I'm new to wxpython. I want to add some text to an existing message box using wxpython GUI programming. I searched on the net, but I couldn't any useful info. Could you please help me with this issue?
My goal is to run a code and then print some text during code running into a window.
Thanks,
I want to have something like this one:
outPut = 'Simulation is done'
wx.MessageBox(outPut, "Results")
newText = 'The results are:\n' #add this text to previous MessageBox
I don't think you can do it with MessageBox, but what about using ProgressDialog? I updated the code and tested it:
# -*- coding: utf-8 -*-
#!/usr/bin/env python
import wx
print(wx.VERSION_STRING)
import wx.lib.sized_controls as sc
class abc(sc.SizedFrame):
def __init__(self, parent, id):
super(abc, self).__init__(parent, id, 'Frame aka window')
cpane = self.GetContentsPane()
button1 = wx.Button(cpane, label="ProgressDialog 1 sample")
button1.Bind(wx.EVT_BUTTON, self.pdlg1)
button1 = wx.Button(cpane, label="ProgressDialog 2 sample")
button1.Bind(wx.EVT_BUTTON, self.pdlg2)
def pdlg1(self, evt):
dlgPro = wx.ProgressDialog(u"Simulation progress 1",
u"It is starting",
3,
None,
wx.PD_AUTO_HIDE | wx.PD_APP_MODAL)
# do something
dlgPro.Update(1, u"first one is done")
# do something
wx.Yield()
wx.Sleep(1)
dlgPro.Update(2, u"second one is done")
# do something
wx.Yield()
wx.Sleep(1)
dlgPro.Update(3, u"we are finished")
def pdlg2(self, evt):
dlgPro = wx.ProgressDialog(u"Simulation progress 2",
u"It is starting",
-1,
None,
wx.PD_AUTO_HIDE | wx.PD_APP_MODAL)
# do something
dlgPro.Pulse(u"first one is done")
# do something
wx.Yield()
wx.Sleep(1)
dlgPro.Pulse(u"second one is done")
# do something
wx.Yield()
wx.Sleep(1)
dlgPro.Pulse(u"we are finished")
if __name__ == '__main__':
app = wx.App()
frame = abc(None, -1)
frame.Show()
app.MainLoop()
http://wxpython.org/Phoenix/docs/html/ProgressDialog.html?highlight=progress
In order to add text to a text box, you will have to add some sort of text object to the frame. For example
class MyFrame(wx.Frame):
def __init__(self, *args, **kwargs):
wx.Frame.__init__(*args, **kwargs)
self.text = wx.StaticText(self, wx.ID_ANY, "Hello World!")
creates a frame that has the text "Hello, World" in it. It is static text, meaning the user cannot change it. If you wanted text that can be changed, look at wx.TextCtrl
Related
I developed a simple Python application doing some stuff, then I decided to add a simple GUI using Tkinter.
The problem is that, while the I call a function called startprocess and begin doing stuff which is processor heavy and the window freezes.
I know it's a common problem and I've already read that I should use multithreads (very complicated, because the function updates the GUI too) or divide my code in different function, each one working for a little time. anyways is there any modification needed in below code to avoid GUI freezing?
import threading
import tkinter as tk
from tkinter import filedialog
from tkinter import messagebox
import os, datetime, sys, subprocess
import parselog_v1
# diplay messagebox window
def MessageBox(windowLable,msg):
messagebox.showinfo(windowLable, msg)
# check if Dir empty
def checkDirEmpty(work_path):
if os.path.isdir(work_path):
if not os.listdir(work_path):
print ("No Files found in directory")
MessageBox('Log Parser', 'No Files found in directory.')
else:
return True
# launch app in center of screen
def center_window(width=300, height=200):
# get screen width and height
screen_width = root.winfo_screenwidth()
screen_height = root.winfo_screenheight()
# calculate position x and y coordinates
x = (screen_width/2) - (width/2)
y = (screen_height/2) - (height/2)
root.geometry('%dx%d+%d+%d' % (width, height, x, y))
# application frame
class Application(tk.Frame):
def __init__(self, master=None):
tk.Frame.__init__(self, master)
self.pack()
self.createWidgets()
self.master.title("Log Parser")
def createWidgets(self):
self.Run_Main = tk.Button(self)
self.Run_Main["text"] = "Browse for logs"
self.Run_Main["fg"] = "blue"
self.Run_Main["command"] = self.startProcess
self.Run_Main.pack(side='left',padx=0)
self.QUIT = tk.Button(self)
self.QUIT["text"] = "Quit!"
