The following code doesn't give the second prompt to "enter message". How do I fix it?
cout << "Enter shifts:" << endl;
cin >> shifts;
cout << "Enter message:" << endl;
getline(cin, msg);
try this one
cout << "Enter shifts:" << endl;
cin >> shifts;
cout << "Enter message:" << endl;
cin.ignore();
getline(cin, msg);
use cin.ignore(); before using getline anywhere.
when you enter shifts there is a newline which read by geline funtion. So You need to ignore that newline.
write :
cout << "Enter shifts:" << endl;
cin >> shifts;
getchar();
cout << "Enter message:" << endl;
getline(cin, msg);
Related
I want to read strings with white spaces into members of a structure. Tried using getline but both the output statements are clubbed with a single cin for both. As per the similar posts here, tried using cin.ignore, but the input is not read into the member of the structure. Pls help. It's a part of my assignment and I'm a beginner in C++. This is how my code looks like:
#include <string.h>
using namespace std;
struct book {
string title, author;
int no_of_pages, year;
float price;
};
int main() {
int N;
cout << "Enter the no. of books whose details are to be entered:" << endl;
cin >> N;
book b[N];
int x;
for (x = 0; x < N; x++) {
cout << "Enter the title of book #" << x + 1 << ":" << endl;
getline(cin, (b[x].title));
// cin.ignore();
cin.ignore(1000, '\n');
cout << "Enter the author's name:" << endl;
getline(cin, (b[x].author));
cout << "Enter the no. of pages:" << endl;
cin >> b[x].no_of_pages;
cout << "Enter the price of book:" << endl;
cin >> b[x].price;
cout << "Enter the year of publishing" << endl;
cin >> b[x].year;
}
for (x = 0; x < N; x++) {
cout << "\n\n";
cout << "The details of book" << x + 1 << " are:" << endl;
cout << "Title :" << b[x].title << endl;
cout << "Author :" << b[x].author << endl;
cout << "No. of pages :" << b[x].no_of_pages << endl;
cout << "Price :" << b[x].price << endl;
cout << "Publishing year:" << b[x].year << endl;
cout << "---------------------------------------------";
}
return 0;
}
There's no point in using cin.ignore() in between two calls to getline. ignore is used to discard remaining characters after numeric input. So the place to use it is after numeric input and before the next getline. Like this
cout << "Enter the title of book #" << x + 1 << ":" << endl;
getline(cin, (b[x].title));
cout << "Enter the author's name:" << endl;
getline(cin, (b[x].author));
cout << "Enter the no. of pages:" << endl;
cin >> b[x].no_of_pages;
cout << "Enter the price of book:" << endl;
cin >> b[x].price;
cout << "Enter the year of publishing" << endl;
cin >> b[x].year;
cin.ignore(1000, '\n');
That said I would just read everything using getline, then convert the strings to numbers where needed. That's simpler and cleaner, all you need to know is how to convert a string to an integer, which you can easily research for yourself.
There are two places you should put cin.ignore in your code:
cout << "Enter the no. of books whose details are to be entered:" << endl;
cin >> N;
// First cin.ignore here
cin.ignore(1000, '\n');
cout << "Enter the year of publishing" << endl;
cin >> b[x].year;
// Second cin.ignore here
cin.ignore(1000, '\n');
Besides this I see two more problems in your code:
#include <string> not <string.h>
add #include <iostream>
Why cin.ignore is necessary? User is expected to provide new line ('\n') delimited input. When getline is used, it leaves the input stream in such a state that the next attempt to read input from stream will start at next line. This is not true for operator >>. What int x; cin >> x; does here is it reads only the integer not the new line character present right after the integer. Hence, the next attempt to read will continue within the same line. getline will then find no character before new line and hence will fetch an empty string. To avoid this and to effectively start reading from the next line, cin.ignore is necessary.
I am trying to make a program that will take a users input to make multiple forms. I am stuck on trying to get the vector (that will be filled with objects of the form class that the user creates) to be use-able in other functions. When I use the address-of operator (&) it gives me this error when the program gets to letting the user input the data to the objects.
This is the screen capture of the program and the error.
