XSLT transformation : Transfer only 1 of the namespaces - xslt

I am new to XSLT transformation and cant seem to get the following result
I have:
<?xml version="1.0" encoding="UTF-8"?>
<Document xmlns="urn:iso:std:iso:20022:tech:xsd:pain.002.001.03" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="urn:iso:std:iso:20022:tech:xsd:pain.002.001.03 pain.002.001.03.xsd">
<CstmrPmtStsRpt>
need this:
<?xml version="1.0" encoding="UTF-8"?>
<Document xmlns="urn:iso:std:iso:20022:tech:xsd:pain.002.001.03">
<CstmrPmtStsRpt>
Where the rest of the document should remain the same.
I have put together the following XSLT:
<?xml version="1.0"?>
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<xsl:output indent="yes" method="xml" encoding="utf-8" />
<!-- template to copy elements -->
<xsl:template match="*">
<xsl:element name="{local-name()}">
<xsl:apply-templates select="#* | node()"/>
</xsl:element>
</xsl:template>
<xsl:template match="#xsi:schemaLocation">
</xsl:template>
<!-- template to copy attributes -->
<xsl:template match="#*">
<xsl:attribute name="{local-name()}">
<xsl:value-of select="."/>
</xsl:attribute>
</xsl:template>
<!-- template to copy the rest of the nodes -->
<xsl:template match="comment() | text() | processing-instruction()">
<xsl:copy/>
</xsl:template>
</xsl:stylesheet>
but get this
<?xml version="1.0" encoding="utf-8"?>
<Document>
<CstmrPmtStsRpt>
Any tips would be appreciated.

Related

XSLT - add prefix for namespace

Here's my input XML:
<?xml version="1.0" encoding="UTF-8"?>
<Sync
xmlns="http://schema.infor.com/InforOAGIS/2" languageCode="en-US" versionID="2.8.0">
<Data>
<ID>0001</ID>
<Text>ABCD</Text>
</Data>
</Sync>
And here's my expected outcome:
<?xml version="1.0" encoding="UTF-8"?>
<ns0:Sync xmlns:ns0="http://schema.infor.com/InforOAGIS/2"
languageCode="en-US"
versionID="2.8.0">
<DataArea xmlns:dns="http://schema.infor.com/InforOAGIS/2" xmlns="">
<ID>0001</ID>
<Text>ABCD</Text>
</DataArea>
</ns0:Sync>
My current XSLT as below (https://xsltfiddle.liberty-development.net/nbiE19N).
There are 2 problems:
I have the extra xmlns="" in DataArea element. I only want to add the dns namespace.
I cannot add the ns0 prefix for my namespace
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:template match="/*:Sync">
<xsl:copy>
<xsl:copy-of select="#*"/>
<xsl:apply-templates/>
</xsl:copy>
</xsl:template>
<xsl:template match="/*:Sync/*:Data">
<DataArea>
<xsl:namespace name="dns" select="'http://schema.infor.com/InforOAGIS/2'"/>
<ID>
<xsl:value-of select="/*:Sync/*:Data/*:ID"/>
</ID>
<Text>
<xsl:value-of select="/*:Sync/*:Data/*:Text"/>
</Text>
</DataArea>
</xsl:template>
</xsl:stylesheet>
Any suggestion is appreciated!

Does this return the expected result:
XSLT 2.0
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xpath-default-namespace="http://schema.infor.com/InforOAGIS/2">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:template match="/Sync">
<ns0:Sync xmlns:ns0="http://schema.infor.com/InforOAGIS/2">
<xsl:copy-of select="#*"/>
<xsl:apply-templates/>
</ns0:Sync>
</xsl:template>
<xsl:template match="Data">
<DataArea xmlns:dns="http://schema.infor.com/InforOAGIS/2">
<xsl:apply-templates/>
</DataArea>
</xsl:template>
<xsl:template match="*">
<xsl:element name="{local-name()}">
<xsl:apply-templates/>
</xsl:element>
</xsl:template>
</xsl:stylesheet>
P.S. I am not sure why you need the xmlns:dns="http://schema.infor.com/InforOAGIS/2" declaration; it's not being used anywhere.