self.QUIT["fg"] = "red"
self.QUIT["command"] = self.quit
self.QUIT.pack(side='right',padx=5)
def startProcess(self):
global Src_foldername
Src_foldername = filedialog.askdirectory()
Src_foldername = Src_foldername.replace("/", "\\")
print("Source folder: " + Src_foldername)
if checkDirEmpty(Src_foldername):
# process logs
# multithread
print("Processing...")
self.refresh()
threading.Thread(target=parselog_v1.main(Src_foldername))
# scroll text inside application frame
class scrollTxtArea:
def __init__(self, root):
frame = tk.Frame(root)
frame.pack()
self.textPad(frame)
return
class IORedirector(object):
'''A general class for redirecting I/O to this Text widget.'''
def __init__(self, text_area):
self.text_area = text_area
class StdoutRedirector(IORedirector):
'''A class for redirecting stdout to this Text widget.'''
def textPad(self, frame):
# add a frame and put a text area into it
textPad = tk.Frame(frame)
self.text = tk.Text(textPad, height=21, width=68)
self.text.config()
# add a vertical scroll bar to the text area
scroll = tk.Scrollbar(textPad)
self.text.configure(yscrollcommand=scroll.set,background="black", foreground="green")
# pack everything
self.text.pack(side=tk.LEFT, pady=2)
scroll.pack(side=tk.RIGHT, fill=tk.Y)
textPad.pack(side=tk.TOP)
self.text.insert("end", "Begin by selecting log folder..." + "\n")
self.text.configure(state='disabled') # disable text editing
sys.stdout = (self) # to begin logging stdio to GUI
return
def write(self, txt):
self.text.configure(state='normal')
self.text.insert('end', txt)
self.text.configure(state='disabled')
root = tk.Tk()
root.resizable(width=False, height=False)
center_window(500, 300) # launch in center of screen
app = Application(master=root)
scrollFrame = scrollTxtArea(root)
app.mainloop()
root.destroy()
You use thread in wrong way.
First: target= needs function name without () and arguments.
You can assign arguments to args= (it have to be tuple even if you have only one argument)
threading.Thread(target=parselog_v1.main, args=(Src_foldername,) )
Now your code runs parselog_v1.main as normal function, waits for result and it will assign this result as function name to taget= - so you have something like this:
result = parselog_v1.main(Src_foldername)
threading.Thread(target=result)
It stops mainloop so it can't get mouse/keyboard events, refresh window, etc. so it looks like window freeze.
Second: after you create thread correctly you have to start it
my_thread = threading.Thread(target=parselog_v1.main, args=(Src_foldername,) )
my_thread.start()
I want each tab to come from it's own class (classes are in their own files - I am just testing the first one for now).
Here is what I tried:
tab1.py
from Tkinter import *
import Tkinter as tk
class Tab(tk.Frame):
def __init__(self, master):
tk.Frame.__init__(self, master)
fr = Frame(self).pack()
Label(fr, text="one", bg='red', bd=2).pack()
Label(fr, text="two", bg='yellow', bd=2).pack()
if __name__ == '__main__':
root = Tk()
frame = Frame(root).pack()
Tab(frame)
Button(frame, text='only if class', command=root.destroy).pack()
mainloop()
noteBook.py
from Tkinter import *
from ttk import *
from tab1 import Tab
root = Tk()
note = Notebook(root)
main_frame = Frame(note)
button1 = Button(main_frame, text='test').pack()
#tab1 = Tab(note)
tab1 = Frame(note)
tab2 = Frame(note)
tab3 = Frame(note)
Tab(tab1)
Button(tab1, text='Exit', command=root.destroy).pack()
note.add(tab1, text = "Tab One", compound=TOP)
note.add(tab2, text = "Tab Two")
note.add(tab3, text = "Tab Three")
note.pack()
root.mainloop()
exit()
run with:
python2.7 noteBook.py
The problem is that the content of tab1.py does not appear within the first tab, it instead appears within the frame that contains the whole noteBook.
Also when running tab1.py directly with python2.7 noteBook.py I need it to behave properly meaning from what it has now it should show just the tab with an extra button from the if __name___... part.
I have come accros multiple examples but only found one that was what I want but it had no working solution and it was for python3 - I would like python2. python3 question with no working answer Thanks.
The problem is this line of code:
fr = Frame(self).pack()
When you do the above, fr is None because .pack() returns None (because x().y() returns the value of y()). Later, you do this:
Label(fr, text="one", bg='red', bd=2).pack()
Since fr is None, the label is created in the root window.