#include "pch.h"
#include <iostream>
#include <string>
#include <vector>
using namespace std;
class Form {
public:
string Fname;
string Lname;
string City;
string Street;
string State;
string ZipCode;
};
void menuMain();
void menu1st(vector<Form> &Fvect);
void menu1st(vector<Form> &Fvect)
{
int MainM;
int n;
cout << "NEW FORM(s)" << endl;
cout << "Enter the number of forms you would like to make (Maximum of 5): "; cin >> n; cout << endl;
for (int i = 0; i < n; i++)
{
cout << "First Name: "; cin >> Fvect[i].Fname; cout << endl;
cout << "Last Name: "; cin >> Fvect[i].Lname; cout << endl;
cout << "City: "; cin >> Fvect[i].City; cout << endl;
cout << "Street: "; cin >> Fvect[i].Street; cout << endl;
cout << "State: "; cin >> Fvect[i].State; cout << endl;
cout << "Zip Code: "; cin >> Fvect[i].ZipCode; cout << endl;
}
cout << "Enter 1 to go back to main: "; cin >> MainM;
if (MainM == 1)
{
menuMain();
}
else
{
cout << "Error not a correct input." << endl;
}
}
void menu2nd()
{
int MainM;
//int Fnum;
vector<Form> Fvect;
cout << "EDIT A FORM" << endl;
cout << Fvect[1].Fname;
cout << "Enter the ";
cout << "Enter 1 to go back to main: "; cin >> MainM;
if (MainM == 1)
{
menuMain();
}
else
{
cout << "Error not a correct input." << endl;
}
}
void menuMain()
{
int Pnum;
cout << "INFORMATION FORMATTING PROGRAM" << endl;
cout << "1. Create new form's." << endl;
cout << "2. Edit a form." << endl;
cout << "3. Print forms." << endl;
cout << "4. Erase a form." << endl;
cout << "5. Exit Program." << endl;
cout << "Enter the action you want to take (1-5): "; cin >> Pnum;
vector<Form> Fvect;
if (Pnum == 1)
{
menu1st(Fvect);
}
if (Pnum == 2)
{
menu2nd();
}
else
{
cout << "Error not a correct input." << endl;
}
}
int main()
{
menuMain();
}
You are accessing Fvect using an invalid index in the following lines:
cout << "First Name: "; cin >> Fvect[i].Fname; cout << endl;
cout << "Last Name: "; cin >> Fvect[i].Lname; cout << endl;
cout << "City: "; cin >> Fvect[i].City; cout << endl;
cout << "Street: "; cin >> Fvect[i].Street; cout << endl;
cout << "State: "; cin >> Fvect[i].State; cout << endl;
cout << "Zip Code: "; cin >> Fvect[i].ZipCode; cout << endl;
Consequently, your program has undefined behavior.
You need to have items in a std::vector before you can access an item from it using the array syntax. What you need to do is:
Read the data to an object of type Form.
Add the object to the std::vector.
Replace those lines with:
Form form;
cout << "First Name: "; cin >> form.Fname; cout << endl;
cout << "Last Name: "; cin >> form.Lname; cout << endl;
cout << "City: "; cin >> form.City; cout << endl;
cout << "Street: "; cin >> form.Street; cout << endl;
cout << "State: "; cin >> form.State; cout << endl;
cout << "Zip Code: "; cin >> form.ZipCode; cout << endl;
Fvect.push_back(form);
PS
I am not sure why you have the cout << endl; in those lines. You don't need them. It will be sufficient to use:
cout << "First Name: "; cin >> form.Fname;
cout << "Last Name: "; cin >> form.Lname;
cout << "City: "; cin >> form.City;
cout << "Street: "; cin >> form.Street;
cout << "State: "; cin >> form.State;
cout << "Zip Code: "; cin >> form.ZipCode;
I wrote this code. It works in the main function
cout << "Enter the patron's name: ";
getline(std::cin, patron.name);
cout << "Enter the book title: ";
getline(std::cin, book.title);
cout << book.title << " is now checked out to " << patron.name << endl;
However, when I put it under a do while loop with switch case, it does not work anymore.
do {
cout << endl << "? "; cin >> choice;
switch (toupper(choice)){
case 'T':
cout << "Enter the patron's name: ";
getline(std::cin, patron.name);
cout << "Enter the book title: ";
getline(std::cin, book.title);
cout << book.title << " is now checked out to " << patron.name << endl;
break;
}[enter image description here][1]
} while (choice != 'Q' && choice!= 'q');
The input was like:
Could anyone explain to me why this happened? Thanks
After this statement
cout << endl << "? "; cin >> choice;
insert
std::cin.ignore( std::numeric_limits<std::streamsize>::max(), '\n' );
to remove the new line character (that corresponds to the pressed Enter key after the input) that is still in the input buffer, Otherwise a call of getline will read an empty string.