XSLT to replace a namespace and also add a new (unused) namespace

I want to replace the namespace of the following XML Document
<?xml version="1.0" encoding="UTF-8"?>
<ns0:Document xmlns:ns0="http://mydata.com/H2H/Automation">
<CstmrCdtTrfInitn>
<GrpHdr>
</GrpHdr>
</CstmrCdtTrfInitn>
</ns0:Document>
with the following
<?xml version="1.0" encoding="UTF-8"?>
<Document xmlns="urn:iso:std:iso"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<CstmrCdtTrfInitn>
<GrpHdr>
</GrpHdr>
</CstmrCdtTrfInitn>
</Document>
Any idea about XSLT which can convert this?
I have tried the following XSL, but it is adding the namespace with second Node and also not able to remove first namespace.
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output encoding="UTF-8" indent="yes"/>
<xsl:template match="/*">
<xsl:element name="{local-name()}" namespace="http://www.w3.org/2001/XMLSchema-instance">
<xsl:copy-of select="./*" />
</xsl:element>
</xsl:template>
</xsl:stylesheet>

Your requirement can be a bit tricky: replacing the default namespace of the Document element is straightforward. But adding the unused xslns:xsi namespace in XSLT-1.0 requires the EXSLT extension and a special technique explained by Michael Kay in reply to this question. It involves creating an unused element in a global variable whose namespace is then copied in the template replacing the default namespace. In XSLT-2.0 and above this would be easier (see below).
The EXSLT extension is not available in all XSLT-1.0 processors. But it is necessary to create a node-set from the variable.
So all namespaces are to be defined in the xsl:stylesheet element, and then the root element (here ns0:Document) is matched by a template and replaced with its local-name() part with the new default namespace added, followed by copying the "dummy" namespace of the element defined in the variable.
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:ns0="http://mydata.com/H2H/Automation" xmlns:urn="urn:iso:std:iso" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:ext="http://exslt.org/common">
<xsl:output method="xml" omit-xml-declaration="yes" indent="yes"/>
<!-- identity template (except elements)-->
<xsl:template match="node()[not(self::*)]|#*">
<xsl:copy>
<xsl:apply-templates select="node()|#*" />
</xsl:copy>
</xsl:template>
<xsl:variable name="nsXSI">
<xsl:element name="xsi:dummy" namespace="http://www.w3.org/2001/XMLSchema-instance" />
</xsl:variable>
<xsl:template match="ns0:*|*">
<xsl:element name="{local-name()}" namespace="urn:iso:std:iso">
<xsl:copy-of select="ext:node-set($nsXSI)/*/namespace::xsi" />
<xsl:apply-templates select="node() | #*" />
</xsl:element>
</xsl:template>
</xsl:stylesheet>
Output should be as expected, even in XSLT-1.0:
<Document xmlns="urn:iso:std:iso" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<CstmrCdtTrfInitn>
<GrpHdr>
</GrpHdr>
</CstmrCdtTrfInitn>
</Document>
The simplified solution requires an XSLT-2.0 capable processor. Then you can use the xsl:namespace instruction as follows and don't need the "dummy" variable:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:ns0="http://mydata.com/H2H/Automation">
<xsl:output method="xml" omit-xml-declaration="yes" indent="yes"/>
<!-- identity template (except elements)-->
<xsl:template match="node()[not(self::element())]|#*">
<xsl:copy>
<xsl:apply-templates select="node()|#*" />
</xsl:copy>
</xsl:template>
<xsl:template match="ns0:*|*">
<xsl:element name="{local-name(.)}" namespace="urn:iso:std:iso">
<xsl:namespace name="xsi">http://www.w3.org/2001/XMLSchema-instance</xsl:namespace>
<xsl:apply-templates select="node() | #*" />
</xsl:element>
</xsl:template>
</xsl:stylesheet>
The output is the same.
The above XSLT-2.0 solution could be further simplified by using XSLT-3.0+'s xsl:mode to replace the identity template with
<xsl:mode on-no-match="shallow-copy"/>