Unrelated to the problem, here's some advice: you are creating too many frames. You don't need fr inside of Tab, and you don't need tab1, tab2, or tab3
Here's all you need for Tab:
class Tab(tk.Frame):
def __init__(self, master):
tk.Frame.__init__(self, master, background="pink")
Label(self, text="one", bg='red', bd=2).pack()
Label(self, text="two", bg='yellow', bd=2).pack()
To add it to the notebook, you just need two lines:
tab1 = Tab(note)
note.add(tab1, text = "Tab One", compound=TOP)
This works perfectly and just for fun I've illustrated the populating of tabs 2 and 3 althought I just reused the same class for simplicity here. The goal was to be able to run the tabs directly to view them alone during developpement without having to run the whole thing every time.
noteBook.py
from Tkinter import *
from ttk import *
from tab1 import Tab
root = Tk()
note = Notebook(root)
main_frame = Frame(note)
button1 = Button(main_frame, text='test').pack()
tab1 = Frame(note)
tab2 = Frame(note)
tab3 = Frame(note)
Tab(tab1)
Tab(tab2)
Tab(tab3)
Button(tab1, text='Exit', command=root.destroy).pack()
note.add(tab1, text = "Tab One", compound=TOP)
note.add(tab2, text = "Tab Two")
note.add(tab3, text = "Tab Three")
note.pack()
root.mainloop()
exit()
tab1.py
import Tkinter as tk
class Tab(tk.Frame):
def __init__(self, parent_widget):
tk.Frame.__init__(self, parent_widget)
self.fr = tk.Frame(parent_widget, width=200, height=200, bg='pink', bd=2)
tk.Label(self.fr, text="one", bg='red', bd=2).pack()
tk.Label(self.fr, text="two", bg='yellow', bd=2).pack()
self.fr.pack() # this packing must be done after 2 above packings
if __name__ == '__main__':
root = tk.Tk() # the app window
main_frame = tk.Frame(root, height=200, width=200, bg='blue', bd=2) # main frame
Tab(main_frame) # instatiate Tab(), sending main_frame as the parent_widget
tk.Button(main_frame, text='only if class', command=root.destroy).pack()
main_frame.pack() # display main frame on window
tk.mainloop()
Hy guys,
in my executable program there is a toolbar. Well, the user decides to move the toolbar. Now the toolbar is floating. I know I have to conntect the floating-signals that is emittted when the toolbar ist arranged by the user. How can I save the new position of the toolbar? I know the method of adding the toolbar to the main window with a position:self.addToolBar( Qt.LeftToolBarArea , toolbar_name). In the handle_floating()-method you see what I want: There I want to get the position currently, but how? You also see I have just added one member variable, named self.toolbar_pos, to hold the position of the toolbar. My idea is, when application is terminated I want to serialize this value to a file, and later, when application is ran again its will read that file and set the toolbar accordingly. But this is no problem. Currently I don't have no idea to get the position of the toolbar.
I need your help :)
#!/usr/bin/python
# -*- coding: utf-8 -*-
import sys
from PyQt4 import QtGui, QtCore
class Example(QtGui.QMainWindow):
def __init__(self, parent=None):
QtGui.QMainWindow.__init__(self, parent)
self.toolbar_pos = None
self.initUI()
def initUI(self):
exitAction = QtGui.QAction(QtGui.QIcon('exit24.png'), 'Exit', self)
exitAction.setShortcut('Ctrl+Q')
exitAction.triggered.connect(QtGui.qApp.quit)
self.toolbar = QtGui.QToolBar(self)
self.toolbar.setToolButtonStyle(QtCore.Qt.ToolButtonTextBesideIcon)
self.addToolBar(self.toolbar )
self.toolbar.addAction(exitAction)
self.toolbar.setAllowedAreas(QtCore.Qt.TopToolBarArea
| QtCore.Qt.BottomToolBarArea
| QtCore.Qt.LeftToolBarArea
| QtCore.Qt.RightToolBarArea)
self.addToolBar( QtCore.Qt.LeftToolBarArea , self.toolbar )
self.toolbar.topLevelChanged.connect(self.handle_floating)
def handle_floating(self, event):
# The topLevel parameter is true
# if the toolbar is now floating
if not event:
# If the toolbar no longer floats,
# then calculate the position where the
# toolbar is located currently.
self.toolbar_pos = None
print "Get position: ?"
def main():
app = QtGui.QApplication(sys.argv)
ex = Example()
ex.setGeometry(300, 300, 300, 200)
ex.setWindowTitle('Toolbar example')
ex.show()
sys.exit(app.exec_())
if __name__ == '__main__':
main()
The QMainWindow class already has APIs for this: i.e. saveState and restoreState. These can be used to save and restore the state of all the toolbars and dock-widgets in your application.
To use them, you first need to make sure that all your toolbars and dock-widgets are given a unique object-name when they are created:
class Example(QtGui.QMainWindow):
...
def initUI(self):
...
self.toolbar = QtGui.QToolBar(self)
self.toolbar.setObjectName('foobar')
Then you can override closeEvent to save the state:
class Example(QtGui.QMainWindow):
...
def closeEvent(self, event):
with open('/tmp/test.conf', 'wb') as stream:
stream.write(self.saveState().data())
(NB: I've just used a temporary file here for testing, but it would obviously be much better to use something like QSettings in your real application).
