How to use regex with Swift? - regex

Question

I am making an app in Swift and I need to catch 8 numbers from a string.
Here's the string:
index.php?page=index&l=99182677
My pattern is:
&l=(\d{8,})
And here's my code:
var yourAccountNumber = "index.php?page=index&l=99182677"
let regex = try! NSRegularExpression(pattern: "&l=(\\d{8,})", options: NSRegularExpressionOptions.CaseInsensitive)
let range = NSMakeRange(0, yourAccountNumber.characters.count)
let match = regex.matchesInString(yourAccountNumber, options: NSMatchingOptions.Anchored, range: range)
Firstly, I don't know what the NSMatchingOptions means, on the official Apple library, I don't get all the .Anchored, .ReportProgress, etc stuff. Anyone would be able to lighten me up on this?
Then, when I print(match), nothing seems to contain on that variable ([]).
I am using Xcode 7 Beta 3, with Swift 2.0.

Answer 1

ORIGINAL ANSWER
Here is a function you can leverage to get captured group texts:
import Foundation
extension String {
func firstMatchIn(string: NSString!, atRangeIndex: Int!) -> String {
var error : NSError?
let re = NSRegularExpression(pattern: self, options: .CaseInsensitive, error: &error)
let match = re.firstMatchInString(string, options: .WithoutAnchoringBounds, range: NSMakeRange(0, string.length))
return string.substringWithRange(match.rangeAtIndex(atRangeIndex))
}
}
And then:
var result = "&l=(\\d{8,})".firstMatchIn(yourAccountNumber, atRangeIndex: 1)
The 1 in atRangeIndex: 1 will extract the text captured by (\d{8,}) capture group.
NOTE1: If you plan to extract 8, and only 8 digits after &l=, you do not need the , in the limiting quantifier, as {8,} means 8 or more. Change to {8} if you plan to capture just 8 digits.
NOTE2: NSMatchingAnchored is something you would like to avoid if your expected result is not at the beginning of a search range. See documentation:
Specifies that matches are limited to those at the start of the search range.
NOTE3: Speaking about "simplest" things, I'd advise to avoid using look-arounds whenever you do not have to. Look-arounds usually come at some cost to performance, and if you are not going to capture overlapping text, I'd recommend to use capture groups.
UPDATE FOR SWIFT 2
I have come up with a function that will return all matches with all capturing groups (similar to preg_match_all in PHP). Here is a way to use it for your scenario:
func regMatchGroup(regex: String, text: String) -> [[String]] {
do {
var resultsFinal = [[String]]()
let regex = try NSRegularExpression(pattern: regex, options: [])
let nsString = text as NSString
let results = regex.matchesInString(text,
options: [], range: NSMakeRange(0, nsString.length))
for result in results {
var internalString = [String]()
for var i = 0; i < result.numberOfRanges; ++i{
internalString.append(nsString.substringWithRange(result.rangeAtIndex(i)))
}
resultsFinal.append(internalString)
}
return resultsFinal
} catch let error as NSError {
print("invalid regex: \(error.localizedDescription)")
return [[]]
}
}
// USAGE:
let yourAccountNumber = "index.php?page=index&l=99182677"
let matches = regMatchGroup("&l=(\\d{8,})", text: yourAccountNumber)
if (matches.count > 0) // If we have matches....
{
print(matches[0][1]) // Print the first one, Group 1.
}

Answer 2

It may be easier just to use the NSString method instead of NSRegularExpression.
var yourAccountNumber = "index.php?page=index&l=99182677"
println(yourAccountNumber) // index.php?page=index&l=99182677
let regexString = "(?<=&l=)\\d{8,}+"
let options :NSStringCompareOptions = .RegularExpressionSearch | .CaseInsensitiveSearch
if let range = yourAccountNumber.rangeOfString(regexString, options:options) {
let digits = yourAccountNumber.substringWithRange(range)
println("digits: \(digits)")
}
else {
print("Match not found")
}
The (?<=&l=) means precedes but not part of.
In detail:
Look-behind assertion. True if the parenthesized pattern matches text preceding the current input position, with the last character of the match being the input character just before the current position. Does not alter the input position. The length of possible strings matched by the look-behind pattern must not be unbounded (no * or + operators.)
In general performance considerations of a look-behind without instrumented proof is just premature optimization. That being said there may be other valid reasons for and against look-arounds in regular expressions.
ICU User Guide: Regular Expressions

Answer 3

For Swift 2, you can use this extension of String:
import Foundation
extension String {
func firstMatchIn(string: NSString!, atRangeIndex: Int!) -> String {
do {
let re = try NSRegularExpression(pattern: self, options: NSRegularExpressionOptions.CaseInsensitive)
let match = re.firstMatchInString(string as String, options: .WithoutAnchoringBounds, range: NSMakeRange(0, string.length))
return string.substringWithRange(match!.rangeAtIndex(atRangeIndex))
} catch {
return ""
}
}
}
You can get the account-number with:
var result = "&l=(\\d{8,})".firstMatchIn(yourAccountNumber, atRangeIndex: 1)

Answer 4

Replace NSMatchingOptions.Anchored with NSMatchingOptions() (no options)