Is there a reason why you cannot do simply:
XSLT 1.0
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:ns0="http://mydata.com/H2H/Automation"
exclude-result-prefixes="ns0">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="*">
<xsl:element name="{local-name()}" namespace="urn:iso:std:iso">
<xsl:apply-templates/>
</xsl:element>
</xsl:template>
<xsl:template match="/ns0:Document">
<Document xmlns="urn:iso:std:iso" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<xsl:apply-templates/>
</Document>
</xsl:template>
</xsl:stylesheet>

XSLT transformation with multiple nodes

I have multiple occurence nodes which need to be generated at output using XSLT transformation. Could you please help me on this.
Following XSLT code only generate one node occurrence only. Could you please help me with below XSLT code how to generate multiple nodes elements in Input XML
Input XML
<?xml version="1.0" encoding="UTF-8" ?>
<soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" >
<soapenv:Body>
<ns1:getGenResponse soapenv:encodingStyle="http://schemas.xmlsoap.org/soap/encoding/"
<ns1:getGenReturn xsi:type="soapenc:Array" soapenc:arrayType="xsd:anyType[2]" xmlns:soapenc="http://schemas.xmlsoap.org/soap/encoding/">
</ns1:getGenReturn>
</ns1:getGenResponse>
<multiRef id="id0" soapenc:root="0" soapenv:encodingStyle="http://schemas.xmlsoap.org/soap/encoding/" xsi:type="ns2:Gen" xmlns:soapenc=http://schemas.xmlsoap.org/soap/encoding/>
<name xsi:type="xsd:string">ULM</name>
<mail xsi:type="xsd:string">ulm#gmail.com</mail>
</multiRef>
<multiRef id="id1" soapenc:root="0" soapenv:encodingStyle="http://schemas.xmlsoap.org/soap/encoding/" xsi:type="ns3:Gen" " xmlns:soapenc="http://schemas.xmlsoap.org/soap/encoding/">
<name xsi:type="xsd:string">ABC</name>
<mail xsi:type="xsd:string">abc#gmail.com</mail>
</multiRef>
</soapenv:Body>
</soapenv:Envelope>
XSLT Code used for this transformation
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" x
xmlns:response="http://tempuri.org/"
xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<!-- Output -->
<xsl:output method="xml" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="/">
<xsl:if test="//soap:Body/multiRef">
<xsl:element name="getGenResponse">
<xsl:element name="getGenReturn">
<xsl:element name="name"><xsl:value-of select="//name"/></xsl:element>
<xsl:element name="mail"><xsl:value-of select="//mail"/></xsl:element>
</xsl:element>
</xsl:element>
</xsl:if>
</xsl:template>
<!-- 'Copy ' node -->
<xsl:template match="#* | node()">
<xsl:copy>
<xsl:apply-templates select="#* | node()"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
Output from above XSLT
<?xml version="1.0" encoding="UTF-8"?>
<getGenResponse>
<getGenReturn>
<name> ULM </name>
<mail>ulm#gmail.com<mail>
</getGenReturn>
/getGenResponse>
Output expected
<?xml version="1.0" encoding="UTF-8"?>
<getGenResponse>
<getGenReturn>
<name> ULM </name>
<mail>ulm#gmail.com<mail>
</getGenReturn>
<getGenReturn>
<name>ABC</name>
<mail>abc#gmail.com<mail>
</getGenReturn>
/getGenResponse>

At you moment all you are doing is testing a multiRef element exists, and outputting only one new getGenReturn element.
All you really need to do is replace the xsl:if with xsl:for-each to select all the elements, then you will get one getGenReturn for each. And also change the xsl:value-of to use a relative path
<xsl:template match="/">
<xsl:element name="getGenResponse">
<xsl:for-each select="//soap:Body/multiRef">
<xsl:element name="getGenReturn">
<xsl:element name="name"><xsl:value-of select="name"/></xsl:element>
<xsl:element name="mail"><xsl:value-of select="mail"/></xsl:element>
</xsl:element>
</xsl:for-each>
</xsl:element>
</xsl:template>
Or better still, do this, as xsl:element is not really needed here if you are using static names
<xsl:template match="/">
<getGenResponse>
<xsl:for-each select="//soap:Body/multiRef">
<getGenReturn>
<name><xsl:value-of select="name"/></name>
<mail><xsl:value-of select="mail"/></mail>
</getGenReturn>
</xsl:for-each>
</getGenResponse>
</xsl:template>
Note, you don't actually need the identity template in this case. Try this XSLT:
<xsl:stylesheet version="1.0" xmlns:response="http://tempuri.org/"
xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" exclude-result-prefixes="soap response">
<!-- Output -->
<xsl:output method="xml" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="/">
<getGenResponse>
<xsl:for-each select="//soap:Body/multiRef">
<getGenReturn>
<name><xsl:value-of select="name"/></name>
<mail><xsl:value-of select="mail"/></mail>
</getGenReturn>
</xsl:for-each>
</getGenResponse>
</xsl:template>
</xsl:stylesheet>

