplayName>
<DisplayName>**example3**</DisplayName>
<DisplayName>**example4**</DisplayName>
Is this possible, to search in all active files under Notepad++. Possible not using Python Script?
Your question implies that the content of file 1 is not relevant (except for the DisplayName tags).
So replace the content of file 1 by pasting all of file 2 and replace new lines by the tags. You can do that in Notepad++ by searching for \n and replacing it by </DisplayName>\n<DisplayName>. All that is left then is manually fixing the first and last line.
I need to perform a search and replace operation on hundreds of SQL script files. The idea is to transform this:
USE [DB]
GO
SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
/* comments xxxx */
ALTER PROCEDURE ....
BEGIN
...
END
Into this:
ALTER PROCEDURE ....
BEGIN
...
END
To do this I would use Notepad++. I want to remove anything before ALTER PROCEDURE. How can I achieve that?
Use the following with . matches newline:
Find what: USE\s+\[[^\]]*?\].*?(ALTER\s+PROCEDURE.*?\bEND\b)
Replace with: $1
\[[^\]]*?\] will make sure you will match any characters from [ up to ] after USE.
EDIT: If you plan to just remove everything from the beginning to the last occurrence of ALTER, you may use .+(?=ALTER) regex in the Find what field, and replace with nothing (empty string).
Settings:
I have a simple json file that isn't well formatted it looks like:
{ ID: '092558667',
NAME: 'Store Made',
PARENT_CATEGORY_ID: '692558669',
INCLUDED_IN_NET_SALES: '1' }
All I need to do is wrap the field names in double quotes. In vim the closest I have gotten is to wrap the field name and the colon in quotes - obviously I need to figure out how to get the string without the colon wrapped. Here's what I am trying:
:%s/[A-Z_]*:/"&"
If I leave the colon out of the query the whole file ends up being selected.
You can use capture groups:
%s/\([A-Z_]*\):/"\1":/
To handle already quoted keys properly:
%s/"\?\([A-Z_]*\)"\?:/"\1":/
Ok, with the information above I ended up with this:
:%s/[ \t]\([A-Za-z_].*\):/"\1":/
it supports upper- and lowercase chars
it skips already quoted fields
Since this can be considered a completion, I mapped it to a vim completion shortcut ctrl-x ctrl-j in .vimrc (they all start with ctrl-x ) :
:noremap <C-x><C-j> :%s/[ \t]\([A-Za-z_].*\):/"\1":/<CR>
I am using a Voice-to-Text application which gives transcription files as output.. The transcribed text contains a few tags like (s) (for sentence beginning)..(/s)( for sentence end ).. (VOCAL_NOISE)(for un-recognized words).. but the text also contains unwanted tags like (VOCAL_N) , (VOCAL_NOISED) , (VOCAL_SOUND), (UNKNOWN).. i am using SED to process the text.. but cannot write an appropriate regex to replace all other tags except (s), (/s) and (VOCAL_NOISE), with the tag ~NS.. would appreciate if someone could help me with it..
Example text:
(s) Hi Stacey , this is Stanley (/s) (s) I would (VOCAL_N) appreciate if you could call (UNKNOWN) and let him know I want an appointment (VOCAL_NOISE) with him (/s)
Output should be:
(s) Hi Stacey , this is Stanley (/s) (s) I would ~NS appreciate if you could call ~NS and let him know I want an appointment (VOCAL_NOISE) with him (/s)
This should take care of it:
sed 's|([^)]*)|\n&\n|g;s#\n\((/\?s)\|(VOCAL_NOISE)\)\n#\1#g;s|\n\(([^)]*)\)\n|~NS|g' inputfile
Explanation:
s|([^)]*)|\n&\n|g - divide the line by putting every parenthesized string between two newlines
s#\n\((/\?s)\|(VOCAL_NOISE)\)\n#\1#g - remove the newlines around "(s)", "(/s)" and "(VOCAL_NOISE)" (keepers)
s|\n\(([^)]*)\)\n|~NS|g - replace anything else between newlines that is within parentheses with "~NS"
This works since newlines are guaranteed not to appear within a newly read line of text.
Edit: Shortened the command by using alternation \(foo\|bar\)
Previous version:
sed 's|([^)]*)|\n&\n|g;s|\n\((/\?s)\)\n|\1|g; s|\n\((VOCAL_NOISE)\)\n|\1|g;s|\n\(([^)]*)\)\n|~NS|g' inputfile
This is a dirty trick that is far from being optimal but it should work for you:
sed '
s|(\(/\?\)s)|[\1AAA]|g;
s|(VOCAL_NOISE)|[BBB]|g;
s/([^)]*)/~NS/g;
s|\[\(/\?\)AAA\]|(\1s)|g;
s|\[BBB\]|(VOCAL_NOISE)|g'
The trick is to replace (s), (/s) and (VOCAL_NOISE) with patterns which are not present in the input text (in this case [AAA], [/AAA] and [BBB]); then we replace every instance of (.*) with ~NS; in the end we get back the fake patterns to their original value.
I could suggest this using vim:
:%s/\((\w\+)\)\&\(\((s)\|(VOCAL_NOISE)\)\#!\)/\~NS/g
Using a shell (bash) you can do the following:
vim file -c '%s/\((\w\+)\)\&\(\((s)\|(VOCAL_NOISE)\)\#!\)/\~NS/g' -c "wq"
Make a backup first, I am not responsible for any damage if this is wrong.
Simply this ?
sed -E 's/\((VOCAL_N|UNKNOWN)\)/~NS/'
In this case, you'd have a blacklist (you know what to filter out). Or do you absolutely need a whitelist (you know what to NOT filter out) ?
awk -vRS=")" -vFS="(" '$2!~/s|\\s|VOCAL_NOISE/{$2="~NS"}RT' ORS=")" file |sed 's/~NS)/~NS/g'