Finally, you can restore the state that was saved previously:
class Example(QtGui.QMainWindow):
def __init__(self, parent=None):
...
self.initUI()
try:
with open('/tmp/test.conf', 'rb') as stream:
self.restoreState(QtCore.QByteArray(stream.read()))
except IOError:
pass
I am using PyQt4 for creating a custom browser using QtWebKit, but I am stuck on saving bookmarks from the browser. Does anyone know how to achieve that?
You're a little vague on how you want this done, so I'll say we wanted to use a button imported from a UI file called bookmarks_Btn. You'll need to use the pickle module.
Here's the example code...
from PyQt4 import QtCore, QtGui, QtWebKit, uic
import pickle
class window(QtGui.QWidget):
def __init__(self, parent=None):
super(httpWidget, self).__init__(parent)
self.ui = uic.loadUi('mybrowser.ui')
self.ui.setupUi(self)
def bookmarksLoad(self):
print 'Loading bookmarks'
try:
bookOpen = open('bookmarks.txt', 'rb')
bookmarks = pickle.load(bookOpen)
bookOpen.close()
print bookmarks # Not necessary, but for example purposes
# Here you decide how "bookmarks" variable is displayed.
except:
bookOpen = open('bookmarks.txt', 'wb')
bookmarks = 'http://www.stackoverflow.com'
bookWrite = pickle.dump(bookmarks, bookOpen)
bookOpen.close()
print bookmarks # Not necessary, but for example purposes
# Here you decide how "bookmarks" variable is displayed.
QtCore.QObject.connect(self.ui.bookmarks_Btn, QtCore.SIGNAL('clicked()'), self.bookmarksLoad)
self.ui.show()
def bookmarks():
url = input 'Enter a URL: '
bookOpen = open('bookmarks.txt', 'wb')
bookOpen.write(url)
bookOpen.close()
print 'Website bookmarked!'
if __name__ == '__main__':
app = QtGui.QApplication(sys.argv)
run = window()
bookmarks()
sys.exit(app.exec_())
# You add on here, for example, deleting bookmarks.
However, if you wanted it to be retrieved from an address bar (named address, make the following changes...
# In the bookmarks function...
global url # Add at beginning
# Remove the input line.
# Add at end of __init__ in window class:
url = self.ui.address.text()
global url
That's pretty much the basics. Please note I normally program in Python 3 and PyQt5 so if there are any errors let me know :)
I have a PhotoImage in tkinter called al_p4 but I want to be able to print the file path of the image. Can anyone help. Here is my code:
al_p4 = Image.open("Media/DVD/image.jpg").resize((100, 150), Image.ANTIALIAS)
al_p4 = ImageTk.PhotoImage(al_p4)
Thanks in advance guys ;)
Because I'm still having trouble interpreting exactly what you mean, here are four different answers regarding how to go about printing.
If you simply need to print it and the path will always be constant, use:
print("Media/DVD/image.jpg")
If you need to print something and the path will be different, try:
filepath = "Media/DVD/image.jpg"
al_p4 = Image.open(filepath).resize((100, 150), Image.ANTIALIAS)
al_p4 = ImageTk.PhotoImage(al_p4)
print(filepath)
If you need to print something to a widget, it's going to depend on the kind of widget you want to use. For something small like a file path, a label would probably be good. Look at effbot's documentation for the label widget for more details.
If you want to redirect all print statements to a widget, which can be useful depending on how your GUI is designed, create a class to redirect stdout. Here's an example with a text widget:
import sys
import Tkinter
def nothing():
print("Nothing")
class Application(Tkinter.Frame):
def __init__(self, master = None):
Tkinter.Frame.__init__(self, master)
self.button = Tkinter.Button(text = "Button 1", command = nothing)
self.button.pack()
class StdoutRedirector(Tkinter.Text):
def __init__(self):
Tkinter.Text.__init__(self)
def write(self, message):
printout.insert(Tkinter.END, message)
printout = StdoutRedirector()
printout.pack()
sys.stdout = printout
root = Tkinter.Tk()
app = Application(root)
app.mainloop()
I'm new to coding, so I'll try the best I can =)
Quick answer:
You need to use .filename in the PIL object (Don't works on TK object)
#This is the image:
al_p4 = Image.open("Media/DVD/image.jpg").resize((100, 150), Image.ANTIALIAS)
#This is to show in Tkinter, Notice I added ..._TK
al_p4_TK = ImageTk.PhotoImage(al_p4)
#This is the filepath I think you want:
print(al_p4.filename)