<xsl:stylesheet version="1.0" xmlns:response="http://tempuri.org/"
xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" exclude-result-prefixes="soap response">
<!-- Output -->
<xsl:output method="xml" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="/">
<getGenResponse>
<xsl:for-each select="//soap:Body/multiRef">
<getGenReturn>
<name><xsl:value-of select="name"/></name>
<mail><xsl:value-of select="mail"/></mail>
</getGenReturn>
</xsl:for-each>
</getGenResponse>
</xsl:template>
</xsl:stylesheet>

How to use one cycle for different tags

I have XML with different same tags:
<?xml version="1.0" encoding="UTF-8"?>
<main>
<ROUTES>
<A1_NE>LSN/EMS_XDM_12/1021</A1_NE>
<A2_NE>LSN/EMS_XDM_12/1022</A2_NE>
<Z1_NE>LSN/EMS_XDM_12/1023</Z1_NE>
<Z2_NE>LSN/EMS_XDM_12/1024</Z2_NE>
</ROUTES>
<ROUTES>
<A1_NE>LSN/EMS_XDM_12/1001</A1_NE>
<A2_NE>LSN/EMS_XDM_12/1002</A2_NE>
<A3_NE>LSN/EMS_XDM_12/1003</A3_NE>
<A4_NE>LSN/EMS_XDM_12/1004</A4_NE>
<Z1_NE>LSN/EMS_XDM_12/1005</Z1_NE>
<Z2_NE>LSN/EMS_XDM_12/1006</Z2_NE>
</ROUTES>
</main>
XSLT:
<?xml version="1.1" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="no"/>
<xsl:template match="/">
<MAIN>
<xsl:for-each select="main/ROUTES">
<xsl:element name="ROUTES">
<A_NE><xsl:value-of select="A1_NE"/></A_NE>
<A_NE><xsl:value-of select="A2_NE"/></A_NE>
<A_NE><xsl:value-of select="A3_NE"/></A_NE>
<A_NE><xsl:value-of select="A4_NE"/></A_NE>
<Z_NE><xsl:value-of select="Z1_NE"/></Z_NE>
<Z_NE><xsl:value-of select="Z2_NE"/></Z_NE>
</xsl:element>
</xsl:for-each>
</MAIN>
</xsl:template>
</xsl:stylesheet>
How I can use for-each command to transform A1_NE, A2_NE etc to A_NE column?
And also I've not understand how I can know number of the row in the source xml.
Perhabs xslt version 1.0 couldn't do this transformation.
<?xml version="1.0" encoding="UTF-8"?>
<main>
<ROUTES>
<A_NE>LSN/EMS_XDM_12/1021</A_NE>
<A_NE>LSN/EMS_XDM_12/1022</A_NE>
<Z_NE>LSN/EMS_XDM_12/1023</Z_NE>
<Z_NE>LSN/EMS_XDM_12/1024</Z_NE>
<A_NE>LSN/EMS_XDM_12/1001</A_NE>
<A_NE>LSN/EMS_XDM_12/1002</A_NE>
<A_NE>LSN/EMS_XDM_12/1003</A_NE>
<A_NE>LSN/EMS_XDM_12/1004</A_NE>
<Z_NE>LSN/EMS_XDM_12/1005</Z_NE>
<Z_NE>LSN/EMS_XDM_12/1006</Z_NE>
</ROUTES>
</main>