You should include the header <limits> to use the class numeric_limits
This \n after T(your input) is being consumed by getline. That's why you are getting such behaviour. You need to flush the newline out of the buffer.
You can do this by adding this statement as shown.
std::cin.ignore (std::numeric_limits<std::streamsize>::max(), '\n');
cout << "Enter the patron's name: ";
I have looked around and can't seem to find an answer to this. I am new to C++ and am attempting to write a program for a class that asks the user for the first and last names of 4 students and their ages. The program will then display the input names and ages and also display the average of the ages.
The issue I am having is that the program allows for input of the first name and age but then skips over the remaining three name input fields and only allows for the remaining three ages to be input.
I apologize if this ends up being a dumb question but I really am at a loss. Any help will be greatly appreciated.
Here is the code I have thus far:
#include <iostream>
#include <string>
using namespace std;
int main()
{
string studentname1;
cout << "Please enter the first student's full name:" << endl;
getline(cin, studentname1);
int age1;
cout << "Please enter the first student's age:" << endl;
cin >> age1;
string studentname2;
cout << "Please enter the second student's full name:" << endl;
getline(cin, studentname2);
int age2;
cout << "Please enter the second student's age:" << endl;
cin >> age2;
string studentname3;
cout << "Please enter the third student's full name:" << endl;
getline(cin, studentname2);
int age3;
cout << "Please enter the third student's age:" << endl;
cin >> age3;
string studentname4;
cout << "Please enter the fourth student's full name:" << endl;
getline(cin, studentname2);
int age4;
cout << "Please enter the fourth student's age:" << endl;
cin >> age4;
cout << "Hello from our group." << endl;
cout << "NAME AGE" << endl;
cout << studentname1 << " " << age1 << endl;
cout << studentname2 << " " << age2 << endl;
cout << studentname3 << " " << age3 << endl;
cout << studentname4 << " " << age4 << endl;
cout << "The average of all our ages is: " << (age1 + age2 + age3 + age4) / 4.00 << endl;
return 0;
}
Since the age variables are int, the cin >> age1; will leave the newline character in the input stream. When next you call getline(), you will get the remainder of that line - which is empty, and so on.
Also, you have a copy-paste bug in your code. getline(cint, studentname2); is run for students 2, 3 and 4.
You can either solve the problem by using getline() for all input:
string agestring;
getline(cin, agestring)
stringstream(agestring) >> age1;
or clear cin when you're done reading the age:
cin >> age1;
cin.ignore();
my program seems to want to enter two inputs for name variable instead of just entering one thing and moving on to phone number?
i'm sure its simple but can someone help me fix this please? is it something it do with the getline?
#include <iostream>
#include <string>
#include <vector>
using namespace std;
//define Car struct
struct Speaker
{
string name;
string phoneNumber;
string emailAddress;
string theme;
double fee;
};
Speaker *getSpeaker();
int main()
{
Speaker thespeaker;
thespeaker = *getSpeaker();
cout << "The speaker entered is!" << endl;
cout << thespeaker.name << endl;
cout << "phone number: " << thespeaker.phoneNumber << endl;
cout << "email: " << thespeaker.emailAddress << endl;
cout << "theme: " << thespeaker.theme << endl;
cout << "fees: " << thespeaker.fee << endl;
}
Speaker *getSpeaker()
{
Speaker *theSpeaker;
theSpeaker = new Speaker;
cout << "Please enter Speakers information" << endl;
cout << "name: " ;
getline(cin, theSpeaker->name);
cin.ignore(100, '\n');
cin.clear();
cout << theSpeaker->name;
cout << "\nphone number: ";
cin >> theSpeaker->phoneNumber;
cout << "\nEmail Address: ";
cin >> theSpeaker->emailAddress;
cout << "\nTheme: ";
cin >> theSpeaker->theme;
cout << "\nFee: ";
cin >>theSpeaker->fee;
return theSpeaker;
}
There's no need for cin.ignore();
Simply write it as:
Speaker *getSpeaker()
{
Speaker *theSpeaker;
theSpeaker = new Speaker;
cout << "Please enter Speakers information" << endl;
cout << "name: " ;
getline(cin, theSpeaker->name);
cout << theSpeaker->name;
cout << "\nphone number: ";
cin >> theSpeaker->phoneNumber;
cout << "\nEmail Address: ";
cin >> theSpeaker->emailAddress;
cout << "\nTheme: ";
cin >> theSpeaker->theme;
cout << "\nFee: ";
cin >>theSpeaker->fee;
return theSpeaker;
}