You should make use of template matching, to change the node names.
First select the child nodes of all ROUTES like so:
<xsl:apply-templates select="main/ROUTES/*" />
Then, have templates like this, for example, to do the renaming
<xsl:template match="A1_NE|A2_NE|A3_NE|A4_NE">
<A_NE><xsl:value-of select="."/></A_NE>
</xsl:template>
Try this XSLT
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes"/>
<xsl:template match="/">
<main>
<ROUTES>
<xsl:apply-templates select="main/ROUTES/*" />
</ROUTES>
</main>
</xsl:template>
<xsl:template match="A1_NE|A2_NE|A3_NE|A4_NE">
<A_NE><xsl:value-of select="."/></A_NE>
</xsl:template>
<xsl:template match="Z1_NE|Z2_NE|Z3_NE|Z4_NE">
<Z_NE><xsl:value-of select="."/></Z_NE>
</xsl:template>
</xsl:stylesheet>
Alternatively, if those are indeed your real element names, you could try and make it generic
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes"/>
<xsl:template match="/">
<main>
<ROUTES>
<xsl:apply-templates select="main/ROUTES/*" />
</ROUTES>
</main>
</xsl:template>
<xsl:template match="ROUTES/*">
<xsl:element name="{substring(local-name(), 1, 1)}_{substring-after(local-name(), '_')}">
<xsl:value-of select="."/>
</xsl:element>
</xsl:template>
</xsl:stylesheet>

The logic that needs to be applied is not apparent from the example given. Perhaps all you need to do is:
XSLT 1.0
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:template match="/main">
<main>
<ROUTES>
<xsl:for-each select="ROUTES/*">
<xsl:element name="{translate(name(), '1234567890', '')}">
<xsl:value-of select="." />
</xsl:element>
</xsl:for-each>
</ROUTES>
</main>
</xsl:template>
</xsl:stylesheet>

XSLT add root node if not exists

I have some XML and having a difficult time transforming it.
Example XML:
<?xml version="1.0" encoding="utf-8"?>
<Cars xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<Car> ... </Car>
</Cars>
I would like to change it to:
<?xml version="1.0" encoding="utf-8"?>
<Depot xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<Cars>
<Car> ... </Car>
</Cars>
</Depot>
Sounds simple enough but the problem is some data is already in the expected format, in which case I don't want to apply the transform. How do I achieve this?
EDIT
Some starting XSLT:
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" mlns:xsi="http://www.w3.org/2001/XMLSchema-
instance"
xmlns:xsd="http://www.w3.org/2001/XMLSchema"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="Cars">
<Depot>
<Cars>
<xsl:apply-templates select="*"/>
</Cars>
</Depot>
</xsl:template>
<xsl:template match="node()|#*">
<xsl:copy>
<xsl:apply-templates select="node()" />
</xsl:copy>
</xsl:template>
</xsl:stylesheet>

I think you only want to match Cars if it is the root element, so instead of your template matching "Cars", change it to match "/Cars"
<xsl:template match="/Cars">
Try this XSLT (which I have slightly amended to get the first template to call the identity template)
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:xsd="http://www.w3.org/2001/XMLSchema" >
<xsl:output method="xml" indent="yes" />
<xsl:template match="/Cars">
<Depot xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<xsl:call-template name="identity" />
</Depot>
</xsl:template>
<xsl:template match="#*|node()" name="identity">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>

I think that it is just necessary to use a choose in the root template to test if the node Depot exists, if not create it:
<xsl:template match="/">
<xsl:choose>
<xsl:when test="Depot">
<xsl:apply-templates/>
</xsl:when>
<xsl:otherwise>
<Depot>
<xsl:apply-templates/>
</Depot>
</xsl:otherwise>
</xsl:choose>
</xsl:template>
<xsl:template match="node()|#*">
<xsl:copy>
<xsl:apply-templates select="node()" />
</xsl:copy>
</xsl:template>

This also gives same output.
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:xsd="http://www.w3.org/2001/XMLSchema" >
<xsl:template match="Cars">
<Depot>
<xsl:copy-of select="."/>
</Depot>
</xsl:template>
</xsl:stylesheet>